boolean data type random integer
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Im trying to create a random number generator and judging the random integers odd or even using a srand call and boolean but i cant figured out how to get it to distinguish properly between whats odd and whats even.
#include <stdio.h>
#include <stdlib.h>
#include <stdbool.h>
#include <time.h>
int i;
int num1;
int num2;
bool isOdd (int num1, int num2);
int main(void)
{
srand(time(NULL));
for (i=1; i <= 10; ++i) {
num1 = rand() % 10 + 1;
num2 = rand() % 10 + 1;
printf("The two random numbers are %u and %un", num1, num2);
bool valueIsOdd = isOdd(num1, num2);
if (valueIsOdd) {
printf("one of these numbers, %u and %u, isOdd.nn", num1, num2);
}
else {
printf("Both of these numbers, %u and %u, are even.nn", num1, num2);
}
}
}
bool isOdd(int num1, int num2)
{
if (num1 % 2 != 0) {
return true;
}
else {
return false;
}
}
c random boolean
asked Nov 29 '18 at 5:37
Mike BelliveauMike Belliveau
1
add a comment |
Im trying to create a random number generator and judging the random integers odd or even using a srand call and boolean but i cant figured out how to get it to distinguish properly between whats odd and whats even.
#include <stdio.h>
#include <stdlib.h>
#include <stdbool.h>
#include <time.h>
int i;
int num1;
int num2;
bool isOdd (int num1, int num2);
int main(void)
{
srand(time(NULL));
for (i=1; i <= 10; ++i) {
num1 = rand() % 10 + 1;
num2 = rand() % 10 + 1;
printf("The two random numbers are %u and %un", num1, num2);
bool valueIsOdd = isOdd(num1, num2);
if (valueIsOdd) {
printf("one of these numbers, %u and %u, isOdd.nn", num1, num2);
}
else {
printf("Both of these numbers, %u and %u, are even.nn", num1, num2);
}
}
}
bool isOdd(int num1, int num2)
{
if (num1 % 2 != 0) {
return true;
}
else {
return false;
}
}
c random boolean
asked Nov 29 '18 at 5:37
Mike BelliveauMike Belliveau
1
1
What's supposed to happen with your program? For some example numbers, what is the expected output and what is the actual output? Please take some time to read about how to ask good questions, as well as this question checklist.
– Some programmer dude
Nov 29 '18 at 5:40
Your printing doesn't explicitly cover the case where both numbers are odd. You could say "At least one of these numbers is odd". Or deal with it another way.
– Jonathan Leffler
Nov 29 '18 at 5:43
1
Note that your printf statements do not seem to handle the case in which both numbers are odd.
– armitus
Nov 29 '18 at 5:43
1
why pass two numbers toisOdd()when only one of them will be checked?
– user3629249
Nov 29 '18 at 6:12
add a comment |
Im trying to create a random number generator and judging the random integers odd or even using a srand call and boolean but i cant figured out how to get it to distinguish properly between whats odd and whats even.
#include <stdio.h>
#include <stdlib.h>
#include <stdbool.h>
#include <time.h>
int i;
int num1;
int num2;
bool isOdd (int num1, int num2);
int main(void)
{
srand(time(NULL));
for (i=1; i <= 10; ++i) {
num1 = rand() % 10 + 1;
num2 = rand() % 10 + 1;
printf("The two random numbers are %u and %un", num1, num2);
bool valueIsOdd = isOdd(num1, num2);
if (valueIsOdd) {
printf("one of these numbers, %u and %u, isOdd.nn", num1, num2);
}
else {
printf("Both of these numbers, %u and %u, are even.nn", num1, num2);
}
}
}
bool isOdd(int num1, int num2)
{
if (num1 % 2 != 0) {
return true;
}
else {
return false;
}
}
c random boolean
asked Nov 29 '18 at 5:37
Mike BelliveauMike Belliveau
1
Im trying to create a random number generator and judging the random integers odd or even using a srand call and boolean but i cant figured out how to get it to distinguish properly between whats odd and whats even.
