Java - Generics - Casting generic object in generic specified object doesn't work
I'm trying to resolve this apparently simple generic casting problem :
First, declaring this simple generic object :
public interface GenericObject<T> {}
Second, declaring this working interface :
public interface Generic { // I don't want to do Generic<T>
<T> void setGenericObject(GenericObject<T> obj);
}
Then, let's implements this interface :
public class GenericImpl implements Generic {
private GenericObject<String> genericObject; // This is needed
@Override
public <String> void setGenericObject(GenericObject<String> obj) {
genericObject = obj; // eclipse give me this error :
// Type mismatch: cannot convert from
// interfaces.GenericObject<String> to
// interfaces.GenericObject<java.lang.String>
}
}
How can I solve this error ?
Edit :
Actualy, the only way I have to solve this issue is to do this :
public class GenericImpl implements Generic {
private GenericObject<String> genericObject;
@SuppressWarnings("unchecked") // I don't realy like this
@Override
public <T> void setGenericObject(GenericObject<T> obj) {
genericObject = (GenericObject<String>) obj;
}
}
java generics methods generic-programming generic-method
add a comment |
I'm trying to resolve this apparently simple generic casting problem :
First, declaring this simple generic object :
public interface GenericObject<T> {}
Second, declaring this working interface :
public interface Generic { // I don't want to do Generic<T>
<T> void setGenericObject(GenericObject<T> obj);
}
Then, let's implements this interface :
public class GenericImpl implements Generic {
private GenericObject<String> genericObject; // This is needed
@Override
public <String> void setGenericObject(GenericObject<String> obj) {
genericObject = obj; // eclipse give me this error :
// Type mismatch: cannot convert from
// interfaces.GenericObject<String> to
// interfaces.GenericObject<java.lang.String>
}
}
How can I solve this error ?
Edit :
Actualy, the only way I have to solve this issue is to do this :
public class GenericImpl implements Generic {
private GenericObject<String> genericObject;
@SuppressWarnings("unchecked") // I don't realy like this
@Override
public <T> void setGenericObject(GenericObject<T> obj) {
genericObject = (GenericObject<String>) obj;
}
}
java generics methods generic-programming generic-method
Sounds like an XY problem.<String> void
is not doing what you think it's doing. You're defining a new generic type parameter using the identifier "String". It may as well say<FooBar> void
. You should remove it. Only problem is that when you do, the method is not correctly overriding the method from the interface
– Michael
Nov 23 '18 at 13:46
1
The problem is thatGeneric
specifies that any implementers should be able to implementsetGenericObject
for all values ofT
. Your implementation only works for strings, so it is not fulfilling the contract as defined by the interface. The best way to achieve what you want is to haveGeneric<T>
andGenericImpl implements Generic<String>
but you said you don't want to do that
– Michael
Nov 23 '18 at 13:48
plaese see stackoverflow.com/questions/7433279/…
– chenzhongpu
Nov 23 '18 at 13:53
Ok. @Michael Do you think there are any way to solve my problem without doing@SuppressWarning
?
– MonkeyJLuffy
Nov 23 '18 at 14:07
add a comment |
I'm trying to resolve this apparently simple generic casting problem :
First, declaring this simple generic object :
public interface GenericObject<T> {}
Second, declaring this working interface :
public interface Generic { // I don't want to do Generic<T>
<T> void setGenericObject(GenericObject<T> obj);
}
Then, let's implements this interface :
public class GenericImpl implements Generic {
private GenericObject<String> genericObject; // This is needed
@Override
public <String> void setGenericObject(GenericObject<String> obj) {
genericObject = obj; // eclipse give me this error :
// Type mismatch: cannot convert from
// interfaces.GenericObject<String> to
// interfaces.GenericObject<java.lang.String>
}
}
How can I solve this error ?
Edit :
Actualy, the only way I have to solve this issue is to do this :
public class GenericImpl implements Generic {
private GenericObject<String> genericObject;
@SuppressWarnings("unchecked") // I don't realy like this
@Override
public <T> void setGenericObject(GenericObject<T> obj) {
genericObject = (GenericObject<String>) obj;
}
}
java generics methods generic-programming generic-method
I'm trying to resolve this apparently simple generic casting problem :
First, declaring this simple generic object :
public interface GenericObject<T> {}
Second, declaring this working interface :
public interface Generic { // I don't want to do Generic<T>
<T> void setGenericObject(GenericObject<T> obj);
}
Then, let's implements this interface :
public class GenericImpl implements Generic {
private GenericObject<String> genericObject; // This is needed
@Override
public <String> void setGenericObject(GenericObject<String> obj) {
genericObject = obj; // eclipse give me this error :
// Type mismatch: cannot convert from
// interfaces.GenericObject<String> to
// interfaces.GenericObject<java.lang.String>
}
}
How can I solve this error ?
