Eloquent save() method not working inside for loop












0















I have a table like given below and this table is going to be used for project images.



id: primary key



project_id: a column that has correlation with projects.



order_num: represents image list order for specific project (eg. interior view of project, exterior view of construction project, a different aspect etc...)



+---------+-------------+-----------+
| id | project_id | order_num |
+---------+-------------+-----------+
| 1 | 15 | 0 |
+---------+-------------+-----------+
| 2 | 15 | 0 |
+---------+-------------+-----------+
| 3 | 16 | 0 |
+---------+-------------+-----------+
| 4 | 16 | 0 |
+---------+-------------+-----------+
| 5 | 16 | 0 |
+---------+-------------+-----------+
.
.
.

GOES ON LIKE THIS


What i want to do:

+---------+-------------+-----------+
| id | project_id | order_num |
+---------+-------------+-----------+
| 1 | 15 | 1 |
+---------+-------------+-----------+
| 2 | 15 | 2 |
+---------+-------------+-----------+
| 3 | 16 | 1 |
+---------+-------------+-----------+
| 4 | 16 | 2 |
+---------+-------------+-----------+
| 5 | 16 | 3 |
+---------+-------------+-----------+


I use Slim with Eloquent



I figured out something like this but i got bad method error for save() method.



$find = Images::where('project_id', '=', $project->id)->count();

$img = Images::where('project_id', '=', $project->id);

for ($i = 1; $i <= $find; $i++) {
$img->order_num = $i;
$img->save();
}


Am i doing something wrong? Any help would be very appreciated.



UPDATE [!!] Both answers are give the correct results but according to the odan's information, apokryfos's answer is clean code. Thanks for your all helps.










share|improve this question

























  • is it order_num or order_id you need to change?

    – apokryfos
    Nov 25 '18 at 17:52











  • ahh sorry for writing wrong but problem is not there

    – bgul
    Nov 25 '18 at 17:54













  • Please use the query builder and not this Active Record Antipattern.

    – odan
    Nov 25 '18 at 18:47











  • @odan hi, odan, you mean the each() function given below?

    – bgul
    Nov 26 '18 at 8:36











  • @bgul Yes, in this context, updating multiple records in a loop is a real antipattern.

    – odan
    Nov 26 '18 at 8:38
















0















I have a table like given below and this table is going to be used for project images.



id: primary key



project_id: a column that has correlation with projects.



order_num: represents image list order for specific project (eg. interior view of project, exterior view of construction project, a different aspect etc...)



+---------+-------------+-----------+
| id | project_id | order_num |
+---------+-------------+-----------+
| 1 | 15 | 0 |
+---------+-------------+-----------+
| 2 | 15 | 0 |
+---------+-------------+-----------+
| 3 | 16 | 0 |
+---------+-------------+-----------+
| 4 | 16 | 0 |
+---------+-------------+-----------+
| 5 | 16 | 0 |
+---------+-------------+-----------+
.
.
.

GOES ON LIKE THIS


What i want to do:

+---------+-------------+-----------+
| id | project_id | order_num |
+---------+-------------+-----------+
| 1 | 15 | 1 |
+---------+-------------+-----------+
| 2 | 15 | 2 |
+---------+-------------+-----------+
| 3 | 16 | 1 |
+---------+-------------+-----------+
| 4 | 16 | 2 |
+---------+-------------+-----------+
| 5 | 16 | 3 |
+---------+-------------+-----------+


I use Slim with Eloquent



I figured out something like this but i got bad method error for save() method.



$find = Images::where('project_id', '=', $project->id)->count();

$img = Images::where('project_id', '=', $project->id);

for ($i = 1; $i <= $find; $i++) {
$img->order_num = $i;
$img->save();
}


Am i doing something wrong? Any help would be very appreciated.



UPDATE [!!] Both answers are give the correct results but according to the odan's information, apokryfos's answer is clean code. Thanks for your all helps.










share|improve this question

























  • is it order_num or order_id you need to change?

