Extract JSON object's values as array from MySQL JSON column
4
I have a MySQL column of json type. In there, a dict like JSON object is stored. Now, I want to extract the values from this JSON object and create a JSON array.
How can I achieve this?
Example Query
with json_objs(json_col) as (
select CAST('{"key1": "value1", "key2": "value2"}' AS JSON)
UNION ALL
select CAST('{"key3": "value3", "key4": "value4"}' AS JSON)
)
select SOME_EXPR_I_CAN_T_FIGURE_OUT from json_objs
Expected result
+----------------------+
| resulting_column |
+----------------------+
| ["value1", "value2"] |
| ["value3", "value4"] |
+----------------------+
(If table DDL is desired:)
CREATE TABLE `json_objs` (
`json_col` json DEFAULT NULL
) ENGINE=InnoDB DEFAULT CHARSET=utf8
mysql arrays json json-extract
edited Nov 28 '18 at 10:13
marekful
10.1k42143
asked Nov 28 '18 at 9:29
Yuki InoueYuki Inoue
53211026
add a comment |
4
I have a MySQL column of json type. In there, a dict like JSON object is stored. Now, I want to extract the values from this JSON object and create a JSON array.
How can I achieve this?
Example Query
with json_objs(json_col) as (
select CAST('{"key1": "value1", "key2": "value2"}' AS JSON)
UNION ALL
select CAST('{"key3": "value3", "key4": "value4"}' AS JSON)
)
select SOME_EXPR_I_CAN_T_FIGURE_OUT from json_objs
Expected result
+----------------------+
| resulting_column |
+----------------------+
| ["value1", "value2"] |
| ["value3", "value4"] |
+----------------------+
(If table DDL is desired:)
CREATE TABLE `json_objs` (
`json_col` json DEFAULT NULL
) ENGINE=InnoDB DEFAULT CHARSET=utf8
mysql arrays json json-extract
edited Nov 28 '18 at 10:13
marekful
10.1k42143
asked Nov 28 '18 at 9:29
Yuki InoueYuki Inoue
53211026
Does mysqlserverteam.com/mysql-8-0-labs-json-aggregation-functions help?
– Nico Haase
Nov 28 '18 at 9:39
Can you post the SHOW CREATE TABLE result?
– marekful
Nov 28 '18 at 9:44
Are your key names all different or repeating?
– marekful
Nov 28 '18 at 9:54
add a comment |
4
4
4
I have a MySQL column of json type. In there, a dict like JSON object is stored. Now, I want to extract the values from this JSON object and create a JSON array.
How can I achieve this?
Example Query
with json_objs(json_col) as (
select CAST('{"key1": "value1", "key2": "value2"}' AS JSON)
UNION ALL
select CAST('{"key3": "value3", "key4": "value4"}' AS JSON)
)
select SOME_EXPR_I_CAN_T_FIGURE_OUT from json_objs
Expected result
+----------------------+
| resulting_column |
+----------------------+
| ["value1", "value2"] |
| ["value3", "value4"] |
+----------------------+
(If table DDL is desired:)
CREATE TABLE `json_objs` (
`json_col` json DEFAULT NULL
) ENGINE=InnoDB DEFAULT CHARSET=utf8
mysql arrays json json-extract
edited Nov 28 '18 at 10:13
marekful
10.1k42143
asked Nov 28 '18 at 9:29
Yuki InoueYuki Inoue
53211026
I have a MySQL column of json type. In there, a dict like JSON object is stored. Now, I want to extract the values from this JSON object and create a JSON array.
How can I achieve this?
Example Query
with json_objs(json_col) as (
select CAST('{"key1": "value1", "key2": "value2"}' AS JSON)
UNION ALL
select CAST('{"key3": "value3", "key4": "value4"}' AS JSON)
)
select SOME_EXPR_I_CAN_T_FIGURE_OUT from json_objs
Expected result
+----------------------+
| resulting_column |
+----------------------+
| ["value1", "value2"] |
| ["value3", "value4"] |
+----------------------+
(If table DDL is desired:)
CREATE TABLE `json_objs` (
`json_col` json DEFAULT NULL
) ENGINE=InnoDB DEFAULT CHARSET=utf8
mysql arrays json json-extract
mysql arrays json json-extract
edited Nov 28 '18 at 10:13
marekful
10.1k42143
asked Nov 28 '18 at 9:29
Yuki InoueYuki Inoue
53211026
edited Nov 28 '18 at 10:13
marekful
10.1k42143
asked Nov 28 '18 at 9:29
Yuki InoueYuki Inoue
53211026
edited Nov 28 '18 at 10:13
marekful
10.1k42143
edited Nov 28 '18 at 10:13
marekful
10.1k42143
edited Nov 28 '18 at 10:13
marekful
10.1k42143
10.1k42143
asked Nov 28 '18 at 9:29
Yuki InoueYuki Inoue
53211026
asked Nov 28 '18 at 9:29
Yuki InoueYuki Inoue
53211026
asked Nov 28 '18 at 9:29
Yuki InoueYuki Inoue
53211026
53211026
Does mysqlserverteam.com/mysql-8-0-labs-json-aggregation-functions help?