Edit :
Actualy, the only way I have to solve this issue is to do this :
public class GenericImpl implements Generic {
private GenericObject<String> genericObject;
@SuppressWarnings("unchecked") // I don't realy like this
@Override
public <T> void setGenericObject(GenericObject<T> obj) {
genericObject = (GenericObject<String>) obj;
}
}
java generics methods generic-programming generic-method
java generics methods generic-programming generic-method
edited Nov 23 '18 at 13:53
asked Nov 23 '18 at 13:41
MonkeyJLuffy
96112
96112
Sounds like an XY problem.<String> void
is not doing what you think it's doing. You're defining a new generic type parameter using the identifier "String". It may as well say<FooBar> void
. You should remove it. Only problem is that when you do, the method is not correctly overriding the method from the interface
– Michael
Nov 23 '18 at 13:46
1
The problem is thatGeneric
specifies that any implementers should be able to implementsetGenericObject
for all values ofT
. Your implementation only works for strings, so it is not fulfilling the contract as defined by the interface. The best way to achieve what you want is to haveGeneric<T>
andGenericImpl implements Generic<String>
but you said you don't want to do that
– Michael
Nov 23 '18 at 13:48
plaese see stackoverflow.com/questions/7433279/…
– chenzhongpu
Nov 23 '18 at 13:53
Ok. @Michael Do you think there are any way to solve my problem without doing@SuppressWarning
?
– MonkeyJLuffy
Nov 23 '18 at 14:07
add a comment |
Sounds like an XY problem.<String> void
is not doing what you think it's doing. You're defining a new generic type parameter using the identifier "String". It may as well say<FooBar> void
. You should remove it. Only problem is that when you do, the method is not correctly overriding the method from the interface
– Michael
Nov 23 '18 at 13:46
1
The problem is thatGeneric
specifies that any implementers should be able to implementsetGenericObject
for all values ofT
. Your implementation only works for strings, so it is not fulfilling the contract as defined by the interface. The best way to achieve what you want is to haveGeneric<T>
andGenericImpl implements Generic<String>
but you said you don't want to do that
– Michael
Nov 23 '18 at 13:48
plaese see stackoverflow.com/questions/7433279/…
– chenzhongpu
Nov 23 '18 at 13:53
Ok. @Michael Do you think there are any way to solve my problem without doing@SuppressWarning
?
– MonkeyJLuffy
Nov 23 '18 at 14:07
Sounds like an XY problem.
<String> void
is not doing what you think it's doing. You're defining a new generic type parameter using the identifier "String". It may as well say <FooBar> void
. You should remove it. Only problem is that when you do, the method is not correctly overriding the method from the interface– Michael
Nov 23 '18 at 13:46
Sounds like an XY problem.
<String> void
is not doing what you think it's doing. You're defining a new generic type parameter using the identifier "String". It may as well say <FooBar> void
. You should remove it. Only problem is that when you do, the method is not correctly overriding the method from the interface– Michael
Nov 23 '18 at 13:46
1
1
The problem is that
Generic
specifies that any implementers should be able to implement setGenericObject
for all values of T
. Your implementation only works for strings, so it is not fulfilling the contract as defined by the interface. The best way to achieve what you want is to have Generic<T>
and GenericImpl implements Generic<String>
but you said you don't want to do that– Michael
Nov 23 '18 at 13:48
The problem is that
Generic
specifies that any implementers should be able to implement setGenericObject
for all values of T
. Your implementation only works for strings, so it is not fulfilling the contract as defined by the interface. The best way to achieve what you want is to have Generic<T>
and GenericImpl implements Generic<String>
but you said you don't want to do that– Michael
Nov 23 '18 at 13:48
plaese see stackoverflow.com/questions/7433279/…
– chenzhongpu
Nov 23 '18 at 13:53
plaese see stackoverflow.com/questions/7433279/…
– chenzhongpu
Nov 23 '18 at 13:53
Ok. @Michael Do you think there are any way to solve my problem without doing
@SuppressWarning
?– MonkeyJLuffy
Nov 23 '18 at 14:07
Ok. @Michael Do you think there are any way to solve my problem without doing
@SuppressWarning
?– MonkeyJLuffy
Nov 23 '18 at 14:07
add a comment |
2 Answers
2
active
oldest
votes
The real problem is that
public <String> void setGenericObject(GenericObject<String> obj)
where the String
has nothing to do with the your intended java.lang.String
. Here the String
is just a type parameter whose name is String
by accident.
