How to cast set in list into list in python?
I want to cast set in list to list like below.
before: [(1, 1, 1), (1, 1, 0), (1, 0, 1)]
after: [[1, 1, 1], [1, 1, 0], [1, 0, 1]]
I need the as simple code as possible.
python casting
asked Nov 23 at 8:08
이춘경
114
add a comment |
I want to cast set in list to list like below.
before: [(1, 1, 1), (1, 1, 0), (1, 0, 1)]
after: [[1, 1, 1], [1, 1, 0], [1, 0, 1]]
I need the as simple code as possible.
python casting
asked Nov 23 at 8:08
이춘경
114
2
Why? Those are mostly equivalent anyway. (And there's no such thing as casting in Python.)
– Daniel Roseman
Nov 23 at 8:08
4
Those aren't sets, they're tuples.after = [list(inner) for inner in before].
– L3viathan
Nov 23 at 8:09
I am confused about that a little. thank you! Right. they are tuples.
– 이춘경
Nov 23 at 8:15
BTW, tuples are more efficient than lists. You should probably leave them as tuples, unless you need to mutate them.
– PM 2Ring
Nov 23 at 8:37
@이춘경: If either of the proposed answers was helpful to you, please mark it as accepted.
– Martin Frodl
Dec 4 at 15:56
add a comment |
I want to cast set in list to list like below.
before: [(1, 1, 1), (1, 1, 0), (1, 0, 1)]
after: [[1, 1, 1], [1, 1, 0], [1, 0, 1]]
I need the as simple code as possible.
python casting
asked Nov 23 at 8:08
이춘경
114
I want to cast set in list to list like below.
before: [(1, 1, 1), (1, 1, 0), (1, 0, 1)]
after: [[1, 1, 1], [1, 1, 0], [1, 0, 1]]
I need the as simple code as possible.
python casting
python casting
asked Nov 23 at 8:08
이춘경
114
asked Nov 23 at 8:08
이춘경
114
asked Nov 23 at 8:08
이춘경
114
asked Nov 23 at 8:08
이춘경
114
asked Nov 23 at 8:08
이춘경
114
114
2
Why? Those are mostly equivalent anyway. (And there's no such thing as casting in Python.)
– Daniel Roseman
Nov 23 at 8:08
4
Those aren't sets, they're tuples.after = [list(inner) for inner in before].
– L3viathan
Nov 23 at 8:09
I am confused about that a little. thank you! Right. they are tuples.
– 이춘경
Nov 23 at 8:15
BTW, tuples are more efficient than lists. You should probably leave them as tuples, unless you need to mutate them.
– PM 2Ring
Nov 23 at 8:37
@이춘경: If either of the proposed answers was helpful to you, please mark it as accepted.
– Martin Frodl
Dec 4 at 15:56
add a comment |
2
Why? Those are mostly equivalent anyway. (And there's no such thing as casting in Python.)
– Daniel Roseman
Nov 23 at 8:08
4
Those aren't sets, they're tuples.after = [list(inner) for inner in before].
– L3viathan
Nov 23 at 8:09
I am confused about that a little. thank you! Right. they are tuples.
– 이춘경
Nov 23 at 8:15
BTW, tuples are more efficient than lists. You should probably leave them as tuples, unless you need to mutate them.
– PM 2Ring
Nov 23 at 8:37
@이춘경: If either of the proposed answers was helpful to you, please mark it as accepted.
– Martin Frodl
Dec 4 at 15:56
2
2
Why? Those are mostly equivalent anyway. (And there's no such thing as casting in Python.)
– Daniel Roseman
Nov 23 at 8:08
Why? Those are mostly equivalent anyway. (And there's no such thing as casting in Python.)
– Daniel Roseman
Nov 23 at 8:08
4
4
Those aren't sets, they're tuples.
after = [list(inner) for inner in before].– L3viathan
Nov 23 at 8:09
Those aren't sets, they're tuples.
after = [list(inner) for inner in before].– L3viathan
Nov 23 at 8:09
I am confused about that a little. thank you! Right. they are tuples.
– 이춘경
Nov 23 at 8:15
I am confused about that a little. thank you! Right. they are tuples.
– 이춘경
Nov 23 at 8:15
BTW, tuples are more efficient than lists. You should probably leave them as tuples, unless you need to mutate them.
– PM 2Ring
Nov 23 at 8:37
BTW, tuples are more efficient than lists. You should probably leave them as tuples, unless you need to mutate them.
– PM 2Ring
Nov 23 at 8:37
@이춘경: If either of the proposed answers was helpful to you, please mark it as accepted.
– Martin Frodl
Dec 4 at 15:56
@이춘경: If either of the proposed answers was helpful to you, please mark it as accepted.