– Nico Haase
Nov 28 '18 at 9:39
Can you post the SHOW CREATE TABLE result?
– marekful
Nov 28 '18 at 9:44
Are your key names all different or repeating?
– marekful
Nov 28 '18 at 9:54
add a comment |
Does mysqlserverteam.com/mysql-8-0-labs-json-aggregation-functions help?
– Nico Haase
Nov 28 '18 at 9:39
Can you post the SHOW CREATE TABLE result?
– marekful
Nov 28 '18 at 9:44
Are your key names all different or repeating?
– marekful
Nov 28 '18 at 9:54
Does mysqlserverteam.com/mysql-8-0-labs-json-aggregation-functions help?
– Nico Haase
Nov 28 '18 at 9:39
Does mysqlserverteam.com/mysql-8-0-labs-json-aggregation-functions help?
– Nico Haase
Nov 28 '18 at 9:39
Can you post the SHOW CREATE TABLE result?
– marekful
Nov 28 '18 at 9:44
Can you post the SHOW CREATE TABLE result?
– marekful
Nov 28 '18 at 9:44
Are your key names all different or repeating?
– marekful
Nov 28 '18 at 9:54
Are your key names all different or repeating?
– marekful
Nov 28 '18 at 9:54
add a comment |
2 Answers
2
active
oldest
votes
2
You can use the -> operator as in the expression column -> path as follows:
create table table1 (
json_dict JSON
);
insert into table1 values('{"ak":"av","bk":"bv"}');
insert into table1 values('{"ak2":"av2","bk2":"bv2"}');
select * from table1;
+------------------------------+
| json_dict |
+------------------------------+
| {"ak": "av", "bk": "bv"} |
| {"ak2": "av2", "bk2": "bv2"} |
+------------------------------+
2 rows in set (0.00 sec)
select json_dict->"$.*" from table1;
+------------------+
| json_dict->"$.*" |
+------------------+
| ["av", "bv"] |
| ["av2", "bv2"] |
+------------------+
2 rows in set (0.00 sec)
https://dev.mysql.com/doc/refman/8.0/en/json-search-functions.html#operator_json-column-path
answered Nov 28 '18 at 10:03
marekfulmarekful
10.1k42143
1
Thanks for the fiddle. also +1 to answer :)
– Madhur Bhaiya
Nov 28 '18 at 10:12
add a comment |
1
Other than -> operator, you can also use the Json_Extract() function:
Schema (MySQL v8.0)
create table table1 (
json_dict JSON
);
insert into table1 values('{"ak":"av","bk":"bv"}');
insert into table1 values('{"ak2":"av2","bk2":"bv2"}');
Query #1
select JSON_EXTRACT(json_dict, '$.*') from table1;
| JSON_EXTRACT(json_dict, '$.*') |
| ------------------------------ |
| ["av", "bv"] |
| ["av2", "bv2"] |
View on DB Fiddle
answered Nov 28 '18 at 10:07
Madhur BhaiyaMadhur Bhaiya
19.6k62236
I was faster and you copied code from my answer. However, I upvoted yours because you showed a slightly different alternative :)
– marekful
Nov 28 '18 at 10:10
@marekful Thanks for the fiddle. I was lazy to create a fiddle; so pouched on your fiddle :P
– Madhur Bhaiya
Nov 28 '18 at 10:11
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
2
You can use the -> operator as in the expression column -> path as follows:
create table table1 (
json_dict JSON
);
insert into table1 values('{"ak":"av","bk":"bv"}');
insert into table1 values('{"ak2":"av2","bk2":"bv2"}');
select * from table1;
+------------------------------+
| json_dict |
+------------------------------+
| {"ak": "av", "bk": "bv"} |
| {"ak2": "av2", "bk2": "bv2"} |
+------------------------------+
2 rows in set (0.00 sec)
select json_dict->"$.*" from table1;
+------------------+
| json_dict->"$.*" |
+------------------+
| ["av", "bv"] |
| ["av2", "bv2"] |
+------------------+
2 rows in set (0.00 sec)
https://dev.mysql.com/doc/refman/8.0/en/json-search-functions.html#operator_json-column-path
answered Nov 28 '18 at 10:03
marekfulmarekful
10.1k42143
1
Thanks for the fiddle. also +1 to answer :)
– Madhur Bhaiya
Nov 28 '18 at 10:12
add a comment |
2
