Replacing a column in a table with values dependent on the current values in the column?












2












$begingroup$


I currently have a table of absorbances vs. wavenumbers. How would I change that to a table of %transmittances vs. wavenumbers? The relationship is given by



%Transmittance = (10^(-absorbance))*100]


I've tried:



newtable = Replace[currenttable, i -> ((10^(-i))*100)]


No errors occur, but nothing happens.






list-manipulation







share|improve this question









New contributor




Christof Israel Fontanilla is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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$endgroup$








  • 2




    $begingroup$
    You may use newtable = currenttable; newtable[[All, i]] = (10^(-newtable[[All, i]]))*100; where i is the number of the column. If you wonder what [[ ]] is, look up Part in the documentation.
    $endgroup$
    – Henrik Schumacher
    12 hours ago






  • 2




    $begingroup$
    Is the table structured as a list of pairs in form {wave-number, absorbance}?
    $endgroup$
    – m_goldberg
    12 hours ago






  • 2




    $begingroup$
    If you could show a brief excerpt of your table in your question, it would be easier to help you more effectively.
    $endgroup$
    – MarcoB
    12 hours ago
















2












$begingroup$


I currently have a table of absorbances vs. wavenumbers. How would I change that to a table of %transmittances vs. wavenumbers? The relationship is given by



%Transmittance = (10^(-absorbance))*100]


I've tried:



newtable = Replace[currenttable, i -> ((10^(-i))*100)]


No errors occur, but nothing happens.






list-manipulation







share|improve this question









New contributor




Christof Israel Fontanilla is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$








  • 2




    $begingroup$
    You may use newtable = currenttable; newtable[[All, i]] = (10^(-newtable[[All, i]]))*100; where i is the number of the column. If you wonder what [[ ]] is, look up Part in the documentation.
    $endgroup$
    – Henrik Schumacher
    12 hours ago






  • 2




    $begingroup$
    Is the table structured as a list of pairs in form {wave-number, absorbance}?
    $endgroup$
    – m_goldberg
    12 hours ago






  • 2




    $begingroup$
    If you could show a brief excerpt of your table in your question, it would be easier to help you more effectively.
    $endgroup$
    – MarcoB
    12 hours ago














2












2








2





$begingroup$


I currently have a table of absorbances vs. wavenumbers. How would I change that to a table of %transmittances vs. wavenumbers? The relationship is given by



%Transmittance = (10^(-absorbance))*100]


I've tried:



newtable = Replace[currenttable, i -> ((10^(-i))*100)]


No errors occur, but nothing happens.






list-manipulation







share|improve this question









New contributor




Christof Israel Fontanilla is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$




I currently have a table of absorbances vs. wavenumbers. How would I change that to a table of %transmittances vs. wavenumbers? The relationship is given by



%Transmittance = (10^(-absorbance))*100]


I've tried:



newtable = Replace[currenttable, i -> ((10^(-i))*100)]


No errors occur, but nothing happens.






list-manipulation




list-manipulation






share|improve this question









New contributor




Christof Israel Fontanilla is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question









New contributor




Christof Israel Fontanilla is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question








edited 12 hours ago









m_goldberg

88.4k872199




88.4k872199






New contributor




Christof Israel Fontanilla is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked 12 hours ago









Christof Israel FontanillaChristof Israel Fontanilla

111




111




New contributor




Christof Israel Fontanilla is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





Christof Israel Fontanilla is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Christof Israel Fontanilla is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








  • 2




    $begingroup$
    You may use newtable = currenttable; newtable[[All, i]] = (10^(-newtable[[All, i]]))*100; where i is the number of the column. If you wonder what [[ ]] is, look up Part in the documentation.
    $endgroup$
    – Henrik Schumacher
    12 hours ago






  • 2




    $begingroup$
    Is the table structured as a list of pairs in form {wave-number, absorbance}?
    $endgroup$
    – m_goldberg
    12 hours ago






  • 2




    $begingroup$
    If you could show a brief excerpt of your table in your question, it would be easier to help you more effectively.
    $endgroup$
    – MarcoB
    12 hours ago














  • 2




    $begingroup$
    You may use newtable = currenttable; newtable[[All, i]] = (10^(-newtable[[All, i]]))*100; where i is the number of the column. If you wonder what [[ ]] is, look up Part in the documentation.
    $endgroup$
    – Henrik Schumacher
    12 hours ago






  • 2




    $begingroup$
    Is the table structured as a list of pairs in form {wave-number, absorbance}?
    $endgroup$
    – m_goldberg
    12 hours ago






  • 2




    $begingroup$
    If you could show a brief excerpt of your table in your question, it would be easier to help you more effectively.
    $endgroup$
    – MarcoB
    12 hours ago








2




2




$begingroup$
You may use newtable = currenttable; newtable[[All, i]] = (10^(-newtable[[All, i]]))*100; where i is the number of the column. If you wonder what [[ ]] is, look up Part in the documentation.
$endgroup$
– Henrik Schumacher
12 hours ago




$begingroup$
You may use newtable = currenttable; newtable[[All, i]] = (10^(-newtable[[All, i]]))*100; where i is the number of the column. If you wonder what [[ ]] is, look up Part in the documentation.
$endgroup$
– Henrik Schumacher
12 hours ago




2




2




$begingroup$
Is the table structured as a list of pairs in form {wave-number, absorbance}?
$endgroup$
– m_goldberg
12 hours ago




$begingroup$
Is the table structured as a list of pairs in form {wave-number, absorbance}?
$endgroup$
– m_goldberg
12 hours ago




2




2




$begingroup$
If you could show a brief excerpt of your table in your question, it would be easier to help you more effectively.
$endgroup$
– MarcoB
12 hours ago




$begingroup$
If you could show a brief excerpt of your table in your question, it would be easier to help you more effectively.
$endgroup$
– MarcoB
12 hours ago










1 Answer
1






active

oldest

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4












$begingroup$

Contrived data based on the element form {wave-number, absorbance}.



