How can I plot a Farey diagram?












4












$begingroup$


How can I plot the following diagram for a Farey series?



enter image description here










share|improve this question









New contributor




Gustavo Rubiano is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$












  • $begingroup$
    From the beautiful book A. Hatcher Topology of numbers
    $endgroup$
    – Gustavo Rubiano
    17 hours ago






  • 1




    $begingroup$
    Could you perhaps expand a bit on how the curves are calculated etc?
    $endgroup$
    – MarcoB
    17 hours ago










  • $begingroup$
    pi.math.cornell.edu/~hatcher/TN/TNch1.pdf
    $endgroup$
    – Moo
    15 hours ago
















4












$begingroup$


How can I plot the following diagram for a Farey series?



enter image description here










share|improve this question









New contributor




Gustavo Rubiano is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$












  • $begingroup$
    From the beautiful book A. Hatcher Topology of numbers
    $endgroup$
    – Gustavo Rubiano
    17 hours ago






  • 1




    $begingroup$
    Could you perhaps expand a bit on how the curves are calculated etc?
    $endgroup$
    – MarcoB
    17 hours ago










  • $begingroup$
    pi.math.cornell.edu/~hatcher/TN/TNch1.pdf
    $endgroup$
    – Moo
    15 hours ago














4












4








4


2



$begingroup$


How can I plot the following diagram for a Farey series?



enter image description here










share|improve this question









New contributor




Gustavo Rubiano is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$




How can I plot the following diagram for a Farey series?



enter image description here







graphics number-theory






share|improve this question









New contributor




Gustavo Rubiano is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question









New contributor




Gustavo Rubiano is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question








edited 12 hours ago









Michael E2

150k12203482




150k12203482






New contributor




Gustavo Rubiano is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked 17 hours ago









Gustavo RubianoGustavo Rubiano

243




243




New contributor




Gustavo Rubiano is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





Gustavo Rubiano is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Gustavo Rubiano is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.












  • $begingroup$
    From the beautiful book A. Hatcher Topology of numbers
    $endgroup$
    – Gustavo Rubiano
    17 hours ago






  • 1




    $begingroup$
    Could you perhaps expand a bit on how the curves are calculated etc?
    $endgroup$
    – MarcoB
    17 hours ago










  • $begingroup$
    pi.math.cornell.edu/~hatcher/TN/TNch1.pdf
    $endgroup$
    – Moo
    15 hours ago


















  • $begingroup$
    From the beautiful book A. Hatcher Topology of numbers
    $endgroup$
    – Gustavo Rubiano
    17 hours ago






  • 1




    $begingroup$
    Could you perhaps expand a bit on how the curves are calculated etc?
    $endgroup$
    – MarcoB
    17 hours ago










  • $begingroup$
    pi.math.cornell.edu/~hatcher/TN/TNch1.pdf
    $endgroup$
    – Moo
    15 hours ago
















$begingroup$
From the beautiful book A. Hatcher Topology of numbers
$endgroup$
– Gustavo Rubiano
17 hours ago




$begingroup$
From the beautiful book A. Hatcher Topology of numbers
$endgroup$
– Gustavo Rubiano
17 hours ago




1




1




$begingroup$
Could you perhaps expand a bit on how the curves are calculated etc?
$endgroup$
– MarcoB
17 hours ago




$begingroup$
Could you perhaps expand a bit on how the curves are calculated etc?
$endgroup$
– MarcoB
17 hours ago












$begingroup$
pi.math.cornell.edu/~hatcher/TN/TNch1.pdf
$endgroup$
– Moo
15 hours ago




$begingroup$
pi.math.cornell.edu/~hatcher/TN/TNch1.pdf
$endgroup$
– Moo
15 hours ago










2 Answers
2






active

oldest

votes


















10












$begingroup$

The curvilinear triangles which are characteristic for this type of plot are called hypocycloid curves. We can use the parametric equations on Wikipedia to plot these, like so:



x[a_, b_, t_] := (b - a) Cos[t] + a Cos[(b - a)/a t]
y[a_, b_, t_] := (b - a) Sin[t] - a Sin[(b - a)/a t]
hypocycloid[n_] := ParametricPlot[
{x[1/n, 1, t], y[1/n, 1, t]},
{t, 0, 2 Pi},
PlotStyle -> {Thickness[0.002], Black}
]

Show[
Graphics[Circle[{0, 0}, 1]],
hypocycloid[2],
hypocycloid[4],
hypocycloid[8],
hypocycloid[16],
hypocycloid[32],
hypocycloid[64],
ImageSize -> 500
]


Mathematica graphics



I've previously written about an application of hypocycloids here, and I showed how to visualize epicycloids here.