You can use the -> operator as in the expression column -> path as follows:
create table table1 (
json_dict JSON
);
insert into table1 values('{"ak":"av","bk":"bv"}');
insert into table1 values('{"ak2":"av2","bk2":"bv2"}');
select * from table1;
+------------------------------+
| json_dict |
+------------------------------+
| {"ak": "av", "bk": "bv"} |
| {"ak2": "av2", "bk2": "bv2"} |
+------------------------------+
2 rows in set (0.00 sec)
select json_dict->"$.*" from table1;
+------------------+
| json_dict->"$.*" |
+------------------+
| ["av", "bv"] |
| ["av2", "bv2"] |
+------------------+
2 rows in set (0.00 sec)
https://dev.mysql.com/doc/refman/8.0/en/json-search-functions.html#operator_json-column-path
answered Nov 28 '18 at 10:03
marekfulmarekful
10.1k42143
1
Thanks for the fiddle. also +1 to answer :)
– Madhur Bhaiya
Nov 28 '18 at 10:12
add a comment |
2
2
2
You can use the -> operator as in the expression column -> path as follows:
create table table1 (
json_dict JSON
);
insert into table1 values('{"ak":"av","bk":"bv"}');
insert into table1 values('{"ak2":"av2","bk2":"bv2"}');
select * from table1;
+------------------------------+
| json_dict |
+------------------------------+
| {"ak": "av", "bk": "bv"} |
| {"ak2": "av2", "bk2": "bv2"} |
+------------------------------+
2 rows in set (0.00 sec)
select json_dict->"$.*" from table1;
+------------------+
| json_dict->"$.*" |
+------------------+
| ["av", "bv"] |
| ["av2", "bv2"] |
+------------------+
2 rows in set (0.00 sec)
https://dev.mysql.com/doc/refman/8.0/en/json-search-functions.html#operator_json-column-path
answered Nov 28 '18 at 10:03
marekfulmarekful
10.1k42143
You can use the -> operator as in the expression column -> path as follows:
create table table1 (
json_dict JSON
);
insert into table1 values('{"ak":"av","bk":"bv"}');
insert into table1 values('{"ak2":"av2","bk2":"bv2"}');
select * from table1;
+------------------------------+
| json_dict |
+------------------------------+
| {"ak": "av", "bk": "bv"} |
| {"ak2": "av2", "bk2": "bv2"} |
+------------------------------+
2 rows in set (0.00 sec)
select json_dict->"$.*" from table1;
+------------------+
| json_dict->"$.*" |
+------------------+
| ["av", "bv"] |
| ["av2", "bv2"] |
+------------------+
2 rows in set (0.00 sec)
https://dev.mysql.com/doc/refman/8.0/en/json-search-functions.html#operator_json-column-path
answered Nov 28 '18 at 10:03
marekfulmarekful
10.1k42143
answered Nov 28 '18 at 10:03
marekfulmarekful
10.1k42143
answered Nov 28 '18 at 10:03
marekfulmarekful
10.1k42143
answered Nov 28 '18 at 10:03
marekfulmarekful
10.1k42143
10.1k42143
1
Thanks for the fiddle. also +1 to answer :)
– Madhur Bhaiya
Nov 28 '18 at 10:12
add a comment |
1
Thanks for the fiddle. also +1 to answer :)
– Madhur Bhaiya
Nov 28 '18 at 10:12
1
1
Thanks for the fiddle. also +1 to answer :)
– Madhur Bhaiya
Nov 28 '18 at 10:12
Thanks for the fiddle. also +1 to answer :)
– Madhur Bhaiya
Nov 28 '18 at 10:12
add a comment |
1
Other than -> operator, you can also use the Json_Extract() function:
Schema (MySQL v8.0)
create table table1 (
json_dict JSON
);
insert into table1 values('{"ak":"av","bk":"bv"}');
insert into table1 values('{"ak2":"av2","bk2":"bv2"}');
Query #1
select JSON_EXTRACT(json_dict, '$.*') from table1;
| JSON_EXTRACT(json_dict, '$.*') |
| ------------------------------ |
| ["av", "bv"] |
| ["av2", "bv2"] |
View on DB Fiddle
answered Nov 28 '18 at 10:07
Madhur BhaiyaMadhur Bhaiya
19.6k62236
I was faster and you copied code from my answer. However, I upvoted yours because you showed a slightly different alternative :)
– marekful
Nov 28 '18 at 10:10
