C# - YAXLib: “No elements with this name found:”
1
I have two classes that are used for de/serializing an XML file.
XmlExampleBasicUnit.cs:
[YAXSerializeAs("Unit")]
public class XmlExampleBasicUnit
{
[YAXSerializeAs("StringVar")]
public String StringVar { get; set; }
[YAXSerializeAs("Int32Var")]
public Int32 Int32Var { get; set; }
[YAXSerializeAs("DoubleVar")]
public Double DoubleVar { get; set; }
[YAXSerializeAs("DateTimeVar")]
public String DateTimeVar { get; set; }
[YAXSerializeAs("CharVar")]
public String CharVar { get; set; }
}
XmlExampleCollectionOfUnits.cs:
[YAXSerializeAs("CollectionOfUnits")]
public class XmlExampleCollectionOfUnits
{
[YAXSerializeAs("Units")]
public List<XmlExampleBasicUnit> Units { get; set; }
public XmlExampleCollectionOfUnits(List<XmlExampleBasicUnit> units)
{
Units = units;
}
public XmlExampleCollectionOfUnits()
{
}
}
I'm trying to deserialize this file:
<?xml version="1.0" encoding="utf-8"?>
<CollectionOfUnits>
<Units>
<Unit>
<StringVar>TohleJeString</StringVar>
<Int32Var>24</Int32Var>
<DoubleVar>29.6</DoubleVar>
<DateTimeVar>17.11.1968</DateTimeVar>
<CharVar>c</CharVar>
</Unit>
<Unit>
<StringVar>TohleJeTakéString</StringVar>
<Int32Var>17</Int32Var>
<DoubleVar>5.9</DoubleVar>
<DateTimeVar>06.07.1415</DateTimeVar>
<CharVar>p</CharVar>
</Unit>
<Unit>
<StringVar>NoATohleTaké</StringVar>
<Int32Var>2</Int32Var>
<DoubleVar>78.5</DoubleVar>
<DateTimeVar>06.12.1774</DateTimeVar>
<CharVar>x</CharVar>
</Unit>
</Units>
It's all handled by this function:
public T Import<T>(String fileName) where T : class
{
YAXSerializer serializer = new YAXSerializer(typeof(T));
return (T)serializer.Deserialize(fileName);
}
When I run the code I get following error: No elements with this name found: './Units'. As you can see there already is an element called Units.
c# xml xml-serialization yaxlib
asked Nov 28 '18 at 10:20
ChyuChyu
157317
|
show 5 more comments
1
I have two classes that are used for de/serializing an XML file.
XmlExampleBasicUnit.cs:
[YAXSerializeAs("Unit")]
public class XmlExampleBasicUnit
{
[YAXSerializeAs("StringVar")]
public String StringVar { get; set; }
[YAXSerializeAs("Int32Var")]
public Int32 Int32Var { get; set; }
[YAXSerializeAs("DoubleVar")]
public Double DoubleVar { get; set; }
[YAXSerializeAs("DateTimeVar")]
public String DateTimeVar { get; set; }
[YAXSerializeAs("CharVar")]
public String CharVar { get; set; }
}
XmlExampleCollectionOfUnits.cs:
[YAXSerializeAs("CollectionOfUnits")]
public class XmlExampleCollectionOfUnits
{
[YAXSerializeAs("Units")]
public List<XmlExampleBasicUnit> Units { get; set; }
public XmlExampleCollectionOfUnits(List<XmlExampleBasicUnit> units)
{
Units = units;
}
public XmlExampleCollectionOfUnits()
{
}
}
I'm trying to deserialize this file:
<?xml version="1.0" encoding="utf-8"?>
<CollectionOfUnits>
<Units>
<Unit>
<StringVar>TohleJeString</StringVar>
<Int32Var>24</Int32Var>
<DoubleVar>29.6</DoubleVar>
<DateTimeVar>17.11.1968</DateTimeVar>
<CharVar>c</CharVar>
</Unit>
<Unit>
<StringVar>TohleJeTakéString</StringVar>
<Int32Var>17</Int32Var>
<DoubleVar>5.9</DoubleVar>
<DateTimeVar>06.07.1415</DateTimeVar>
<CharVar>p</CharVar>
</Unit>
<Unit>
<StringVar>NoATohleTaké</StringVar>
<Int32Var>2</Int32Var>
<DoubleVar>78.5</DoubleVar>
<DateTimeVar>06.12.1774</DateTimeVar>
<CharVar>x</CharVar>
</Unit>
</Units>
It's all handled by this function:
public T Import<T>(String fileName) where T : class
{
YAXSerializer serializer = new YAXSerializer(typeof(T));
return (T)serializer.Deserialize(fileName);
}
When I run the code I get following error: No elements with this name found: './Units'. As you can see there already is an element called Units.
