Padding lists for accurate plotting
$begingroup$
I have the following data which is in the form of irregular/non rectangular arrays
list1 = {{1}, {2}, {3}, {4}, {5, 6, 7}, {8, 9, 10}, {11}, {12}}
To transpose it for plotting, I have to use (because of the irregular shape)
list2 = Flatten[list1, {{2}, {1}}]
This is now a $3times1$ column.
I want to plot this data, So I use the ListLinePlot as
ListLinePlot[list2, DataRange -> {1, 3}, Frame -> True]
The three rows are plotted as three curves, but the problem is that the upper two curves which correspond to the second and third row of list2 also start from 1 on the x-axis.? Shouldn't they start from 2 instead of 1? I thought I could use PadLeft or PadRight with empty entries {} to the left or right of the last two (2 element) rows of list2 (to make them 6 element rows, like the first row of list2) to force the two curves to start from 2, but I failed. Could someone tell any workaround?
plotting list-manipulation
asked 56 mins ago
AtoZAtoZ
1436
$endgroup$
add a comment |
$begingroup$
I have the following data which is in the form of irregular/non rectangular arrays
list1 = {{1}, {2}, {3}, {4}, {5, 6, 7}, {8, 9, 10}, {11}, {12}}
To transpose it for plotting, I have to use (because of the irregular shape)
list2 = Flatten[list1, {{2}, {1}}]
This is now a $3times1$ column.
I want to plot this data, So I use the ListLinePlot as
ListLinePlot[list2, DataRange -> {1, 3}, Frame -> True]
The three rows are plotted as three curves, but the problem is that the upper two curves which correspond to the second and third row of list2 also start from 1 on the x-axis.? Shouldn't they start from 2 instead of 1? I thought I could use PadLeft or PadRight with empty entries {} to the left or right of the last two (2 element) rows of list2 (to make them 6 element rows, like the first row of list2) to force the two curves to start from 2, but I failed. Could someone tell any workaround?
plotting list-manipulation
asked 56 mins ago
AtoZAtoZ
1436
$endgroup$
1
$begingroup$
DoesListLinePlot[Transpose[PadRight[list1]], DataRange -> {1, 3}]do what you want?
$endgroup$
– J. M. is slightly pensive♦
50 mins ago
$begingroup$
@J.M.isslightlypensive Thanks. But it gives zeros on right and left which actually do not do the trick, however, if they are somehow empty, would do the trick.
$endgroup$
– AtoZ
30 mins ago
add a comment |
$begingroup$
I have the following data which is in the form of irregular/non rectangular arrays
list1 = {{1}, {2}, {3}, {4}, {5, 6, 7}, {8, 9, 10}, {11}, {12}}
To transpose it for plotting, I have to use (because of the irregular shape)
list2 = Flatten[list1, {{2}, {1}}]
This is now a $3times1$ column.
I want to plot this data, So I use the ListLinePlot as
ListLinePlot[list2, DataRange -> {1, 3}, Frame -> True]
The three rows are plotted as three curves, but the problem is that the upper two curves which correspond to the second and third row of list2 also start from 1 on the x-axis.? Shouldn't they start from 2 instead of 1? I thought I could use PadLeft or PadRight with empty entries {} to the left or right of the last two (2 element) rows of list2 (to make them 6 element rows, like the first row of list2) to force the two curves to start from 2, but I failed. Could someone tell any workaround?
plotting list-manipulation
asked 56 mins ago
AtoZAtoZ
1436
$endgroup$
I have the following data which is in the form of irregular/non rectangular arrays
list1 = {{1}, {2}, {3}, {4}, {5, 6, 7}, {8, 9, 10}, {11}, {12}}
To transpose it for plotting, I have to use (because of the irregular shape)
list2 = Flatten[list1, {{2}, {1}}]
This is now a $3times1$ column.
