XQuery 3 merging two node sequences and de-duplicating












1














In XQuery 3.1 (under eXistDB 4.4) I have two functions which return two sets of nodes that describe family relations of a person. The results of the two functions can overlap.



A first function person:person-relationship-as-object("#Guilhem_Faure_SML-AU") returns:



<person relation="Peire_Faure_SML-AU">
<span class="en">Sibling(s)</span>
<span class="fr">Frère(s)/sœur(s)</span>
</person>

<person relation="Arnald_Faure_SML-AU">
<span class="en">Sibling(s)</span>
<span class="fr">Frère(s)/sœur(s)</span>
</person>

<person relation="Esteve_Faure_SML-AU">
<span class="en">Sibling(s)</span>
<span class="fr">Frère(s)/sœur(s)</span>
</person>

<person relation="Martin_de_Verazilh_SML-AU">
<span class="en">Aunt(s)/Uncle(s)</span>
<span class="fr">Tante(s)/Oncle(s)</span>
</person>

<person relation="Raimund_de_Verazilh_SML-AU">
<span class="en">Aunt(s)/Uncle(s)</span>
<span class="fr">Tante(s)/Oncle(s)</span>
</person>


A second function person:person-relationship-as-subject("#Guilhem_Faure_SML-AU") returns



<person relation="Arnald_Faure_SML-AU">
<span class="en">Sibling(s)</span>
<span class="fr">Frère(s)/sœur(s)</span>
</person>

<person relation="Peire_Faure_SML-AU">
<span class="en">Sibling(s)</span>
<span class="fr">Frère(s)/sœur(s)</span>
</person>

<person relation="Esteve_Faure_SML-AU">
<span class="en">Sibling(s)</span>
<span class="fr">Frère(s)/sœur(s)</span>
</person>

<person relation="Bernarda_Guilhem_Faure_SML-AU">
<span class="en">Spouse(s)</span>
<span class="fr">Époux/épouse(s)</span>
</person>


Now I want to merge the two sets of nodes into one, and return each distinct node only once.



I attempted a rough SQL-like structure, but failed:



let $x := person:person-relationship-as-object("#Guilhem_Faure_SML-AU") 
| person:person-relationship-as-subject("#Guilhem_Faure_SML-AU")

for $y in $x

order by $y/@relation ascending

group by $y/@relation, $y/span[@class="en"], $y/span[@class="fr"]

return $y


I don't think I really understand why the group by doesn't work here. Moreover, if group by doesn't do the job, how else can I approach what (I think?) should be a simple exercise in grouping/distinct results?










share|improve this question
























  • return functx:distinct-deep($x) does the job, without grouping...
    – jbrehr
    Nov 23 '18 at 16:40
















1














In XQuery 3.1 (under eXistDB 4.4) I have two functions which return two sets of nodes that describe family relations of a person. The results of the two functions can overlap.



A first function person:person-relationship-as-object("#Guilhem_Faure_SML-AU") returns:



<person relation="Peire_Faure_SML-AU">
<span class="en">Sibling(s)</span>
<span class="fr">Frère(s)/sœur(s)</span>
</person>

<person relation="Arnald_Faure_SML-AU">
<span class="en">Sibling(s)</span>
<span class="fr">Frère(s)/sœur(s)</span>
</person>

<person relation="Esteve_Faure_SML-AU">
<span class="en">Sibling(s)</span>
<span class="fr">Frère(s)/sœur(s)</span>
</person>

<person relation="Martin_de_Verazilh_SML-AU">
<span class="en">Aunt(s)/Uncle(s)</span>
<span class="fr">Tante(s)/Oncle(s)</span>
</person>

<person relation="Raimund_de_Verazilh_SML-AU">
<span class="en">Aunt(s)/Uncle(s)</span>
<span class="fr">Tante(s)/Oncle(s)</span>
</person>


A second function person:person-relationship-as-subject("#Guilhem_Faure_SML-AU") returns



<person relation="Arnald_Faure_SML-AU">
<span class="en">Sibling(s)</span>
<span class="fr">Frère(s)/sœur(s)</span>
</person>

<person relation="Peire_Faure_SML-AU">
<span class="en">Sibling(s)</span>
<span class="fr">Frère(s)/sœur(s)</span>
</person>

<person relation="Esteve_Faure_SML-AU">
<span class="en">Sibling(s)</span>
<span class="fr">Frère(s)/sœur(s)</span>
</person>

<person relation="Bernarda_Guilhem_Faure_SML-AU">
<span class="en">Spouse(s)</span>
<span class="fr">Époux/épouse(s)</span>
</person>


Now I want to merge the two sets of nodes into one, and return each distinct node only once.



