Replacing a column in a table with values dependent on the current values in the column?
$begingroup$
I currently have a table of absorbances vs. wavenumbers. How would I change that to a table of %transmittances vs. wavenumbers? The relationship is given by
%Transmittance = (10^(-absorbance))*100]
I've tried:
newtable = Replace[currenttable, i -> ((10^(-i))*100)]
No errors occur, but nothing happens.
list-manipulation
edited 12 hours ago
m_goldberg
88.4k872199
asked 12 hours ago
Christof Israel FontanillaChristof Israel Fontanilla
111
New contributor
Christof Israel Fontanilla is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
I currently have a table of absorbances vs. wavenumbers. How would I change that to a table of %transmittances vs. wavenumbers? The relationship is given by
%Transmittance = (10^(-absorbance))*100]
I've tried:
newtable = Replace[currenttable, i -> ((10^(-i))*100)]
No errors occur, but nothing happens.
list-manipulation
edited 12 hours ago
m_goldberg
88.4k872199
asked 12 hours ago
Christof Israel FontanillaChristof Israel Fontanilla
111
New contributor
Christof Israel Fontanilla is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
2
$begingroup$
You may usenewtable = currenttable; newtable[[All, i]] = (10^(-newtable[[All, i]]))*100;whereiis the number of the column. If you wonder what[[ ]]is, look upPartin the documentation.
$endgroup$
– Henrik Schumacher
12 hours ago
2
$begingroup$
Is the table structured as a list of pairs in form {wave-number, absorbance}?
$endgroup$
– m_goldberg
12 hours ago
2
$begingroup$
If you could show a brief excerpt of your table in your question, it would be easier to help you more effectively.
$endgroup$
– MarcoB
12 hours ago
add a comment |
$begingroup$
I currently have a table of absorbances vs. wavenumbers. How would I change that to a table of %transmittances vs. wavenumbers? The relationship is given by
%Transmittance = (10^(-absorbance))*100]
I've tried:
newtable = Replace[currenttable, i -> ((10^(-i))*100)]
No errors occur, but nothing happens.
list-manipulation
edited 12 hours ago
m_goldberg
88.4k872199
asked 12 hours ago
Christof Israel FontanillaChristof Israel Fontanilla
111
New contributor
Christof Israel Fontanilla is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
I currently have a table of absorbances vs. wavenumbers. How would I change that to a table of %transmittances vs. wavenumbers? The relationship is given by
%Transmittance = (10^(-absorbance))*100]
I've tried:
newtable = Replace[currenttable, i -> ((10^(-i))*100)]
No errors occur, but nothing happens.
list-manipulation
list-manipulation
edited 12 hours ago
m_goldberg
88.4k872199
asked 12 hours ago
Christof Israel FontanillaChristof Israel Fontanilla
111
New contributor
Christof Israel Fontanilla is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 12 hours ago
m_goldberg
88.4k872199
asked 12 hours ago
Christof Israel FontanillaChristof Israel Fontanilla
111
New contributor
Christof Israel Fontanilla is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 12 hours ago
m_goldberg
88.4k872199
edited 12 hours ago
m_goldberg
88.4k872199
edited 12 hours ago
m_goldberg
88.4k872199
88.4k872199
asked 12 hours ago
Christof Israel FontanillaChristof Israel Fontanilla
111
New contributor
Christof Israel Fontanilla is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 12 hours ago
Christof Israel FontanillaChristof Israel Fontanilla
111
asked 12 hours ago
Christof Israel FontanillaChristof Israel Fontanilla
111
111
New contributor
Christof Israel Fontanilla is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Christof Israel Fontanilla is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Christof Israel Fontanilla is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
2
$begingroup$
You may usenewtable = currenttable; newtable[[All, i]] = (10^(-newtable[[All, i]]))*100;whereiis the number of the column. If you wonder what[[ ]]is, look upPartin the documentation.
$endgroup$
– Henrik Schumacher
12 hours ago
2
$begingroup$
Is the table structured as a list of pairs in form {wave-number, absorbance}?
