Pattern recognition using a, b, c, d, and e












5














I need to find the solution of this pattern:




{a,b,c}, {c,d,e}, ?, ?, ?, {b,c,e}, {a,c,d}, {b,c,d}, {a,c,e}, ?




The solution should be something like this:




{a,b,c}, {c,d,e} {x,x,x} {x,x,x} {x,x,x},{b,c,e},{a,c,d}, {b,c,d}, {a,c,e}, {x,x,x}




where instead of the x you should replace letters.



Source: http://zagaza.ru/za548.htm






logical-deduction pattern combinatorics







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    5














    I need to find the solution of this pattern:




    {a,b,c}, {c,d,e}, ?, ?, ?, {b,c,e}, {a,c,d}, {b,c,d}, {a,c,e}, ?




    The solution should be something like this:




    {a,b,c}, {c,d,e} {x,x,x} {x,x,x} {x,x,x},{b,c,e},{a,c,d}, {b,c,d}, {a,c,e}, {x,x,x}




    where instead of the x you should replace letters.



    Source: http://zagaza.ru/za548.htm






    logical-deduction pattern combinatorics







    share|improve this question









    New contributor




    alnesi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.























      5












      5








      5







      I need to find the solution of this pattern:




      {a,b,c}, {c,d,e}, ?, ?, ?, {b,c,e}, {a,c,d}, {b,c,d}, {a,c,e}, ?




      The solution should be something like this:




      {a,b,c}, {c,d,e} {x,x,x} {x,x,x} {x,x,x},{b,c,e},{a,c,d}, {b,c,d}, {a,c,e}, {x,x,x}




      where instead of the x you should replace letters.



      Source: http://zagaza.ru/za548.htm






      logical-deduction pattern combinatorics







      share|improve this question









      New contributor




      alnesi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      I need to find the solution of this pattern:




      {a,b,c}, {c,d,e}, ?, ?, ?, {b,c,e}, {a,c,d}, {b,c,d}, {a,c,e}, ?




      The solution should be something like this:




      {a,b,c}, {c,d,e} {x,x,x} {x,x,x} {x,x,x},{b,c,e},{a,c,d}, {b,c,d}, {a,c,e}, {x,x,x}




      where instead of the x you should replace letters.



      Source: http://zagaza.ru/za548.htm






      logical-deduction pattern combinatorics




      logical-deduction pattern combinatorics






      share|improve this question









      New contributor




      alnesi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|improve this question









      New contributor




      alnesi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      share|improve this question




      share|improve this question








      edited 50 mins ago









      Peter Mortensen

      1253




      1253






      New contributor




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      asked 10 hours ago









      alnesi

      457




      457




      New contributor




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      New contributor





      alnesi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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      Check out our Code of Conduct.






















          1 Answer
          1






          active

          oldest

          votes


















          6














          How about:




          {a,b,c}, {c,d,e}, {a,b,d}, {b,d,e}, {a,b,e}, {b,c,e}, {a,c,d}, {b,c,d}, {a,c,e}, {a,d,e}.




          Because:




          We know there are $binom53=10$ variants, and there are $10$ slots, so a one-to-one correspondence seems likely.


          The lexical order is {a,b,c}, {a,b,d}, {a,b,e}, {a,c,d}, {a,c,e}, {a,d,e}, {b,c,d}, {b,c,e}, {b,d,e}, {c,d,e}.


          Alternate indices cover 1,2,3,4,5 and 10,9,8,7,6, i.e. 1,10,2,9,3,8,4,7,5,6.







          share|improve this answer





















          • This is logical. I was going for Permutations instead.
            – ABcDexter
            7 hours ago










          • thanks for answering,could you please explain me how you understood the order of those variants,i mean inside the x.x.x at the beginning there could even be C as first letter,please explain that to an heretical guy xD
            – alnesi
            7 hours ago










          • do u have any other contact,like discord,steam even a twitter account that you use to communicate thanks in advace
            – alnesi
            7 hours ago










          • @alnesi I think the explanation is already very good and clear. maybe you don't see how the lexical order is determined? Just take three letters, and order them as if they were words: "abc", "abd",... Once that is established, the index alternation should pretty easy.
            – Silly Freak
            7 hours ago












          • oh thank you,i just wanted to know that :D .Really thank you
            – alnesi
            6 hours ago













          Your Answer





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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          6














          How about:




          {a,b,c}, {c,d,e}, {a,b,d}, {b,d,e}, {a,b,e}, {b,c,e}, {a,c,d}, {b,c,d}, {a,c,e}, {a,d,e}.




