Encoder in GeoTools does not work for SLD












1















I'm trying to use GeoTools to write SLDs on the fly for an application I am developing. But try as I might, I can't get the SLDs to be output.



Starting with an SLD that looks like this:



<StyledLayerDescriptor xmlns="http://www.opengis.net/sld" version="1.0.0"
xsi:schemaLocation="http://www.opengis.net/sld http://schemas.opengis.net/sld/1.0.0/StyledLayerDescriptor.xsd"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<NamedLayer>
<Name>named_layer</Name>
<UserStyle>
<Name>style</Name>
<IsDefault>true</IsDefault>
<FeatureTypeStyle>
<Rule>
<PointSymbolizer>
<Graphic>
<Mark>
<WellKnownName>circle</WellKnownName>
<Fill>
<CssParameter name="fill">#00aa00</CssParameter>
</Fill>
<Stroke>
<CssParameter name="stroke">#000000</CssParameter>
<CssParameter name="stroke-width">0.15</CssParameter>
</Stroke>
</Mark>
<Size>8</Size>
</Graphic>
</PointSymbolizer>
</Rule>
</FeatureTypeStyle>
</UserStyle>
</NamedLayer>
</StyledLayerDescriptor>


I use the following code:



package com.example.sld;

import org.geotools.sld.SLDConfiguration;
import org.geotools.sld.bindings.SLD;
import org.geotools.styling.StyledLayerDescriptor;
import org.geotools.xml.Configuration;
import org.geotools.xml.Encoder;
import org.geotools.xml.Parser;
import org.xml.sax.SAXException;

import javax.xml.parsers.ParserConfigurationException;
import java.io.IOException;
import java.io.InputStream;

public class TestStyle {

private String style;

public TestStyle() {

Configuration config = new SLDConfiguration();
Parser parser = new Parser(config);

InputStream is = getClass().getResourceAsStream("test-sld.xml");

StyledLayerDescriptor sld = null;
try {
sld = (StyledLayerDescriptor) parser.parse(is);
} catch (SAXException e) {
e.printStackTrace();
} catch (ParserConfigurationException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}

Configuration configuration = new SLDConfiguration();
Encoder encoder = new Encoder(configuration);
encoder.setOmitXMLDeclaration(true);
try {
this.style = encoder.encodeAsString(sld, SLD.STYLEDLAYERDESCRIPTOR);
} catch (IOException e) {
e.printStackTrace();
}

this.style = new String();

}
}


The SLD parses OK. I can inspect its structure in my debugger and it is read correctly. But on encoding, the resultant SLD is empty:



<sld:StyledLayerDescriptor xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:ogc="http://www.opengis.net/ogc" xmlns:sld="http://www.opengis.net/sld" xmlns:xlink="http://www.w3.org/1999/xlink"/>


What am I doing wrong?



(Version of GeoTools is 20.1, following the guide here: http://docs.geotools.org/latest/userguide/library/xml/style.html#encoder)



Thanks in advance










share|improve this question



























    1















    I'm trying to use GeoTools to write SLDs on the fly for an application I am developing. But try as I might, I can't get the SLDs to be output.



    Starting with an SLD that looks like this:



    <StyledLayerDescriptor xmlns="http://www.opengis.net/sld" version="1.0.0"
    xsi:schemaLocation="http://www.opengis.net/sld http://schemas.opengis.net/sld/1.0.0/StyledLayerDescriptor.xsd"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
    <NamedLayer>
    <Name>named_layer</Name>
    <UserStyle>
    <Name>style</Name>
    <IsDefault>true</IsDefault>
    <FeatureTypeStyle>
    <Rule>
    <PointSymbolizer>
    <Graphic>
    <Mark>
    <WellKnownName>circle</WellKnownName>
    <Fill>
    <CssParameter name="fill">#00aa00</CssParameter>
    </Fill>
    <Stroke>
    <CssParameter name="stroke">#000000</CssParameter>
    <CssParameter name="stroke-width">0.15</CssParameter>
    </Stroke>
    </Mark>
    <Size>8</Size>
    </Graphic>
    </PointSymbolizer>
    </Rule>
    </FeatureTypeStyle>
    </UserStyle>
    </NamedLayer>
    </StyledLayerDescriptor>


