TypeError: 'NoneType' object is not callable (Beginner) Python
It tells me there is an AssertionError in line 11.I'm new to programming, not sure if this helps.The code is supposed to give me the i-th element of the x-th row, so for row3(3) = 9 for row4(10) = 40.
def multiplicationtable(x):
def row(i):
print (x * i)
return row
row3 = multiplicationtable(3)
assert row3(3) == 9
AssertionError Traceback (most recent call last)
in
10 row3 = multiplicationtable(3)
---> 11 assert row3(3) == 9
AssertionError:
python typeerror
add a comment |
It tells me there is an AssertionError in line 11.I'm new to programming, not sure if this helps.The code is supposed to give me the i-th element of the x-th row, so for row3(3) = 9 for row4(10) = 40.
def multiplicationtable(x):
def row(i):
print (x * i)
return row
row3 = multiplicationtable(3)
assert row3(3) == 9
AssertionError Traceback (most recent call last)
in
10 row3 = multiplicationtable(3)
---> 11 assert row3(3) == 9
AssertionError:
python typeerror
3
multiplicationtable
doesn't return anything. Maybe you meant to returnrow
?
– Peter Wood
Nov 28 '18 at 13:29
It helps a lot to give a more complete error message. (Look at this question for a good example of showing the error message.)
– JETM
Nov 28 '18 at 13:30
Oh yeah you are right, thanks. But now i get an AssertionError instead.
– Jan Dreier
Nov 28 '18 at 13:33
It is unclear what you expect your code to do, and how to produce an AssertionError from code which doesn't callassert
. See if you could edit this into a proper Minimal, Complete, and Verifiable example
– tripleee
Nov 28 '18 at 13:39
add a comment |
It tells me there is an AssertionError in line 11.I'm new to programming, not sure if this helps.The code is supposed to give me the i-th element of the x-th row, so for row3(3) = 9 for row4(10) = 40.
def multiplicationtable(x):
def row(i):
print (x * i)
return row
row3 = multiplicationtable(3)
assert row3(3) == 9
AssertionError Traceback (most recent call last)
in
10 row3 = multiplicationtable(3)
---> 11 assert row3(3) == 9
AssertionError:
python typeerror
It tells me there is an AssertionError in line 11.I'm new to programming, not sure if this helps.The code is supposed to give me the i-th element of the x-th row, so for row3(3) = 9 for row4(10) = 40.
def multiplicationtable(x):
def row(i):
print (x * i)
return row
row3 = multiplicationtable(3)
assert row3(3) == 9
AssertionError Traceback (most recent call last)
in
10 row3 = multiplicationtable(3)
---> 11 assert row3(3) == 9
AssertionError:
python typeerror
python typeerror
edited Nov 28 '18 at 13:44
Jan Dreier
asked Nov 28 '18 at 13:27
Jan DreierJan Dreier
32
32
3
multiplicationtable
doesn't return anything. Maybe you meant to returnrow
?
– Peter Wood
Nov 28 '18 at 13:29
It helps a lot to give a more complete error message. (Look at this question for a good example of showing the error message.)
– JETM
Nov 28 '18 at 13:30
Oh yeah you are right, thanks. But now i get an AssertionError instead.
– Jan Dreier
Nov 28 '18 at 13:33
It is unclear what you expect your code to do, and how to produce an AssertionError from code which doesn't callassert
. See if you could edit this into a proper Minimal, Complete, and Verifiable example
– tripleee
Nov 28 '18 at 13:39
add a comment |
3
multiplicationtable
doesn't return anything. Maybe you meant to returnrow
?
– Peter Wood
Nov 28 '18 at 13:29
It helps a lot to give a more complete error message. (Look at this question for a good example of showing the error message.)
– JETM
Nov 28 '18 at 13:30
Oh yeah you are right, thanks. But now i get an AssertionError instead.