c# xml xml-serialization yaxlib
asked Nov 28 '18 at 10:20
ChyuChyu
157317
1
it doesn't give me any error ! how did you callImportfunction?
– er-sho
Nov 28 '18 at 10:38
1
Thank you! I have realized theImport()function is reading incorrect values.
– Chyu
Nov 28 '18 at 10:58
you need to pass xml content toImportfunction rather than passing path of xml file
– er-sho
Nov 28 '18 at 11:00
What if I want to use path of XML file?
– Chyu
Nov 28 '18 at 11:43
then you have to fetch content of xml in yourImportfunction from path. let me add an solution for you
– er-sho
Nov 28 '18 at 11:51
|
show 5 more comments
1
1
1
I have two classes that are used for de/serializing an XML file.
XmlExampleBasicUnit.cs:
[YAXSerializeAs("Unit")]
public class XmlExampleBasicUnit
{
[YAXSerializeAs("StringVar")]
public String StringVar { get; set; }
[YAXSerializeAs("Int32Var")]
public Int32 Int32Var { get; set; }
[YAXSerializeAs("DoubleVar")]
public Double DoubleVar { get; set; }
[YAXSerializeAs("DateTimeVar")]
public String DateTimeVar { get; set; }
[YAXSerializeAs("CharVar")]
public String CharVar { get; set; }
}
XmlExampleCollectionOfUnits.cs:
[YAXSerializeAs("CollectionOfUnits")]
public class XmlExampleCollectionOfUnits
{
[YAXSerializeAs("Units")]
public List<XmlExampleBasicUnit> Units { get; set; }
public XmlExampleCollectionOfUnits(List<XmlExampleBasicUnit> units)
{
Units = units;
}
public XmlExampleCollectionOfUnits()
{
}
}
I'm trying to deserialize this file:
<?xml version="1.0" encoding="utf-8"?>
<CollectionOfUnits>
<Units>
<Unit>
<StringVar>TohleJeString</StringVar>
<Int32Var>24</Int32Var>
<DoubleVar>29.6</DoubleVar>
<DateTimeVar>17.11.1968</DateTimeVar>
<CharVar>c</CharVar>
</Unit>
<Unit>
<StringVar>TohleJeTakéString</StringVar>
<Int32Var>17</Int32Var>
<DoubleVar>5.9</DoubleVar>
<DateTimeVar>06.07.1415</DateTimeVar>
<CharVar>p</CharVar>
</Unit>
<Unit>
<StringVar>NoATohleTaké</StringVar>
<Int32Var>2</Int32Var>
<DoubleVar>78.5</DoubleVar>
<DateTimeVar>06.12.1774</DateTimeVar>
<CharVar>x</CharVar>
</Unit>
</Units>
It's all handled by this function:
public T Import<T>(String fileName) where T : class
{
YAXSerializer serializer = new YAXSerializer(typeof(T));
return (T)serializer.Deserialize(fileName);
}
When I run the code I get following error: No elements with this name found: './Units'. As you can see there already is an element called Units.
c# xml xml-serialization yaxlib
asked Nov 28 '18 at 10:20
ChyuChyu
157317
I have two classes that are used for de/serializing an XML file.