    – apokryfos
    Nov 25 '18 at 17:52











  • ahh sorry for writing wrong but problem is not there

    – bgul
    Nov 25 '18 at 17:54













  • Please use the query builder and not this Active Record Antipattern.

    – odan
    Nov 25 '18 at 18:47











  • @odan hi, odan, you mean the each() function given below?

    – bgul
    Nov 26 '18 at 8:36











  • @bgul Yes, in this context, updating multiple records in a loop is a real antipattern.

    – odan
    Nov 26 '18 at 8:38














0












0








0








I have a table like given below and this table is going to be used for project images.



id: primary key



project_id: a column that has correlation with projects.



order_num: represents image list order for specific project (eg. interior view of project, exterior view of construction project, a different aspect etc...)



+---------+-------------+-----------+
| id | project_id | order_num |
+---------+-------------+-----------+
| 1 | 15 | 0 |
+---------+-------------+-----------+
| 2 | 15 | 0 |
+---------+-------------+-----------+
| 3 | 16 | 0 |
+---------+-------------+-----------+
| 4 | 16 | 0 |
+---------+-------------+-----------+
| 5 | 16 | 0 |
+---------+-------------+-----------+
.
.
.

GOES ON LIKE THIS


What i want to do:

+---------+-------------+-----------+
| id | project_id | order_num |
+---------+-------------+-----------+
| 1 | 15 | 1 |
+---------+-------------+-----------+
| 2 | 15 | 2 |
+---------+-------------+-----------+
| 3 | 16 | 1 |
+---------+-------------+-----------+
| 4 | 16 | 2 |
+---------+-------------+-----------+
| 5 | 16 | 3 |
+---------+-------------+-----------+


I use Slim with Eloquent



I figured out something like this but i got bad method error for save() method.



$find = Images::where('project_id', '=', $project->id)->count();

$img = Images::where('project_id', '=', $project->id);

for ($i = 1; $i <= $find; $i++) {
$img->order_num = $i;
$img->save();
}


Am i doing something wrong? Any help would be very appreciated.



UPDATE [!!] Both answers are give the correct results but according to the odan's information, apokryfos's answer is clean code. Thanks for your all helps.










share|improve this question
















I have a table like given below and this table is going to be used for project images.



id: primary key



project_id: a column that has correlation with projects.



order_num: represents image list order for specific project (eg. interior view of project, exterior view of construction project, a different aspect etc...)



+---------+-------------+-----------+
| id | project_id | order_num |
+---------+-------------+-----------+
| 1 | 15 | 0 |
+---------+-------------+-----------+
| 2 | 15 | 0 |
+---------+-------------+-----------+
| 3 | 16 | 0 |
+---------+-------------+-----------+
| 4 | 16 | 0 |
+---------+-------------+-----------+
| 5 | 16 | 0 |
+---------+-------------+-----------+
.
.
.

GOES ON LIKE THIS


What i want to do:

+---------+-------------+-----------+
| id | project_id | order_num |
+---------+-------------+-----------+
| 1 | 15 | 1 |
+---------+-------------+-----------+
| 2 | 15 | 2 |
+---------+-------------+-----------+
| 3 | 16 | 1 |
+---------+-------------+-----------+
| 4 | 16 | 2 |
+---------+-------------+-----------+
| 5 | 16 | 3 |
+---------+-------------+-----------+


I use Slim with Eloquent



I figured out something like this but i got bad method error for save() method.



$find = Images::where('project_id', '=', $project->id)->count();

$img = Images::where('project_id', '=', $project->id);

for ($i = 1; $i <= $find; $i++) {
$img->order_num = $i;
$img->save();
}


Am i doing something wrong? Any help would be very appreciated.



UPDATE [!!] Both answers are give the correct results but according to the odan's information, apokryfos's answer is clean code. Thanks for your all helps.







php laravel eloquent slim






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 26 '18 at 8:51







bgul

















asked Nov 25 '18 at 17:51









bgulbgul

144




144













  • is it order_num or order_id you need to change?