#include <stdio.h>
#include <stdlib.h>
#include <stdbool.h>
#include <time.h>
int i;
int num1;
int num2;
bool isOdd (int num1, int num2);
int main(void)
{
srand(time(NULL));
for (i=1; i <= 10; ++i) {
num1 = rand() % 10 + 1;
num2 = rand() % 10 + 1;
printf("The two random numbers are %u and %un", num1, num2);
bool valueIsOdd = isOdd(num1, num2);
if (valueIsOdd) {
printf("one of these numbers, %u and %u, isOdd.nn", num1, num2);
}
else {
printf("Both of these numbers, %u and %u, are even.nn", num1, num2);
}
}
}
bool isOdd(int num1, int num2)
{
if (num1 % 2 != 0) {
return true;
}
else {
return false;
}
}
c random boolean
c random boolean
asked Nov 29 '18 at 5:37
Mike BelliveauMike Belliveau
1
asked Nov 29 '18 at 5:37
Mike BelliveauMike Belliveau
1
asked Nov 29 '18 at 5:37
Mike BelliveauMike Belliveau
1
asked Nov 29 '18 at 5:37
Mike BelliveauMike Belliveau
1
asked Nov 29 '18 at 5:37
Mike BelliveauMike Belliveau
1
1
1
What's supposed to happen with your program? For some example numbers, what is the expected output and what is the actual output? Please take some time to read about how to ask good questions, as well as this question checklist.
– Some programmer dude
Nov 29 '18 at 5:40
Your printing doesn't explicitly cover the case where both numbers are odd. You could say "At least one of these numbers is odd". Or deal with it another way.
– Jonathan Leffler
Nov 29 '18 at 5:43
1
Note that your printf statements do not seem to handle the case in which both numbers are odd.
– armitus
Nov 29 '18 at 5:43
1
why pass two numbers toisOdd()when only one of them will be checked?
– user3629249
Nov 29 '18 at 6:12
add a comment |
1
What's supposed to happen with your program? For some example numbers, what is the expected output and what is the actual output? Please take some time to read about how to ask good questions, as well as this question checklist.
– Some programmer dude
Nov 29 '18 at 5:40
Your printing doesn't explicitly cover the case where both numbers are odd. You could say "At least one of these numbers is odd". Or deal with it another way.
– Jonathan Leffler
Nov 29 '18 at 5:43
1
Note that your printf statements do not seem to handle the case in which both numbers are odd.
– armitus
Nov 29 '18 at 5:43
1
why pass two numbers toisOdd()when only one of them will be checked?
– user3629249
Nov 29 '18 at 6:12
1
1
What's supposed to happen with your program? For some example numbers, what is the expected output and what is the actual output? Please take some time to read about how to ask good questions, as well as this question checklist.
– Some programmer dude
Nov 29 '18 at 5:40
What's supposed to happen with your program? For some example numbers, what is the expected output and what is the actual output? Please take some time to read about how to ask good questions, as well as this question checklist.
– Some programmer dude
Nov 29 '18 at 5:40
Your printing doesn't explicitly cover the case where both numbers are odd. You could say "At least one of these numbers is odd". Or deal with it another way.
– Jonathan Leffler
Nov 29 '18 at 5:43
Your printing doesn't explicitly cover the case where both numbers are odd. You could say "At least one of these numbers is odd". Or deal with it another way.
– Jonathan Leffler
Nov 29 '18 at 5:43
1
1
Note that your printf statements do not seem to handle the case in which both numbers are odd.
– armitus
Nov 29 '18 at 5:43
Note that your printf statements do not seem to handle the case in which both numbers are odd.
– armitus
Nov 29 '18 at 5:43
1
1
why pass two numbers to
isOdd() when only one of them will be checked?– user3629249
Nov 29 '18 at 6:12
why pass two numbers to
isOdd() when only one of them will be checked?– user3629249
Nov 29 '18 at 6:12
add a comment |
2 Answers
2
active
oldest
votes
You are only checking one number in the function isOdd. You need to check both numbers.
if ((num1 % 2 != 0) || (num2 %2 !=0)) {
return true;
}
else {
return false;
}
Or, you can check for both even and make the code a bit cleaner.
if ((num1 % 2 == 0) && (num2 %2 ==0)) {
return false;
}
else {
return true;
}
answered Nov 29 '18 at 5:41
Rishikesh RajeRishikesh Raje
5,6221828
1
Or plainreturn num1 % 2 != 0 || num1%2 !=0;
– Some programmer dude
Nov 29 '18 at 5:42
You testednum1twice and forgotnum2...
