Declare variable to function without running it
0
def user(choose):
if (choose == "1"):
play = game()
elif (choose == "2"):
return stats(play)
else:
return quit()
I want to take the value from function game() and use it in stats(), but I get an error saying that play is not defined. How do I declare game() and use it in another function?
python python-3.x
asked Nov 25 '18 at 18:05
GringoGringo
137
add a comment |
0
def user(choose):
if (choose == "1"):
play = game()
elif (choose == "2"):
return stats(play)
else:
return quit()
I want to take the value from function game() and use it in stats(), but I get an error saying that play is not defined. How do I declare game() and use it in another function?
python python-3.x
asked Nov 25 '18 at 18:05
GringoGringo
137
2
What do you mean? If you don't run the function it can't return anything... (or do anything for that matter)
– Jon Clements♦
Nov 25 '18 at 18:09
a function "runs". That's its job. you want a function that knows what to return but skips over all the lines before returning a value? That is....strange, and very...unfunctionlike. what is the point of "code" in function1 then? Can it even be done? No, a function will evaluate things and cannot return results until it runs.
– Paritosh Singh
Nov 25 '18 at 18:09
1
Check if this is not a so called XY Problem . What are you actually trying to do?
– Paritosh Singh
Nov 25 '18 at 18:10
I was not clear. I've updated the post
– Gringo
Nov 25 '18 at 18:18
1
Hi Gringo, when you fix your questions, try to keep as much as possible from original, just keep adding "clarifications". Otherwise comments/answers for future readers look really strange.
– vav
Nov 25 '18 at 18:36
add a comment |
0
0
0
def user(choose):
if (choose == "1"):
play = game()
elif (choose == "2"):
return stats(play)
else:
return quit()
I want to take the value from function game() and use it in stats(), but I get an error saying that play is not defined. How do I declare game() and use it in another function?
python python-3.x
asked Nov 25 '18 at 18:05
GringoGringo
137
def user(choose):
if (choose == "1"):
play = game()
elif (choose == "2"):
return stats(play)
else:
return quit()
I want to take the value from function game() and use it in stats(), but I get an error saying that play is not defined. How do I declare game() and use it in another function?
python python-3.x
python python-3.x
asked Nov 25 '18 at 18:05
GringoGringo
137
asked Nov 25 '18 at 18:05
GringoGringo
137
edited Nov 25 '18 at 18:17
Gringo
asked Nov 25 '18 at 18:05
GringoGringo
137
asked Nov 25 '18 at 18:05
GringoGringo
137
asked Nov 25 '18 at 18:05
GringoGringo
137
137
2
What do you mean? If you don't run the function it can't return anything... (or do anything for that matter)
– Jon Clements♦
Nov 25 '18 at 18:09
a function "runs". That's its job. you want a function that knows what to return but skips over all the lines before returning a value? That is....strange, and very...unfunctionlike. what is the point of "code" in function1 then? Can it even be done? No, a function will evaluate things and cannot return results until it runs.
– Paritosh Singh
Nov 25 '18 at 18:09
1
Check if this is not a so called XY Problem . What are you actually trying to do?
– Paritosh Singh
Nov 25 '18 at 18:10
I was not clear. I've updated the post
– Gringo
Nov 25 '18 at 18:18
1
Hi Gringo, when you fix your questions, try to keep as much as possible from original, just keep adding "clarifications". Otherwise comments/answers for future readers look really strange.
– vav
Nov 25 '18 at 18:36
add a comment |
2
What do you mean? If you don't run the function it can't return anything... (or do anything for that matter)
– Jon Clements♦
Nov 25 '18 at 18:09
a function "runs". That's its job. you want a function that knows what to return but skips over all the lines before returning a value? That is....strange, and very...unfunctionlike. what is the point of "code" in function1 then? Can it even be done? No, a function will evaluate things and cannot return results until it runs.
