Ways to generate word-frequency plot w/ Python?

I have a file that contains a word and the frequency that it occurs. I would like to generate a sort of plot; I'm looking for a sort of 'bubble' like graph. The idea is that the size of these bubbles corresponds to the relative frequencies and the corresponding word is labeled on these bubbles. Does anyone know if this can be done with the standard matplotlib or anything similar?

asked Nov 28 '18 at 1:45

Ayumu Kasugano

21619

add a comment |

asked Nov 28 '18 at 1:45

Ayumu Kasugano

21619

add a comment |

asked Nov 28 '18 at 1:45

Ayumu Kasugano

21619

python plot

asked Nov 28 '18 at 1:45

Ayumu Kasugano

21619

asked Nov 28 '18 at 1:45

Ayumu Kasugano

21619

asked Nov 28 '18 at 1:45

Ayumu Kasugano

21619

asked Nov 28 '18 at 1:45

Ayumu Kasugano

21619

asked Nov 28 '18 at 1:45

Ayumu Kasugano

21619

add a comment |

2 Answers
2

active

oldest

votes

There are lots of libraries out there.

Here's an example from WordCloud

#!/usr/bin/env python

"""

Minimal Example

===============

Generating a square wordcloud from the US constitution using default arguments.

"""



import os



from os import path

from wordcloud import WordCloud



# using word frequency list:

#word_freq = open("/tmp/word_freq.txt").read()

# say it looks like this:

word_freq = {'apple': 4, 'banana': 1, 'melon': 2, 'strawberry': 3, 'grape': 8}

text = " ".join([(k + " ")*v for k,v in word_freq.items()])



# Generate a word cloud image

wordcloud = WordCloud().generate(text)





# Display the generated image:

# the matplotlib way:

import matplotlib.pyplot as plt

plt.imshow(wordcloud, interpolation='bilinear')

plt.axis("off")



# lower max_font_size

wordcloud = WordCloud(max_font_size=40).generate(text)

plt.figure()

plt.imshow(wordcloud, interpolation="bilinear")

plt.axis("off")

plt.show()



# The pil way (if you don't have matplotlib)

# image = wordcloud.to_image()

# image.show()

WordCloud from different text:

edited Nov 28 '18 at 2:22

answered Nov 28 '18 at 1:55

keithpjolley

1,060915

Yes this looks nice, but this assumes that I have the entire text. All I have are the words and the frequency. Is there a way to work with this besides generating a dummy file?

– Ayumu Kasugano
Nov 28 '18 at 2:00

add a comment |

Let's say you have the frequency data in dict data

Following code should work

import os

from os import path

from wordcloud import WordCloud

import matplotlib.pyplot as plt



data = {

    'Bla': 10,

    'Bl': 2,

    'cold' : 9,

    'random': 6

}

wordcloud = WordCloud(max_font_size=40).generate(" ".join([(k + ' ') * v for k,v in data.items()]))

plt.figure()

plt.imshow(wordcloud, interpolation="bilinear")

plt.axis("off")

plt.show()

answered Nov 28 '18 at 2:17

Krishna

6021515

add a comment |

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

There are lots of libraries out there.

Here's an example from WordCloud

#!/usr/bin/env python

"""

Minimal Example

===============

Generating a square wordcloud from the US constitution using default arguments.

"""



import os



from os import path

from wordcloud import WordCloud



# using word frequency list:

#word_freq = open("/tmp/word_freq.txt").read()

# say it looks like this:

word_freq = {'apple': 4, 'banana': 1, 'melon': 2, 'strawberry': 3, 'grape': 8}

text = " ".join([(k + " ")*v for k,v in word_freq.items()])



# Generate a word cloud image

wordcloud = WordCloud().generate(text)





# Display the generated image:

# the matplotlib way:

import matplotlib.pyplot as plt

plt.imshow(wordcloud, interpolation='bilinear')

plt.axis("off")



# lower max_font_size

wordcloud = WordCloud(max_font_size=40).generate(text)

plt.figure()

plt.imshow(wordcloud, interpolation="bilinear")

plt.axis("off")

plt.show()



# The pil way (if you don't have matplotlib)

# image = wordcloud.to_image()

# image.show()

WordCloud from different text:

edited Nov 28 '18 at 2:22

answered Nov 28 '18 at 1:55

keithpjolley

1,060915

Yes this looks nice, but this assumes that I have the entire text. All I have are the words and the frequency. Is there a way to work with this besides generating a dummy file?