@marekful Thanks for the fiddle. I was lazy to create a fiddle; so pouched on your fiddle :P
– Madhur Bhaiya
Nov 28 '18 at 10:11
add a comment |
1
Other than -> operator, you can also use the Json_Extract() function:
Schema (MySQL v8.0)
create table table1 (
json_dict JSON
);
insert into table1 values('{"ak":"av","bk":"bv"}');
insert into table1 values('{"ak2":"av2","bk2":"bv2"}');
Query #1
select JSON_EXTRACT(json_dict, '$.*') from table1;
| JSON_EXTRACT(json_dict, '$.*') |
| ------------------------------ |
| ["av", "bv"] |
| ["av2", "bv2"] |
View on DB Fiddle
answered Nov 28 '18 at 10:07
Madhur BhaiyaMadhur Bhaiya
19.6k62236
I was faster and you copied code from my answer. However, I upvoted yours because you showed a slightly different alternative :)
– marekful
Nov 28 '18 at 10:10
@marekful Thanks for the fiddle. I was lazy to create a fiddle; so pouched on your fiddle :P
– Madhur Bhaiya
Nov 28 '18 at 10:11
add a comment |
1
1
1
Other than -> operator, you can also use the Json_Extract() function:
Schema (MySQL v8.0)
create table table1 (
json_dict JSON
);
insert into table1 values('{"ak":"av","bk":"bv"}');
insert into table1 values('{"ak2":"av2","bk2":"bv2"}');
Query #1
select JSON_EXTRACT(json_dict, '$.*') from table1;
| JSON_EXTRACT(json_dict, '$.*') |
| ------------------------------ |
| ["av", "bv"] |
| ["av2", "bv2"] |
View on DB Fiddle
answered Nov 28 '18 at 10:07
Madhur BhaiyaMadhur Bhaiya
19.6k62236
Other than -> operator, you can also use the Json_Extract() function:
Schema (MySQL v8.0)
create table table1 (
json_dict JSON
);
insert into table1 values('{"ak":"av","bk":"bv"}');
insert into table1 values('{"ak2":"av2","bk2":"bv2"}');
Query #1
select JSON_EXTRACT(json_dict, '$.*') from table1;
| JSON_EXTRACT(json_dict, '$.*') |
| ------------------------------ |
| ["av", "bv"] |
| ["av2", "bv2"] |
View on DB Fiddle
answered Nov 28 '18 at 10:07
Madhur BhaiyaMadhur Bhaiya
19.6k62236
answered Nov 28 '18 at 10:07
Madhur BhaiyaMadhur Bhaiya
19.6k62236
answered Nov 28 '18 at 10:07
Madhur BhaiyaMadhur Bhaiya
19.6k62236
answered Nov 28 '18 at 10:07
Madhur BhaiyaMadhur Bhaiya
19.6k62236
19.6k62236
I was faster and you copied code from my answer. However, I upvoted yours because you showed a slightly different alternative :)
– marekful
Nov 28 '18 at 10:10
@marekful Thanks for the fiddle. I was lazy to create a fiddle; so pouched on your fiddle :P
– Madhur Bhaiya
Nov 28 '18 at 10:11
add a comment |
I was faster and you copied code from my answer. However, I upvoted yours because you showed a slightly different alternative :)
– marekful
Nov 28 '18 at 10:10
@marekful Thanks for the fiddle. I was lazy to create a fiddle; so pouched on your fiddle :P
– Madhur Bhaiya
Nov 28 '18 at 10:11
I was faster and you copied code from my answer. However, I upvoted yours because you showed a slightly different alternative :)
– marekful
Nov 28 '18 at 10:10
I was faster and you copied code from my answer. However, I upvoted yours because you showed a slightly different alternative :)
– marekful
Nov 28 '18 at 10:10
@marekful Thanks for the fiddle. I was lazy to create a fiddle; so pouched on your fiddle :P
– Madhur Bhaiya
Nov 28 '18 at 10:11
@marekful Thanks for the fiddle. I was lazy to create a fiddle; so pouched on your fiddle :P
– Madhur Bhaiya
Nov 28 '18 at 10:11
add a comment |
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Does mysqlserverteam.com/mysql-8-0-labs-json-aggregation-functions help?
– Nico Haase
Nov 28 '18 at 9:39
Can you post the SHOW CREATE TABLE result?
– marekful
Nov 28 '18 at 9:44
Are your key names all different or repeating?
– marekful
Nov 28 '18 at 9:54