– Martin Frodl
Dec 4 at 15:56
add a comment |
2 Answers
2
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oldest
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>>> x = [(1, 1, 1), (1, 1, 0), (1, 0, 1)]
>>> list(map(list, x))
[[1, 1, 1], [1, 1, 0], [1, 0, 1]]
Explanation
map(list, x) takes an iterable x and applies function list to each element of this iterable. Thus the tuple (1, 1, 1) becomes the list [1, 1, 1], (1, 1, 0) becomes [1, 1, 0] and (1, 0, 1) becomes [1, 0, 1].
These lists are then stored in a map object (assuming Python 3.x). A map object is an iterator, which can be converted to a list by calling list on it, as shown above. Often, though, you don't need to make this explicit conversion because iterator allows you to traverse the elements directly:
>>> for elem in map(list, x):
... print(elem)
...
[1, 1, 1]
[1, 1, 0]
[1, 0, 1]
answered Nov 23 at 8:11
Martin Frodl
638310
add a comment |
Let's define "before" as a variable called "array". Then we take the for-loop of the "array" while casting each element to a list.
array = [(1,1,1), (1,1,0), (1,0,1)]
casted_array =
for tuples in array:
casted_array.append(list(tuples))
There are slightly easier ways to do this, but they are harder to understand. Explanation: You define the list [(1,1,1), (1,1,0), (1,0,1)] as a variable and then define a "dummy" variable called "casted_array". You then loop through the items in the "array" variable while saving them to the "tuples" iteration variable. Every time the iteration cycle loops, the sets/tuples are converted into lists and then added on to the "casted_array" variable. The casted set/tuple is now stored in the "casted_array" variable.
answered Nov 23 at 8:24
Delkarix
85
add a comment |
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2 Answers
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2 Answers
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>>> x = [(1, 1, 1), (1, 1, 0), (1, 0, 1)]
>>> list(map(list, x))
[[1, 1, 1], [1, 1, 0], [1, 0, 1]]
Explanation
map(list, x) takes an iterable x and applies function list to each element of this iterable. Thus the tuple (1, 1, 1) becomes the list [1, 1, 1], (1, 1, 0) becomes [1, 1, 0] and (1, 0, 1) becomes [1, 0, 1].
These lists are then stored in a map object (assuming Python 3.x). A map object is an iterator, which can be converted to a list by calling list on it, as shown above. Often, though, you don't need to make this explicit conversion because iterator allows you to traverse the elements directly:
>>> for elem in map(list, x):
... print(elem)
...
[1, 1, 1]
[1, 1, 0]
[1, 0, 1]
answered Nov 23 at 8:11
Martin Frodl
638310
add a comment |
>>> x = [(1, 1, 1), (1, 1, 0), (1, 0, 1)]
>>> list(map(list, x))
[[1, 1, 1], [1, 1, 0], [1, 0, 1]]
Explanation
map(list, x) takes an iterable x and applies function list to each element of this iterable. Thus the tuple (1, 1, 1) becomes the list [1, 1, 1], (1, 1, 0) becomes [1, 1, 0] and (1, 0, 1) becomes [1, 0, 1].
These lists are then stored in a map object (assuming Python 3.x). A map object is an iterator, which can be converted to a list by calling list on it, as shown above. Often, though, you don't need to make this explicit conversion because iterator allows you to traverse the elements directly:
>>> for elem in map(list, x):
... print(elem)
...
[1, 1, 1]
[1, 1, 0]
[1, 0, 1]
answered Nov 23 at 8:11
Martin Frodl
638310
add a comment |
>>> x = [(1, 1, 1), (1, 1, 0), (1, 0, 1)]
>>> list(map(list, x))
[[1, 1, 1], [1, 1, 0], [1, 0, 1]]
Explanation
map(list, x) takes an iterable x and applies function list to each element of this iterable. Thus the tuple (1, 1, 1) becomes the list [1, 1, 1], (1, 1, 0) becomes [1, 1, 0] and (1, 0, 1) becomes [1, 0, 1].
These lists are then stored in a map object (assuming Python 3.x). A map object is an iterator, which can be converted to a list by calling list on it, as shown above. Often, though, you don't need to make this explicit conversion because iterator allows you to traverse the elements directly:
>>> for elem in map(list, x):
... print(elem)
...
[1, 1, 1]
[1, 1, 0]
[1, 0, 1]
answered Nov 23 at 8:11
Martin Frodl
638310
>>> x = [(1, 1, 1), (1, 1, 0), (1, 0, 1)]
>>> list(map(list, x))
[[1, 1, 1], [1, 1, 0], [1, 0, 1]]
Explanation
map(list, x) takes an iterable x and applies function list to each element of this iterable. Thus the tuple (1, 1, 1) becomes the list [1, 1, 1], (1, 1, 0) becomes [1, 1, 0] and (1, 0, 1) becomes [1, 0, 1].