– Paritosh Singh
Nov 25 '18 at 18:09
1
Check if this is not a so called XY Problem . What are you actually trying to do?
– Paritosh Singh
Nov 25 '18 at 18:10
I was not clear. I've updated the post
– Gringo
Nov 25 '18 at 18:18
1
Hi Gringo, when you fix your questions, try to keep as much as possible from original, just keep adding "clarifications". Otherwise comments/answers for future readers look really strange.
– vav
Nov 25 '18 at 18:36
2
2
What do you mean? If you don't run the function it can't return anything... (or do anything for that matter)
– Jon Clements♦
Nov 25 '18 at 18:09
What do you mean? If you don't run the function it can't return anything... (or do anything for that matter)
– Jon Clements♦
Nov 25 '18 at 18:09
a function "runs". That's its job. you want a function that knows what to return but skips over all the lines before returning a value? That is....strange, and very...unfunctionlike. what is the point of "code" in function1 then? Can it even be done? No, a function will evaluate things and cannot return results until it runs.
– Paritosh Singh
Nov 25 '18 at 18:09
a function "runs". That's its job. you want a function that knows what to return but skips over all the lines before returning a value? That is....strange, and very...unfunctionlike. what is the point of "code" in function1 then? Can it even be done? No, a function will evaluate things and cannot return results until it runs.
– Paritosh Singh
Nov 25 '18 at 18:09
1
1
Check if this is not a so called XY Problem . What are you actually trying to do?
– Paritosh Singh
Nov 25 '18 at 18:10
Check if this is not a so called XY Problem . What are you actually trying to do?
– Paritosh Singh
Nov 25 '18 at 18:10
I was not clear. I've updated the post
– Gringo
Nov 25 '18 at 18:18
I was not clear. I've updated the post
– Gringo
Nov 25 '18 at 18:18
1
1
Hi Gringo, when you fix your questions, try to keep as much as possible from original, just keep adding "clarifications". Otherwise comments/answers for future readers look really strange.
– vav
Nov 25 '18 at 18:36
Hi Gringo, when you fix your questions, try to keep as much as possible from original, just keep adding "clarifications". Otherwise comments/answers for future readers look really strange.
– vav
Nov 25 '18 at 18:36
add a comment |
1 Answer
1
active
oldest
votes
1
You could "postpone" execution of func1:
def func1():
return 'abc'
def something_else(callable):
callable()
def main():
hello = None
def f():
"""set result of func1 to variable hello"""
nonlocal hello
hello = func1()
# over here func1 is not executed yet, hello have not got its value
# you could pass function f to some other code and when it is executed,
# it would set result for hello
print(str(hello)) # would print "None"
call_something_else(f)
print(str(hello)) # would print "abc"
main()
After question has changed...
Right now, your local variable play is out of scope for stats.
Also, looks like you expect that function would be called twice.
You need to save play in global content
play = None # let's set it to some default value
def user(choose):
global play # let python know, that it is not local variable
if choose == "1": # no need for extra brackets
play = game()
if choose == "2" and play: # double check that play is set
return stats(play)
return quit()
answered Nov 25 '18 at 18:23
vavvav
3,39911130
add a comment |
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1 Answer
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votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
You could "postpone" execution of func1:
def func1():
return 'abc'
def something_else(callable):
callable()
def main():
hello = None
def f():
"""set result of func1 to variable hello"""
nonlocal hello
hello = func1()
# over here func1 is not executed yet, hello have not got its value
# you could pass function f to some other code and when it is executed,
# it would set result for hello
print(str(hello)) # would print "None"
call_something_else(f)
print(str(hello)) # would print "abc"
main()
After question has changed...
Right now, your local variable play is out of scope for stats.
Also, looks like you expect that function would be called twice.