XmlExampleBasicUnit.cs:
[YAXSerializeAs("Unit")]
public class XmlExampleBasicUnit
{
[YAXSerializeAs("StringVar")]
public String StringVar { get; set; }
[YAXSerializeAs("Int32Var")]
public Int32 Int32Var { get; set; }
[YAXSerializeAs("DoubleVar")]
public Double DoubleVar { get; set; }
[YAXSerializeAs("DateTimeVar")]
public String DateTimeVar { get; set; }
[YAXSerializeAs("CharVar")]
public String CharVar { get; set; }
}
XmlExampleCollectionOfUnits.cs:
[YAXSerializeAs("CollectionOfUnits")]
public class XmlExampleCollectionOfUnits
{
[YAXSerializeAs("Units")]
public List<XmlExampleBasicUnit> Units { get; set; }
public XmlExampleCollectionOfUnits(List<XmlExampleBasicUnit> units)
{
Units = units;
}
public XmlExampleCollectionOfUnits()
{
}
}
I'm trying to deserialize this file:
<?xml version="1.0" encoding="utf-8"?>
<CollectionOfUnits>
<Units>
<Unit>
<StringVar>TohleJeString</StringVar>
<Int32Var>24</Int32Var>
<DoubleVar>29.6</DoubleVar>
<DateTimeVar>17.11.1968</DateTimeVar>
<CharVar>c</CharVar>
</Unit>
<Unit>
<StringVar>TohleJeTakéString</StringVar>
<Int32Var>17</Int32Var>
<DoubleVar>5.9</DoubleVar>
<DateTimeVar>06.07.1415</DateTimeVar>
<CharVar>p</CharVar>
</Unit>
<Unit>
<StringVar>NoATohleTaké</StringVar>
<Int32Var>2</Int32Var>
<DoubleVar>78.5</DoubleVar>
<DateTimeVar>06.12.1774</DateTimeVar>
<CharVar>x</CharVar>
</Unit>
</Units>
It's all handled by this function:
public T Import<T>(String fileName) where T : class
{
YAXSerializer serializer = new YAXSerializer(typeof(T));
return (T)serializer.Deserialize(fileName);
}
When I run the code I get following error: No elements with this name found: './Units'. As you can see there already is an element called Units.
c# xml xml-serialization yaxlib
c# xml xml-serialization yaxlib
asked Nov 28 '18 at 10:20
ChyuChyu
157317
asked Nov 28 '18 at 10:20
ChyuChyu
157317
asked Nov 28 '18 at 10:20
ChyuChyu
157317
asked Nov 28 '18 at 10:20
ChyuChyu
157317
asked Nov 28 '18 at 10:20
ChyuChyu
157317
157317
1
it doesn't give me any error ! how did you callImportfunction?
– er-sho
Nov 28 '18 at 10:38
1
Thank you! I have realized theImport()function is reading incorrect values.
– Chyu
Nov 28 '18 at 10:58
you need to pass xml content toImportfunction rather than passing path of xml file
– er-sho
Nov 28 '18 at 11:00
What if I want to use path of XML file?
– Chyu
Nov 28 '18 at 11:43
then you have to fetch content of xml in yourImportfunction from path. let me add an solution for you
– er-sho
Nov 28 '18 at 11:51
|
show 5 more comments
1
it doesn't give me any error ! how did you callImportfunction?
– er-sho
Nov 28 '18 at 10:38
1
Thank you! I have realized theImport()function is reading incorrect values.
– Chyu
Nov 28 '18 at 10:58
you need to pass xml content toImportfunction rather than passing path of xml file
– er-sho
Nov 28 '18 at 11:00
What if I want to use path of XML file?
– Chyu
Nov 28 '18 at 11:43
then you have to fetch content of xml in yourImportfunction from path. let me add an solution for you
– er-sho
Nov 28 '18 at 11:51
1
1
it doesn't give me any error ! how did you call
Import function?– er-sho
Nov 28 '18 at 10:38
it doesn't give me any error ! how did you call
Import function?– er-sho
Nov 28 '18 at 10:38
1
1
Thank you! I have realized the
Import() function is reading incorrect values.– Chyu
Nov 28 '18 at 10:58
Thank you! I have realized the
Import() function is reading incorrect values.– Chyu
Nov 28 '18 at 10:58
you need to pass xml content to
Import function rather than passing path of xml file– er-sho
Nov 28 '18 at 11:00
you need to pass xml content to
Import function rather than passing path of xml file– er-sho
Nov 28 '18 at 11:00
What if I want to use path of XML file?
