How to set a specific return type to a method in Java
So I have a class called Person
I can easily do something like
Person getPerson(){ return new Person(); }
But instead of using the 'Person' I want to declare my own class as a return type
Class<?> personClass = Class.forName("Person");
personClass getPerson() { return new Person(); }
Is this possible?
java methods return-type
asked Nov 28 '18 at 13:24
Isvoran AndreiIsvoran Andrei
145
add a comment |
So I have a class called Person
I can easily do something like
Person getPerson(){ return new Person(); }
But instead of using the 'Person' I want to declare my own class as a return type
Class<?> personClass = Class.forName("Person");
personClass getPerson() { return new Person(); }
Is this possible?
java methods return-type
asked Nov 28 '18 at 13:24
Isvoran AndreiIsvoran Andrei
145
add a comment |
So I have a class called Person
I can easily do something like
Person getPerson(){ return new Person(); }
But instead of using the 'Person' I want to declare my own class as a return type
Class<?> personClass = Class.forName("Person");
personClass getPerson() { return new Person(); }
Is this possible?
java methods return-type
asked Nov 28 '18 at 13:24
Isvoran AndreiIsvoran Andrei
145
So I have a class called Person
I can easily do something like
Person getPerson(){ return new Person(); }
But instead of using the 'Person' I want to declare my own class as a return type
Class<?> personClass = Class.forName("Person");
personClass getPerson() { return new Person(); }
Is this possible?
java methods return-type
java methods return-type
asked Nov 28 '18 at 13:24
Isvoran AndreiIsvoran Andrei
145
asked Nov 28 '18 at 13:24
Isvoran AndreiIsvoran Andrei
145
asked Nov 28 '18 at 13:24
Isvoran AndreiIsvoran Andrei
145
asked Nov 28 '18 at 13:24
Isvoran AndreiIsvoran Andrei
145
asked Nov 28 '18 at 13:24
Isvoran AndreiIsvoran Andrei
145
145
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
Your design is almost certainly wrong if you want to implement this, but yes, it's possible.
Object getThing(String className) throws Exception
{
return Class.forName(className).getConstructor().newInstance();
}
You'll have to cast the result.
add a comment |
If you want Person class object (I mean, Class<Person>), you can just use Person.class or personInstance.getClass().
Also, if you want a custom method that will return it, then you can use:
public Class<Person> getPersonClass() {
return Person.class;
}
But it is almost pointless, because you can just call Person.class. Beware, also, that Person.class is evaluated in compile time, and Class.forName("...") - in runtime.
answered Nov 28 '18 at 13:32
Andrey IlyuninAndrey Ilyunin
1,434221
I'm mainly look on a way to call getPerson() without using Person as a type but instead using a Class instance of Person.
– Isvoran Andrei
Nov 28 '18 at 13:40
Than Michael's answer should suit you nicely, isn't it?
– Andrey Ilyunin
Nov 28 '18 at 13:52
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Your design is almost certainly wrong if you want to implement this, but yes, it's possible.
Object getThing(String className) throws Exception
{
return Class.forName(className).getConstructor().newInstance();
}
You'll have to cast the result.
add a comment |
Your design is almost certainly wrong if you want to implement this, but yes, it's possible.
Object getThing(String className) throws Exception
{
return Class.forName(className).getConstructor().newInstance();
}
You'll have to cast the result.
add a comment |
Your design is almost certainly wrong if you want to implement this, but yes, it's possible.
Object getThing(String className) throws Exception
{
return Class.forName(className).getConstructor().newInstance();
}
You'll have to cast the result.
Your design is almost certainly wrong if you want to implement this, but yes, it's possible.
Object getThing(String className) throws Exception
{
return Class.forName(className).getConstructor().newInstance();
}
You'll have to cast the result.
answered Nov 28 '18 at 13:30
community wiki
Michael
add a comment |
add a comment |
If you want Person class object (I mean, Class<Person>), you can just use Person.class or personInstance.getClass().