You need to save play in global content
play = None # let's set it to some default value
def user(choose):
global play # let python know, that it is not local variable
if choose == "1": # no need for extra brackets
play = game()
if choose == "2" and play: # double check that play is set
return stats(play)
return quit()
answered Nov 25 '18 at 18:23
vavvav
3,39911130
add a comment |
1
You could "postpone" execution of func1:
def func1():
return 'abc'
def something_else(callable):
callable()
def main():
hello = None
def f():
"""set result of func1 to variable hello"""
nonlocal hello
hello = func1()
# over here func1 is not executed yet, hello have not got its value
# you could pass function f to some other code and when it is executed,
# it would set result for hello
print(str(hello)) # would print "None"
call_something_else(f)
print(str(hello)) # would print "abc"
main()
After question has changed...
Right now, your local variable play is out of scope for stats.
Also, looks like you expect that function would be called twice.
You need to save play in global content
play = None # let's set it to some default value
def user(choose):
global play # let python know, that it is not local variable
if choose == "1": # no need for extra brackets
play = game()
if choose == "2" and play: # double check that play is set
return stats(play)
return quit()
answered Nov 25 '18 at 18:23
vavvav
3,39911130
add a comment |
1
1
1
You could "postpone" execution of func1:
def func1():
return 'abc'
def something_else(callable):
callable()
def main():
hello = None
def f():
"""set result of func1 to variable hello"""
nonlocal hello
hello = func1()
# over here func1 is not executed yet, hello have not got its value
# you could pass function f to some other code and when it is executed,
# it would set result for hello
print(str(hello)) # would print "None"
call_something_else(f)
print(str(hello)) # would print "abc"
main()
After question has changed...
Right now, your local variable play is out of scope for stats.
Also, looks like you expect that function would be called twice.
You need to save play in global content
play = None # let's set it to some default value
def user(choose):
global play # let python know, that it is not local variable
if choose == "1": # no need for extra brackets
play = game()
if choose == "2" and play: # double check that play is set
return stats(play)
return quit()
answered Nov 25 '18 at 18:23
vavvav
3,39911130
You could "postpone" execution of func1:
def func1():
return 'abc'
def something_else(callable):
callable()
def main():
hello = None
def f():
"""set result of func1 to variable hello"""
nonlocal hello
hello = func1()
# over here func1 is not executed yet, hello have not got its value
# you could pass function f to some other code and when it is executed,
# it would set result for hello
print(str(hello)) # would print "None"
call_something_else(f)
print(str(hello)) # would print "abc"
main()
After question has changed...
Right now, your local variable play is out of scope for stats.
Also, looks like you expect that function would be called twice.
You need to save play in global content
play = None # let's set it to some default value
def user(choose):
global play # let python know, that it is not local variable
if choose == "1": # no need for extra brackets
play = game()
if choose == "2" and play: # double check that play is set
return stats(play)
return quit()
answered Nov 25 '18 at 18:23
vavvav
3,39911130
edited Nov 25 '18 at 18:29
answered Nov 25 '18 at 18:23
vavvav
3,39911130
answered Nov 25 '18 at 18:23
vavvav
3,39911130
answered Nov 25 '18 at 18:23
vavvav
3,39911130
3,39911130
add a comment |
add a comment |
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2
What do you mean? If you don't run the function it can't return anything... (or do anything for that matter)
– Jon Clements♦
Nov 25 '18 at 18:09
a function "runs". That's its job. you want a function that knows what to return but skips over all the lines before returning a value? That is....strange, and very...unfunctionlike. what is the point of "code" in function1 then? Can it even be done? No, a function will evaluate things and cannot return results until it runs.
– Paritosh Singh
Nov 25 '18 at 18:09
1
Check if this is not a so called XY Problem . What are you actually trying to do?
– Paritosh Singh
Nov 25 '18 at 18:10
I was not clear. I've updated the post
– Gringo
Nov 25 '18 at 18:18
1
Hi Gringo, when you fix your questions, try to keep as much as possible from original, just keep adding "clarifications". Otherwise comments/answers for future readers look really strange.
– vav
Nov 25 '18 at 18:36