    – apokryfos
    Nov 25 '18 at 17:52











  • ahh sorry for writing wrong but problem is not there

    – bgul
    Nov 25 '18 at 17:54













  • Please use the query builder and not this Active Record Antipattern.

    – odan
    Nov 25 '18 at 18:47











  • @odan hi, odan, you mean the each() function given below?

    – bgul
    Nov 26 '18 at 8:36











  • @bgul Yes, in this context, updating multiple records in a loop is a real antipattern.

    – odan
    Nov 26 '18 at 8:38



















  • is it order_num or order_id you need to change?

    – apokryfos
    Nov 25 '18 at 17:52











  • ahh sorry for writing wrong but problem is not there

    – bgul
    Nov 25 '18 at 17:54













  • Please use the query builder and not this Active Record Antipattern.

    – odan
    Nov 25 '18 at 18:47











  • @odan hi, odan, you mean the each() function given below?

    – bgul
    Nov 26 '18 at 8:36











  • @bgul Yes, in this context, updating multiple records in a loop is a real antipattern.

    – odan
    Nov 26 '18 at 8:38

















is it order_num or order_id you need to change?

– apokryfos
Nov 25 '18 at 17:52





is it order_num or order_id you need to change?

– apokryfos
Nov 25 '18 at 17:52













ahh sorry for writing wrong but problem is not there

– bgul
Nov 25 '18 at 17:54







ahh sorry for writing wrong but problem is not there

– bgul
Nov 25 '18 at 17:54















Please use the query builder and not this Active Record Antipattern.

– odan
Nov 25 '18 at 18:47





Please use the query builder and not this Active Record Antipattern.

– odan
Nov 25 '18 at 18:47













@odan hi, odan, you mean the each() function given below?

– bgul
Nov 26 '18 at 8:36





@odan hi, odan, you mean the each() function given below?

– bgul
Nov 26 '18 at 8:36













@bgul Yes, in this context, updating multiple records in a loop is a real antipattern.

– odan
Nov 26 '18 at 8:38





@bgul Yes, in this context, updating multiple records in a loop is a real antipattern.

– odan
Nov 26 '18 at 8:38












2 Answers
2






active

oldest

votes


















0














$img seems to be a query builder object.



If you do $img = Images::where('project_id', '=', $project->id)->get(); you will get everything that needs updading example:



 $index = 1;
Images::where('project_id', '=', $project->id)->get()
->each(function ($img) use (&$index) {
$img->order_num = $index++;
$img->save();
});


This will update all image indices for a single project id. If you want to do all of them then you can do:



 $index = 0;
$lastProjectId = null;
Images::orderBy('project_id')->get()
->each(function ($img) use (&$index, $lastProjectId) {
if ($lastProjectId == null) {
$lastProjectId = $img->project_id;
}
if ($img->project_id != $lastProjectId) {
$index = 1;
$lastProjectId = $img->project_id;
}
$img->order_num = $index++;
$img->save();
});





share|improve this answer
























  • Thanks for your helps @apokryfos. I haven't heard the each() method(I have to do some research about this). Thanks for your additional code for upgrade all values

    – bgul
    Nov 25 '18 at 18:27



















2














try simply this



$imgs = Images::where('project_id', '=', $project->id)->get();
foreach($imgs as $i => $img) {
$img->order_id = $i + 1;
$img->save();
}





share|improve this answer
























  • Thank you very much for your answer. I think the problem is caused by for loop... But this one works perfectly. Thanks again.

    – bgul
    Nov 25 '18 at 18:01











  • you may need to do $img = Images::where('project_id', '=', $project->id)->get()->values() . There's a chance the collection result is keyed by the id.

    – apokryfos
    Nov 25 '18 at 18:01













  • It works well without values(). But i'll keep that in mind thanks for your sharing knowledge. :)

    – bgul
    Nov 25 '18 at 18:10











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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









0














$img seems to be a query builder object.