– Ayumu Kasugano
Nov 28 '18 at 2:00

add a comment |

There are lots of libraries out there.

Here's an example from WordCloud

#!/usr/bin/env python

"""

Minimal Example

===============

Generating a square wordcloud from the US constitution using default arguments.

"""



import os



from os import path

from wordcloud import WordCloud



# using word frequency list:

#word_freq = open("/tmp/word_freq.txt").read()

# say it looks like this:

word_freq = {'apple': 4, 'banana': 1, 'melon': 2, 'strawberry': 3, 'grape': 8}

text = " ".join([(k + " ")*v for k,v in word_freq.items()])



# Generate a word cloud image

wordcloud = WordCloud().generate(text)





# Display the generated image:

# the matplotlib way:

import matplotlib.pyplot as plt

plt.imshow(wordcloud, interpolation='bilinear')

plt.axis("off")



# lower max_font_size

wordcloud = WordCloud(max_font_size=40).generate(text)

plt.figure()

plt.imshow(wordcloud, interpolation="bilinear")

plt.axis("off")

plt.show()



# The pil way (if you don't have matplotlib)

# image = wordcloud.to_image()

# image.show()

WordCloud from different text:

edited Nov 28 '18 at 2:22

answered Nov 28 '18 at 1:55

keithpjolley

1,060915

Yes this looks nice, but this assumes that I have the entire text. All I have are the words and the frequency. Is there a way to work with this besides generating a dummy file?

– Ayumu Kasugano
Nov 28 '18 at 2:00

add a comment |

There are lots of libraries out there.

Here's an example from WordCloud

#!/usr/bin/env python

"""

Minimal Example

===============

Generating a square wordcloud from the US constitution using default arguments.

"""



import os



from os import path

from wordcloud import WordCloud



# using word frequency list:

#word_freq = open("/tmp/word_freq.txt").read()

# say it looks like this:

word_freq = {'apple': 4, 'banana': 1, 'melon': 2, 'strawberry': 3, 'grape': 8}

text = " ".join([(k + " ")*v for k,v in word_freq.items()])



# Generate a word cloud image

wordcloud = WordCloud().generate(text)





# Display the generated image:

# the matplotlib way:

import matplotlib.pyplot as plt

plt.imshow(wordcloud, interpolation='bilinear')

plt.axis("off")



# lower max_font_size

wordcloud = WordCloud(max_font_size=40).generate(text)

plt.figure()

plt.imshow(wordcloud, interpolation="bilinear")

plt.axis("off")

plt.show()



# The pil way (if you don't have matplotlib)

# image = wordcloud.to_image()

# image.show()

WordCloud from different text:

edited Nov 28 '18 at 2:22

answered Nov 28 '18 at 1:55

keithpjolley

1,060915

There are lots of libraries out there.

Here's an example from WordCloud

#!/usr/bin/env python

"""

Minimal Example

===============

Generating a square wordcloud from the US constitution using default arguments.