– Jan Dreier
Nov 28 '18 at 13:33
It is unclear what you expect your code to do, and how to produce an AssertionError from code which doesn't callassert
. See if you could edit this into a proper Minimal, Complete, and Verifiable example
– tripleee
Nov 28 '18 at 13:39
3
3
multiplicationtable
doesn't return anything. Maybe you meant to return row
?– Peter Wood
Nov 28 '18 at 13:29
multiplicationtable
doesn't return anything. Maybe you meant to return row
?– Peter Wood
Nov 28 '18 at 13:29
It helps a lot to give a more complete error message. (Look at this question for a good example of showing the error message.)
– JETM
Nov 28 '18 at 13:30
It helps a lot to give a more complete error message. (Look at this question for a good example of showing the error message.)
– JETM
Nov 28 '18 at 13:30
Oh yeah you are right, thanks. But now i get an AssertionError instead.
– Jan Dreier
Nov 28 '18 at 13:33
Oh yeah you are right, thanks. But now i get an AssertionError instead.
– Jan Dreier
Nov 28 '18 at 13:33
It is unclear what you expect your code to do, and how to produce an AssertionError from code which doesn't call
assert
. See if you could edit this into a proper Minimal, Complete, and Verifiable example– tripleee
Nov 28 '18 at 13:39
It is unclear what you expect your code to do, and how to produce an AssertionError from code which doesn't call
assert
. See if you could edit this into a proper Minimal, Complete, and Verifiable example– tripleee
Nov 28 '18 at 13:39
add a comment |
1 Answer
1
active
oldest
votes
You are getting AssertionError
because row(i)
function is not returning any value. It should be written in this way:
def multiplicationtable(x):
def row(i):
print (x * i)
return x * i
return row
row3 = multiplicationtable(3)
assert row3(3) == 9
1
This really helped, thank you very much.
– Jan Dreier
Nov 28 '18 at 13:54
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You are getting AssertionError
because row(i)
function is not returning any value. It should be written in this way:
def multiplicationtable(x):
def row(i):
print (x * i)
return x * i
return row
row3 = multiplicationtable(3)
assert row3(3) == 9
1
This really helped, thank you very much.
– Jan Dreier
Nov 28 '18 at 13:54
add a comment |
You are getting AssertionError
because row(i)
function is not returning any value. It should be written in this way:
def multiplicationtable(x):
def row(i):
print (x * i)
return x * i
return row
row3 = multiplicationtable(3)
assert row3(3) == 9
1
This really helped, thank you very much.
– Jan Dreier
Nov 28 '18 at 13:54
add a comment |
You are getting AssertionError
because row(i)
function is not returning any value. It should be written in this way:
def multiplicationtable(x):
def row(i):
print (x * i)
return x * i
return row
row3 = multiplicationtable(3)
assert row3(3) == 9
You are getting AssertionError
because row(i)
function is not returning any value. It should be written in this way:
def multiplicationtable(x):
def row(i):
print (x * i)
return x * i
return row
row3 = multiplicationtable(3)
assert row3(3) == 9
edited Nov 28 '18 at 13:50
answered Nov 28 '18 at 13:34
SseinSsein
1,0241922
1,0241922
1
This really helped, thank you very much.
– Jan Dreier
Nov 28 '18 at 13:54
add a comment |
1
This really helped, thank you very much.
– Jan Dreier
Nov 28 '18 at 13:54
1
1
This really helped, thank you very much.
– Jan Dreier
Nov 28 '18 at 13:54
This really helped, thank you very much.
– Jan Dreier
Nov 28 '18 at 13:54
add a comment |
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3
multiplicationtable
doesn't return anything. Maybe you meant to returnrow
?– Peter Wood
Nov 28 '18 at 13:29
It helps a lot to give a more complete error message. (Look at this question for a good example of showing the error message.)
– JETM
Nov 28 '18 at 13:30
Oh yeah you are right, thanks. But now i get an AssertionError instead.
– Jan Dreier
Nov 28 '18 at 13:33
It is unclear what you expect your code to do, and how to produce an AssertionError from code which doesn't call
assert
. See if you could edit this into a proper Minimal, Complete, and Verifiable example– tripleee
Nov 28 '18 at 13:39