How to remove underscore character with awk
I have a file as below:
This is an _PLUTO_
This is _PINEAPPLE_
This is _ORANGE_
This is _RICE_
I'm using below code to extract the output:
awk '{ print "Country: " $NF }' report.txt
Output:
Country: _PLUTO_
Country: _PINEAPPLE_
Country: _ORANGE_
Country: _RICE_
How do I remove all the underscore so that my output looks below:
Country: PLUTO
Country: PINEAPPLE
Country: ORANGE
Country: RICE
awk
add a comment |
I have a file as below:
This is an _PLUTO_
This is _PINEAPPLE_
This is _ORANGE_
This is _RICE_
I'm using below code to extract the output:
awk '{ print "Country: " $NF }' report.txt
Output:
Country: _PLUTO_
Country: _PINEAPPLE_
Country: _ORANGE_
Country: _RICE_
How do I remove all the underscore so that my output looks below:
Country: PLUTO
Country: PINEAPPLE
Country: ORANGE
Country: RICE
awk
1
substr
orgsub
- see gnu.org/software/gawk/manual/gawk.html#String-Functions
– steeldriver
1 hour ago
sed -i "s/_//" report.txt
– Rui F Ribeiro
1 hour ago
add a comment |
I have a file as below:
This is an _PLUTO_
This is _PINEAPPLE_
This is _ORANGE_
This is _RICE_
I'm using below code to extract the output:
awk '{ print "Country: " $NF }' report.txt
Output:
Country: _PLUTO_
Country: _PINEAPPLE_
Country: _ORANGE_
Country: _RICE_
How do I remove all the underscore so that my output looks below:
Country: PLUTO
Country: PINEAPPLE
Country: ORANGE
Country: RICE
awk
I have a file as below:
This is an _PLUTO_
This is _PINEAPPLE_
This is _ORANGE_
This is _RICE_
I'm using below code to extract the output:
awk '{ print "Country: " $NF }' report.txt
Output:
Country: _PLUTO_
Country: _PINEAPPLE_
Country: _ORANGE_
Country: _RICE_
How do I remove all the underscore so that my output looks below:
Country: PLUTO
Country: PINEAPPLE
Country: ORANGE
Country: RICE
awk
awk
edited 1 hour ago
Rui F Ribeiro
39.1k1479130
39.1k1479130
asked 1 hour ago
user324294
113
113
1
substr
orgsub
- see gnu.org/software/gawk/manual/gawk.html#String-Functions
– steeldriver
1 hour ago
sed -i "s/_//" report.txt
– Rui F Ribeiro
1 hour ago
add a comment |
1
substr
orgsub
- see gnu.org/software/gawk/manual/gawk.html#String-Functions
– steeldriver
1 hour ago
sed -i "s/_//" report.txt
– Rui F Ribeiro
1 hour ago
1
1
substr
or gsub
- see gnu.org/software/gawk/manual/gawk.html#String-Functions– steeldriver
1 hour ago
substr
or gsub
- see gnu.org/software/gawk/manual/gawk.html#String-Functions– steeldriver
1 hour ago
sed -i "s/_//" report.txt
– Rui F Ribeiro
1 hour ago
sed -i "s/_//" report.txt
– Rui F Ribeiro
1 hour ago
add a comment |
2 Answers
2
active
oldest
votes
You can use this snippet:
$ awk '{ gsub("_", "", $NF); print "Country: " $NF }' report.txt
Country: PLUTO
Country: PINEAPPLE
Country: ORANGE
Country: RICE
Note that gsub()
will perform the modification in place, so it will store the result of the substitution back to $NF
, in your case.
If you're using GNU awk, you can use gensub()
instead, which is slightly simpler:
$ gawk '{ print "Country: " gensub("_", "", "g", $NF) }' report.txt
Country: PLUTO
Country: PINEAPPLE
Country: ORANGE
Country: RICE
See GNU awk documentation for gsub() and gensub() for more details.
add a comment |
try
awk -F_ '{ print "Country: " $(NF-1) }' infile
You could try sed
instead.
sed -r 's/[^_]*_([^_]*)_.*/Country: 1/' infile
[^_]*_
matches everything until a first_
seen.
([^_]*)_
matches everything after above match untill next_
seen and.*
matches everything after that, but only keep(...)
part as a captured group.
1
is the back-reference to the([^_]*)
captured group.