          Because:




          We know there are $binom53=10$ variants, and there are $10$ slots, so a one-to-one correspondence seems likely.


          The lexical order is {a,b,c}, {a,b,d}, {a,b,e}, {a,c,d}, {a,c,e}, {a,d,e}, {b,c,d}, {b,c,e}, {b,d,e}, {c,d,e}.


          Alternate indices cover 1,2,3,4,5 and 10,9,8,7,6, i.e. 1,10,2,9,3,8,4,7,5,6.







          share|improve this answer





















          • This is logical. I was going for Permutations instead.
            – ABcDexter
            7 hours ago










          • thanks for answering,could you please explain me how you understood the order of those variants,i mean inside the x.x.x at the beginning there could even be C as first letter,please explain that to an heretical guy xD
            – alnesi
            7 hours ago










          • do u have any other contact,like discord,steam even a twitter account that you use to communicate thanks in advace
            – alnesi
            7 hours ago










          • @alnesi I think the explanation is already very good and clear. maybe you don't see how the lexical order is determined? Just take three letters, and order them as if they were words: "abc", "abd",... Once that is established, the index alternation should pretty easy.
            – Silly Freak
            7 hours ago












          • oh thank you,i just wanted to know that :D .Really thank you
            – alnesi
            6 hours ago


















          6














          How about:




          {a,b,c}, {c,d,e}, {a,b,d}, {b,d,e}, {a,b,e}, {b,c,e}, {a,c,d}, {b,c,d}, {a,c,e}, {a,d,e}.




          Because:




          We know there are $binom53=10$ variants, and there are $10$ slots, so a one-to-one correspondence seems likely.


          The lexical order is {a,b,c}, {a,b,d}, {a,b,e}, {a,c,d}, {a,c,e}, {a,d,e}, {b,c,d}, {b,c,e}, {b,d,e}, {c,d,e}.


          Alternate indices cover 1,2,3,4,5 and 10,9,8,7,6, i.e. 1,10,2,9,3,8,4,7,5,6.







          share|improve this answer





















          • This is logical. I was going for Permutations instead.
            – ABcDexter
            7 hours ago










          • thanks for answering,could you please explain me how you understood the order of those variants,i mean inside the x.x.x at the beginning there could even be C as first letter,please explain that to an heretical guy xD
            – alnesi
            7 hours ago










          • do u have any other contact,like discord,steam even a twitter account that you use to communicate thanks in advace
            – alnesi
            7 hours ago










          • @alnesi I think the explanation is already very good and clear. maybe you don't see how the lexical order is determined? Just take three letters, and order them as if they were words: "abc", "abd",... Once that is established, the index alternation should pretty easy.
            – Silly Freak
            7 hours ago












          • oh thank you,i just wanted to know that :D .Really thank you
            – alnesi
            6 hours ago
















          6












          6








          6






          How about:




          {a,b,c}, {c,d,e}, {a,b,d}, {b,d,e}, {a,b,e}, {b,c,e}, {a,c,d}, {b,c,d}, {a,c,e}, {a,d,e}.




          Because:




          We know there are $binom53=10$ variants, and there are $10$ slots, so a one-to-one correspondence seems likely.


          The lexical order is {a,b,c}, {a,b,d}, {a,b,e}, {a,c,d}, {a,c,e}, {a,d,e}, {b,c,d}, {b,c,e}, {b,d,e}, {c,d,e}.