If you do $img = Images::where('project_id', '=', $project->id)->get(); you will get everything that needs updading example:



 $index = 1;
Images::where('project_id', '=', $project->id)->get()
->each(function ($img) use (&$index) {
$img->order_num = $index++;
$img->save();
});


This will update all image indices for a single project id. If you want to do all of them then you can do:



 $index = 0;
$lastProjectId = null;
Images::orderBy('project_id')->get()
->each(function ($img) use (&$index, $lastProjectId) {
if ($lastProjectId == null) {
$lastProjectId = $img->project_id;
}
if ($img->project_id != $lastProjectId) {
$index = 1;
$lastProjectId = $img->project_id;
}
$img->order_num = $index++;
$img->save();
});





share|improve this answer
























  • Thanks for your helps @apokryfos. I haven't heard the each() method(I have to do some research about this). Thanks for your additional code for upgrade all values

    – bgul
    Nov 25 '18 at 18:27
















0














$img seems to be a query builder object.



If you do $img = Images::where('project_id', '=', $project->id)->get(); you will get everything that needs updading example:



 $index = 1;
Images::where('project_id', '=', $project->id)->get()
->each(function ($img) use (&$index) {
$img->order_num = $index++;
$img->save();
});


This will update all image indices for a single project id. If you want to do all of them then you can do:



 $index = 0;
$lastProjectId = null;
Images::orderBy('project_id')->get()
->each(function ($img) use (&$index, $lastProjectId) {
if ($lastProjectId == null) {
$lastProjectId = $img->project_id;
}
if ($img->project_id != $lastProjectId) {
$index = 1;
$lastProjectId = $img->project_id;
}
$img->order_num = $index++;
$img->save();
});





share|improve this answer
























  • Thanks for your helps @apokryfos. I haven't heard the each() method(I have to do some research about this). Thanks for your additional code for upgrade all values

    – bgul
    Nov 25 '18 at 18:27














0












0








0







$img seems to be a query builder object.



If you do $img = Images::where('project_id', '=', $project->id)->get(); you will get everything that needs updading example:



 $index = 1;
Images::where('project_id', '=', $project->id)->get()
->each(function ($img) use (&$index) {
$img->order_num = $index++;
$img->save();
});


This will update all image indices for a single project id. If you want to do all of them then you can do:



 $index = 0;
$lastProjectId = null;
Images::orderBy('project_id')->get()
->each(function ($img) use (&$index, $lastProjectId) {
if ($lastProjectId == null) {
$lastProjectId = $img->project_id;
}
if ($img->project_id != $lastProjectId) {
$index = 1;
$lastProjectId = $img->project_id;
}
$img->order_num = $index++;
$img->save();
});





share|improve this answer













$img seems to be a query builder object.



If you do $img = Images::where('project_id', '=', $project->id)->get(); you will get everything that needs updading example:



 $index = 1;
Images::where('project_id', '=', $project->id)->get()
->each(function ($img) use (&$index) {
$img->order_num = $index++;
$img->save();
});


This will update all image indices for a single project id. If you want to do all of them then you can do:



 $index = 0;
$lastProjectId = null;
Images::orderBy('project_id')->get()
->each(function ($img) use (&$index, $lastProjectId) {
if ($lastProjectId == null) {
$lastProjectId = $img->project_id;
}
if ($img->project_id != $lastProjectId) {
$index = 1;
$lastProjectId = $img->project_id;
}
$img->order_num = $index++;
$img->save();
});






share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 25 '18 at 18:00









apokryfosapokryfos

18.6k43056




18.6k43056













  • Thanks for your helps @apokryfos. I haven't heard the each() method(I have to do some research about this). Thanks for your additional code for upgrade all values

    – bgul
    Nov 25 '18 at 18:27



















  • Thanks for your helps @apokryfos. I haven't heard the each() method(I have to do some research about this). Thanks for your additional code for upgrade all values

    – bgul
    Nov 25 '18 at 18:27

















Thanks for your helps @apokryfos. I haven't heard the each() method(I have to do some research about this). Thanks for your additional code for upgrade all values

– bgul
Nov 25 '18 at 18:27





Thanks for your helps @apokryfos. I haven't heard the each() method(I have to do some research about this). Thanks for your additional code for upgrade all values

– bgul
Nov 25 '18 at 18:27













2














try simply this



$imgs = Images::where('project_id', '=', $project->id)->get();
foreach($imgs as $i => $img) {
$img->order_id = $i + 1;
$img->save();
}





share|improve this answer
























  • Thank you very much for your answer. I think the problem is caused by for loop... But this one works perfectly. Thanks again.

