Change drop down option to button
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I am trying to change the drop down option to button. But i was unable to do it. The code i have was done by a professional but i am quite new.The drop down option is taking the values from a database and displaying it. The drop works as if any user selects the currency the values of the items also changes according to it.
<div id='curr_picker''>
<strong >Currency:</strong>
<?php
$curr_query = "SELECT * FROM `currency_sett` WHERE `curr_id` >= '1'";
$curr_result = $mysqli->query($curr_query) or die ($mysqli- >error);
if($curr_result->num_rows > 0){
while($curr_row = $curr_result->fetch_assoc()){
$curr_id = $curr_row[curr_id];
$curr_code = $curr_row[curr_code];
$lower_curr_code = strtolower($curr_code);
$prefix = $curr_row[curr_pref];
$suffix = $curr_row[curr_suff];
$format = $curr_row[curr_form];
$base_rate = $curr_row[base_rate];
$calc_monthly_price = $base_monthly_price * $base_rate;
$calc_quarterly_price = $base_quarterly_price * $base_rate;
$calc_semi_ann_price = $base_semi_ann_price * $base_rate;
$calc_ann_price = $base_ann_price * $base_rate;
if($curr_id == $page_load_currency){
$selctd_opt_attr = "selected='selected'";
}
else{
$selctd_opt_attr = NULL;
}
if(!in_array($curr_code, $curr_shown_array)){
$disp_curr_opts .= "<option value='$lower_curr_code' $selctd_opt_attr>$curr_code </option>";
$form_inp_hidden_var .= "<input type='hidden' id='curr2id_{$lower_curr_code}' name='curr2id_{$lower_curr_code}' value='$curr_id'>";
$curr_shown_array = $curr_code;
}
echo("
<div class='selectouter'><select name='pick_currency' id='pick_currency' '>
$disp_curr_opts
</select></div>
<div style='display:none;'>
<form>
$form_inp_hidden_var
</form>
</div>
");
?>
</div>
i was able to change the drop down to button
$disp_curr_opts .= "<input type='button' id='button_{$lower_curr_code}' value='$lower_curr_code' />";
But now i am stuck as i dont know how i will implement the onclick and which part of the code would go under it. So can anyone help me how should i do it? If some also helps me understanding how the code is working incase of the dropdown mentioned it would do a great help.
php sql button drop-down-menu
add a comment |
I am trying to change the drop down option to button. But i was unable to do it. The code i have was done by a professional but i am quite new.The drop down option is taking the values from a database and displaying it. The drop works as if any user selects the currency the values of the items also changes according to it.
<div id='curr_picker''>
<strong >Currency:</strong>
<?php
$curr_query = "SELECT * FROM `currency_sett` WHERE `curr_id` >= '1'";
$curr_result = $mysqli->query($curr_query) or die ($mysqli- >error);
if($curr_result->num_rows > 0){
while($curr_row = $curr_result->fetch_assoc()){
$curr_id = $curr_row[curr_id];
$curr_code = $curr_row[curr_code];
$lower_curr_code = strtolower($curr_code);
$prefix = $curr_row[curr_pref];
$suffix = $curr_row[curr_suff];
$format = $curr_row[curr_form];
$base_rate = $curr_row[base_rate];
$calc_monthly_price = $base_monthly_price * $base_rate;
$calc_quarterly_price = $base_quarterly_price * $base_rate;
$calc_semi_ann_price = $base_semi_ann_price * $base_rate;
$calc_ann_price = $base_ann_price * $base_rate;
if($curr_id == $page_load_currency){
$selctd_opt_attr = "selected='selected'";
}
else{
$selctd_opt_attr = NULL;
}
if(!in_array($curr_code, $curr_shown_array)){
$disp_curr_opts .= "<option value='$lower_curr_code' $selctd_opt_attr>$curr_code </option>";
$form_inp_hidden_var .= "<input type='hidden' id='curr2id_{$lower_curr_code}' name='curr2id_{$lower_curr_code}' value='$curr_id'>";
$curr_shown_array = $curr_code;
}
echo("
<div class='selectouter'><select name='pick_currency' id='pick_currency' '>
$disp_curr_opts
</select></div>
<div style='display:none;'>
<form>
$form_inp_hidden_var
</form>
</div>
");
?>
</div>
i was able to change the drop down to button
$disp_curr_opts .= "<input type='button' id='button_{$lower_curr_code}' value='$lower_curr_code' />";
But now i am stuck as i dont know how i will implement the onclick and which part of the code would go under it. So can anyone help me how should i do it? If some also helps me understanding how the code is working incase of the dropdown mentioned it would do a great help.
php sql button drop-down-menu
add a comment |
I am trying to change the drop down option to button. But i was unable to do it. The code i have was done by a professional but i am quite new.The drop down option is taking the values from a database and displaying it. The drop works as if any user selects the currency the values of the items also changes according to it.