    I use the following code:



    package com.example.sld;

    import org.geotools.sld.SLDConfiguration;
    import org.geotools.sld.bindings.SLD;
    import org.geotools.styling.StyledLayerDescriptor;
    import org.geotools.xml.Configuration;
    import org.geotools.xml.Encoder;
    import org.geotools.xml.Parser;
    import org.xml.sax.SAXException;

    import javax.xml.parsers.ParserConfigurationException;
    import java.io.IOException;
    import java.io.InputStream;

    public class TestStyle {

    private String style;

    public TestStyle() {

    Configuration config = new SLDConfiguration();
    Parser parser = new Parser(config);

    InputStream is = getClass().getResourceAsStream("test-sld.xml");

    StyledLayerDescriptor sld = null;
    try {
    sld = (StyledLayerDescriptor) parser.parse(is);
    } catch (SAXException e) {
    e.printStackTrace();
    } catch (ParserConfigurationException e) {
    e.printStackTrace();
    } catch (IOException e) {
    e.printStackTrace();
    }

    Configuration configuration = new SLDConfiguration();
    Encoder encoder = new Encoder(configuration);
    encoder.setOmitXMLDeclaration(true);
    try {
    this.style = encoder.encodeAsString(sld, SLD.STYLEDLAYERDESCRIPTOR);
    } catch (IOException e) {
    e.printStackTrace();
    }

    this.style = new String();

    }
    }


    The SLD parses OK. I can inspect its structure in my debugger and it is read correctly. But on encoding, the resultant SLD is empty:



    <sld:StyledLayerDescriptor xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:ogc="http://www.opengis.net/ogc" xmlns:sld="http://www.opengis.net/sld" xmlns:xlink="http://www.w3.org/1999/xlink"/>


    What am I doing wrong?



    (Version of GeoTools is 20.1, following the guide here: http://docs.geotools.org/latest/userguide/library/xml/style.html#encoder)



    Thanks in advance










    share|improve this question

























      1












      1








      1


      1






      I'm trying to use GeoTools to write SLDs on the fly for an application I am developing. But try as I might, I can't get the SLDs to be output.



      Starting with an SLD that looks like this:



      <StyledLayerDescriptor xmlns="http://www.opengis.net/sld" version="1.0.0"
      xsi:schemaLocation="http://www.opengis.net/sld http://schemas.opengis.net/sld/1.0.0/StyledLayerDescriptor.xsd"
      xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
      <NamedLayer>
      <Name>named_layer</Name>
      <UserStyle>
      <Name>style</Name>
      <IsDefault>true</IsDefault>
      <FeatureTypeStyle>
      <Rule>
      <PointSymbolizer>
      <Graphic>
      <Mark>
      <WellKnownName>circle</WellKnownName>
      <Fill>
      <CssParameter name="fill">#00aa00</CssParameter>
      </Fill>
      <Stroke>
      <CssParameter name="stroke">#000000</CssParameter>
      <CssParameter name="stroke-width">0.15</CssParameter>
      </Stroke>
      </Mark>
      <Size>8</Size>
      </Graphic>
      </PointSymbolizer>
      </Rule>
      </FeatureTypeStyle>
      </UserStyle>
      </NamedLayer>
      </StyledLayerDescriptor>


      I use the following code:



      package com.example.sld;

      import org.geotools.sld.SLDConfiguration;
      import org.geotools.sld.bindings.SLD;
      import org.geotools.styling.StyledLayerDescriptor;
      import org.geotools.xml.Configuration;
      import org.geotools.xml.Encoder;
      import org.geotools.xml.Parser;
      import org.xml.sax.SAXException;

      import javax.xml.parsers.ParserConfigurationException;
      import java.io.IOException;
      import java.io.InputStream;

      public class TestStyle {

      private String style;

      public TestStyle() {

      Configuration config = new SLDConfiguration();
      Parser parser = new Parser(config);

