How to slice a csr_matrix by certain list of rows/columns?
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Suppose my csr_matrix is
I = [0, 1, 3 ,4 ,5, 0, 3]
J = [1, 3 , 4, 9 ,1 , 0, 8]
V = [1]*6
V.append(0)
data=sparse.coo_matrix((V,(I,J)),shape=(7,10)).tocsr()
which outputs
(0, 0) 1
(0, 1) 1
(1, 3) 1
(3, 4) 1
(3, 8) 0
(4, 9) 1
(5, 1) 1
So,I want to get entries with specific list of rows/columns. For example:
print(data[:,[3,5,8]])
(1, 0) 1
But I expected to get,
(1, 3) 1
(3, 8) 0
Similarly I want to get specific rows, but data[list:] does not give desired output. How can I solve this?
python numpy scipy sparse-matrix
add a comment |
Suppose my csr_matrix is
I = [0, 1, 3 ,4 ,5, 0, 3]
J = [1, 3 , 4, 9 ,1 , 0, 8]
V = [1]*6
V.append(0)
data=sparse.coo_matrix((V,(I,J)),shape=(7,10)).tocsr()
which outputs
(0, 0) 1
(0, 1) 1
(1, 3) 1
(3, 4) 1
(3, 8) 0
(4, 9) 1
(5, 1) 1
So,I want to get entries with specific list of rows/columns. For example:
print(data[:,[3,5,8]])
(1, 0) 1
But I expected to get,
(1, 3) 1
(3, 8) 0
Similarly I want to get specific rows, but data[list:] does not give desired output. How can I solve this?
python numpy scipy sparse-matrix
1
If you want to preserve explicit zeros, be prepared to do a lot of things manually. Mostscipy.sparse
operations make no guarantees about explicit zeros.
– user2357112
Nov 29 '18 at 5:25
The result of that indexing is a (7,3) matrix, not the original (7,10). Indexing reflects that.
– hpaulj
Nov 29 '18 at 5:52
yea, but how I can preserve the indexing tho?
– user3086871
Nov 29 '18 at 5:57
add a comment |
Suppose my csr_matrix is
I = [0, 1, 3 ,4 ,5, 0, 3]
J = [1, 3 , 4, 9 ,1 , 0, 8]
V = [1]*6
V.append(0)
data=sparse.coo_matrix((V,(I,J)),shape=(7,10)).tocsr()
which outputs
(0, 0) 1
(0, 1) 1
(1, 3) 1
(3, 4) 1
(3, 8) 0
(4, 9) 1
(5, 1) 1
So,I want to get entries with specific list of rows/columns. For example:
print(data[:,[3,5,8]])
(1, 0) 1
But I expected to get,
(1, 3) 1
(3, 8) 0
Similarly I want to get specific rows, but data[list:] does not give desired output. How can I solve this?
python numpy scipy sparse-matrix
Suppose my csr_matrix is
I = [0, 1, 3 ,4 ,5, 0, 3]
J = [1, 3 , 4, 9 ,1 , 0, 8]
V = [1]*6
V.append(0)
data=sparse.coo_matrix((V,(I,J)),shape=(7,10)).tocsr()
which outputs
(0, 0) 1
(0, 1) 1
(1, 3) 1
(3, 4) 1
(3, 8) 0
(4, 9) 1
(5, 1) 1
So,I want to get entries with specific list of rows/columns. For example:
print(data[:,[3,5,8]])
(1, 0) 1
But I expected to get,
(1, 3) 1
(3, 8) 0
Similarly I want to get specific rows, but data[list:] does not give desired output. How can I solve this?
python numpy scipy sparse-matrix
python numpy scipy sparse-matrix
edited Nov 29 '18 at 7:50
hpaulj
117k786160
117k786160
asked Nov 29 '18 at 5:19
user3086871user3086871
113114
113114
1
If you want to preserve explicit zeros, be prepared to do a lot of things manually. Mostscipy.sparse
operations make no guarantees about explicit zeros.
– user2357112
Nov 29 '18 at 5:25
The result of that indexing is a (7,3) matrix, not the original (7,10). Indexing reflects that.
– hpaulj
Nov 29 '18 at 5:52
yea, but how I can preserve the indexing tho?
– user3086871
Nov 29 '18 at 5:57
add a comment |
1
If you want to preserve explicit zeros, be prepared to do a lot of things manually. Mostscipy.sparse
operations make no guarantees about explicit zeros.
– user2357112
Nov 29 '18 at 5:25
The result of that indexing is a (7,3) matrix, not the original (7,10). Indexing reflects that.
– hpaulj
Nov 29 '18 at 5:52
yea, but how I can preserve the indexing tho?
– user3086871
Nov 29 '18 at 5:57
1
1
If you want to preserve explicit zeros, be prepared to do a lot of things manually. Most
scipy.sparse
operations make no guarantees about explicit zeros.– user2357112
Nov 29 '18 at 5:25
If you want to preserve explicit zeros, be prepared to do a lot of things manually. Most
scipy.sparse
operations make no guarantees about explicit zeros.– user2357112
Nov 29 '18 at 5:25
The result of that indexing is a (7,3) matrix, not the original (7,10). Indexing reflects that.
– hpaulj
Nov 29 '18 at 5:52
The result of that indexing is a (7,3) matrix, not the original (7,10). Indexing reflects that.
– hpaulj
Nov 29 '18 at 5:52
yea, but how I can preserve the indexing tho?
– user3086871
Nov 29 '18 at 5:57
yea, but how I can preserve the indexing tho?
– user3086871
Nov 29 '18 at 5:57
add a comment |
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1
If you want to preserve explicit zeros, be prepared to do a lot of things manually. Most
scipy.sparse
operations make no guarantees about explicit zeros.– user2357112
Nov 29 '18 at 5:25
The result of that indexing is a (7,3) matrix, not the original (7,10). Indexing reflects that.
– hpaulj
Nov 29 '18 at 5:52
yea, but how I can preserve the indexing tho?
– user3086871
Nov 29 '18 at 5:57