$endgroup$
– m_goldberg
12 hours ago
2
$begingroup$
If you could show a brief excerpt of your table in your question, it would be easier to help you more effectively.
$endgroup$
– MarcoB
12 hours ago
add a comment |
2
$begingroup$
You may usenewtable = currenttable; newtable[[All, i]] = (10^(-newtable[[All, i]]))*100;whereiis the number of the column. If you wonder what[[ ]]is, look upPartin the documentation.
$endgroup$
– Henrik Schumacher
12 hours ago
2
$begingroup$
Is the table structured as a list of pairs in form {wave-number, absorbance}?
$endgroup$
– m_goldberg
12 hours ago
2
$begingroup$
If you could show a brief excerpt of your table in your question, it would be easier to help you more effectively.
$endgroup$
– MarcoB
12 hours ago
2
2
$begingroup$
You may use
newtable = currenttable; newtable[[All, i]] = (10^(-newtable[[All, i]]))*100; where i is the number of the column. If you wonder what [[ ]] is, look up Part in the documentation.$endgroup$
– Henrik Schumacher
12 hours ago
$begingroup$
You may use
newtable = currenttable; newtable[[All, i]] = (10^(-newtable[[All, i]]))*100; where i is the number of the column. If you wonder what [[ ]] is, look up Part in the documentation.$endgroup$
– Henrik Schumacher
12 hours ago
2
2
$begingroup$
Is the table structured as a list of pairs in form {wave-number, absorbance}?
$endgroup$
– m_goldberg
12 hours ago
$begingroup$
Is the table structured as a list of pairs in form {wave-number, absorbance}?
$endgroup$
– m_goldberg
12 hours ago
2
2
$begingroup$
If you could show a brief excerpt of your table in your question, it would be easier to help you more effectively.
$endgroup$
– MarcoB
12 hours ago
$begingroup$
If you could show a brief excerpt of your table in your question, it would be easier to help you more effectively.
$endgroup$
– MarcoB
12 hours ago
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
Contrived data based on the element form {wave-number, absorbance}.
SeedRandom[42];
With[{n = 5}, data = Sort @ Transpose[{RandomInteger[100, n], RandomReal[1., n]}]]
{{4, 0.142803}, {6, 0.628702}, {15, 0.290081}, {54, 0.0292846}, {66, 0.105067}}
Assuming you want to keep the original data and not destructively change the 2nd column in it, you could proceed as follows:
newdata = data;
newdata[[All, 2]] = 100 10^-data[[All, 2]];
newdata
{{4, 71.9776}, {6, 23.5124}, {15, 51.2765}, {54, 93.4793}, {66, 78.5114}}
This works because all Mathematica's arithmetic operators have a property called Listable, which means they automatically map over lists such as data[[All, 2]]. In this case the operator doing the mapping is Power.
answered 11 hours ago
m_goldbergm_goldberg
88.4k872199
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add a comment |
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1 Answer
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active
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votes
1 Answer
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active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Contrived data based on the element form {wave-number, absorbance}.
SeedRandom[42];
With[{n = 5}, data = Sort @ Transpose[{RandomInteger[100, n], RandomReal[1., n]}]]
{{4, 0.142803}, {6, 0.628702}, {15, 0.290081}, {54, 0.0292846}, {66, 0.105067}}
Assuming you want to keep the original data and not destructively change the 2nd column in it, you could proceed as follows:
newdata = data;
newdata[[All, 2]] = 100 10^-data[[All, 2]];
newdata
{{4, 71.9776}, {6, 23.5124}, {15, 51.2765}, {54, 93.4793}, {66, 78.5114}}
This works because all Mathematica's arithmetic operators have a property called Listable, which means they automatically map over lists such as data[[All, 2]]. In this case the operator doing the mapping is Power.
answered 11 hours ago
m_goldbergm_goldberg
88.4k872199
$endgroup$
add a comment |
$begingroup$
Contrived data based on the element form {wave-number, absorbance}.