      InputStream is = getClass().getResourceAsStream("test-sld.xml");

      StyledLayerDescriptor sld = null;
      try {
      sld = (StyledLayerDescriptor) parser.parse(is);
      } catch (SAXException e) {
      e.printStackTrace();
      } catch (ParserConfigurationException e) {
      e.printStackTrace();
      } catch (IOException e) {
      e.printStackTrace();
      }

      Configuration configuration = new SLDConfiguration();
      Encoder encoder = new Encoder(configuration);
      encoder.setOmitXMLDeclaration(true);
      try {
      this.style = encoder.encodeAsString(sld, SLD.STYLEDLAYERDESCRIPTOR);
      } catch (IOException e) {
      e.printStackTrace();
      }

      this.style = new String();

      }
      }


      The SLD parses OK. I can inspect its structure in my debugger and it is read correctly. But on encoding, the resultant SLD is empty:



      <sld:StyledLayerDescriptor xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:ogc="http://www.opengis.net/ogc" xmlns:sld="http://www.opengis.net/sld" xmlns:xlink="http://www.w3.org/1999/xlink"/>


      What am I doing wrong?



      (Version of GeoTools is 20.1, following the guide here: http://docs.geotools.org/latest/userguide/library/xml/style.html#encoder)



      Thanks in advance










      share|improve this question














      I'm trying to use GeoTools to write SLDs on the fly for an application I am developing. But try as I might, I can't get the SLDs to be output.



      Starting with an SLD that looks like this:



      <StyledLayerDescriptor xmlns="http://www.opengis.net/sld" version="1.0.0"
      xsi:schemaLocation="http://www.opengis.net/sld http://schemas.opengis.net/sld/1.0.0/StyledLayerDescriptor.xsd"
      xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
      <NamedLayer>
      <Name>named_layer</Name>
      <UserStyle>
      <Name>style</Name>
      <IsDefault>true</IsDefault>
      <FeatureTypeStyle>
      <Rule>
      <PointSymbolizer>
      <Graphic>
      <Mark>
      <WellKnownName>circle</WellKnownName>
      <Fill>
      <CssParameter name="fill">#00aa00</CssParameter>
      </Fill>
      <Stroke>
      <CssParameter name="stroke">#000000</CssParameter>
      <CssParameter name="stroke-width">0.15</CssParameter>
      </Stroke>
      </Mark>
      <Size>8</Size>
      </Graphic>
      </PointSymbolizer>
      </Rule>
      </FeatureTypeStyle>
      </UserStyle>
      </NamedLayer>
      </StyledLayerDescriptor>


      I use the following code:



      package com.example.sld;

      import org.geotools.sld.SLDConfiguration;
      import org.geotools.sld.bindings.SLD;
      import org.geotools.styling.StyledLayerDescriptor;
      import org.geotools.xml.Configuration;
      import org.geotools.xml.Encoder;
      import org.geotools.xml.Parser;
      import org.xml.sax.SAXException;

      import javax.xml.parsers.ParserConfigurationException;
      import java.io.IOException;
      import java.io.InputStream;

      public class TestStyle {

      private String style;

      public TestStyle() {

      Configuration config = new SLDConfiguration();
      Parser parser = new Parser(config);

      InputStream is = getClass().getResourceAsStream("test-sld.xml");

      StyledLayerDescriptor sld = null;
      try {
      sld = (StyledLayerDescriptor) parser.parse(is);
      } catch (SAXException e) {
      e.printStackTrace();
      } catch (ParserConfigurationException e) {
      e.printStackTrace();
      } catch (IOException e) {
      e.printStackTrace();
      }

      Configuration configuration = new SLDConfiguration();
      Encoder encoder = new Encoder(configuration);
      encoder.setOmitXMLDeclaration(true);
      try {
      this.style = encoder.encodeAsString(sld, SLD.STYLEDLAYERDESCRIPTOR);
      } catch (IOException e) {
      e.printStackTrace();
      }

      this.style = new String();

      }
      }


      The SLD parses OK. I can inspect its structure in my debugger and it is read correctly. But on encoding, the resultant SLD is empty:



      <sld:StyledLayerDescriptor xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:ogc="http://www.opengis.net/ogc" xmlns:sld="http://www.opengis.net/sld" xmlns:xlink="http://www.w3.org/1999/xlink"/>


      What am I doing wrong?