How to generate the labels is described here (also linked to by moo in a comment). I will simply provide the code.



mediant[{a_, b_}, {c_, d_}] := {a + c, b + d}
recursive[v1_, v2_, depth_] := If[
depth > 2,
mediant[v1, v2], {
recursive[v1, mediant[v1, v2], depth + 1],
mediant[v1, v2],
recursive[mediant[v1, v2], v2, depth + 1]
}]

computeLabels[v1_, v2_] := Module[{numbers},
numbers =
Cases[recursive[v1, v2, 0], {_Integer, _Integer}, Infinity];
StringTemplate["``/``"] @@@ numbers
]
computeLabelsNegative[v1_, v2_] := Module[{numbers},
numbers =
Cases[recursive[v1, v2, 0], {_Integer, _Integer}, Infinity];
StringTemplate["-`2`/`1`"] @@@ numbers
]

labels = Reverse@Join[
{"1/0"},
computeLabels[{1, 0}, {1, 1}],
{"1/1"},
computeLabels[{1, 1}, {0, 1}],
{"0/1"},
computeLabelsNegative[{1, 0}, {1, 1}],
{"-1,1"},
computeLabelsNegative[{1, 1}, {0, 1}]
];

coords = CirclePoints[{1.1, 186 Degree}, 64];

Show[
Graphics[Circle[{0, 0}, 1]],
hypocycloid[2],
hypocycloid[4],
hypocycloid[8],
hypocycloid[16],
hypocycloid[32],
hypocycloid[64],
Graphics@MapThread[Text, {labels, coords}],
ImageSize -> 500
]


Mathematica graphics






share|improve this answer











$endgroup$





















    3












    $begingroup$

    I looked up the Farey sequence on Wikipedia, out of curiosity, because I had not heard of it before. The Farey sequence of order $n$ is "the sequence of completely reduced fractions between 0 and 1 which, when in lowest terms, have denominators less than or equal to $n$, arranged in order of increasing size".



    On that basis, you can generate the sequence as follows, for instance:



    ClearAll[farey]
    farey[n_Integer] := (Divide @@@ Subsets[Range[n], {2}]) ~ Join ~ {0, 1} //DeleteDuplicates //Sort


    So for instance:



    farey[5]



    {0, 1/5, 1/4, 1/3, 2/5, 1/2, 3/5, 2/3, 3/4, 4/5, 1}




    I am not sure how these sequences are connected with the figure you showed though.






    share|improve this answer









    $endgroup$













    • $begingroup$
      Thanks to C.E., it is a concrete answer
      $endgroup$
      – Gustavo Rubiano
      2 hours ago












    Your Answer





    StackExchange.ifUsing("editor", function () {
    return StackExchange.using("mathjaxEditing", function () {
    StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
    StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
    });
    });
    }, "mathjax-editing");

    StackExchange.ready(function() {
    var channelOptions = {
    tags: "".split(" "),
    id: "387"
    };
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function() {
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled) {
    StackExchange.using("snippets", function() {
    createEditor();
    });
    }
    else {
    createEditor();
    }
    });

    function createEditor() {
    StackExchange.prepareEditor({
    heartbeatType: 'answer',
    autoActivateHeartbeat: false,
    convertImagesToLinks: false,
    noModals: true,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: null,
    bindNavPrevention: true,
    postfix: "",
    imageUploader: {
    brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
    contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
    allowUrls: true
    },
    onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    });


    }
    });






    Gustavo Rubiano is a new contributor. Be nice, and check out our Code of Conduct.