          Alternate indices cover 1,2,3,4,5 and 10,9,8,7,6, i.e. 1,10,2,9,3,8,4,7,5,6.







          share|improve this answer












          How about:




          {a,b,c}, {c,d,e}, {a,b,d}, {b,d,e}, {a,b,e}, {b,c,e}, {a,c,d}, {b,c,d}, {a,c,e}, {a,d,e}.




          Because:




          We know there are $binom53=10$ variants, and there are $10$ slots, so a one-to-one correspondence seems likely.


          The lexical order is {a,b,c}, {a,b,d}, {a,b,e}, {a,c,d}, {a,c,e}, {a,d,e}, {b,c,d}, {b,c,e}, {b,d,e}, {c,d,e}.


          Alternate indices cover 1,2,3,4,5 and 10,9,8,7,6, i.e. 1,10,2,9,3,8,4,7,5,6.








          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 8 hours ago









          JonMark Perry

          17.6k63585




          17.6k63585












          • This is logical. I was going for Permutations instead.
            – ABcDexter
            7 hours ago










          • thanks for answering,could you please explain me how you understood the order of those variants,i mean inside the x.x.x at the beginning there could even be C as first letter,please explain that to an heretical guy xD
            – alnesi
            7 hours ago










          • do u have any other contact,like discord,steam even a twitter account that you use to communicate thanks in advace
            – alnesi
            7 hours ago










          • @alnesi I think the explanation is already very good and clear. maybe you don't see how the lexical order is determined? Just take three letters, and order them as if they were words: "abc", "abd",... Once that is established, the index alternation should pretty easy.
            – Silly Freak
            7 hours ago












          • oh thank you,i just wanted to know that :D .Really thank you
            – alnesi
            6 hours ago




















          • This is logical. I was going for Permutations instead.
            – ABcDexter
            7 hours ago










          • thanks for answering,could you please explain me how you understood the order of those variants,i mean inside the x.x.x at the beginning there could even be C as first letter,please explain that to an heretical guy xD
            – alnesi
            7 hours ago










          • do u have any other contact,like discord,steam even a twitter account that you use to communicate thanks in advace
            – alnesi
            7 hours ago










          • @alnesi I think the explanation is already very good and clear. maybe you don't see how the lexical order is determined? Just take three letters, and order them as if they were words: "abc", "abd",... Once that is established, the index alternation should pretty easy.
            – Silly Freak
            7 hours ago












          • oh thank you,i just wanted to know that :D .Really thank you
            – alnesi
            6 hours ago


















          This is logical. I was going for Permutations instead.
          – ABcDexter
          7 hours ago




          This is logical. I was going for Permutations instead.
          – ABcDexter
          7 hours ago












          thanks for answering,could you please explain me how you understood the order of those variants,i mean inside the x.x.x at the beginning there could even be C as first letter,please explain that to an heretical guy xD
          – alnesi
          7 hours ago




          thanks for answering,could you please explain me how you understood the order of those variants,i mean inside the x.x.x at the beginning there could even be C as first letter,please explain that to an heretical guy xD
          – alnesi
          7 hours ago












          do u have any other contact,like discord,steam even a twitter account that you use to communicate thanks in advace
          – alnesi
          7 hours ago




          do u have any other contact,like discord,steam even a twitter account that you use to communicate thanks in advace
          – alnesi
          7 hours ago












          @alnesi I think the explanation is already very good and clear. maybe you don't see how the lexical order is determined? Just take three letters, and order them as if they were words: "abc", "abd",... Once that is established, the index alternation should pretty easy.
          – Silly Freak
          7 hours ago






          @alnesi I think the explanation is already very good and clear. maybe you don't see how the lexical order is determined? Just take three letters, and order them as if they were words: "abc", "abd",... Once that is established, the index alternation should pretty easy.
          – Silly Freak
          7 hours ago














          oh thank you,i just wanted to know that :D .Really thank you
          – alnesi
          6 hours ago






          oh thank you,i just wanted to know that :D .Really thank you
          – alnesi
          6 hours ago












          alnesi is a new contributor. Be nice, and check out our Code of Conduct.










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