How to check if entire string matches regular expression in Javascript?












0















Is there a function in javascript which checks if entire string matches some regular expression



'00'.match(/^0|([1-9][0-9]*)$/g) for example returns ['0']



I know I can simply check if the matched part is equal to the string, but I'm just curious if such function already exists



edit:



'01'.match(/^0|1$/g) returns ['0', '1']
and '01'.match(/^(0|1)$/g) returns null as expected.



I though | has precedence over ^ or $. Can someone explain what /^0|1$/g actually matches?






javascript







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  • 2





    /^0|1$/g matches a 0 at the beginning of the string or a 1 at the end of the string.

    – Donat
    Nov 25 '18 at 22:02


















0















Is there a function in javascript which checks if entire string matches some regular expression



'00'.match(/^0|([1-9][0-9]*)$/g) for example returns ['0']



I know I can simply check if the matched part is equal to the string, but I'm just curious if such function already exists



edit:



'01'.match(/^0|1$/g) returns ['0', '1']
and '01'.match(/^(0|1)$/g) returns null as expected.



I though | has precedence over ^ or $. Can someone explain what /^0|1$/g actually matches?






javascript







share|improve this question




















  • 2





    /^0|1$/g matches a 0 at the beginning of the string or a 1 at the end of the string.

    – Donat
    Nov 25 '18 at 22:02
















0












0








0








Is there a function in javascript which checks if entire string matches some regular expression



'00'.match(/^0|([1-9][0-9]*)$/g) for example returns ['0']



I know I can simply check if the matched part is equal to the string, but I'm just curious if such function already exists



edit:



'01'.match(/^0|1$/g) returns ['0', '1']
and '01'.match(/^(0|1)$/g) returns null as expected.



I though | has precedence over ^ or $. Can someone explain what /^0|1$/g actually matches?






javascript







share|improve this question
















Is there a function in javascript which checks if entire string matches some regular expression



'00'.match(/^0|([1-9][0-9]*)$/g) for example returns ['0']



I know I can simply check if the matched part is equal to the string, but I'm just curious if such function already exists



edit:



'01'.match(/^0|1$/g) returns ['0', '1']
and '01'.match(/^(0|1)$/g) returns null as expected.



I though | has precedence over ^ or $. Can someone explain what /^0|1$/g actually matches?






javascript




javascript






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Dec 8 '18 at 10:35







displayName

















asked Nov 25 '18 at 18:06









displayNamedisplayName

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  • 2





    /^0|1$/g matches a 0 at the beginning of the string or a 1 at the end of the string.

    – Donat
    Nov 25 '18 at 22:02
















  • 2





    /^0|1$/g matches a 0 at the beginning of the string or a 1 at the end of the string.

    – Donat
    Nov 25 '18 at 22:02










2




2





/^0|1$/g matches a 0 at the beginning of the string or a 1 at the end of the string.

– Donat
Nov 25 '18 at 22:02







/^0|1$/g matches a 0 at the beginning of the string or a 1 at the end of the string.

– Donat
Nov 25 '18 at 22:02














1 Answer
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I don't know what you exacty want to achieve. I suppose you want to match eiter zero or a number, not beginning with zero. Then try this:



'00'.match(/^(0|[1-9][0-9]*)$/g)


This does not match '00', but all the other cases.






share|improve this answer

























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    1 Answer
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    active

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    active

    oldest

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    1














    I don't know what you exacty want to achieve. I suppose you want to match eiter zero or a number, not beginning with zero. Then try this:



    '00'.match(/^(0|[1-9][0-9]*)$/g)


    This does not match '00', but all the other cases.






    share|improve this answer






























      1














      I don't know what you exacty want to achieve. I suppose you want to match eiter zero or a number, not beginning with zero. Then try this:



      '00'.match(/^(0|[1-9][0-9]*)$/g)


      This does not match '00', but all the other cases.






      share|improve this answer




























        1












        1








        1







        I don't know what you exacty want to achieve. I suppose you want to match eiter zero or a number, not beginning with zero. Then try this:



        '00'.match(/^(0|[1-9][0-9]*)$/g)


        This does not match '00', but all the other cases.






        share|improve this answer















        I don't know what you exacty want to achieve. I suppose you want to match eiter zero or a number, not beginning with zero. Then try this:



        '00'.match(/^(0|[1-9][0-9]*)$/g)


        This does not match '00', but all the other cases.







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Nov 25 '18 at 21:54

























        answered Nov 25 '18 at 18:16









        DonatDonat

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