    draft saved

    draft discarded


















    StackExchange.ready(
    function () {
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f194838%2fhow-can-i-plot-a-farey-diagram%23new-answer', 'question_page');
    }
    );

    Post as a guest















    Required, but never shown

























    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    10












    $begingroup$

    The curvilinear triangles which are characteristic for this type of plot are called hypocycloid curves. We can use the parametric equations on Wikipedia to plot these, like so:



    x[a_, b_, t_] := (b - a) Cos[t] + a Cos[(b - a)/a t]
    y[a_, b_, t_] := (b - a) Sin[t] - a Sin[(b - a)/a t]
    hypocycloid[n_] := ParametricPlot[
    {x[1/n, 1, t], y[1/n, 1, t]},
    {t, 0, 2 Pi},
    PlotStyle -> {Thickness[0.002], Black}
    ]

    Show[
    Graphics[Circle[{0, 0}, 1]],
    hypocycloid[2],
    hypocycloid[4],
    hypocycloid[8],
    hypocycloid[16],
    hypocycloid[32],
    hypocycloid[64],
    ImageSize -> 500
    ]


    Mathematica graphics



    I've previously written about an application of hypocycloids here, and I showed how to visualize epicycloids here.



    How to generate the labels is described here (also linked to by moo in a comment). I will simply provide the code.



    mediant[{a_, b_}, {c_, d_}] := {a + c, b + d}
    recursive[v1_, v2_, depth_] := If[
    depth > 2,
    mediant[v1, v2], {
    recursive[v1, mediant[v1, v2], depth + 1],
    mediant[v1, v2],
    recursive[mediant[v1, v2], v2, depth + 1]
    }]

    computeLabels[v1_, v2_] := Module[{numbers},
    numbers =
    Cases[recursive[v1, v2, 0], {_Integer, _Integer}, Infinity];
    StringTemplate["``/``"] @@@ numbers
    ]
    computeLabelsNegative[v1_, v2_] := Module[{numbers},
    numbers =
    Cases[recursive[v1, v2, 0], {_Integer, _Integer}, Infinity];
    StringTemplate["-`2`/`1`"] @@@ numbers
    ]

    labels = Reverse@Join[
    {"1/0"},
    computeLabels[{1, 0}, {1, 1}],
    {"1/1"},
    computeLabels[{1, 1}, {0, 1}],
    {"0/1"},
    computeLabelsNegative[{1, 0}, {1, 1}],
    {"-1,1"},
    computeLabelsNegative[{1, 1}, {0, 1}]
    ];

    coords = CirclePoints[{1.1, 186 Degree}, 64];

    Show[
    Graphics[Circle[{0, 0}, 1]],
    hypocycloid[2],
    hypocycloid[4],
    hypocycloid[8],
    hypocycloid[16],
    hypocycloid[32],
    hypocycloid[64],
    Graphics@MapThread[Text, {labels, coords}],
    ImageSize -> 500
    ]


    Mathematica graphics






    share|improve this answer











    $endgroup$


















      10












      $begingroup$

      The curvilinear triangles which are characteristic for this type of plot are called hypocycloid curves. We can use the parametric equations on Wikipedia to plot these, like so:



      x[a_, b_, t_] := (b - a) Cos[t] + a Cos[(b - a)/a t]
      y[a_, b_, t_] := (b - a) Sin[t] - a Sin[(b - a)/a t]
      hypocycloid[n_] := ParametricPlot[
      {x[1/n, 1, t], y[1/n, 1, t]},
      {t, 0, 2 Pi},
      PlotStyle -> {Thickness[0.002], Black}
      ]

      Show[
      Graphics[Circle[{0, 0}, 1]],
      hypocycloid[2],
      hypocycloid[4],
      hypocycloid[8],
      hypocycloid[16],
      hypocycloid[32],
      hypocycloid[64],
      ImageSize -> 500
      ]


      Mathematica graphics



      I've previously written about an application of hypocycloids here, and I showed how to visualize epicycloids here.