These lists are then stored in a map object (assuming Python 3.x). A map object is an iterator, which can be converted to a list by calling list on it, as shown above. Often, though, you don't need to make this explicit conversion because iterator allows you to traverse the elements directly:
>>> for elem in map(list, x):
... print(elem)
...
[1, 1, 1]
[1, 1, 0]
[1, 0, 1]
answered Nov 23 at 8:11
Martin Frodl
638310
edited Nov 23 at 8:42
answered Nov 23 at 8:11
Martin Frodl
638310
answered Nov 23 at 8:11
Martin Frodl
638310
answered Nov 23 at 8:11
Martin Frodl
638310
638310
add a comment |
add a comment |
Let's define "before" as a variable called "array". Then we take the for-loop of the "array" while casting each element to a list.
array = [(1,1,1), (1,1,0), (1,0,1)]
casted_array =
for tuples in array:
casted_array.append(list(tuples))
There are slightly easier ways to do this, but they are harder to understand. Explanation: You define the list [(1,1,1), (1,1,0), (1,0,1)] as a variable and then define a "dummy" variable called "casted_array". You then loop through the items in the "array" variable while saving them to the "tuples" iteration variable. Every time the iteration cycle loops, the sets/tuples are converted into lists and then added on to the "casted_array" variable. The casted set/tuple is now stored in the "casted_array" variable.
answered Nov 23 at 8:24
Delkarix
85
add a comment |
Let's define "before" as a variable called "array". Then we take the for-loop of the "array" while casting each element to a list.
array = [(1,1,1), (1,1,0), (1,0,1)]
casted_array =
for tuples in array:
casted_array.append(list(tuples))
There are slightly easier ways to do this, but they are harder to understand. Explanation: You define the list [(1,1,1), (1,1,0), (1,0,1)] as a variable and then define a "dummy" variable called "casted_array". You then loop through the items in the "array" variable while saving them to the "tuples" iteration variable. Every time the iteration cycle loops, the sets/tuples are converted into lists and then added on to the "casted_array" variable. The casted set/tuple is now stored in the "casted_array" variable.
answered Nov 23 at 8:24
Delkarix
85
add a comment |
Let's define "before" as a variable called "array". Then we take the for-loop of the "array" while casting each element to a list.
array = [(1,1,1), (1,1,0), (1,0,1)]
casted_array =
for tuples in array:
casted_array.append(list(tuples))
There are slightly easier ways to do this, but they are harder to understand. Explanation: You define the list [(1,1,1), (1,1,0), (1,0,1)] as a variable and then define a "dummy" variable called "casted_array". You then loop through the items in the "array" variable while saving them to the "tuples" iteration variable. Every time the iteration cycle loops, the sets/tuples are converted into lists and then added on to the "casted_array" variable. The casted set/tuple is now stored in the "casted_array" variable.
answered Nov 23 at 8:24
Delkarix
85
Let's define "before" as a variable called "array". Then we take the for-loop of the "array" while casting each element to a list.
array = [(1,1,1), (1,1,0), (1,0,1)]
casted_array =
for tuples in array:
casted_array.append(list(tuples))
There are slightly easier ways to do this, but they are harder to understand. Explanation: You define the list [(1,1,1), (1,1,0), (1,0,1)] as a variable and then define a "dummy" variable called "casted_array". You then loop through the items in the "array" variable while saving them to the "tuples" iteration variable. Every time the iteration cycle loops, the sets/tuples are converted into lists and then added on to the "casted_array" variable. The casted set/tuple is now stored in the "casted_array" variable.
answered Nov 23 at 8:24
Delkarix
85
answered Nov 23 at 8:24
Delkarix
85
answered Nov 23 at 8:24
Delkarix
85
answered Nov 23 at 8:24
Delkarix
85
85
add a comment |
add a comment |
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2
Why? Those are mostly equivalent anyway. (And there's no such thing as casting in Python.)
– Daniel Roseman
Nov 23 at 8:08
4
Those aren't sets, they're tuples.
after = [list(inner) for inner in before].– L3viathan
Nov 23 at 8:09
I am confused about that a little. thank you! Right. they are tuples.
– 이춘경
Nov 23 at 8:15
BTW, tuples are more efficient than lists. You should probably leave them as tuples, unless you need to mutate them.
– PM 2Ring
Nov 23 at 8:37
@이춘경: If either of the proposed answers was helpful to you, please mark it as accepted.
– Martin Frodl
Dec 4 at 15:56