define name and content of dataframe dynamically with list in input
I wrote the following function :
def extractFromInput(inputName: String, colNames: List[String]): DataFrame = {
val inputData: List[String] = inputName.split("-").map(_.trim).toList
inputData.foldLeft(df) {
(df: DataFrame, columnName: String) =>
df.withColumn(columnName, lit(columnName))
}
}
I rather want to traverse colNames List and use it to define the new columns names with the content of this list.
With the actual function the content of the columns is filled properly , but I can't make them be named properly.
Any idea how to do this please
scala apache-spark dataframe
add a comment |
I wrote the following function :
def extractFromInput(inputName: String, colNames: List[String]): DataFrame = {
val inputData: List[String] = inputName.split("-").map(_.trim).toList
inputData.foldLeft(df) {
(df: DataFrame, columnName: String) =>
df.withColumn(columnName, lit(columnName))
}
}
I rather want to traverse colNames List and use it to define the new columns names with the content of this list.
With the actual function the content of the columns is filled properly , but I can't make them be named properly.
Any idea how to do this please
scala apache-spark dataframe
It is not clear what you're asking. What is the purpose ofcolNames
in your method ? It is never used. Please edit your question with a concrete example
– cheseaux
Nov 27 '18 at 22:17
add a comment |
I wrote the following function :
def extractFromInput(inputName: String, colNames: List[String]): DataFrame = {
val inputData: List[String] = inputName.split("-").map(_.trim).toList
inputData.foldLeft(df) {
(df: DataFrame, columnName: String) =>
df.withColumn(columnName, lit(columnName))
}
}
I rather want to traverse colNames List and use it to define the new columns names with the content of this list.
With the actual function the content of the columns is filled properly , but I can't make them be named properly.
Any idea how to do this please
scala apache-spark dataframe
I wrote the following function :
def extractFromInput(inputName: String, colNames: List[String]): DataFrame = {
val inputData: List[String] = inputName.split("-").map(_.trim).toList
inputData.foldLeft(df) {
(df: DataFrame, columnName: String) =>
df.withColumn(columnName, lit(columnName))
}
}
I rather want to traverse colNames List and use it to define the new columns names with the content of this list.
With the actual function the content of the columns is filled properly , but I can't make them be named properly.
Any idea how to do this please
scala apache-spark dataframe
scala apache-spark dataframe
edited Nov 27 '18 at 17:01
scalacode
asked Nov 27 '18 at 16:27
scalacodescalacode
12919
12919
It is not clear what you're asking. What is the purpose ofcolNames
in your method ? It is never used. Please edit your question with a concrete example
– cheseaux
Nov 27 '18 at 22:17
add a comment |
It is not clear what you're asking. What is the purpose ofcolNames
in your method ? It is never used. Please edit your question with a concrete example
– cheseaux
Nov 27 '18 at 22:17
It is not clear what you're asking. What is the purpose of
colNames
in your method ? It is never used. Please edit your question with a concrete example– cheseaux
Nov 27 '18 at 22:17
It is not clear what you're asking. What is the purpose of
colNames
in your method ? It is never used. Please edit your question with a concrete example– cheseaux
Nov 27 '18 at 22:17
add a comment |
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It is not clear what you're asking. What is the purpose of
colNames
in your method ? It is never used. Please edit your question with a concrete example– cheseaux
Nov 27 '18 at 22:17