I attempted a rough SQL-like structure, but failed:



let $x := person:person-relationship-as-object("#Guilhem_Faure_SML-AU") 
| person:person-relationship-as-subject("#Guilhem_Faure_SML-AU")

for $y in $x

order by $y/@relation ascending

group by $y/@relation, $y/span[@class="en"], $y/span[@class="fr"]

return $y


I don't think I really understand why the group by doesn't work here. Moreover, if group by doesn't do the job, how else can I approach what (I think?) should be a simple exercise in grouping/distinct results?










share|improve this question
























  • return functx:distinct-deep($x) does the job, without grouping...
    – jbrehr
    Nov 23 '18 at 16:40














1












1








1







In XQuery 3.1 (under eXistDB 4.4) I have two functions which return two sets of nodes that describe family relations of a person. The results of the two functions can overlap.



A first function person:person-relationship-as-object("#Guilhem_Faure_SML-AU") returns:



<person relation="Peire_Faure_SML-AU">
<span class="en">Sibling(s)</span>
<span class="fr">Frère(s)/sœur(s)</span>
</person>

<person relation="Arnald_Faure_SML-AU">
<span class="en">Sibling(s)</span>
<span class="fr">Frère(s)/sœur(s)</span>
</person>

<person relation="Esteve_Faure_SML-AU">
<span class="en">Sibling(s)</span>
<span class="fr">Frère(s)/sœur(s)</span>
</person>

<person relation="Martin_de_Verazilh_SML-AU">
<span class="en">Aunt(s)/Uncle(s)</span>
<span class="fr">Tante(s)/Oncle(s)</span>
</person>

<person relation="Raimund_de_Verazilh_SML-AU">
<span class="en">Aunt(s)/Uncle(s)</span>
<span class="fr">Tante(s)/Oncle(s)</span>
</person>


A second function person:person-relationship-as-subject("#Guilhem_Faure_SML-AU") returns



<person relation="Arnald_Faure_SML-AU">
<span class="en">Sibling(s)</span>
<span class="fr">Frère(s)/sœur(s)</span>
</person>

<person relation="Peire_Faure_SML-AU">
<span class="en">Sibling(s)</span>
<span class="fr">Frère(s)/sœur(s)</span>
</person>

<person relation="Esteve_Faure_SML-AU">
<span class="en">Sibling(s)</span>
<span class="fr">Frère(s)/sœur(s)</span>
</person>

<person relation="Bernarda_Guilhem_Faure_SML-AU">
<span class="en">Spouse(s)</span>
<span class="fr">Époux/épouse(s)</span>
</person>


Now I want to merge the two sets of nodes into one, and return each distinct node only once.



I attempted a rough SQL-like structure, but failed:



let $x := person:person-relationship-as-object("#Guilhem_Faure_SML-AU") 
| person:person-relationship-as-subject("#Guilhem_Faure_SML-AU")

for $y in $x

order by $y/@relation ascending

group by $y/@relation, $y/span[@class="en"], $y/span[@class="fr"]

return $y


I don't think I really understand why the group by doesn't work here. Moreover, if group by doesn't do the job, how else can I approach what (I think?) should be a simple exercise in grouping/distinct results?










share|improve this question















In XQuery 3.1 (under eXistDB 4.4) I have two functions which return two sets of nodes that describe family relations of a person. The results of the two functions can overlap.