<div id='curr_picker''>
<strong >Currency:</strong>
<?php
$curr_query = "SELECT * FROM `currency_sett` WHERE `curr_id` >= '1'";
$curr_result = $mysqli->query($curr_query) or die ($mysqli- >error);
if($curr_result->num_rows > 0){
while($curr_row = $curr_result->fetch_assoc()){
$curr_id = $curr_row[curr_id];
$curr_code = $curr_row[curr_code];
$lower_curr_code = strtolower($curr_code);
$prefix = $curr_row[curr_pref];
$suffix = $curr_row[curr_suff];
$format = $curr_row[curr_form];
$base_rate = $curr_row[base_rate];
$calc_monthly_price = $base_monthly_price * $base_rate;
$calc_quarterly_price = $base_quarterly_price * $base_rate;
$calc_semi_ann_price = $base_semi_ann_price * $base_rate;
$calc_ann_price = $base_ann_price * $base_rate;
if($curr_id == $page_load_currency){
$selctd_opt_attr = "selected='selected'";
}
else{
$selctd_opt_attr = NULL;
}
if(!in_array($curr_code, $curr_shown_array)){
$disp_curr_opts .= "<option value='$lower_curr_code' $selctd_opt_attr>$curr_code </option>";
$form_inp_hidden_var .= "<input type='hidden' id='curr2id_{$lower_curr_code}' name='curr2id_{$lower_curr_code}' value='$curr_id'>";
$curr_shown_array = $curr_code;
}
echo("
<div class='selectouter'><select name='pick_currency' id='pick_currency' '>
$disp_curr_opts
</select></div>
<div style='display:none;'>
<form>
$form_inp_hidden_var
</form>
</div>
");
?>
</div>
i was able to change the drop down to button
$disp_curr_opts .= "<input type='button' id='button_{$lower_curr_code}' value='$lower_curr_code' />";
But now i am stuck as i dont know how i will implement the onclick and which part of the code would go under it. So can anyone help me how should i do it? If some also helps me understanding how the code is working incase of the dropdown mentioned it would do a great help.
php sql button drop-down-menu
I am trying to change the drop down option to button. But i was unable to do it. The code i have was done by a professional but i am quite new.The drop down option is taking the values from a database and displaying it. The drop works as if any user selects the currency the values of the items also changes according to it.
<div id='curr_picker''>
<strong >Currency:</strong>
<?php
$curr_query = "SELECT * FROM `currency_sett` WHERE `curr_id` >= '1'";
$curr_result = $mysqli->query($curr_query) or die ($mysqli- >error);
if($curr_result->num_rows > 0){
while($curr_row = $curr_result->fetch_assoc()){
$curr_id = $curr_row[curr_id];
$curr_code = $curr_row[curr_code];
$lower_curr_code = strtolower($curr_code);
$prefix = $curr_row[curr_pref];
$suffix = $curr_row[curr_suff];
$format = $curr_row[curr_form];
$base_rate = $curr_row[base_rate];
$calc_monthly_price = $base_monthly_price * $base_rate;
$calc_quarterly_price = $base_quarterly_price * $base_rate;
$calc_semi_ann_price = $base_semi_ann_price * $base_rate;
$calc_ann_price = $base_ann_price * $base_rate;
if($curr_id == $page_load_currency){
$selctd_opt_attr = "selected='selected'";
}
else{
$selctd_opt_attr = NULL;
}
if(!in_array($curr_code, $curr_shown_array)){
$disp_curr_opts .= "<option value='$lower_curr_code' $selctd_opt_attr>$curr_code </option>";
$form_inp_hidden_var .= "<input type='hidden' id='curr2id_{$lower_curr_code}' name='curr2id_{$lower_curr_code}' value='$curr_id'>";
$curr_shown_array = $curr_code;
}
echo("
<div class='selectouter'><select name='pick_currency' id='pick_currency' '>
$disp_curr_opts
</select></div>
<div style='display:none;'>
<form>
$form_inp_hidden_var
</form>
</div>
");
?>
</div>
i was able to change the drop down to button
$disp_curr_opts .= "<input type='button' id='button_{$lower_curr_code}' value='$lower_curr_code' />";
But now i am stuck as i dont know how i will implement the onclick and which part of the code would go under it. So can anyone help me how should i do it? If some also helps me understanding how the code is working incase of the dropdown mentioned it would do a great help.
php sql button drop-down-menu
php sql button drop-down-menu
asked Nov 29 '18 at 5:30
taufeeq zamantaufeeq zaman
177
177
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