How do I implement collision detection?
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from graphics import*
import time
import random
def main():
numx=random.randint(10,700)
wn=GraphWin("AK",700,700)
wn.setBackground("white")
msg=Text(Point(25,30),"Score")
msg.setSize(12)
msg.setTextColor('blue')
msg.draw(wn)
inch=Entry(Point(60,30),2)
inch.setFill('white')
inch.draw(wn)
sqrg=Rectangle(Point(330,650),Point(430,665))
sqrg.setFill("red")
sqrg.draw(wn)
blx=Circle(Point(numx,80),20)
blx.setFill("blue")
blx.draw(wn)
xval=10
yval=0
wn.getMouse()
for i in range(150):
sqrg.move(xval,yval)
symbl=wn.checkKey()
if symbl=="Right":
xval=10
yval=0
if symbl=="Left":
xval=-10
yval=0
time.sleep(0.08)
blx.move(0,20)
main()
I'm very confused my professor is very confusing, and I need to do this for a project where when collision is detected the score goes up.
python python-3.x collision-detection zelle-graphics
edited Nov 23 '18 at 21:11
cdlane
20k21245
asked Nov 21 '18 at 22:54
joseph vivianojoseph viviano
122
add a comment |
from graphics import*
import time
import random
def main():
numx=random.randint(10,700)
wn=GraphWin("AK",700,700)
wn.setBackground("white")
msg=Text(Point(25,30),"Score")
msg.setSize(12)
msg.setTextColor('blue')
msg.draw(wn)
inch=Entry(Point(60,30),2)
inch.setFill('white')
inch.draw(wn)
sqrg=Rectangle(Point(330,650),Point(430,665))
sqrg.setFill("red")
sqrg.draw(wn)
blx=Circle(Point(numx,80),20)
blx.setFill("blue")
blx.draw(wn)
xval=10
yval=0
wn.getMouse()
for i in range(150):
sqrg.move(xval,yval)
symbl=wn.checkKey()
if symbl=="Right":
xval=10
yval=0
if symbl=="Left":
xval=-10
yval=0
time.sleep(0.08)
blx.move(0,20)
main()
I'm very confused my professor is very confusing, and I need to do this for a project where when collision is detected the score goes up.
python python-3.x collision-detection zelle-graphics
edited Nov 23 '18 at 21:11
cdlane
20k21245
asked Nov 21 '18 at 22:54
joseph vivianojoseph viviano
122
Looks like if you know the location of sqrg and blx with the dimensions, you should be able to determine if those points intersect each iteration.
– bison
Nov 21 '18 at 23:00
add a comment |
from graphics import*
import time
import random
def main():
numx=random.randint(10,700)
wn=GraphWin("AK",700,700)
wn.setBackground("white")
msg=Text(Point(25,30),"Score")
msg.setSize(12)
msg.setTextColor('blue')
msg.draw(wn)
inch=Entry(Point(60,30),2)
inch.setFill('white')
inch.draw(wn)
sqrg=Rectangle(Point(330,650),Point(430,665))
sqrg.setFill("red")
sqrg.draw(wn)
blx=Circle(Point(numx,80),20)
blx.setFill("blue")
blx.draw(wn)
xval=10
yval=0
wn.getMouse()
for i in range(150):
sqrg.move(xval,yval)
symbl=wn.checkKey()
if symbl=="Right":
xval=10
yval=0
if symbl=="Left":
xval=-10
yval=0
time.sleep(0.08)
blx.move(0,20)
main()
I'm very confused my professor is very confusing, and I need to do this for a project where when collision is detected the score goes up.
python python-3.x collision-detection zelle-graphics
edited Nov 23 '18 at 21:11
cdlane
20k21245
asked Nov 21 '18 at 22:54
joseph vivianojoseph viviano
122
from graphics import*
import time
import random
def main():
numx=random.randint(10,700)
wn=GraphWin("AK",700,700)
wn.setBackground("white")
msg=Text(Point(25,30),"Score")
msg.setSize(12)
msg.setTextColor('blue')
msg.draw(wn)
inch=Entry(Point(60,30),2)
inch.setFill('white')
inch.draw(wn)
sqrg=Rectangle(Point(330,650),Point(430,665))
sqrg.setFill("red")
sqrg.draw(wn)
blx=Circle(Point(numx,80),20)
blx.setFill("blue")
blx.draw(wn)
xval=10
yval=0
wn.getMouse()
for i in range(150):
sqrg.move(xval,yval)
symbl=wn.checkKey()
if symbl=="Right":
xval=10
yval=0
if symbl=="Left":
xval=-10
yval=0
time.sleep(0.08)
blx.move(0,20)
main()
I'm very confused my professor is very confusing, and I need to do this for a project where when collision is detected the score goes up.
