Check if one json value is in the json value from another JSON, for each key












0















With SQL in postgres, I want to know if one JSON is 'IN' another JSON.



For example:



json_1 = {"a": ["123"], "b": ["456", "789"]}
json_2 = {"a": ["123"], "b": ["456"]}


In the above case, json_2["a"] is in json_1["a"] and json_2["b"] is in json_1["b"].



If I would know all the possible keys of the json, I would easily be able to write the above per key. However, the problem is that I don't know how many and which keys are in the JSON. How can I check for every key in the JSON, if json_2 is in json_1?










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  • So json_1/2 can contain any number of keys with any names, and each of those keys will always be an array, and for each array in json_2, you want to check the corresponding key (which may not exist) in json_1, and then see if all the values from the json_2 array are found in the json_1 array in any order?

    – 404
    Nov 27 '18 at 14:45











  • Correct. However, if the key is in json_2, I do know it also will be in json_1. So the 'may not exist' part doesn't hold. However, the value of the key in json_1 could be then.

    – Marjolein
    Nov 27 '18 at 15:16


















0















With SQL in postgres, I want to know if one JSON is 'IN' another JSON.



For example:



json_1 = {"a": ["123"], "b": ["456", "789"]}
json_2 = {"a": ["123"], "b": ["456"]}


In the above case, json_2["a"] is in json_1["a"] and json_2["b"] is in json_1["b"].



If I would know all the possible keys of the json, I would easily be able to write the above per key. However, the problem is that I don't know how many and which keys are in the JSON. How can I check for every key in the JSON, if json_2 is in json_1?










share|improve this question























  • So json_1/2 can contain any number of keys with any names, and each of those keys will always be an array, and for each array in json_2, you want to check the corresponding key (which may not exist) in json_1, and then see if all the values from the json_2 array are found in the json_1 array in any order?

    – 404
    Nov 27 '18 at 14:45











  • Correct. However, if the key is in json_2, I do know it also will be in json_1. So the 'may not exist' part doesn't hold. However, the value of the key in json_1 could be then.

    – Marjolein
    Nov 27 '18 at 15:16
















0












0








0








With SQL in postgres, I want to know if one JSON is 'IN' another JSON.



For example:



json_1 = {"a": ["123"], "b": ["456", "789"]}
json_2 = {"a": ["123"], "b": ["456"]}


In the above case, json_2["a"] is in json_1["a"] and json_2["b"] is in json_1["b"].



If I would know all the possible keys of the json, I would easily be able to write the above per key. However, the problem is that I don't know how many and which keys are in the JSON. How can I check for every key in the JSON, if json_2 is in json_1?










share|improve this question














With SQL in postgres, I want to know if one JSON is 'IN' another JSON.



For example:



json_1 = {"a": ["123"], "b": ["456", "789"]}
json_2 = {"a": ["123"], "b": ["456"]}


In the above case, json_2["a"] is in json_1["a"] and json_2["b"] is in json_1["b"].



If I would know all the possible keys of the json, I would easily be able to write the above per key. However, the problem is that I don't know how many and which keys are in the JSON. How can I check for every key in the JSON, if json_2 is in json_1?







sql json postgresql compare






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share|improve this question




share|improve this question










asked Nov 27 '18 at 14:32









MarjoleinMarjolein

436




436













  • So json_1/2 can contain any number of keys with any names, and each of those keys will always be an array, and for each array in json_2, you want to check the corresponding key (which may not exist) in json_1, and then see if all the values from the json_2 array are found in the json_1 array in any order?

    – 404
    Nov 27 '18 at 14:45











  • Correct. However, if the key is in json_2, I do know it also will be in json_1. So the 'may not exist' part doesn't hold. However, the value of the key in json_1 could be then.

    – Marjolein
    Nov 27 '18 at 15:16





















  • So json_1/2 can contain any number of keys with any names, and each of those keys will always be an array, and for each array in json_2, you want to check the corresponding key (which may not exist) in json_1, and then see if all the values from the json_2 array are found in the json_1 array in any order?

    – 404
    Nov 27 '18 at 14:45











  • Correct. However, if the key is in json_2, I do know it also will be in json_1. So the 'may not exist' part doesn't hold. However, the value of the key in json_1 could be then.

    – Marjolein
    Nov 27 '18 at 15:16



















So json_1/2 can contain any number of keys with any names, and each of those keys will always be an array, and for each array in json_2, you want to check the corresponding key (which may not exist) in json_1, and then see if all the values from the json_2 array are found in the json_1 array in any order?

– 404
Nov 27 '18 at 14:45





So json_1/2 can contain any number of keys with any names, and each of those keys will always be an array, and for each array in json_2, you want to check the corresponding key (which may not exist) in json_1, and then see if all the values from the json_2 array are found in the json_1 array in any order?