      How to generate the labels is described here (also linked to by moo in a comment). I will simply provide the code.



      mediant[{a_, b_}, {c_, d_}] := {a + c, b + d}
      recursive[v1_, v2_, depth_] := If[
      depth > 2,
      mediant[v1, v2], {
      recursive[v1, mediant[v1, v2], depth + 1],
      mediant[v1, v2],
      recursive[mediant[v1, v2], v2, depth + 1]
      }]

      computeLabels[v1_, v2_] := Module[{numbers},
      numbers =
      Cases[recursive[v1, v2, 0], {_Integer, _Integer}, Infinity];
      StringTemplate["``/``"] @@@ numbers
      ]
      computeLabelsNegative[v1_, v2_] := Module[{numbers},
      numbers =
      Cases[recursive[v1, v2, 0], {_Integer, _Integer}, Infinity];
      StringTemplate["-`2`/`1`"] @@@ numbers
      ]

      labels = Reverse@Join[
      {"1/0"},
      computeLabels[{1, 0}, {1, 1}],
      {"1/1"},
      computeLabels[{1, 1}, {0, 1}],
      {"0/1"},
      computeLabelsNegative[{1, 0}, {1, 1}],
      {"-1,1"},
      computeLabelsNegative[{1, 1}, {0, 1}]
      ];

      coords = CirclePoints[{1.1, 186 Degree}, 64];

      Show[
      Graphics[Circle[{0, 0}, 1]],
      hypocycloid[2],
      hypocycloid[4],
      hypocycloid[8],
      hypocycloid[16],
      hypocycloid[32],
      hypocycloid[64],
      Graphics@MapThread[Text, {labels, coords}],
      ImageSize -> 500
      ]


      Mathematica graphics






      share|improve this answer











      $endgroup$
















        10












        10








        10





        $begingroup$

        The curvilinear triangles which are characteristic for this type of plot are called hypocycloid curves. We can use the parametric equations on Wikipedia to plot these, like so:



        x[a_, b_, t_] := (b - a) Cos[t] + a Cos[(b - a)/a t]
        y[a_, b_, t_] := (b - a) Sin[t] - a Sin[(b - a)/a t]
        hypocycloid[n_] := ParametricPlot[
        {x[1/n, 1, t], y[1/n, 1, t]},
        {t, 0, 2 Pi},
        PlotStyle -> {Thickness[0.002], Black}
        ]

        Show[
        Graphics[Circle[{0, 0}, 1]],
        hypocycloid[2],
        hypocycloid[4],
        hypocycloid[8],
        hypocycloid[16],
        hypocycloid[32],
        hypocycloid[64],
        ImageSize -> 500
        ]


        Mathematica graphics



        I've previously written about an application of hypocycloids here, and I showed how to visualize epicycloids here.



        How to generate the labels is described here (also linked to by moo in a comment). I will simply provide the code.



        mediant[{a_, b_}, {c_, d_}] := {a + c, b + d}
        recursive[v1_, v2_, depth_] := If[
        depth > 2,
        mediant[v1, v2], {
        recursive[v1, mediant[v1, v2], depth + 1],
        mediant[v1, v2],
        recursive[mediant[v1, v2], v2, depth + 1]
        }]

        computeLabels[v1_, v2_] := Module[{numbers},
        numbers =
        Cases[recursive[v1, v2, 0], {_Integer, _Integer}, Infinity];
        StringTemplate["``/``"] @@@ numbers
        ]
        computeLabelsNegative[v1_, v2_] := Module[{numbers},
        numbers =
        Cases[recursive[v1, v2, 0], {_Integer, _Integer}, Infinity];
        StringTemplate["-`2`/`1`"] @@@ numbers
        ]

        labels = Reverse@Join[
        {"1/0"},
        computeLabels[{1, 0}, {1, 1}],
        {"1/1"},
        computeLabels[{1, 1}, {0, 1}],
        {"0/1"},
        computeLabelsNegative[{1, 0}, {1, 1}],
        {"-1,1"},
        computeLabelsNegative[{1, 1}, {0, 1}]
        ];

        coords = CirclePoints[{1.1, 186 Degree}, 64];

        Show[
        Graphics[Circle[{0, 0}, 1]],
        hypocycloid[2],
        hypocycloid[4],
        hypocycloid[8],
        hypocycloid[16],
        hypocycloid[32],
        hypocycloid[64],
        Graphics@MapThread[Text, {labels, coords}],
        ImageSize -> 500
        ]