Also, if you want a custom method that will return it, then you can use:
public Class<Person> getPersonClass() {
return Person.class;
}
But it is almost pointless, because you can just call Person.class. Beware, also, that Person.class is evaluated in compile time, and Class.forName("...") - in runtime.
answered Nov 28 '18 at 13:32
Andrey IlyuninAndrey Ilyunin
1,434221
I'm mainly look on a way to call getPerson() without using Person as a type but instead using a Class instance of Person.
– Isvoran Andrei
Nov 28 '18 at 13:40
Than Michael's answer should suit you nicely, isn't it?
– Andrey Ilyunin
Nov 28 '18 at 13:52
add a comment |
If you want Person class object (I mean, Class<Person>), you can just use Person.class or personInstance.getClass().
Also, if you want a custom method that will return it, then you can use:
public Class<Person> getPersonClass() {
return Person.class;
}
But it is almost pointless, because you can just call Person.class. Beware, also, that Person.class is evaluated in compile time, and Class.forName("...") - in runtime.
answered Nov 28 '18 at 13:32
Andrey IlyuninAndrey Ilyunin
1,434221
I'm mainly look on a way to call getPerson() without using Person as a type but instead using a Class instance of Person.
– Isvoran Andrei
Nov 28 '18 at 13:40
Than Michael's answer should suit you nicely, isn't it?
– Andrey Ilyunin
Nov 28 '18 at 13:52
add a comment |
If you want Person class object (I mean, Class<Person>), you can just use Person.class or personInstance.getClass().
Also, if you want a custom method that will return it, then you can use:
public Class<Person> getPersonClass() {
return Person.class;
}
But it is almost pointless, because you can just call Person.class. Beware, also, that Person.class is evaluated in compile time, and Class.forName("...") - in runtime.
answered Nov 28 '18 at 13:32
Andrey IlyuninAndrey Ilyunin
1,434221
If you want Person class object (I mean, Class<Person>), you can just use Person.class or personInstance.getClass().
Also, if you want a custom method that will return it, then you can use:
public Class<Person> getPersonClass() {
return Person.class;
}
But it is almost pointless, because you can just call Person.class. Beware, also, that Person.class is evaluated in compile time, and Class.forName("...") - in runtime.
answered Nov 28 '18 at 13:32
Andrey IlyuninAndrey Ilyunin
1,434221
answered Nov 28 '18 at 13:32
Andrey IlyuninAndrey Ilyunin
1,434221
answered Nov 28 '18 at 13:32
Andrey IlyuninAndrey Ilyunin
1,434221
answered Nov 28 '18 at 13:32
Andrey IlyuninAndrey Ilyunin
1,434221
1,434221
I'm mainly look on a way to call getPerson() without using Person as a type but instead using a Class instance of Person.
– Isvoran Andrei
Nov 28 '18 at 13:40
Than Michael's answer should suit you nicely, isn't it?
– Andrey Ilyunin
Nov 28 '18 at 13:52
add a comment |
I'm mainly look on a way to call getPerson() without using Person as a type but instead using a Class instance of Person.
– Isvoran Andrei
Nov 28 '18 at 13:40
Than Michael's answer should suit you nicely, isn't it?
– Andrey Ilyunin
Nov 28 '18 at 13:52
I'm mainly look on a way to call getPerson() without using Person as a type but instead using a Class instance of Person.
– Isvoran Andrei
Nov 28 '18 at 13:40
I'm mainly look on a way to call getPerson() without using Person as a type but instead using a Class instance of Person.
– Isvoran Andrei
Nov 28 '18 at 13:40
Than Michael's answer should suit you nicely, isn't it?
– Andrey Ilyunin
Nov 28 '18 at 13:52
Than Michael's answer should suit you nicely, isn't it?
– Andrey Ilyunin
Nov 28 '18 at 13:52
add a comment |
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