    – bgul
    Nov 25 '18 at 18:01











  • you may need to do $img = Images::where('project_id', '=', $project->id)->get()->values() . There's a chance the collection result is keyed by the id.

    – apokryfos
    Nov 25 '18 at 18:01













  • It works well without values(). But i'll keep that in mind thanks for your sharing knowledge. :)

    – bgul
    Nov 25 '18 at 18:10
















2














try simply this



$imgs = Images::where('project_id', '=', $project->id)->get();
foreach($imgs as $i => $img) {
$img->order_id = $i + 1;
$img->save();
}





share|improve this answer
























  • Thank you very much for your answer. I think the problem is caused by for loop... But this one works perfectly. Thanks again.

    – bgul
    Nov 25 '18 at 18:01











  • you may need to do $img = Images::where('project_id', '=', $project->id)->get()->values() . There's a chance the collection result is keyed by the id.

    – apokryfos
    Nov 25 '18 at 18:01













  • It works well without values(). But i'll keep that in mind thanks for your sharing knowledge. :)

    – bgul
    Nov 25 '18 at 18:10














2












2








2







try simply this



$imgs = Images::where('project_id', '=', $project->id)->get();
foreach($imgs as $i => $img) {
$img->order_id = $i + 1;
$img->save();
}





share|improve this answer













try simply this



$imgs = Images::where('project_id', '=', $project->id)->get();
foreach($imgs as $i => $img) {
$img->order_id = $i + 1;
$img->save();
}






share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 25 '18 at 17:54









simonecoscisimonecosci

81158




81158













  • Thank you very much for your answer. I think the problem is caused by for loop... But this one works perfectly. Thanks again.

    – bgul
    Nov 25 '18 at 18:01











  • you may need to do $img = Images::where('project_id', '=', $project->id)->get()->values() . There's a chance the collection result is keyed by the id.

    – apokryfos
    Nov 25 '18 at 18:01













  • It works well without values(). But i'll keep that in mind thanks for your sharing knowledge. :)

    – bgul
    Nov 25 '18 at 18:10



















  • Thank you very much for your answer. I think the problem is caused by for loop... But this one works perfectly. Thanks again.

    – bgul
    Nov 25 '18 at 18:01











  • you may need to do $img = Images::where('project_id', '=', $project->id)->get()->values() . There's a chance the collection result is keyed by the id.

    – apokryfos
    Nov 25 '18 at 18:01













  • It works well without values(). But i'll keep that in mind thanks for your sharing knowledge. :)

    – bgul
    Nov 25 '18 at 18:10

















Thank you very much for your answer. I think the problem is caused by for loop... But this one works perfectly. Thanks again.

– bgul
Nov 25 '18 at 18:01





Thank you very much for your answer. I think the problem is caused by for loop... But this one works perfectly. Thanks again.

– bgul
Nov 25 '18 at 18:01













you may need to do $img = Images::where('project_id', '=', $project->id)->get()->values() . There's a chance the collection result is keyed by the id.

– apokryfos
Nov 25 '18 at 18:01







you may need to do $img = Images::where('project_id', '=', $project->id)->get()->values() . There's a chance the collection result is keyed by the id.

– apokryfos
Nov 25 '18 at 18:01















It works well without values(). But i'll keep that in mind thanks for your sharing knowledge. :)

– bgul
Nov 25 '18 at 18:10





It works well without values(). But i'll keep that in mind thanks for your sharing knowledge. :)

– bgul
Nov 25 '18 at 18:10


















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