How do you rename a list to a variable in Python
I'm trying to create a random string of numbers saved to a list, then rename the list further in the code. I've tried using dictionaries to store the names but that didn't work, I've also tried simply newListName=oldListName which when I attempted to print newListName it returns a NameError
python list rename
asked Nov 28 '18 at 2:09
SadDuckSadDuck
32
add a comment |
I'm trying to create a random string of numbers saved to a list, then rename the list further in the code. I've tried using dictionaries to store the names but that didn't work, I've also tried simply newListName=oldListName which when I attempted to print newListName it returns a NameError
python list rename
asked Nov 28 '18 at 2:09
SadDuckSadDuck
32
Can you include the code?
– All Knower
Nov 28 '18 at 2:11
I do not understand what you are trying to do, and saying "I tried using dictionaries but that didn't work" is not an adequate problem description. Almost certainly you want to use a dictionary. Please provide a Minimal, Complete, and Verifiable example
– juanpa.arrivillaga
Nov 28 '18 at 2:40
add a comment |
I'm trying to create a random string of numbers saved to a list, then rename the list further in the code. I've tried using dictionaries to store the names but that didn't work, I've also tried simply newListName=oldListName which when I attempted to print newListName it returns a NameError
python list rename
asked Nov 28 '18 at 2:09
SadDuckSadDuck
32
I'm trying to create a random string of numbers saved to a list, then rename the list further in the code. I've tried using dictionaries to store the names but that didn't work, I've also tried simply newListName=oldListName which when I attempted to print newListName it returns a NameError
python list rename
python list rename
asked Nov 28 '18 at 2:09
SadDuckSadDuck
32
asked Nov 28 '18 at 2:09
SadDuckSadDuck
32
asked Nov 28 '18 at 2:09
SadDuckSadDuck
32
asked Nov 28 '18 at 2:09
SadDuckSadDuck
32
asked Nov 28 '18 at 2:09
SadDuckSadDuck
32
32
Can you include the code?
– All Knower
Nov 28 '18 at 2:11
I do not understand what you are trying to do, and saying "I tried using dictionaries but that didn't work" is not an adequate problem description. Almost certainly you want to use a dictionary. Please provide a Minimal, Complete, and Verifiable example
– juanpa.arrivillaga
Nov 28 '18 at 2:40
add a comment |
Can you include the code?
– All Knower
Nov 28 '18 at 2:11
I do not understand what you are trying to do, and saying "I tried using dictionaries but that didn't work" is not an adequate problem description. Almost certainly you want to use a dictionary. Please provide a Minimal, Complete, and Verifiable example
– juanpa.arrivillaga
Nov 28 '18 at 2:40
Can you include the code?
– All Knower
Nov 28 '18 at 2:11
Can you include the code?
– All Knower
Nov 28 '18 at 2:11
I do not understand what you are trying to do, and saying "I tried using dictionaries but that didn't work" is not an adequate problem description. Almost certainly you want to use a dictionary. Please provide a Minimal, Complete, and Verifiable example
– juanpa.arrivillaga
Nov 28 '18 at 2:40
I do not understand what you are trying to do, and saying "I tried using dictionaries but that didn't work" is not an adequate problem description. Almost certainly you want to use a dictionary. Please provide a Minimal, Complete, and Verifiable example
– juanpa.arrivillaga
Nov 28 '18 at 2:40
add a comment |
1 Answer
1
active
oldest
votes
You can copy the list into a new one as:
newListName=oldListName[:]
This would not give you the NameError!
Make sure that oldListName is defined as list before and then copied into another list.
answered Nov 28 '18 at 7:42
Somya AvasthiSomya Avasthi
885
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can copy the list into a new one as:
newListName=oldListName[:]
This would not give you the NameError!
Make sure that oldListName is defined as list before and then copied into another list.
answered Nov 28 '18 at 7:42
Somya AvasthiSomya Avasthi
885
add a comment |
You can copy the list into a new one as:
newListName=oldListName[:]
This would not give you the NameError!
Make sure that oldListName is defined as list before and then copied into another list.
answered Nov 28 '18 at 7:42
Somya AvasthiSomya Avasthi
885
add a comment |
You can copy the list into a new one as:
newListName=oldListName[:]
This would not give you the NameError!
Make sure that oldListName is defined as list before and then copied into another list.
answered Nov 28 '18 at 7:42
Somya AvasthiSomya Avasthi
885
You can copy the list into a new one as:
newListName=oldListName[:]
This would not give you the NameError!
Make sure that oldListName is defined as list before and then copied into another list.
answered Nov 28 '18 at 7:42
Somya AvasthiSomya Avasthi
885
answered Nov 28 '18 at 7:42
Somya AvasthiSomya Avasthi
885
answered Nov 28 '18 at 7:42
Somya AvasthiSomya Avasthi
885
answered Nov 28 '18 at 7:42
Somya AvasthiSomya Avasthi
885
885
add a comment |
add a comment |
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Can you include the code?
– All Knower
Nov 28 '18 at 2:11
I do not understand what you are trying to do, and saying "I tried using dictionaries but that didn't work" is not an adequate problem description. Almost certainly you want to use a dictionary. Please provide a Minimal, Complete, and Verifiable example
– juanpa.arrivillaga
Nov 28 '18 at 2:40