$reduce and $setUnion for nested arrays in MongoDB





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I am looking to merge nested arrays using $reduce and $setUnion in MongoDB. Following is the sample input -



levels: [
[[80,100,120]],[[100,150]],[[200,80,100]],[[80,100]]
]


The output what I am intended to get (i.e. merge nested arrays with unique values) -
levels: [80,100,120,150,100]



I am able to get the above output using two ways -



1) Using two $project stages in pipeline -



aggregate([
$project: { levels : { $reduce: {
input: "$levels", initialValue: , in:{$setUnion:["$$value","$$this"]}}}},
$project: { levels : { $reduce: {
input: "$levels", initialValue: , in:{$setUnion:["$$value","$$this"]}}}}
])


2) First $unwind and then $project



aggregate([
$unwind: { '$levels'}},
$project: { levels : { $reduce: {
input: "$levels", initialValue: , in:{$setUnion:["$$value","$$this"]}}}}
])


Can there be any improved way of first option where I don't need to use the same $project twice? I am trying to avoid unwind.










share|improve this question





























    1















    I am looking to merge nested arrays using $reduce and $setUnion in MongoDB. Following is the sample input -



    levels: [
    [[80,100,120]],[[100,150]],[[200,80,100]],[[80,100]]
    ]


    The output what I am intended to get (i.e. merge nested arrays with unique values) -
    levels: [80,100,120,150,100]



    I am able to get the above output using two ways -



    1) Using two $project stages in pipeline -



    aggregate([
    $project: { levels : { $reduce: {
    input: "$levels", initialValue: , in:{$setUnion:["$$value","$$this"]}}}},
    $project: { levels : { $reduce: {
    input: "$levels", initialValue: , in:{$setUnion:["$$value","$$this"]}}}}
    ])


    2) First $unwind and then $project



    aggregate([
    $unwind: { '$levels'}},
    $project: { levels : { $reduce: {
    input: "$levels", initialValue: , in:{$setUnion:["$$value","$$this"]}}}}
    ])


    Can there be any improved way of first option where I don't need to use the same $project twice? I am trying to avoid unwind.










    share|improve this question

























      1












      1








      1








      I am looking to merge nested arrays using $reduce and $setUnion in MongoDB. Following is the sample input -



      levels: [
      [[80,100,120]],[[100,150]],[[200,80,100]],[[80,100]]
      ]


      The output what I am intended to get (i.e. merge nested arrays with unique values) -
      levels: [80,100,120,150,100]



      I am able to get the above output using two ways -



      1) Using two $project stages in pipeline -



      aggregate([
      $project: { levels : { $reduce: {
      input: "$levels", initialValue: , in:{$setUnion:["$$value","$$this"]}}}},
      $project: { levels : { $reduce: {
      input: "$levels", initialValue: , in:{$setUnion:["$$value","$$this"]}}}}
      ])


      2) First $unwind and then $project



      aggregate([
      $unwind: { '$levels'}},
      $project: { levels : { $reduce: {
      input: "$levels", initialValue: , in:{$setUnion:["$$value","$$this"]}}}}
      ])


      Can there be any improved way of first option where I don't need to use the same $project twice? I am trying to avoid unwind.










      share|improve this question














      I am looking to merge nested arrays using $reduce and $setUnion in MongoDB. Following is the sample input -



      levels: [
      [[80,100,120]],[[100,150]],[[200,80,100]],[[80,100]]
      ]


      The output what I am intended to get (i.e. merge nested arrays with unique values) -
      levels: [80,100,120,150,100]



      I am able to get the above output using two ways -



      1) Using two $project stages in pipeline -



      aggregate([
      $project: { levels : { $reduce: {
      input: "$levels", initialValue: , in:{$setUnion:["$$value","$$this"]}}}},
      $project: { levels : { $reduce: {
      input: "$levels", initialValue: , in:{$setUnion:["$$value","$$this"]}}}}
      ])


      2) First $unwind and then $project



      aggregate([
      $unwind: { '$levels'}},
      $project: { levels : { $reduce: {
      input: "$levels", initialValue: , in:{$setUnion:["$$value","$$this"]}}}}
      ])


      Can there be any improved way of first option where I don't need to use the same $project twice? I am trying to avoid unwind.







      mongodb mongodb-query aggregation-framework






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      asked Nov 29 '18 at 5:37









      AkashAkash

      19519




      19519
























          1 Answer
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          You can use below aggregation with single $project stage



          db.collection.aggregate([
          { "$project": {
          "levels": {
          "$reduce": {
          "input": {
          "$reduce": {
          "input": "$levels",
          "initialValue": ,
          "in": { "$setUnion": ["$$this", "$$value"] }
          }
          },
          "initialValue": ,
          "in": { "$setUnion": ["$$this", "$$value"] }
          }
          }
          }}
          ])





          share|improve this answer





















          • 1





            Thank you @Anthony. It is working as expected!

            – Akash
            Nov 29 '18 at 6:11












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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          1














          You can use below aggregation with single $project stage



          db.collection.aggregate([
          { "$project": {
          "levels": {
          "$reduce": {
          "input": {
          "$reduce": {
          "input": "$levels",
          "initialValue": ,
          "in": { "$setUnion": ["$$this", "$$value"] }
          }
          },
          "initialValue": ,
          "in": { "$setUnion": ["$$this", "$$value"] }
          }
          }
          }}
          ])





          share|improve this answer





















          • 1





            Thank you @Anthony. It is working as expected!

            – Akash
            Nov 29 '18 at 6:11
















          1














          You can use below aggregation with single $project stage



          db.collection.aggregate([
          { "$project": {
          "levels": {
          "$reduce": {
          "input": {
          "$reduce": {
          "input": "$levels",
          "initialValue": ,
          "in": { "$setUnion": ["$$this", "$$value"] }
          }
          },
          "initialValue": ,
          "in": { "$setUnion": ["$$this", "$$value"] }
          }
          }
          }}
          ])





          share|improve this answer





















          • 1





            Thank you @Anthony. It is working as expected!

            – Akash
            Nov 29 '18 at 6:11














          1












          1








          1







          You can use below aggregation with single $project stage



          db.collection.aggregate([
          { "$project": {
          "levels": {
          "$reduce": {
          "input": {
          "$reduce": {
          "input": "$levels",
          "initialValue": ,
          "in": { "$setUnion": ["$$this", "$$value"] }
          }
          },
          "initialValue": ,
          "in": { "$setUnion": ["$$this", "$$value"] }
          }
          }
          }}
          ])





          share|improve this answer















          You can use below aggregation with single $project stage



          db.collection.aggregate([
          { "$project": {
          "levels": {
          "$reduce": {
          "input": {
          "$reduce": {
          "input": "$levels",
          "initialValue": ,
          "in": { "$setUnion": ["$$this", "$$value"] }
          }
          },
          "initialValue": ,
          "in": { "$setUnion": ["$$this", "$$value"] }
          }
          }
          }}
          ])






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Nov 29 '18 at 5:49

























          answered Nov 29 '18 at 5:43









          Anthony WinzletAnthony Winzlet

          18.3k42346




          18.3k42346








          • 1





            Thank you @Anthony. It is working as expected!

            – Akash
            Nov 29 '18 at 6:11














          • 1





            Thank you @Anthony. It is working as expected!

            – Akash
            Nov 29 '18 at 6:11








          1




          1





          Thank you @Anthony. It is working as expected!

          – Akash
          Nov 29 '18 at 6:11





          Thank you @Anthony. It is working as expected!

          – Akash
          Nov 29 '18 at 6:11




















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