– Chyu
Nov 28 '18 at 11:43
What if I want to use path of XML file?
– Chyu
Nov 28 '18 at 11:43
then you have to fetch content of xml in your
Import function from path. let me add an solution for you– er-sho
Nov 28 '18 at 11:51
then you have to fetch content of xml in your
Import function from path. let me add an solution for you– er-sho
Nov 28 '18 at 11:51
|
show 5 more comments
1 Answer
1
active
oldest
votes
1
Read all your xml content from your path by using File.ReadAllText(fileName) and pass it to Deserialize method like.
public static T Import<T>(String fileName) where T : class
{
string xmlData = File.ReadAllText(fileName); //Read xml content from path
YAXSerializer serializer = new YAXSerializer(typeof(T));
return (T)serializer.Deserialize(xmlData); //Pass xml content to Deserialize.
}
answered Nov 28 '18 at 13:35
er-shoer-sho
6,4752619
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
Read all your xml content from your path by using File.ReadAllText(fileName) and pass it to Deserialize method like.
public static T Import<T>(String fileName) where T : class
{
string xmlData = File.ReadAllText(fileName); //Read xml content from path
YAXSerializer serializer = new YAXSerializer(typeof(T));
return (T)serializer.Deserialize(xmlData); //Pass xml content to Deserialize.
}
answered Nov 28 '18 at 13:35
er-shoer-sho
6,4752619
add a comment |
1
Read all your xml content from your path by using File.ReadAllText(fileName) and pass it to Deserialize method like.
public static T Import<T>(String fileName) where T : class
{
string xmlData = File.ReadAllText(fileName); //Read xml content from path
YAXSerializer serializer = new YAXSerializer(typeof(T));
return (T)serializer.Deserialize(xmlData); //Pass xml content to Deserialize.
}
answered Nov 28 '18 at 13:35
er-shoer-sho
6,4752619
add a comment |
1
1
1
Read all your xml content from your path by using File.ReadAllText(fileName) and pass it to Deserialize method like.
public static T Import<T>(String fileName) where T : class
{
string xmlData = File.ReadAllText(fileName); //Read xml content from path
YAXSerializer serializer = new YAXSerializer(typeof(T));
return (T)serializer.Deserialize(xmlData); //Pass xml content to Deserialize.
}
answered Nov 28 '18 at 13:35
er-shoer-sho
6,4752619
Read all your xml content from your path by using File.ReadAllText(fileName) and pass it to Deserialize method like.
public static T Import<T>(String fileName) where T : class
{
string xmlData = File.ReadAllText(fileName); //Read xml content from path
YAXSerializer serializer = new YAXSerializer(typeof(T));
return (T)serializer.Deserialize(xmlData); //Pass xml content to Deserialize.
}
answered Nov 28 '18 at 13:35
er-shoer-sho
6,4752619
answered Nov 28 '18 at 13:35
er-shoer-sho
6,4752619
answered Nov 28 '18 at 13:35
er-shoer-sho
6,4752619
answered Nov 28 '18 at 13:35
er-shoer-sho
6,4752619
6,4752619
add a comment |
add a comment |
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1
it doesn't give me any error ! how did you call
Importfunction?– er-sho
Nov 28 '18 at 10:38
1
Thank you! I have realized the
Import()function is reading incorrect values.– Chyu
Nov 28 '18 at 10:58
you need to pass xml content to
Importfunction rather than passing path of xml file– er-sho
Nov 28 '18 at 11:00
What if I want to use path of XML file?
– Chyu
Nov 28 '18 at 11:43
then you have to fetch content of xml in your
Importfunction from path. let me add an solution for you– er-sho
Nov 28 '18 at 11:51