– Joël Hecht
Nov 29 '18 at 6:21
add a comment |
I understand your question.
u are asking that to differentiate from the two number which is odd right.
The main purpose of the bool is to represent either 1 or 0 why to use char consists of 8 bits.
If u want to check 1 number use bool datatype.
Otherwise if u want to know two number of all possible results better go with char datatype.
Here u have two numbers.4 possibility.
number 1 number 2
1 odd even
2 even odd
3 even even
4 odd od
if ((num1 % 2 != 0) && (num2 % 2 == 0)) {
return 1;
}
else if ((num1 % 2 == 0) && (num2 % 2 != 0)) {
return 2;
}
else if ((num1 % 2 == 0) && (num2 % 2 == 0)) {
return 3;
}
else {
return 4;
}
answered Nov 29 '18 at 6:55
Ramya MuralidharanRamya Muralidharan
995
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
You are only checking one number in the function isOdd. You need to check both numbers.
if ((num1 % 2 != 0) || (num2 %2 !=0)) {
return true;
}
else {
return false;
}
Or, you can check for both even and make the code a bit cleaner.
if ((num1 % 2 == 0) && (num2 %2 ==0)) {
return false;
}
else {
return true;
}
answered Nov 29 '18 at 5:41
Rishikesh RajeRishikesh Raje
5,6221828
1
Or plainreturn num1 % 2 != 0 || num1%2 !=0;
– Some programmer dude
Nov 29 '18 at 5:42
You testednum1twice and forgotnum2...
– Joël Hecht
Nov 29 '18 at 6:21
add a comment |
You are only checking one number in the function isOdd. You need to check both numbers.
if ((num1 % 2 != 0) || (num2 %2 !=0)) {
return true;
}
else {
return false;
}
Or, you can check for both even and make the code a bit cleaner.
if ((num1 % 2 == 0) && (num2 %2 ==0)) {
return false;
}
else {
return true;
}
answered Nov 29 '18 at 5:41
Rishikesh RajeRishikesh Raje
5,6221828
1
Or plainreturn num1 % 2 != 0 || num1%2 !=0;
– Some programmer dude
Nov 29 '18 at 5:42
You testednum1twice and forgotnum2...
– Joël Hecht
Nov 29 '18 at 6:21
add a comment |
You are only checking one number in the function isOdd. You need to check both numbers.
if ((num1 % 2 != 0) || (num2 %2 !=0)) {
return true;
}
else {
return false;
}
Or, you can check for both even and make the code a bit cleaner.
if ((num1 % 2 == 0) && (num2 %2 ==0)) {
return false;
}
else {
return true;
}
answered Nov 29 '18 at 5:41
Rishikesh RajeRishikesh Raje
5,6221828
You are only checking one number in the function isOdd. You need to check both numbers.
if ((num1 % 2 != 0) || (num2 %2 !=0)) {
return true;
}
else {
return false;
}
Or, you can check for both even and make the code a bit cleaner.
if ((num1 % 2 == 0) && (num2 %2 ==0)) {
return false;
}
else {
return true;
}
answered Nov 29 '18 at 5:41
Rishikesh RajeRishikesh Raje
5,6221828
edited Nov 29 '18 at 6:39
answered Nov 29 '18 at 5:41
Rishikesh RajeRishikesh Raje
5,6221828
answered Nov 29 '18 at 5:41
Rishikesh RajeRishikesh Raje
5,6221828
answered Nov 29 '18 at 5:41
Rishikesh RajeRishikesh Raje
5,6221828
5,6221828
1
Or plainreturn num1 % 2 != 0 || num1%2 !=0;
– Some programmer dude
Nov 29 '18 at 5:42
You testednum1twice and forgotnum2...
– Joël Hecht
Nov 29 '18 at 6:21
add a comment |
1
Or plainreturn num1 % 2 != 0 || num1%2 !=0;
– Some programmer dude
Nov 29 '18 at 5:42
You testednum1twice and forgotnum2...
– Joël Hecht
Nov 29 '18 at 6:21
1
1
Or plain
return num1 % 2 != 0 || num1%2 !=0;– Some programmer dude
Nov 29 '18 at 5:42
Or plain
return num1 % 2 != 0 || num1%2 !=0;– Some programmer dude
Nov 29 '18 at 5:42
You tested
num1 twice and forgot num2...– Joël Hecht
Nov 29 '18 at 6:21
You tested
num1 twice and forgot num2...– Joël Hecht
Nov 29 '18 at 6:21
add a comment |
I understand your question.
u are asking that to differentiate from the two number which is odd right.
