Btukfyl

currently I am trying to unify license names in rpm packages.

Therefore I parse rpms, get the license information as lists and want to compare these list with a lookup table I build.

Here is an example:

lic = ['GPLv2', ' & ', 'LGPLv2+', ' & ', 'LGPLv2.1+', ' | ', 'LGPLv3+']



duplicates = (

            ('GPL-2.0', 'GPL-2', 'GPLv2', 'GPLv2.0'),

            ('GPL-2.0+', 'GPL-2+', 'GPLv2+', 'GPLv2.0+'),

            ('GPL-3.0', 'GPL-3', 'GPLv3', 'GPLv3.0'),

            ('GPL-3.0+', 'GPL-3+', 'GPLv3+', 'GPLv3.0+'),

            ('LGPL-2.0', 'LGPLv2.0', 'LGPLv2', 'LGPL2'),

            ('LGPL-2.0+', 'LGPLv2.0+', 'LGPLv2+', 'LGPL2+'),

            ('LGPL-2.1', 'LGPLv2.1', 'LGPL2.1'),

            ('LGPL-2.1+', 'LGPLv2.1+', 'LGPL2.1+'),

            ('LGPL-3.0', 'LGPLv3.0', 'LGPLv3', 'LGPL3'),

            ('LGPL-3.0+', 'LGPLv3.0+', 'LGPLv3+', 'LGPL3+')

            )

What would be the most efficient and most pythonic way of replacing all occurrences of any element in duplicates in lic with the corresponding first element of each tuple?

eg: GPLv2 needs to be replaced with GPL-2.0, LGPLv2+ with LGPL-2.0+ and so on.

I am on Python 3.5.2

You could iterate over your lic and compare each of its elements with duplicates and if you find match replace that element with first element of matching tuple.

lic = ['GPLv2', ' & ', 'LGPLv2+', ' & ', 'LGPLv2.1+', ' | ', 'LGPLv3+']



duplicates = (

            ('GPL-2.0', 'GPL-2', 'GPLv2', 'GPLv2.0'),

            ('GPL-2.0+', 'GPL-2+', 'GPLv2+', 'GPLv2.0+'),

            ('GPL-3.0', 'GPL-3', 'GPLv3', 'GPLv3.0'),

            ('GPL-3.0+', 'GPL-3+', 'GPLv3+', 'GPLv3.0+'),

            ('LGPL-2.0', 'LGPLv2.0', 'LGPLv2', 'LGPL2'),

            ('LGPL-2.0+', 'LGPLv2.0+', 'LGPLv2+', 'LGPL2+'),

            ('LGPL-2.1', 'LGPLv2.1', 'LGPL2.1'),

            ('LGPL-2.1+', 'LGPLv2.1+', 'LGPL2.1+'),

            ('LGPL-3.0', 'LGPLv3.0', 'LGPLv3', 'LGPL3'),

            ('LGPL-3.0+', 'LGPLv3.0+', 'LGPLv3+', 'LGPL3+')

            )



for idx, i in enumerate(lic):

    for match in duplicates:

        if i in match:

            lic[idx] = match[0]

            break



print(lic)

Output:

['GPL-2.0', ' & ', 'LGPL-2.0+', ' & ', 'LGPL-2.1+', ' | ', 'LGPL-3.0+']

I would modify the duplicates tuple of tuples to a dict first. like so:

duplicates = {k: v for k, *v in duplicates}  # {'GPL-2.0': ['GPL-2', 'GPLv2', 'GPLv2.0'], ...}

and then do:

lic_clean = [next((k for k, v in duplicates.items() if x in v), x) for x in lic]

which produces:

['GPL-2.0', ' & ', 'LGPL-2.0+', ' & ', 'LGPL-2.1+', ' | ', 'LGPL-3.0+']