Please refer to Is it possible to have an interface method defined with a generic return type and a concrete implementation define the return type?.
Ok, I understand that my<String>
tag is like<T>
, but what do you propose to solve my problem ? And keep in mind that I don't want to doGeneric<T>
– MonkeyJLuffy
Nov 23 '18 at 14:02
add a comment |
Case 1:
If T
is not used in Generic
, then just use a wildcard.
class Generic {
List<?> list;
void set(List<?> list) {
this.list = list;
}
int size() {
return list.size(); // doesn't care about T
}
}
Case 2:
If T
is only used as local variables, then declare <T>
on the method
class Generic {
<T> void swapFirstAndSecond(List<T> list) {
T first = list.get(0), second = list.get(1);
list.set(1, first);
list.set(0, second);
}
}
Case 3:
If several fields and methods use the same type T
, but the exact type of T
is not important, then delacre <T>
on the class
class Generic<T> {
List<T> list;
void set(List<T> list) {
this.list = list;
}
T getFirst() {
return list.get(0);
}
}
Case 4:
If T
must be a specific type, like String
, then don't declare type parameter <T>
class Generic {
List<String> list;
void set(List<String> list) {
this.list = list;
}
boolean isFirstContainsSecond() {
String first = list.get(0), second = list.get(1);
// call String.contains here, so T must be String
return first.contains(second);
}
}
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
The real problem is that
public <String> void setGenericObject(GenericObject<String> obj)
where the String
has nothing to do with the your intended java.lang.String
. Here the String
is just a type parameter whose name is String
by accident.
Please refer to Is it possible to have an interface method defined with a generic return type and a concrete implementation define the return type?.
Ok, I understand that my<String>
tag is like<T>
, but what do you propose to solve my problem ? And keep in mind that I don't want to doGeneric<T>
– MonkeyJLuffy
Nov 23 '18 at 14:02
add a comment |
The real problem is that
public <String> void setGenericObject(GenericObject<String> obj)
where the String
has nothing to do with the your intended java.lang.String
. Here the String
is just a type parameter whose name is String
by accident.
Please refer to Is it possible to have an interface method defined with a generic return type and a concrete implementation define the return type?.
Ok, I understand that my<String>
tag is like<T>
, but what do you propose to solve my problem ? And keep in mind that I don't want to doGeneric<T>
– MonkeyJLuffy
Nov 23 '18 at 14:02
add a comment |
The real problem is that
public <String> void setGenericObject(GenericObject<String> obj)
where the String
has nothing to do with the your intended java.lang.String
. Here the String
is just a type parameter whose name is String
by accident.
Please refer to Is it possible to have an interface method defined with a generic return type and a concrete implementation define the return type?.
The real problem is that
public <String> void setGenericObject(GenericObject<String> obj)
where the String
has nothing to do with the your intended java.lang.String
. Here the String
is just a type parameter whose name is String
by accident.
Please refer to Is it possible to have an interface method defined with a generic return type and a concrete implementation define the return type?.
answered Nov 23 '18 at 13:57
chenzhongpu
2,24732451
2,24732451
Ok, I understand that my<String>
tag is like<T>
, but what do you propose to solve my problem ? And keep in mind that I don't want to doGeneric<T>
– MonkeyJLuffy
Nov 23 '18 at 14:02
add a comment |
Ok, I understand that my<String>
tag is like<T>
, but what do you propose to solve my problem ? And keep in mind that I don't want to doGeneric<T>
– MonkeyJLuffy
Nov 23 '18 at 14:02
Ok, I understand that my
<String>
tag is like <T>
, but what do you propose to solve my problem ? And keep in mind that I don't want to do Generic<T>
– MonkeyJLuffy
Nov 23 '18 at 14:02
Ok, I understand that my
<String>
tag is like <T>
, but what do you propose to solve my problem ? And keep in mind that I don't want to do Generic<T>
– MonkeyJLuffy
Nov 23 '18 at 14:02
add a comment |
Case 1:
If T
is not used in Generic
, then just use a wildcard.