SeedRandom[42];
With[{n = 5}, data = Sort @ Transpose[{RandomInteger[100, n], RandomReal[1., n]}]]
{{4, 0.142803}, {6, 0.628702}, {15, 0.290081}, {54, 0.0292846}, {66, 0.105067}}
Assuming you want to keep the original data and not destructively change the 2nd column in it, you could proceed as follows:
newdata = data;
newdata[[All, 2]] = 100 10^-data[[All, 2]];
newdata
{{4, 71.9776}, {6, 23.5124}, {15, 51.2765}, {54, 93.4793}, {66, 78.5114}}
This works because all Mathematica's arithmetic operators have a property called Listable, which means they automatically map over lists such as data[[All, 2]]. In this case the operator doing the mapping is Power.
answered 11 hours ago
m_goldbergm_goldberg
88.4k872199
$endgroup$
add a comment |
$begingroup$
Contrived data based on the element form {wave-number, absorbance}.
SeedRandom[42];
With[{n = 5}, data = Sort @ Transpose[{RandomInteger[100, n], RandomReal[1., n]}]]
{{4, 0.142803}, {6, 0.628702}, {15, 0.290081}, {54, 0.0292846}, {66, 0.105067}}
Assuming you want to keep the original data and not destructively change the 2nd column in it, you could proceed as follows:
newdata = data;
newdata[[All, 2]] = 100 10^-data[[All, 2]];
newdata
{{4, 71.9776}, {6, 23.5124}, {15, 51.2765}, {54, 93.4793}, {66, 78.5114}}
This works because all Mathematica's arithmetic operators have a property called Listable, which means they automatically map over lists such as data[[All, 2]]. In this case the operator doing the mapping is Power.
answered 11 hours ago
m_goldbergm_goldberg
88.4k872199
$endgroup$
Contrived data based on the element form {wave-number, absorbance}.
SeedRandom[42];
With[{n = 5}, data = Sort @ Transpose[{RandomInteger[100, n], RandomReal[1., n]}]]
{{4, 0.142803}, {6, 0.628702}, {15, 0.290081}, {54, 0.0292846}, {66, 0.105067}}
Assuming you want to keep the original data and not destructively change the 2nd column in it, you could proceed as follows:
newdata = data;
newdata[[All, 2]] = 100 10^-data[[All, 2]];
newdata
{{4, 71.9776}, {6, 23.5124}, {15, 51.2765}, {54, 93.4793}, {66, 78.5114}}
This works because all Mathematica's arithmetic operators have a property called Listable, which means they automatically map over lists such as data[[All, 2]]. In this case the operator doing the mapping is Power.
answered 11 hours ago
m_goldbergm_goldberg
88.4k872199
edited 11 hours ago
answered 11 hours ago
m_goldbergm_goldberg
88.4k872199
answered 11 hours ago
m_goldbergm_goldberg
88.4k872199
answered 11 hours ago
m_goldbergm_goldberg
88.4k872199
88.4k872199
add a comment |
add a comment |
Christof Israel Fontanilla is a new contributor. Be nice, and check out our Code of Conduct.
Christof Israel Fontanilla is a new contributor. Be nice, and check out our Code of Conduct.
Christof Israel Fontanilla is a new contributor. Be nice, and check out our Code of Conduct.
Christof Israel Fontanilla is a new contributor. Be nice, and check out our Code of Conduct.
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2
$begingroup$
You may use
newtable = currenttable; newtable[[All, i]] = (10^(-newtable[[All, i]]))*100;whereiis the number of the column. If you wonder what[[ ]]is, look upPartin the documentation.$endgroup$
– Henrik Schumacher
12 hours ago
2
$begingroup$
Is the table structured as a list of pairs in form {wave-number, absorbance}?
$endgroup$
– m_goldberg
12 hours ago
2
$begingroup$
If you could show a brief excerpt of your table in your question, it would be easier to help you more effectively.
$endgroup$
– MarcoB
12 hours ago