– 404
Nov 27 '18 at 14:45













Correct. However, if the key is in json_2, I do know it also will be in json_1. So the 'may not exist' part doesn't hold. However, the value of the key in json_1 could be then.

– Marjolein
Nov 27 '18 at 15:16







Correct. However, if the key is in json_2, I do know it also will be in json_1. So the 'may not exist' part doesn't hold. However, the value of the key in json_1 could be then.

– Marjolein
Nov 27 '18 at 15:16














1 Answer
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oldest

votes


















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I'm not sure about what output format you want, but this will create one row per key, with a boolean stating whether the json_2 key's array values are contained within the json_1 key's values.



CREATE TABLE t (json_1 JSONB, json_2 JSONB);
INSERT INTO t
VALUES
('{"a":["123"],"b":["456","789","aaa"],"c":["999"],"d":}',
'{"a":["123"],"b":["789","456"],"c":["123"],"d":["x"]}');




Query #1



SELECT key, value <@ (json_1->key) AS contained
FROM (
SELECT (JSONB_EACH(json_2)).*, json_1
FROM t
) j;


Returns:



| key | contained |
| --- | --------- |
| a | true |
| b | true |
| c | false |
| d | false |




View on DB Fiddle






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    1 Answer
    1






    active

    oldest

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    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    0














    I'm not sure about what output format you want, but this will create one row per key, with a boolean stating whether the json_2 key's array values are contained within the json_1 key's values.



    CREATE TABLE t (json_1 JSONB, json_2 JSONB);
    INSERT INTO t
    VALUES
    ('{"a":["123"],"b":["456","789","aaa"],"c":["999"],"d":}',
    '{"a":["123"],"b":["789","456"],"c":["123"],"d":["x"]}');




    Query #1



    SELECT key, value <@ (json_1->key) AS contained
    FROM (
    SELECT (JSONB_EACH(json_2)).*, json_1
    FROM t
    ) j;


    Returns:



    | key | contained |
    | --- | --------- |
    | a | true |
    | b | true |
    | c | false |
    | d | false |




    View on DB Fiddle






    share|improve this answer




























      0














      I'm not sure about what output format you want, but this will create one row per key, with a boolean stating whether the json_2 key's array values are contained within the json_1 key's values.



      CREATE TABLE t (json_1 JSONB, json_2 JSONB);
      INSERT INTO t
      VALUES
      ('{"a":["123"],"b":["456","789","aaa"],"c":["999"],"d":}',
      '{"a":["123"],"b":["789","456"],"c":["123"],"d":["x"]}');




      Query #1



      SELECT key, value <@ (json_1->key) AS contained
      FROM (
      SELECT (JSONB_EACH(json_2)).*, json_1
      FROM t
      ) j;


      Returns:



      | key | contained |
      | --- | --------- |
      | a | true |
      | b | true |
      | c | false |
      | d | false |




      View on DB Fiddle






      share|improve this answer


























        0












        0








        0







        I'm not sure about what output format you want, but this will create one row per key, with a boolean stating whether the json_2 key's array values are contained within the json_1 key's values.



        CREATE TABLE t (json_1 JSONB, json_2 JSONB);
        INSERT INTO t
        VALUES
        ('{"a":["123"],"b":["456","789","aaa"],"c":["999"],"d":}',
        '{"a":["123"],"b":["789","456"],"c":["123"],"d":["x"]}');




        Query #1



        SELECT key, value <@ (json_1->key) AS contained
        FROM (
        SELECT (JSONB_EACH(json_2)).*, json_1
        FROM t
        ) j;


        Returns:



        | key | contained |
        | --- | --------- |
        | a | true |
        | b | true |
        | c | false |
        | d | false |




        View on DB Fiddle






        share|improve this answer













        I'm not sure about what output format you want, but this will create one row per key, with a boolean stating whether the json_2 key's array values are contained within the json_1 key's values.



        CREATE TABLE t (json_1 JSONB, json_2 JSONB);
        INSERT INTO t
        VALUES
        ('{"a":["123"],"b":["456","789","aaa"],"c":["999"],"d":}',
        '{"a":["123"],"b":["789","456"],"c":["123"],"d":["x"]}');




        Query #1



        SELECT key, value <@ (json_1->key) AS contained
        FROM (
        SELECT (JSONB_EACH(json_2)).*, json_1
        FROM t
        ) j;


        Returns:



        | key | contained |
        | --- | --------- |
        | a | true |
        | b | true |
        | c | false |
        | d | false |




        View on DB Fiddle







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 27 '18 at 15:51









        404404

        3,1401726




        3,1401726
































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