class Generic {
List<?> list;
void set(List<?> list) {
this.list = list;
}
int size() {
return list.size(); // doesn't care about T
}
}
Case 2:
If T
is only used as local variables, then declare <T>
on the method
class Generic {
<T> void swapFirstAndSecond(List<T> list) {
T first = list.get(0), second = list.get(1);
list.set(1, first);
list.set(0, second);
}
}
Case 3:
If several fields and methods use the same type T
, but the exact type of T
is not important, then delacre <T>
on the class
class Generic<T> {
List<T> list;
void set(List<T> list) {
this.list = list;
}
T getFirst() {
return list.get(0);
}
}
Case 4:
If T
must be a specific type, like String
, then don't declare type parameter <T>
class Generic {
List<String> list;
void set(List<String> list) {
this.list = list;
}
boolean isFirstContainsSecond() {
String first = list.get(0), second = list.get(1);
// call String.contains here, so T must be String
return first.contains(second);
}
}
add a comment |
Case 1:
If T
is not used in Generic
, then just use a wildcard.
class Generic {
List<?> list;
void set(List<?> list) {
this.list = list;
}
int size() {
return list.size(); // doesn't care about T
}
}
Case 2:
If T
is only used as local variables, then declare <T>
on the method
class Generic {
<T> void swapFirstAndSecond(List<T> list) {
T first = list.get(0), second = list.get(1);
list.set(1, first);
list.set(0, second);
}
}
Case 3:
If several fields and methods use the same type T
, but the exact type of T
is not important, then delacre <T>
on the class
class Generic<T> {
List<T> list;
void set(List<T> list) {
this.list = list;
}
T getFirst() {
return list.get(0);
}
}
Case 4:
If T
must be a specific type, like String
, then don't declare type parameter <T>
class Generic {
List<String> list;
void set(List<String> list) {
this.list = list;
}
boolean isFirstContainsSecond() {
String first = list.get(0), second = list.get(1);
// call String.contains here, so T must be String
return first.contains(second);
}
}
add a comment |
Case 1:
If T
is not used in Generic
, then just use a wildcard.
class Generic {
List<?> list;
void set(List<?> list) {
this.list = list;
}
int size() {
return list.size(); // doesn't care about T
}
}
Case 2:
If T
is only used as local variables, then declare <T>
on the method
class Generic {
<T> void swapFirstAndSecond(List<T> list) {
T first = list.get(0), second = list.get(1);
list.set(1, first);
list.set(0, second);
}
}
Case 3:
If several fields and methods use the same type T
, but the exact type of T
is not important, then delacre <T>
on the class
class Generic<T> {
List<T> list;
void set(List<T> list) {
this.list = list;
}
T getFirst() {
return list.get(0);
}
}
Case 4:
If T
must be a specific type, like String
, then don't declare type parameter <T>
class Generic {
List<String> list;
void set(List<String> list) {
this.list = list;
}
boolean isFirstContainsSecond() {
String first = list.get(0), second = list.get(1);
// call String.contains here, so T must be String
return first.contains(second);
}
}
Case 1:
If T
is not used in Generic
, then just use a wildcard.
class Generic {
List<?> list;
void set(List<?> list) {
this.list = list;
}
int size() {
return list.size(); // doesn't care about T
}
}
Case 2:
If T
is only used as local variables, then declare <T>
on the method
class Generic {
<T> void swapFirstAndSecond(List<T> list) {
T first = list.get(0), second = list.get(1);
list.set(1, first);
list.set(0, second);
}
}
Case 3:
If several fields and methods use the same type T
, but the exact type of T
is not important, then delacre <T>
on the class
class Generic<T> {
List<T> list;
void set(List<T> list) {
this.list = list;
}
T getFirst() {
return list.get(0);
}
}
Case 4:
If T
must be a specific type, like String
, then don't declare type parameter <T>
class Generic {
List<String> list;
void set(List<String> list) {
this.list = list;
}
boolean isFirstContainsSecond() {
String first = list.get(0), second = list.get(1);
// call String.contains here, so T must be String
return first.contains(second);
}
}
edited Nov 23 '18 at 15:49
answered Nov 23 '18 at 14:35
yyyy
635
635
add a comment |
add a comment |
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Sounds like an XY problem.
<String> void
is not doing what you think it's doing. You're defining a new generic type parameter using the identifier "String". It may as well say<FooBar> void
. You should remove it. Only problem is that when you do, the method is not correctly overriding the method from the interface– Michael
Nov 23 '18 at 13:46
1
The problem is that
Generic
specifies that any implementers should be able to implementsetGenericObject
for all values ofT
. Your implementation only works for strings, so it is not fulfilling the contract as defined by the interface. The best way to achieve what you want is to haveGeneric<T>
andGenericImpl implements Generic<String>
but you said you don't want to do that– Michael
Nov 23 '18 at 13:48
plaese see stackoverflow.com/questions/7433279/…
– chenzhongpu
Nov 23 '18 at 13:53
Ok. @Michael Do you think there are any way to solve my problem without doing
@SuppressWarning
?– MonkeyJLuffy
Nov 23 '18 at 14:07