I want to plot this data, So I use the ListLinePlot as
ListLinePlot[list2, DataRange -> {1, 3}, Frame -> True]
The three rows are plotted as three curves, but the problem is that the upper two curves which correspond to the second and third row of list2 also start from 1 on the x-axis.? Shouldn't they start from 2 instead of 1? I thought I could use PadLeft or PadRight with empty entries {} to the left or right of the last two (2 element) rows of list2 (to make them 6 element rows, like the first row of list2) to force the two curves to start from 2, but I failed. Could someone tell any workaround?
plotting list-manipulation
plotting list-manipulation
asked 56 mins ago
AtoZAtoZ
1436
asked 56 mins ago
AtoZAtoZ
1436
asked 56 mins ago
AtoZAtoZ
1436
asked 56 mins ago
AtoZAtoZ
1436
asked 56 mins ago
AtoZAtoZ
1436
1436
1
$begingroup$
DoesListLinePlot[Transpose[PadRight[list1]], DataRange -> {1, 3}]do what you want?
$endgroup$
– J. M. is slightly pensive♦
50 mins ago
$begingroup$
@J.M.isslightlypensive Thanks. But it gives zeros on right and left which actually do not do the trick, however, if they are somehow empty, would do the trick.
$endgroup$
– AtoZ
30 mins ago
add a comment |
1
$begingroup$
DoesListLinePlot[Transpose[PadRight[list1]], DataRange -> {1, 3}]do what you want?
$endgroup$
– J. M. is slightly pensive♦
50 mins ago
$begingroup$
@J.M.isslightlypensive Thanks. But it gives zeros on right and left which actually do not do the trick, however, if they are somehow empty, would do the trick.
$endgroup$
– AtoZ
30 mins ago
1
1
$begingroup$
Does
ListLinePlot[Transpose[PadRight[list1]], DataRange -> {1, 3}] do what you want?$endgroup$
– J. M. is slightly pensive♦
50 mins ago
$begingroup$
Does
ListLinePlot[Transpose[PadRight[list1]], DataRange -> {1, 3}] do what you want?$endgroup$
– J. M. is slightly pensive♦
50 mins ago
$begingroup$
@J.M.isslightlypensive Thanks. But it gives zeros on right and left which actually do not do the trick, however, if they are somehow empty, would do the trick.
$endgroup$
– AtoZ
30 mins ago
$begingroup$
@J.M.isslightlypensive Thanks. But it gives zeros on right and left which actually do not do the trick, however, if they are somehow empty, would do the trick.
$endgroup$
– AtoZ
30 mins ago
add a comment |
1 Answer
1
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$begingroup$
ListLinePlot[Transpose[PadRight[list1, Automatic, Null]],
DataRange -> {1, 3}]
answered 45 mins ago
kglrkglr
188k10204422
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add a comment |
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$begingroup$
ListLinePlot[Transpose[PadRight[list1, Automatic, Null]],
DataRange -> {1, 3}]
answered 45 mins ago
kglrkglr
188k10204422
$endgroup$
add a comment |
$begingroup$
ListLinePlot[Transpose[PadRight[list1, Automatic, Null]],
DataRange -> {1, 3}]
answered 45 mins ago
kglrkglr
188k10204422
$endgroup$
add a comment |
$begingroup$
ListLinePlot[Transpose[PadRight[list1, Automatic, Null]],
DataRange -> {1, 3}]
answered 45 mins ago
kglrkglr
188k10204422
$endgroup$
ListLinePlot[Transpose[PadRight[list1, Automatic, Null]],
DataRange -> {1, 3}]
answered 45 mins ago
kglrkglr
188k10204422
answered 45 mins ago
kglrkglr
188k10204422
answered 45 mins ago
kglrkglr
188k10204422
answered 45 mins ago
kglrkglr
188k10204422
188k10204422
add a comment |
add a comment |
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$begingroup$
Does
ListLinePlot[Transpose[PadRight[list1]], DataRange -> {1, 3}]do what you want?$endgroup$
– J. M. is slightly pensive♦
50 mins ago
$begingroup$
@J.M.isslightlypensive Thanks. But it gives zeros on right and left which actually do not do the trick, however, if they are somehow empty, would do the trick.
$endgroup$
– AtoZ
30 mins ago