The main purpose of the bool is to represent either 1 or 0 why to use char consists of 8 bits.
If u want to check 1 number use bool datatype.
Otherwise if u want to know two number of all possible results better go with char datatype.
Here u have two numbers.4 possibility.
number 1 number 2
1 odd even
2 even odd
3 even even
4 odd od
if ((num1 % 2 != 0) && (num2 % 2 == 0)) {
return 1;
}
else if ((num1 % 2 == 0) && (num2 % 2 != 0)) {
return 2;
}
else if ((num1 % 2 == 0) && (num2 % 2 == 0)) {
return 3;
}
else {
return 4;
}
answered Nov 29 '18 at 6:55
Ramya MuralidharanRamya Muralidharan
995
add a comment |
I understand your question.
u are asking that to differentiate from the two number which is odd right.
The main purpose of the bool is to represent either 1 or 0 why to use char consists of 8 bits.
If u want to check 1 number use bool datatype.
Otherwise if u want to know two number of all possible results better go with char datatype.
Here u have two numbers.4 possibility.
number 1 number 2
1 odd even
2 even odd
3 even even
4 odd od
if ((num1 % 2 != 0) && (num2 % 2 == 0)) {
return 1;
}
else if ((num1 % 2 == 0) && (num2 % 2 != 0)) {
return 2;
}
else if ((num1 % 2 == 0) && (num2 % 2 == 0)) {
return 3;
}
else {
return 4;
}
answered Nov 29 '18 at 6:55
Ramya MuralidharanRamya Muralidharan
995
add a comment |
I understand your question.
u are asking that to differentiate from the two number which is odd right.
The main purpose of the bool is to represent either 1 or 0 why to use char consists of 8 bits.
If u want to check 1 number use bool datatype.
Otherwise if u want to know two number of all possible results better go with char datatype.
Here u have two numbers.4 possibility.
number 1 number 2
1 odd even
2 even odd
3 even even
4 odd od
if ((num1 % 2 != 0) && (num2 % 2 == 0)) {
return 1;
}
else if ((num1 % 2 == 0) && (num2 % 2 != 0)) {
return 2;
}
else if ((num1 % 2 == 0) && (num2 % 2 == 0)) {
return 3;
}
else {
return 4;
}
answered Nov 29 '18 at 6:55
Ramya MuralidharanRamya Muralidharan
995
I understand your question.
u are asking that to differentiate from the two number which is odd right.
The main purpose of the bool is to represent either 1 or 0 why to use char consists of 8 bits.
If u want to check 1 number use bool datatype.
Otherwise if u want to know two number of all possible results better go with char datatype.
Here u have two numbers.4 possibility.
number 1 number 2
1 odd even
2 even odd
3 even even
4 odd od
if ((num1 % 2 != 0) && (num2 % 2 == 0)) {
return 1;
}
else if ((num1 % 2 == 0) && (num2 % 2 != 0)) {
return 2;
}
else if ((num1 % 2 == 0) && (num2 % 2 == 0)) {
return 3;
}
else {
return 4;
}
answered Nov 29 '18 at 6:55
Ramya MuralidharanRamya Muralidharan
995
answered Nov 29 '18 at 6:55
Ramya MuralidharanRamya Muralidharan
995
answered Nov 29 '18 at 6:55
Ramya MuralidharanRamya Muralidharan
995
answered Nov 29 '18 at 6:55
Ramya MuralidharanRamya Muralidharan
995
995
add a comment |
add a comment |
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1
What's supposed to happen with your program? For some example numbers, what is the expected output and what is the actual output? Please take some time to read about how to ask good questions, as well as this question checklist.
– Some programmer dude
Nov 29 '18 at 5:40
Your printing doesn't explicitly cover the case where both numbers are odd. You could say "At least one of these numbers is odd". Or deal with it another way.
– Jonathan Leffler
Nov 29 '18 at 5:43
1
Note that your printf statements do not seem to handle the case in which both numbers are odd.
– armitus
Nov 29 '18 at 5:43
1
why pass two numbers to
isOdd()when only one of them will be checked?– user3629249
Nov 29 '18 at 6:12