        Mathematica graphics






        share|improve this answer











        $endgroup$



        The curvilinear triangles which are characteristic for this type of plot are called hypocycloid curves. We can use the parametric equations on Wikipedia to plot these, like so:



        x[a_, b_, t_] := (b - a) Cos[t] + a Cos[(b - a)/a t]
        y[a_, b_, t_] := (b - a) Sin[t] - a Sin[(b - a)/a t]
        hypocycloid[n_] := ParametricPlot[
        {x[1/n, 1, t], y[1/n, 1, t]},
        {t, 0, 2 Pi},
        PlotStyle -> {Thickness[0.002], Black}
        ]

        Show[
        Graphics[Circle[{0, 0}, 1]],
        hypocycloid[2],
        hypocycloid[4],
        hypocycloid[8],
        hypocycloid[16],
        hypocycloid[32],
        hypocycloid[64],
        ImageSize -> 500
        ]


        Mathematica graphics



        I've previously written about an application of hypocycloids here, and I showed how to visualize epicycloids here.



        How to generate the labels is described here (also linked to by moo in a comment). I will simply provide the code.



        mediant[{a_, b_}, {c_, d_}] := {a + c, b + d}
        recursive[v1_, v2_, depth_] := If[
        depth > 2,
        mediant[v1, v2], {
        recursive[v1, mediant[v1, v2], depth + 1],
        mediant[v1, v2],
        recursive[mediant[v1, v2], v2, depth + 1]
        }]

        computeLabels[v1_, v2_] := Module[{numbers},
        numbers =
        Cases[recursive[v1, v2, 0], {_Integer, _Integer}, Infinity];
        StringTemplate["``/``"] @@@ numbers
        ]
        computeLabelsNegative[v1_, v2_] := Module[{numbers},
        numbers =
        Cases[recursive[v1, v2, 0], {_Integer, _Integer}, Infinity];
        StringTemplate["-`2`/`1`"] @@@ numbers
        ]

        labels = Reverse@Join[
        {"1/0"},
        computeLabels[{1, 0}, {1, 1}],
        {"1/1"},
        computeLabels[{1, 1}, {0, 1}],
        {"0/1"},
        computeLabelsNegative[{1, 0}, {1, 1}],
        {"-1,1"},
        computeLabelsNegative[{1, 1}, {0, 1}]
        ];

        coords = CirclePoints[{1.1, 186 Degree}, 64];

        Show[
        Graphics[Circle[{0, 0}, 1]],
        hypocycloid[2],
        hypocycloid[4],
        hypocycloid[8],
        hypocycloid[16],
        hypocycloid[32],
        hypocycloid[64],
        Graphics@MapThread[Text, {labels, coords}],
        ImageSize -> 500
        ]


        Mathematica graphics







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited 8 hours ago

























        answered 11 hours ago









        C. E.C. E.

        51.1k3101207




        51.1k3101207























            3












            $begingroup$

            I looked up the Farey sequence on Wikipedia, out of curiosity, because I had not heard of it before. The Farey sequence of order $n$ is "the sequence of completely reduced fractions between 0 and 1 which, when in lowest terms, have denominators less than or equal to $n$, arranged in order of increasing size".



            On that basis, you can generate the sequence as follows, for instance:



            ClearAll[farey]
            farey[n_Integer] := (Divide @@@ Subsets[Range[n], {2}]) ~ Join ~ {0, 1} //DeleteDuplicates //Sort


            So for instance:



            farey[5]



            {0, 1/5, 1/4, 1/3, 2/5, 1/2, 3/5, 2/3, 3/4, 4/5, 1}




            I am not sure how these sequences are connected with the figure you showed though.






            share|improve this answer









            $endgroup$













            • $begingroup$
              Thanks to C.E., it is a concrete answer
              $endgroup$
              – Gustavo Rubiano
              2 hours ago
















            3












            $begingroup$

            I looked up the Farey sequence on Wikipedia, out of curiosity, because I had not heard of it before. The Farey sequence of order $n$ is "the sequence of completely reduced fractions between 0 and 1 which, when in lowest terms, have denominators less than or equal to $n$, arranged in order of increasing size".



