count files with regex in java












1















I want to count files using regex to match filenames.But My regex didn't match. My "F:" has two files named "a(1).txt"&"a(1)(1).txt" .But regex only can match one of them,the count is 1. But when I change "()" to "-" in my regex and files' names.It can match all of them.I think the problem is in my regex.But I don't know why?
here is my code:



public static void main(String args) {
File dest = new File("F:\");
File file = new File("E:\a(1).txt");
move(file, dest);
}

public static void move(File file, File dest) {
//get file name
String name = file.getName();
int index = name.lastIndexOf(".");
String realname = name.substring(0, index);
String suffix = name.substring(index + 1, name.length());
//get files in F:
File fs = dest.listFiles(new FileFilter() {
@Override
public boolean accept(File pathname) {
//get File name
String fname = pathname.getName();
return fname.equals(name) || fname.matches(realname + "\(\d+\)." + suffix);
}
});
int count = fs.length;
System.out.println(count);
file.renameTo(new File(dest + realname + (count == 0 ? "." : "(" + count + ").") + suffix);
}









share|improve this question

























  • Typo: liatFiles

    – Pavitra
    Nov 25 '18 at 3:55
















1















I want to count files using regex to match filenames.But My regex didn't match. My "F:" has two files named "a(1).txt"&"a(1)(1).txt" .But regex only can match one of them,the count is 1. But when I change "()" to "-" in my regex and files' names.It can match all of them.I think the problem is in my regex.But I don't know why?
here is my code:



public static void main(String args) {
File dest = new File("F:\");
File file = new File("E:\a(1).txt");
move(file, dest);
}

public static void move(File file, File dest) {
//get file name
String name = file.getName();
int index = name.lastIndexOf(".");
String realname = name.substring(0, index);
String suffix = name.substring(index + 1, name.length());
//get files in F:
File fs = dest.listFiles(new FileFilter() {
@Override
public boolean accept(File pathname) {
//get File name
String fname = pathname.getName();
return fname.equals(name) || fname.matches(realname + "\(\d+\)." + suffix);
}
});
int count = fs.length;
System.out.println(count);
file.renameTo(new File(dest + realname + (count == 0 ? "." : "(" + count + ").") + suffix);
}









share|improve this question

























  • Typo: liatFiles

    – Pavitra
    Nov 25 '18 at 3:55














1












1








1








I want to count files using regex to match filenames.But My regex didn't match. My "F:" has two files named "a(1).txt"&"a(1)(1).txt" .But regex only can match one of them,the count is 1. But when I change "()" to "-" in my regex and files' names.It can match all of them.I think the problem is in my regex.But I don't know why?
here is my code:



public static void main(String args) {
File dest = new File("F:\");
File file = new File("E:\a(1).txt");
move(file, dest);
}

public static void move(File file, File dest) {
//get file name
String name = file.getName();
int index = name.lastIndexOf(".");
String realname = name.substring(0, index);
String suffix = name.substring(index + 1, name.length());
//get files in F:
File fs = dest.listFiles(new FileFilter() {
@Override
public boolean accept(File pathname) {
//get File name
String fname = pathname.getName();
return fname.equals(name) || fname.matches(realname + "\(\d+\)." + suffix);
}
});
int count = fs.length;
System.out.println(count);
file.renameTo(new File(dest + realname + (count == 0 ? "." : "(" + count + ").") + suffix);
}









share|improve this question
















I want to count files using regex to match filenames.But My regex didn't match. My "F:" has two files named "a(1).txt"&"a(1)(1).txt" .But regex only can match one of them,the count is 1. But when I change "()" to "-" in my regex and files' names.It can match all of them.I think the problem is in my regex.But I don't know why?
here is my code:



public static void main(String args) {
File dest = new File("F:\");
File file = new File("E:\a(1).txt");
move(file, dest);
}

public static void move(File file, File dest) {
//get file name
String name = file.getName();
int index = name.lastIndexOf(".");
String realname = name.substring(0, index);
String suffix = name.substring(index + 1, name.length());
//get files in F:
File fs = dest.listFiles(new FileFilter() {
@Override
public boolean accept(File pathname) {
//get File name
String fname = pathname.getName();
return fname.equals(name) || fname.matches(realname + "\(\d+\)." + suffix);
}
});
int count = fs.length;
System.out.println(count);
file.renameTo(new File(dest + realname + (count == 0 ? "." : "(" + count + ").") + suffix);
}






java regex






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edited Nov 25 '18 at 4:53









uli

519313




519313










asked Nov 25 '18 at 3:41









HanHan

84




84













  • Typo: liatFiles

    – Pavitra
    Nov 25 '18 at 3:55



















  • Typo: liatFiles

    – Pavitra
    Nov 25 '18 at 3:55

















Typo: liatFiles

– Pavitra
Nov 25 '18 at 3:55





Typo: liatFiles

– Pavitra
Nov 25 '18 at 3:55












2 Answers
2






active

oldest

votes


















0














You should learn debugging with IDE or at least printing values at sum checkpoint to narrow the source of issue.