python python-3.x collision-detection zelle-graphics
python python-3.x collision-detection zelle-graphics
edited Nov 23 '18 at 21:11
cdlane
20k21245
asked Nov 21 '18 at 22:54
joseph vivianojoseph viviano
122
edited Nov 23 '18 at 21:11
cdlane
20k21245
asked Nov 21 '18 at 22:54
joseph vivianojoseph viviano
122
edited Nov 23 '18 at 21:11
cdlane
20k21245
edited Nov 23 '18 at 21:11
cdlane
20k21245
edited Nov 23 '18 at 21:11
cdlane
20k21245
20k21245
asked Nov 21 '18 at 22:54
joseph vivianojoseph viviano
122
asked Nov 21 '18 at 22:54
joseph vivianojoseph viviano
122
asked Nov 21 '18 at 22:54
joseph vivianojoseph viviano
122
122
Looks like if you know the location of sqrg and blx with the dimensions, you should be able to determine if those points intersect each iteration.
– bison
Nov 21 '18 at 23:00
add a comment |
Looks like if you know the location of sqrg and blx with the dimensions, you should be able to determine if those points intersect each iteration.
– bison
Nov 21 '18 at 23:00
Looks like if you know the location of sqrg and blx with the dimensions, you should be able to determine if those points intersect each iteration.
– bison
Nov 21 '18 at 23:00
Looks like if you know the location of sqrg and blx with the dimensions, you should be able to determine if those points intersect each iteration.
– bison
Nov 21 '18 at 23:00
add a comment |
2 Answers
2
active
oldest
votes
Your radius is twenty. Inside the loop, just test whether Euclidean distance between sqrg and blx is within 20.
answered Nov 22 '18 at 1:45
J_HJ_H
4,5461922
add a comment |
Below is a stripped down example based on your code. It measures the distance between the centers of the two moving objects to determine if a collision has occurred. If you manage to get the ball to hit the square, the ball should bounce straight up:
from random import randint
from time import sleep
from graphics import *
def distance(p1, p2):
return ((p2.x - p1.x) ** 2 + (p2.y - p1.y) ** 2) ** 0.5
wn = GraphWin("AK", 700, 700)
sqrg = Rectangle(Point(325, 625), Point(375, 675))
sqrg.setFill("red")
sqrg.draw(wn)
numx = randint(10, 700)
blx = Circle(Point(numx, 80), 20)
blx.setFill("blue")
blx.draw(wn)
xval, yval = 10, 0
bheading = 1
wn.getMouse()
for i in range(150):
sqrg.move(xval, yval)
if distance(blx.getCenter(), sqrg.getCenter()) < 25:
bheading *= -1
symbl = wn.checkKey()
if symbl == "Right":
xval = 10
elif symbl == "Left":
xval = -10
sleep(0.1)
blx.move(0, bheading * 20)
Cleary not a viable game as-is, but a demonstration of collision detection.
answered Nov 23 '18 at 21:10
cdlanecdlane
20k21245
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Your radius is twenty. Inside the loop, just test whether Euclidean distance between sqrg and blx is within 20.
answered Nov 22 '18 at 1:45
J_HJ_H
4,5461922
add a comment |
Your radius is twenty. Inside the loop, just test whether Euclidean distance between sqrg and blx is within 20.
answered Nov 22 '18 at 1:45
J_HJ_H
4,5461922
add a comment |
Your radius is twenty. Inside the loop, just test whether Euclidean distance between sqrg and blx is within 20.
answered Nov 22 '18 at 1:45
J_HJ_H
4,5461922
Your radius is twenty. Inside the loop, just test whether Euclidean distance between sqrg and blx is within 20.
answered Nov 22 '18 at 1:45
J_HJ_H
4,5461922
answered Nov 22 '18 at 1:45
J_HJ_H
4,5461922
answered Nov 22 '18 at 1:45
J_HJ_H
4,5461922
answered Nov 22 '18 at 1:45
J_HJ_H
4,5461922
4,5461922
add a comment |
add a comment |
Below is a stripped down example based on your code. It measures the distance between the centers of the two moving objects to determine if a collision has occurred. If you manage to get the ball to hit the square, the ball should bounce straight up:
from random import randint
from time import sleep
from graphics import *
def distance(p1, p2):
return ((p2.x - p1.x) ** 2 + (p2.y - p1.y) ** 2) ** 0.5
wn = GraphWin("AK", 700, 700)
sqrg = Rectangle(Point(325, 625), Point(375, 675))
sqrg.setFill("red")
sqrg.draw(wn)
numx = randint(10, 700)
blx = Circle(Point(numx, 80), 20)
blx.setFill("blue")
blx.draw(wn)
xval, yval = 10, 0
bheading = 1
wn.getMouse()
for i in range(150):
sqrg.move(xval, yval)
if distance(blx.getCenter(), sqrg.getCenter()) < 25:
bheading *= -1
symbl = wn.checkKey()
if symbl == "Right":
xval = 10
elif symbl == "Left":
xval = -10
sleep(0.1)
blx.move(0, bheading * 20)
Cleary not a viable game as-is, but a demonstration of collision detection.