            On that basis, you can generate the sequence as follows, for instance:



            ClearAll[farey]
            farey[n_Integer] := (Divide @@@ Subsets[Range[n], {2}]) ~ Join ~ {0, 1} //DeleteDuplicates //Sort


            So for instance:



            farey[5]



            {0, 1/5, 1/4, 1/3, 2/5, 1/2, 3/5, 2/3, 3/4, 4/5, 1}




            I am not sure how these sequences are connected with the figure you showed though.






            share|improve this answer









            $endgroup$













            • $begingroup$
              Thanks to C.E., it is a concrete answer
              $endgroup$
              – Gustavo Rubiano
              2 hours ago














            3












            3








            3





            $begingroup$

            I looked up the Farey sequence on Wikipedia, out of curiosity, because I had not heard of it before. The Farey sequence of order $n$ is "the sequence of completely reduced fractions between 0 and 1 which, when in lowest terms, have denominators less than or equal to $n$, arranged in order of increasing size".



            On that basis, you can generate the sequence as follows, for instance:



            ClearAll[farey]
            farey[n_Integer] := (Divide @@@ Subsets[Range[n], {2}]) ~ Join ~ {0, 1} //DeleteDuplicates //Sort


            So for instance:



            farey[5]



            {0, 1/5, 1/4, 1/3, 2/5, 1/2, 3/5, 2/3, 3/4, 4/5, 1}




            I am not sure how these sequences are connected with the figure you showed though.






            share|improve this answer









            $endgroup$



            I looked up the Farey sequence on Wikipedia, out of curiosity, because I had not heard of it before. The Farey sequence of order $n$ is "the sequence of completely reduced fractions between 0 and 1 which, when in lowest terms, have denominators less than or equal to $n$, arranged in order of increasing size".



            On that basis, you can generate the sequence as follows, for instance:



            ClearAll[farey]
            farey[n_Integer] := (Divide @@@ Subsets[Range[n], {2}]) ~ Join ~ {0, 1} //DeleteDuplicates //Sort


            So for instance:



            farey[5]



            {0, 1/5, 1/4, 1/3, 2/5, 1/2, 3/5, 2/3, 3/4, 4/5, 1}




            I am not sure how these sequences are connected with the figure you showed though.







            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered 17 hours ago









            MarcoBMarcoB

            38.6k557115




            38.6k557115












            • $begingroup$
              Thanks to C.E., it is a concrete answer
              $endgroup$
              – Gustavo Rubiano
              2 hours ago


















            • $begingroup$
              Thanks to C.E., it is a concrete answer
              $endgroup$
              – Gustavo Rubiano
              2 hours ago
















            $begingroup$
            Thanks to C.E., it is a concrete answer
            $endgroup$
            – Gustavo Rubiano
            2 hours ago




            $begingroup$
            Thanks to C.E., it is a concrete answer
            $endgroup$
            – Gustavo Rubiano
            2 hours ago










            Gustavo Rubiano is a new contributor. Be nice, and check out our Code of Conduct.










            draft saved

            draft discarded


















            Gustavo Rubiano is a new contributor. Be nice, and check out our Code of Conduct.













            Gustavo Rubiano is a new contributor. Be nice, and check out our Code of Conduct.












            Gustavo Rubiano is a new contributor. Be nice, and check out our Code of Conduct.
















            Thanks for contributing an answer to Mathematica Stack Exchange!


            • Please be sure to answer the question. Provide details and share your research!

            But avoid



            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.


            Use MathJax to format equations. MathJax reference.


            To learn more, see our tips on writing great answers.




            draft saved


            draft discarded














            StackExchange.ready(
            function () {
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f194838%2fhow-can-i-plot-a-farey-diagram%23new-answer', 'question_page');
            }
            );

            Post as a guest















            Required, but never shown





















































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown

































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown







            Popular posts from this blog

            Contact image not getting when fetch all contact list from iPhone by CNContact

            Idjassú

            count number of partitions of a set with n elements into k subsets