Your pattern for fname.matches() is a(1)(d+).txt. Round brackets are special symbols in regex to escape them you could use java.util.regex.Pattern.quote(realname). It will change the pattern to a(1)(d+).txt.



Thoughts:

input file = a(2).txt to match a(2).txt and a(2)(1).txt you could remove fname.equals(name) and modify regex to fname.matches(Pattern.quote(realname) + "(\(\d+\))*\." + suffix). * means zero or more times inside round brackets; "." - dot is a special symbol and should be escaped.






share|improve this answer































    0














    I think your regex should be



    ((d+))+.


    You also need to escape special character to use this regex in Java code as followed:



    (\(\d+\))+\.





    share|improve this answer
























    • The issue is with realname.

      – uli
      Nov 25 '18 at 4:56











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    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    0














    You should learn debugging with IDE or at least printing values at sum checkpoint to narrow the source of issue.



    Your pattern for fname.matches() is a(1)(d+).txt. Round brackets are special symbols in regex to escape them you could use java.util.regex.Pattern.quote(realname). It will change the pattern to a(1)(d+).txt.



    Thoughts:

    input file = a(2).txt to match a(2).txt and a(2)(1).txt you could remove fname.equals(name) and modify regex to fname.matches(Pattern.quote(realname) + "(\(\d+\))*\." + suffix). * means zero or more times inside round brackets; "." - dot is a special symbol and should be escaped.






    share|improve this answer




























      0














      You should learn debugging with IDE or at least printing values at sum checkpoint to narrow the source of issue.



      Your pattern for fname.matches() is a(1)(d+).txt. Round brackets are special symbols in regex to escape them you could use java.util.regex.Pattern.quote(realname). It will change the pattern to a(1)(d+).txt.



      Thoughts:

      input file = a(2).txt to match a(2).txt and a(2)(1).txt you could remove fname.equals(name) and modify regex to fname.matches(Pattern.quote(realname) + "(\(\d+\))*\." + suffix). * means zero or more times inside round brackets; "." - dot is a special symbol and should be escaped.






      share|improve this answer


























        0












        0








        0







        You should learn debugging with IDE or at least printing values at sum checkpoint to narrow the source of issue.



        Your pattern for fname.matches() is a(1)(d+).txt. Round brackets are special symbols in regex to escape them you could use java.util.regex.Pattern.quote(realname). It will change the pattern to a(1)(d+).txt.



        Thoughts:

        input file = a(2).txt to match a(2).txt and a(2)(1).txt you could remove fname.equals(name) and modify regex to fname.matches(Pattern.quote(realname) + "(\(\d+\))*\." + suffix). * means zero or more times inside round brackets; "." - dot is a special symbol and should be escaped.






        share|improve this answer













        You should learn debugging with IDE or at least printing values at sum checkpoint to narrow the source of issue.



        Your pattern for fname.matches() is a(1)(d+).txt. Round brackets are special symbols in regex to escape them you could use java.util.regex.Pattern.quote(realname). It will change the pattern to a(1)(d+).txt.



        Thoughts:

        input file = a(2).txt to match a(2).txt and a(2)(1).txt you could remove fname.equals(name) and modify regex to fname.matches(Pattern.quote(realname) + "(\(\d+\))*\." + suffix). * means zero or more times inside round brackets; "." - dot is a special symbol and should be escaped.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 25 '18 at 5:18









        uliuli

        519313




        519313

























            0














            I think your regex should be



            ((d+))+.


            You also need to escape special character to use this regex in Java code as followed:



            (\(\d+\))+\.





            share|improve this answer
























            • The issue is with realname.

              – uli
              Nov 25 '18 at 4:56
















            0














            I think your regex should be



            ((d+))+.


            You also need to escape special character to use this regex in Java code as followed:



            (\(\d+\))+\.





            share|improve this answer
























            • The issue is with realname.

              – uli
              Nov 25 '18 at 4:56














            0












            0








            0







            I think your regex should be



            ((d+))+.


            You also need to escape special character to use this regex in Java code as followed:



            (\(\d+\))+\.





            share|improve this answer













            I think your regex should be



            ((d+))+.


            You also need to escape special character to use this regex in Java code as followed:



            (\(\d+\))+\.






            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered Nov 25 '18 at 4:10









            thanh ngothanh ngo

            53939




            53939













            • The issue is with realname.

              – uli
              Nov 25 '18 at 4:56



















            • The issue is with realname.

              – uli
              Nov 25 '18 at 4:56

















            The issue is with realname.

            – uli
            Nov 25 '18 at 4:56





            The issue is with realname.

            – uli
            Nov 25 '18 at 4:56


















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