"""



import os



from os import path

from wordcloud import WordCloud



# using word frequency list:

#word_freq = open("/tmp/word_freq.txt").read()

# say it looks like this:

word_freq = {'apple': 4, 'banana': 1, 'melon': 2, 'strawberry': 3, 'grape': 8}

text = " ".join([(k + " ")*v for k,v in word_freq.items()])



# Generate a word cloud image

wordcloud = WordCloud().generate(text)





# Display the generated image:

# the matplotlib way:

import matplotlib.pyplot as plt

plt.imshow(wordcloud, interpolation='bilinear')

plt.axis("off")



# lower max_font_size

wordcloud = WordCloud(max_font_size=40).generate(text)

plt.figure()

plt.imshow(wordcloud, interpolation="bilinear")

plt.axis("off")

plt.show()



# The pil way (if you don't have matplotlib)

# image = wordcloud.to_image()

# image.show()

WordCloud from different text:

edited Nov 28 '18 at 2:22

answered Nov 28 '18 at 1:55

keithpjolley

1,060915

edited Nov 28 '18 at 2:22

answered Nov 28 '18 at 1:55

keithpjolley

1,060915

answered Nov 28 '18 at 1:55

keithpjolley

1,060915

answered Nov 28 '18 at 1:55

keithpjolley

1,060915

Yes this looks nice, but this assumes that I have the entire text. All I have are the words and the frequency. Is there a way to work with this besides generating a dummy file?

– Ayumu Kasugano
Nov 28 '18 at 2:00

add a comment |

Yes this looks nice, but this assumes that I have the entire text. All I have are the words and the frequency. Is there a way to work with this besides generating a dummy file?

– Ayumu Kasugano
Nov 28 '18 at 2:00

Yes this looks nice, but this assumes that I have the entire text. All I have are the words and the frequency. Is there a way to work with this besides generating a dummy file?

– Ayumu Kasugano
Nov 28 '18 at 2:00

add a comment |

Let's say you have the frequency data in dict data

Following code should work

import os

from os import path

from wordcloud import WordCloud

import matplotlib.pyplot as plt



data = {

    'Bla': 10,

    'Bl': 2,

    'cold' : 9,

    'random': 6

}

wordcloud = WordCloud(max_font_size=40).generate(" ".join([(k + ' ') * v for k,v in data.items()]))

plt.figure()

plt.imshow(wordcloud, interpolation="bilinear")

plt.axis("off")

plt.show()

answered Nov 28 '18 at 2:17

Krishna

6021515

add a comment |

Let's say you have the frequency data in dict data

Following code should work

import os

from os import path

from wordcloud import WordCloud

import matplotlib.pyplot as plt



data = {

    'Bla': 10,

    'Bl': 2,

    'cold' : 9,

    'random': 6

}

wordcloud = WordCloud(max_font_size=40).generate(" ".join([(k + ' ') * v for k,v in data.items()]))

plt.figure()

plt.imshow(wordcloud, interpolation="bilinear")

plt.axis("off")

plt.show()

answered Nov 28 '18 at 2:17

Krishna

6021515

add a comment |

Let's say you have the frequency data in dict data

Following code should work

import os

from os import path

from wordcloud import WordCloud

import matplotlib.pyplot as plt



data = {

    'Bla': 10,

    'Bl': 2,

    'cold' : 9,

    'random': 6

}

wordcloud = WordCloud(max_font_size=40).generate(" ".join([(k + ' ') * v for k,v in data.items()]))

plt.figure()

plt.imshow(wordcloud, interpolation="bilinear")

plt.axis("off")

plt.show()

answered Nov 28 '18 at 2:17

Krishna

6021515

Let's say you have the frequency data in dict data

Following code should work

import os

from os import path

from wordcloud import WordCloud

import matplotlib.pyplot as plt



data = {

    'Bla': 10,

    'Bl': 2,

    'cold' : 9,

    'random': 6

}

wordcloud = WordCloud(max_font_size=40).generate(" ".join([(k + ' ') * v for k,v in data.items()]))

plt.figure()

plt.imshow(wordcloud, interpolation="bilinear")

plt.axis("off")

plt.show()

answered Nov 28 '18 at 2:17

Krishna

6021515

answered Nov 28 '18 at 2:17

Krishna

6021515

answered Nov 28 '18 at 2:17

Krishna

6021515

answered Nov 28 '18 at 2:17

Krishna

6021515

add a comment |

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