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can use this snippet:
$ awk '{ gsub("_", "", $NF); print "Country: " $NF }' report.txt
Country: PLUTO
Country: PINEAPPLE
Country: ORANGE
Country: RICE
Note that gsub()
will perform the modification in place, so it will store the result of the substitution back to $NF
, in your case.
If you're using GNU awk, you can use gensub()
instead, which is slightly simpler:
$ gawk '{ print "Country: " gensub("_", "", "g", $NF) }' report.txt
Country: PLUTO
Country: PINEAPPLE
Country: ORANGE
Country: RICE
See GNU awk documentation for gsub() and gensub() for more details.
add a comment |
You can use this snippet:
$ awk '{ gsub("_", "", $NF); print "Country: " $NF }' report.txt
Country: PLUTO
Country: PINEAPPLE
Country: ORANGE
Country: RICE
Note that gsub()
will perform the modification in place, so it will store the result of the substitution back to $NF
, in your case.
If you're using GNU awk, you can use gensub()
instead, which is slightly simpler:
$ gawk '{ print "Country: " gensub("_", "", "g", $NF) }' report.txt
Country: PLUTO
Country: PINEAPPLE
Country: ORANGE
Country: RICE
See GNU awk documentation for gsub() and gensub() for more details.
add a comment |
You can use this snippet:
$ awk '{ gsub("_", "", $NF); print "Country: " $NF }' report.txt
Country: PLUTO
Country: PINEAPPLE
Country: ORANGE
Country: RICE
Note that gsub()
will perform the modification in place, so it will store the result of the substitution back to $NF
, in your case.
If you're using GNU awk, you can use gensub()
instead, which is slightly simpler:
$ gawk '{ print "Country: " gensub("_", "", "g", $NF) }' report.txt
Country: PLUTO
Country: PINEAPPLE
Country: ORANGE
Country: RICE
See GNU awk documentation for gsub() and gensub() for more details.
You can use this snippet:
$ awk '{ gsub("_", "", $NF); print "Country: " $NF }' report.txt
Country: PLUTO
Country: PINEAPPLE
Country: ORANGE
Country: RICE
Note that gsub()
will perform the modification in place, so it will store the result of the substitution back to $NF
, in your case.
If you're using GNU awk, you can use gensub()
instead, which is slightly simpler:
$ gawk '{ print "Country: " gensub("_", "", "g", $NF) }' report.txt
Country: PLUTO
Country: PINEAPPLE
Country: ORANGE
Country: RICE
See GNU awk documentation for gsub() and gensub() for more details.
answered 1 hour ago
filbranden
7,0152735
7,0152735
add a comment |
add a comment |
try
awk -F_ '{ print "Country: " $(NF-1) }' infile
You could try sed
instead.
sed -r 's/[^_]*_([^_]*)_.*/Country: 1/' infile
[^_]*_
matches everything until a first_
seen.
([^_]*)_
matches everything after above match untill next_
seen and.*
matches everything after that, but only keep(...)
part as a captured group.
1
is the back-reference to the([^_]*)
captured group.
add a comment |
try
awk -F_ '{ print "Country: " $(NF-1) }' infile
You could try sed
instead.
sed -r 's/[^_]*_([^_]*)_.*/Country: 1/' infile
[^_]*_
matches everything until a first_
seen.
([^_]*)_
matches everything after above match untill next_
seen and.*
matches everything after that, but only keep(...)
part as a captured group.
1
is the back-reference to the([^_]*)
captured group.
add a comment |
try
awk -F_ '{ print "Country: " $(NF-1) }' infile
You could try sed
instead.
sed -r 's/[^_]*_([^_]*)_.*/Country: 1/' infile
[^_]*_
matches everything until a first_
seen.
([^_]*)_
matches everything after above match untill next_
seen and.*
matches everything after that, but only keep(...)
part as a captured group.
1
is the back-reference to the([^_]*)
captured group.
try
awk -F_ '{ print "Country: " $(NF-1) }' infile
You could try sed
instead.
sed -r 's/[^_]*_([^_]*)_.*/Country: 1/' infile
[^_]*_
matches everything until a first_
seen.
([^_]*)_
matches everything after above match untill next_
seen and.*
matches everything after that, but only keep(...)
part as a captured group.
1
is the back-reference to the([^_]*)
captured group.
edited 44 mins ago
answered 52 mins ago
αғsнιη
16.5k102865
16.5k102865
add a comment |
add a comment |
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1
substr
orgsub
- see gnu.org/software/gawk/manual/gawk.html#String-Functions– steeldriver
1 hour ago
sed -i "s/_//" report.txt
– Rui F Ribeiro
1 hour ago