Linear independence of symmetric matrix [on hold]
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If a symmetric matrix consists of pairwise linear independent vectors, does then follow that all vectors are linear independent, or can you give a counter example?
linear-algebra symmetric-matrices
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put on hold as off-topic by user21820, Xander Henderson, rschwieb, quid♦ 9 hours ago
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If a symmetric matrix consists of pairwise linear independent vectors, does then follow that all vectors are linear independent, or can you give a counter example?
linear-algebra symmetric-matrices
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put on hold as off-topic by user21820, Xander Henderson, rschwieb, quid♦ 9 hours ago
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – user21820, Xander Henderson, rschwieb, quid
If this question can be reworded to fit the rules in the help center, please edit the question.
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Welcome to the site. Please explain via an edit what the context of this question is. The links in the box above give more explanation what is meant by "context";
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– quid♦
9 hours ago
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If a symmetric matrix consists of pairwise linear independent vectors, does then follow that all vectors are linear independent, or can you give a counter example?
linear-algebra symmetric-matrices
New contributor
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If a symmetric matrix consists of pairwise linear independent vectors, does then follow that all vectors are linear independent, or can you give a counter example?
linear-algebra symmetric-matrices
linear-algebra symmetric-matrices
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New contributor
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asked 12 hours ago
ThorbenThorben
151
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put on hold as off-topic by user21820, Xander Henderson, rschwieb, quid♦ 9 hours ago
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – user21820, Xander Henderson, rschwieb, quid
If this question can be reworded to fit the rules in the help center, please edit the question.
put on hold as off-topic by user21820, Xander Henderson, rschwieb, quid♦ 9 hours ago
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – user21820, Xander Henderson, rschwieb, quid
If this question can be reworded to fit the rules in the help center, please edit the question.
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Welcome to the site. Please explain via an edit what the context of this question is. The links in the box above give more explanation what is meant by "context";
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– quid♦
9 hours ago
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Welcome to the site. Please explain via an edit what the context of this question is. The links in the box above give more explanation what is meant by "context";
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– quid♦
9 hours ago
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– quid♦
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1 Answer
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How about $$begin{bmatrix}1&1&0\1&0&1\0&1&-1end{bmatrix}$$ the middle column is the first column minus the third.
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1 Answer
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1 Answer
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How about $$begin{bmatrix}1&1&0\1&0&1\0&1&-1end{bmatrix}$$ the middle column is the first column minus the third.
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How about $$begin{bmatrix}1&1&0\1&0&1\0&1&-1end{bmatrix}$$ the middle column is the first column minus the third.
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How about $$begin{bmatrix}1&1&0\1&0&1\0&1&-1end{bmatrix}$$ the middle column is the first column minus the third.
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How about $$begin{bmatrix}1&1&0\1&0&1\0&1&-1end{bmatrix}$$ the middle column is the first column minus the third.
answered 11 hours ago
DaveDave
9,19111033
9,19111033
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– quid♦
9 hours ago