answered Nov 23 '18 at 21:10
cdlanecdlane
20k21245
add a comment |
Below is a stripped down example based on your code. It measures the distance between the centers of the two moving objects to determine if a collision has occurred. If you manage to get the ball to hit the square, the ball should bounce straight up:
from random import randint
from time import sleep
from graphics import *
def distance(p1, p2):
return ((p2.x - p1.x) ** 2 + (p2.y - p1.y) ** 2) ** 0.5
wn = GraphWin("AK", 700, 700)
sqrg = Rectangle(Point(325, 625), Point(375, 675))
sqrg.setFill("red")
sqrg.draw(wn)
numx = randint(10, 700)
blx = Circle(Point(numx, 80), 20)
blx.setFill("blue")
blx.draw(wn)
xval, yval = 10, 0
bheading = 1
wn.getMouse()
for i in range(150):
sqrg.move(xval, yval)
if distance(blx.getCenter(), sqrg.getCenter()) < 25:
bheading *= -1
symbl = wn.checkKey()
if symbl == "Right":
xval = 10
elif symbl == "Left":
xval = -10
sleep(0.1)
blx.move(0, bheading * 20)
Cleary not a viable game as-is, but a demonstration of collision detection.
answered Nov 23 '18 at 21:10
cdlanecdlane
20k21245
add a comment |
Below is a stripped down example based on your code. It measures the distance between the centers of the two moving objects to determine if a collision has occurred. If you manage to get the ball to hit the square, the ball should bounce straight up:
from random import randint
from time import sleep
from graphics import *
def distance(p1, p2):
return ((p2.x - p1.x) ** 2 + (p2.y - p1.y) ** 2) ** 0.5
wn = GraphWin("AK", 700, 700)
sqrg = Rectangle(Point(325, 625), Point(375, 675))
sqrg.setFill("red")
sqrg.draw(wn)
numx = randint(10, 700)
blx = Circle(Point(numx, 80), 20)
blx.setFill("blue")
blx.draw(wn)
xval, yval = 10, 0
bheading = 1
wn.getMouse()
for i in range(150):
sqrg.move(xval, yval)
if distance(blx.getCenter(), sqrg.getCenter()) < 25:
bheading *= -1
symbl = wn.checkKey()
if symbl == "Right":
xval = 10
elif symbl == "Left":
xval = -10
sleep(0.1)
blx.move(0, bheading * 20)
Cleary not a viable game as-is, but a demonstration of collision detection.
answered Nov 23 '18 at 21:10
cdlanecdlane
20k21245
Below is a stripped down example based on your code. It measures the distance between the centers of the two moving objects to determine if a collision has occurred. If you manage to get the ball to hit the square, the ball should bounce straight up:
from random import randint
from time import sleep
from graphics import *
def distance(p1, p2):
return ((p2.x - p1.x) ** 2 + (p2.y - p1.y) ** 2) ** 0.5
wn = GraphWin("AK", 700, 700)
sqrg = Rectangle(Point(325, 625), Point(375, 675))
sqrg.setFill("red")
sqrg.draw(wn)
numx = randint(10, 700)
blx = Circle(Point(numx, 80), 20)
blx.setFill("blue")
blx.draw(wn)
xval, yval = 10, 0
bheading = 1
wn.getMouse()
for i in range(150):
sqrg.move(xval, yval)
if distance(blx.getCenter(), sqrg.getCenter()) < 25:
bheading *= -1
symbl = wn.checkKey()
if symbl == "Right":
xval = 10
elif symbl == "Left":
xval = -10
sleep(0.1)
blx.move(0, bheading * 20)
Cleary not a viable game as-is, but a demonstration of collision detection.
answered Nov 23 '18 at 21:10
cdlanecdlane
20k21245
answered Nov 23 '18 at 21:10
cdlanecdlane
20k21245
answered Nov 23 '18 at 21:10
cdlanecdlane
20k21245
answered Nov 23 '18 at 21:10
cdlanecdlane
20k21245
20k21245
add a comment |
add a comment |
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Looks like if you know the location of sqrg and blx with the dimensions, you should be able to determine if those points intersect each iteration.
– bison
Nov 21 '18 at 23:00