RxJava2: Merge/concat two streams












0















I have two data sources which are used in the following manner.



For any data that is needed by a consumer:




  1. Check if data is there is CACHE. If yes, provide data.


  2. Regardless of 1, then goto REMOTE and fetch the data. Note: To
    create the remote observable, Observable.fromCallable() is being
    used.


  3. Update the DB and then provide the updated data to the consumer.



Now the above was achieved by concat() , ObservableCache and ObservableRemote.



But now there is another requirement.
I would like to keep the stream alive until the observable is disposed by the consumer.
And that is because, there might be an update to the Cache, which I would like to automatically be sent to the consumer.
Would concat() above, keep the stream alive until the observable is disposed by the consumer?
If that is not the case, could someone provide a solution to this problem?



Also, since I would like to keep the stream alive, until the observable is disposed by the consumer, is there a way to terminate the stream once it is disposed?



Thanks.






rx-java2 rx-android reactive







share|improve this question

























  • It seems you are reinventing github.com/NYTimes/Store

    – Maxim Volgin
    Nov 27 '18 at 9:57
















0















I have two data sources which are used in the following manner.



For any data that is needed by a consumer:




  1. Check if data is there is CACHE. If yes, provide data.


  2. Regardless of 1, then goto REMOTE and fetch the data. Note: To
    create the remote observable, Observable.fromCallable() is being
    used.


  3. Update the DB and then provide the updated data to the consumer.



Now the above was achieved by concat() , ObservableCache and ObservableRemote.



But now there is another requirement.
I would like to keep the stream alive until the observable is disposed by the consumer.
And that is because, there might be an update to the Cache, which I would like to automatically be sent to the consumer.
Would concat() above, keep the stream alive until the observable is disposed by the consumer?
If that is not the case, could someone provide a solution to this problem?



Also, since I would like to keep the stream alive, until the observable is disposed by the consumer, is there a way to terminate the stream once it is disposed?



Thanks.






rx-java2 rx-android reactive







share|improve this question

























  • It seems you are reinventing github.com/NYTimes/Store

    – Maxim Volgin
    Nov 27 '18 at 9:57














0












0








0








I have two data sources which are used in the following manner.



For any data that is needed by a consumer:




  1. Check if data is there is CACHE. If yes, provide data.


  2. Regardless of 1, then goto REMOTE and fetch the data. Note: To
    create the remote observable, Observable.fromCallable() is being
    used.


  3. Update the DB and then provide the updated data to the consumer.



Now the above was achieved by concat() , ObservableCache and ObservableRemote.



But now there is another requirement.
I would like to keep the stream alive until the observable is disposed by the consumer.
And that is because, there might be an update to the Cache, which I would like to automatically be sent to the consumer.
Would concat() above, keep the stream alive until the observable is disposed by the consumer?
If that is not the case, could someone provide a solution to this problem?



Also, since I would like to keep the stream alive, until the observable is disposed by the consumer, is there a way to terminate the stream once it is disposed?



Thanks.






rx-java2 rx-android reactive







share|improve this question
















I have two data sources which are used in the following manner.



For any data that is needed by a consumer:




  1. Check if data is there is CACHE. If yes, provide data.


  2. Regardless of 1, then goto REMOTE and fetch the data. Note: To
    create the remote observable, Observable.fromCallable() is being
    used.


  3. Update the DB and then provide the updated data to the consumer.



Now the above was achieved by concat() , ObservableCache and ObservableRemote.



But now there is another requirement.
I would like to keep the stream alive until the observable is disposed by the consumer.
And that is because, there might be an update to the Cache, which I would like to automatically be sent to the consumer.
Would concat() above, keep the stream alive until the observable is disposed by the consumer?
If that is not the case, could someone provide a solution to this problem?



Also, since I would like to keep the stream alive, until the observable is disposed by the consumer, is there a way to terminate the stream once it is disposed?



Thanks.






rx-java2 rx-android reactive




rx-java2 rx-android reactive






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 27 '18 at 6:47









Shreya Prajapati

8411




8411










asked Nov 27 '18 at 1:47









SunnySunny

2,710144578




2,710144578













  • It seems you are reinventing github.com/NYTimes/Store

    – Maxim Volgin
    Nov 27 '18 at 9:57



















  • It seems you are reinventing github.com/NYTimes/Store

    – Maxim Volgin
    Nov 27 '18 at 9:57

















It seems you are reinventing github.com/NYTimes/Store

– Maxim Volgin
Nov 27 '18 at 9:57





It seems you are reinventing github.com/NYTimes/Store

– Maxim Volgin
Nov 27 '18 at 9:57












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