      (Version of GeoTools is 20.1, following the guide here: http://docs.geotools.org/latest/userguide/library/xml/style.html#encoder)



      Thanks in advance







      java xml gis geotools sld






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 28 '18 at 6:10









      MichaelMichael

      174




      174
























          1 Answer
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          1














          Your approach would work if you had a version 1.1.0 SLD (or more properly an SE) document, and if you used a import org.geotools.sld.v1_1.SLD object to pass to the encoder. However you have a version 1.0.0 SLD document so you need to use a
          SLDTransformer class to output your style objects. So something like:



          ByteArrayOutputStream bos = new ByteArrayOutputStream();
          SLDTransformer transformer = new SLDTransformer();
          transformer.setIndentation(2);
          transformer.transform(sld, bos);
          String style = bos.toString();
          System.out.println(style);





          share|improve this answer

























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            1 Answer
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            1 Answer
            1






            active

            oldest

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            active

            oldest

            votes






            active

            oldest

            votes









            1














            Your approach would work if you had a version 1.1.0 SLD (or more properly an SE) document, and if you used a import org.geotools.sld.v1_1.SLD object to pass to the encoder. However you have a version 1.0.0 SLD document so you need to use a
            SLDTransformer class to output your style objects. So something like:



            ByteArrayOutputStream bos = new ByteArrayOutputStream();
            SLDTransformer transformer = new SLDTransformer();
            transformer.setIndentation(2);
            transformer.transform(sld, bos);
            String style = bos.toString();
            System.out.println(style);





            share|improve this answer






























              1














              Your approach would work if you had a version 1.1.0 SLD (or more properly an SE) document, and if you used a import org.geotools.sld.v1_1.SLD object to pass to the encoder. However you have a version 1.0.0 SLD document so you need to use a
              SLDTransformer class to output your style objects. So something like:



              ByteArrayOutputStream bos = new ByteArrayOutputStream();
              SLDTransformer transformer = new SLDTransformer();
              transformer.setIndentation(2);
              transformer.transform(sld, bos);
              String style = bos.toString();
              System.out.println(style);





              share|improve this answer




























                1












                1








                1







                Your approach would work if you had a version 1.1.0 SLD (or more properly an SE) document, and if you used a import org.geotools.sld.v1_1.SLD object to pass to the encoder. However you have a version 1.0.0 SLD document so you need to use a
                SLDTransformer class to output your style objects. So something like:



                ByteArrayOutputStream bos = new ByteArrayOutputStream();
                SLDTransformer transformer = new SLDTransformer();
                transformer.setIndentation(2);
                transformer.transform(sld, bos);
                String style = bos.toString();
                System.out.println(style);





                share|improve this answer















                Your approach would work if you had a version 1.1.0 SLD (or more properly an SE) document, and if you used a import org.geotools.sld.v1_1.SLD object to pass to the encoder. However you have a version 1.0.0 SLD document so you need to use a
                SLDTransformer class to output your style objects. So something like:



                ByteArrayOutputStream bos = new ByteArrayOutputStream();
                SLDTransformer transformer = new SLDTransformer();
                transformer.setIndentation(2);
                transformer.transform(sld, bos);
                String style = bos.toString();
                System.out.println(style);






                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited Nov 29 '18 at 9:09

























                answered Nov 29 '18 at 8:48









                Ian TurtonIan Turton

                4,67612036




                4,67612036
































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