How to start a program with bash -c, redirect / disable GUI of that app

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0
down vote

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Currently I'm starting a java application with

bash -c java -jar app.jar -config config.json

The app opens a window, displaying some output and closes. The output is also available on stdout, so I don't need (want) the GUI to display.

How can I prevent bash to forward the X output?

Follow up:

I'm running this in a go application, so based on el.pescado's answer, I have implemented this as:

func runcmd(cmd string, workdir string) (byte, error) {

  ex := exec.Command("bash", "-c", cmd)

  ex.Env = string{"DISPLAY= "}

  ex.Dir = workdir

  return ex.Output()

}

edited yesterday

asked yesterday

G-M

961111

add a comment |

up vote
0
down vote

favorite

Currently I'm starting a java application with

bash -c java -jar app.jar -config config.json

The app opens a window, displaying some output and closes. The output is also available on stdout, so I don't need (want) the GUI to display.

How can I prevent bash to forward the X output?

Follow up:

I'm running this in a go application, so based on el.pescado's answer, I have implemented this as:

func runcmd(cmd string, workdir string) (byte, error) {

  ex := exec.Command("bash", "-c", cmd)

  ex.Env = string{"DISPLAY= "}

  ex.Dir = workdir

  return ex.Output()

}

edited yesterday

asked yesterday

G-M

961111

add a comment |

up vote
0
down vote

favorite

Currently I'm starting a java application with

bash -c java -jar app.jar -config config.json

The app opens a window, displaying some output and closes. The output is also available on stdout, so I don't need (want) the GUI to display.

How can I prevent bash to forward the X output?

Follow up:

I'm running this in a go application, so based on el.pescado's answer, I have implemented this as:

func runcmd(cmd string, workdir string) (byte, error) {

  ex := exec.Command("bash", "-c", cmd)

  ex.Env = string{"DISPLAY= "}

  ex.Dir = workdir

  return ex.Output()

}

edited yesterday

asked yesterday

G-M

961111

Currently I'm starting a java application with

bash -c java -jar app.jar -config config.json

The app opens a window, displaying some output and closes. The output is also available on stdout, so I don't need (want) the GUI to display.

How can I prevent bash to forward the X output?

Follow up:

I'm running this in a go application, so based on el.pescado's answer, I have implemented this as:

func runcmd(cmd string, workdir string) (byte, error) {

  ex := exec.Command("bash", "-c", cmd)

  ex.Env = string{"DISPLAY= "}

  ex.Dir = workdir

  return ex.Output()

}

bash go

edited yesterday

asked yesterday

G-M

961111

edited yesterday

asked yesterday

G-M

961111

edited yesterday

asked yesterday

G-M

961111

asked yesterday

G-M

961111

asked yesterday

G-M

961111

add a comment |

1 Answer
1

active

oldest

votes

up vote
2
down vote

accepted

You have several options:

First, you should check if that application can run without GUI (often called "headless" mode)

You can unset DISPLAY variable, so that your app won't find your X11 server - but keep in mind that application might not work without X server

eg.

DISPLAY= bash -c java -jar app.jar -config config.json # note space after '='

# or

env -u DISPLAY bash -c java -jar app.jar -config config.json

You could use in-memory virtual X server such as xfvb and point your application to display its windows there.

eg.

Xvfb :1 -screen 0 1600x1200x32

DISPLAY=:1 bash -c java -jar app.jar -config config.json

answered yesterday

el.pescado

15.7k22771

Thanks, works like a charm!
– G-M
yesterday

@G-M Which solution works for you ?
– mgagnon
yesterday

@mgagnon #2 DISPLAY= bash -c java -jar app.jar -config config.json
– G-M
yesterday

add a comment |

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1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

up vote
2
down vote

accepted

You have several options:

First, you should check if that application can run without GUI (often called "headless" mode)

You can unset DISPLAY variable, so that your app won't find your X11 server - but keep in mind that application might not work without X server

eg.

DISPLAY= bash -c java -jar app.jar -config config.json # note space after '='

# or

env -u DISPLAY bash -c java -jar app.jar -config config.json

You could use in-memory virtual X server such as xfvb and point your application to display its windows there.

eg.

Xvfb :1 -screen 0 1600x1200x32

DISPLAY=:1 bash -c java -jar app.jar -config config.json

answered yesterday

el.pescado

15.7k22771

Thanks, works like a charm!
– G-M
yesterday

@G-M Which solution works for you ?
– mgagnon
yesterday

@mgagnon #2 DISPLAY= bash -c java -jar app.jar -config config.json
– G-M
yesterday

add a comment |

up vote
2
down vote

accepted

You have several options:

First, you should check if that application can run without GUI (often called "headless" mode)

You can unset DISPLAY variable, so that your app won't find your X11 server - but keep in mind that application might not work without X server

eg.

DISPLAY= bash -c java -jar app.jar -config config.json # note space after '='

# or

env -u DISPLAY bash -c java -jar app.jar -config config.json

You could use in-memory virtual X server such as xfvb and point your application to display its windows there.

eg.

Xvfb :1 -screen 0 1600x1200x32

DISPLAY=:1 bash -c java -jar app.jar -config config.json

answered yesterday

el.pescado

15.7k22771

Thanks, works like a charm!
– G-M
yesterday

@G-M Which solution works for you ?
– mgagnon
yesterday

@mgagnon #2 DISPLAY= bash -c java -jar app.jar -config config.json
– G-M
yesterday

add a comment |

up vote
2
down vote

accepted

You have several options:

First, you should check if that application can run without GUI (often called "headless" mode)

You can unset DISPLAY variable, so that your app won't find your X11 server - but keep in mind that application might not work without X server

eg.

DISPLAY= bash -c java -jar app.jar -config config.json # note space after '='

# or

env -u DISPLAY bash -c java -jar app.jar -config config.json

You could use in-memory virtual X server such as xfvb and point your application to display its windows there.

eg.

Xvfb :1 -screen 0 1600x1200x32

DISPLAY=:1 bash -c java -jar app.jar -config config.json

answered yesterday

el.pescado

15.7k22771

You have several options:

First, you should check if that application can run without GUI (often called "headless" mode)

You can unset DISPLAY variable, so that your app won't find your X11 server - but keep in mind that application might not work without X server

eg.

DISPLAY= bash -c java -jar app.jar -config config.json # note space after '='

# or

env -u DISPLAY bash -c java -jar app.jar -config config.json

You could use in-memory virtual X server such as xfvb and point your application to display its windows there.

eg.

Xvfb :1 -screen 0 1600x1200x32

DISPLAY=:1 bash -c java -jar app.jar -config config.json

answered yesterday

el.pescado

15.7k22771

answered yesterday

el.pescado

15.7k22771

answered yesterday

el.pescado

15.7k22771

answered yesterday

el.pescado

15.7k22771

Thanks, works like a charm!
– G-M
yesterday

@G-M Which solution works for you ?
– mgagnon
yesterday

@mgagnon #2 DISPLAY= bash -c java -jar app.jar -config config.json
– G-M
yesterday

add a comment |

Thanks, works like a charm!
– G-M
yesterday

@G-M Which solution works for you ?
– mgagnon
yesterday

@mgagnon #2 DISPLAY= bash -c java -jar app.jar -config config.json
– G-M
yesterday

Thanks, works like a charm!
– G-M
yesterday

@G-M Which solution works for you ?
– mgagnon
yesterday

@mgagnon #2 DISPLAY= bash -c java -jar app.jar -config config.json
– G-M
yesterday

add a comment |

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