SeedRandom[42]; 

With[{n = 5}, data = Sort @ Transpose[{RandomInteger[100, n], RandomReal[1., n]}]]





{{4, 0.142803}, {6, 0.628702}, {15, 0.290081}, {54, 0.0292846}, {66, 0.105067}}



Assuming you want to keep the original data and not destructively change the 2nd column in it, you could proceed as follows:



newdata = data;

newdata[[All, 2]] = 100 10^-data[[All, 2]];

newdata





{{4, 71.9776}, {6, 23.5124}, {15, 51.2765}, {54, 93.4793}, {66, 78.5114}}



This works because all Mathematica's arithmetic operators have a property called Listable, which means they automatically map over lists such as data[[All, 2]]. In this case the operator doing the mapping is Power.






share|improve this answer











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    4












    $begingroup$

    Contrived data based on the element form {wave-number, absorbance}.



    SeedRandom[42]; 
    
With[{n = 5}, data = Sort @ Transpose[{RandomInteger[100, n], RandomReal[1., n]}]]
    




    {{4, 0.142803}, {6, 0.628702}, {15, 0.290081}, {54, 0.0292846}, {66, 0.105067}}



    Assuming you want to keep the original data and not destructively change the 2nd column in it, you could proceed as follows:



    newdata = data;
    
newdata[[All, 2]] = 100 10^-data[[All, 2]];
    
newdata
    




    {{4, 71.9776}, {6, 23.5124}, {15, 51.2765}, {54, 93.4793}, {66, 78.5114}}



    This works because all Mathematica's arithmetic operators have a property called Listable, which means they automatically map over lists such as data[[All, 2]]. In this case the operator doing the mapping is Power.






    share|improve this answer











    $endgroup$


















      4












      $begingroup$

      Contrived data based on the element form {wave-number, absorbance}.



      SeedRandom[42]; 
      
With[{n = 5}, data = Sort @ Transpose[{RandomInteger[100, n], RandomReal[1., n]}]]
      




      {{4, 0.142803}, {6, 0.628702}, {15, 0.290081}, {54, 0.0292846}, {66, 0.105067}}



      Assuming you want to keep the original data and not destructively change the 2nd column in it, you could proceed as follows:



      newdata = data;
      
newdata[[All, 2]] = 100 10^-data[[All, 2]];
      
newdata
      




      {{4, 71.9776}, {6, 23.5124}, {15, 51.2765}, {54, 93.4793}, {66, 78.5114}}



      This works because all Mathematica's arithmetic operators have a property called Listable, which means they automatically map over lists such as data[[All, 2]]. In this case the operator doing the mapping is Power.






      share|improve this answer











      $endgroup$
















        4












        4








        4





        $begingroup$

        Contrived data based on the element form {wave-number, absorbance}.



        SeedRandom[42]; 
        
With[{n = 5}, data = Sort @ Transpose[{RandomInteger[100, n], RandomReal[1., n]}]]
        




        {{4, 0.142803}, {6, 0.628702}, {15, 0.290081}, {54, 0.0292846}, {66, 0.105067}}



        Assuming you want to keep the original data and not destructively change the 2nd column in it, you could proceed as follows:



        newdata = data;
        
newdata[[All, 2]] = 100 10^-data[[All, 2]];
        
newdata
        




        {{4, 71.9776}, {6, 23.5124}, {15, 51.2765}, {54, 93.4793}, {66, 78.5114}}



        This works because all Mathematica's arithmetic operators have a property called Listable, which means they automatically map over lists such as data[[All, 2]]. In this case the operator doing the mapping is Power.






        share|improve this answer











        $endgroup$



        Contrived data based on the element form {wave-number, absorbance}.



        SeedRandom[42]; 
        
With[{n = 5}, data = Sort @ Transpose[{RandomInteger[100, n], RandomReal[1., n]}]]
        




        {{4, 0.142803}, {6, 0.628702}, {15, 0.290081}, {54, 0.0292846}, {66, 0.105067}}



        Assuming you want to keep the original data and not destructively change the 2nd column in it, you could proceed as follows:



        newdata = data;
        
newdata[[All, 2]] = 100 10^-data[[All, 2]];
        
newdata
        




        {{4, 71.9776}, {6, 23.5124}, {15, 51.2765}, {54, 93.4793}, {66, 78.5114}}



        This works because all Mathematica's arithmetic operators have a property called Listable, which means they automatically map over lists such as data[[All, 2]]. In this case the operator doing the mapping is Power.







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited 11 hours ago

























        answered 11 hours ago









        m_goldbergm_goldberg

        88.4k872199




        88.4k872199






















            Christof Israel Fontanilla is a new contributor. Be nice, and check out our Code of Conduct.










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