RxJava2: Merge/concat two streams
I have two data sources which are used in the following manner.
For any data that is needed by a consumer:
Check if data is there is CACHE. If yes, provide data.
Regardless of 1, then goto REMOTE and fetch the data. Note: To
create the remote observable,Observable.fromCallable()is being
used.Update the DB and then provide the updated data to the consumer.
Now the above was achieved by concat() , ObservableCache and ObservableRemote.
But now there is another requirement.
I would like to keep the stream alive until the observable is disposed by the consumer.
And that is because, there might be an update to the Cache, which I would like to automatically be sent to the consumer.
Would concat() above, keep the stream alive until the observable is disposed by the consumer?
If that is not the case, could someone provide a solution to this problem?
Also, since I would like to keep the stream alive, until the observable is disposed by the consumer, is there a way to terminate the stream once it is disposed?
Thanks.
rx-java2 rx-android reactive
edited Nov 27 '18 at 6:47
Shreya Prajapati
8411
asked Nov 27 '18 at 1:47
SunnySunny
2,710144578
add a comment |
I have two data sources which are used in the following manner.
For any data that is needed by a consumer:
Check if data is there is CACHE. If yes, provide data.
Regardless of 1, then goto REMOTE and fetch the data. Note: To
create the remote observable,Observable.fromCallable()is being
used.Update the DB and then provide the updated data to the consumer.
Now the above was achieved by concat() , ObservableCache and ObservableRemote.
But now there is another requirement.
I would like to keep the stream alive until the observable is disposed by the consumer.
And that is because, there might be an update to the Cache, which I would like to automatically be sent to the consumer.
Would concat() above, keep the stream alive until the observable is disposed by the consumer?
If that is not the case, could someone provide a solution to this problem?
Also, since I would like to keep the stream alive, until the observable is disposed by the consumer, is there a way to terminate the stream once it is disposed?
Thanks.
rx-java2 rx-android reactive
edited Nov 27 '18 at 6:47
Shreya Prajapati
8411
asked Nov 27 '18 at 1:47
SunnySunny
2,710144578
It seems you are reinventing github.com/NYTimes/Store
– Maxim Volgin
Nov 27 '18 at 9:57
add a comment |
I have two data sources which are used in the following manner.
For any data that is needed by a consumer:
Check if data is there is CACHE. If yes, provide data.
Regardless of 1, then goto REMOTE and fetch the data. Note: To
create the remote observable,Observable.fromCallable()is being
used.Update the DB and then provide the updated data to the consumer.
Now the above was achieved by concat() , ObservableCache and ObservableRemote.
But now there is another requirement.
I would like to keep the stream alive until the observable is disposed by the consumer.
And that is because, there might be an update to the Cache, which I would like to automatically be sent to the consumer.
Would concat() above, keep the stream alive until the observable is disposed by the consumer?
If that is not the case, could someone provide a solution to this problem?
Also, since I would like to keep the stream alive, until the observable is disposed by the consumer, is there a way to terminate the stream once it is disposed?
Thanks.
rx-java2 rx-android reactive
edited Nov 27 '18 at 6:47
Shreya Prajapati
8411
asked Nov 27 '18 at 1:47
SunnySunny
2,710144578
I have two data sources which are used in the following manner.
For any data that is needed by a consumer:
Check if data is there is CACHE. If yes, provide data.
Regardless of 1, then goto REMOTE and fetch the data. Note: To
create the remote observable,Observable.fromCallable()is being
used.Update the DB and then provide the updated data to the consumer.
Now the above was achieved by concat() , ObservableCache and ObservableRemote.
But now there is another requirement.
I would like to keep the stream alive until the observable is disposed by the consumer.
And that is because, there might be an update to the Cache, which I would like to automatically be sent to the consumer.
Would concat() above, keep the stream alive until the observable is disposed by the consumer?
If that is not the case, could someone provide a solution to this problem?
Also, since I would like to keep the stream alive, until the observable is disposed by the consumer, is there a way to terminate the stream once it is disposed?
Thanks.
rx-java2 rx-android reactive
rx-java2 rx-android reactive
edited Nov 27 '18 at 6:47
Shreya Prajapati
8411
asked Nov 27 '18 at 1:47
SunnySunny
2,710144578
edited Nov 27 '18 at 6:47
Shreya Prajapati
8411
asked Nov 27 '18 at 1:47
SunnySunny
2,710144578
edited Nov 27 '18 at 6:47
Shreya Prajapati
8411
edited Nov 27 '18 at 6:47
Shreya Prajapati
8411
edited Nov 27 '18 at 6:47
Shreya Prajapati
8411
8411
asked Nov 27 '18 at 1:47
SunnySunny
2,710144578
asked Nov 27 '18 at 1:47
SunnySunny
2,710144578
asked Nov 27 '18 at 1:47
SunnySunny
2,710144578
2,710144578
It seems you are reinventing github.com/NYTimes/Store
– Maxim Volgin
Nov 27 '18 at 9:57
add a comment |
It seems you are reinventing github.com/NYTimes/Store
– Maxim Volgin
Nov 27 '18 at 9:57
It seems you are reinventing github.com/NYTimes/Store
– Maxim Volgin
Nov 27 '18 at 9:57
It seems you are reinventing github.com/NYTimes/Store
– Maxim Volgin
Nov 27 '18 at 9:57
add a comment |
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It seems you are reinventing github.com/NYTimes/Store
– Maxim Volgin
Nov 27 '18 at 9:57