A first function person:person-relationship-as-object("#Guilhem_Faure_SML-AU") returns:



<person relation="Peire_Faure_SML-AU">
<span class="en">Sibling(s)</span>
<span class="fr">Frère(s)/sœur(s)</span>
</person>

<person relation="Arnald_Faure_SML-AU">
<span class="en">Sibling(s)</span>
<span class="fr">Frère(s)/sœur(s)</span>
</person>

<person relation="Esteve_Faure_SML-AU">
<span class="en">Sibling(s)</span>
<span class="fr">Frère(s)/sœur(s)</span>
</person>

<person relation="Martin_de_Verazilh_SML-AU">
<span class="en">Aunt(s)/Uncle(s)</span>
<span class="fr">Tante(s)/Oncle(s)</span>
</person>

<person relation="Raimund_de_Verazilh_SML-AU">
<span class="en">Aunt(s)/Uncle(s)</span>
<span class="fr">Tante(s)/Oncle(s)</span>
</person>


A second function person:person-relationship-as-subject("#Guilhem_Faure_SML-AU") returns



<person relation="Arnald_Faure_SML-AU">
<span class="en">Sibling(s)</span>
<span class="fr">Frère(s)/sœur(s)</span>
</person>

<person relation="Peire_Faure_SML-AU">
<span class="en">Sibling(s)</span>
<span class="fr">Frère(s)/sœur(s)</span>
</person>

<person relation="Esteve_Faure_SML-AU">
<span class="en">Sibling(s)</span>
<span class="fr">Frère(s)/sœur(s)</span>
</person>

<person relation="Bernarda_Guilhem_Faure_SML-AU">
<span class="en">Spouse(s)</span>
<span class="fr">Époux/épouse(s)</span>
</person>


Now I want to merge the two sets of nodes into one, and return each distinct node only once.



I attempted a rough SQL-like structure, but failed:



let $x := person:person-relationship-as-object("#Guilhem_Faure_SML-AU") 
| person:person-relationship-as-subject("#Guilhem_Faure_SML-AU")

for $y in $x

order by $y/@relation ascending

group by $y/@relation, $y/span[@class="en"], $y/span[@class="fr"]

return $y


I don't think I really understand why the group by doesn't work here. Moreover, if group by doesn't do the job, how else can I approach what (I think?) should be a simple exercise in grouping/distinct results?







xquery exist-db






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share|improve this question








edited Nov 23 '18 at 16:00

























asked Nov 23 '18 at 15:02









jbrehr

115212




115212












  • return functx:distinct-deep($x) does the job, without grouping...
    – jbrehr
    Nov 23 '18 at 16:40


















  • return functx:distinct-deep($x) does the job, without grouping...
    – jbrehr
    Nov 23 '18 at 16:40
















return functx:distinct-deep($x) does the job, without grouping...
– jbrehr
Nov 23 '18 at 16:40




return functx:distinct-deep($x) does the job, without grouping...
– jbrehr
Nov 23 '18 at 16:40












1 Answer
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oldest

votes


















2














With XQuery and group by, the variable $y in your return clause is bound to the whole group you have created so to eliminate duplicates you need to use return $y[1]. See https://www.w3.org/TR/xquery-31/#id-group-by which says




In the post-grouping tuple generated for a given group, each
non-grouping variable is bound to a sequence containing the
concatenated values of that variable in all the pre-grouping tuples
that were assigned to that group.




and then




This behavior may be surprising to SQL programmers, since SQL reduces
the equivalent of a non-grouping variable to one representative value.







share|improve this answer























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    With XQuery and group by, the variable $y in your return clause is bound to the whole group you have created so to eliminate duplicates you need to use return $y[1]. See https://www.w3.org/TR/xquery-31/#id-group-by which says




    In the post-grouping tuple generated for a given group, each
    non-grouping variable is bound to a sequence containing the
    concatenated values of that variable in all the pre-grouping tuples
    that were assigned to that group.




    and then




    This behavior may be surprising to SQL programmers, since SQL reduces
    the equivalent of a non-grouping variable to one representative value.







    share|improve this answer




























      2














      With XQuery and group by, the variable $y in your return clause is bound to the whole group you have created so to eliminate duplicates you need to use return $y[1]. See https://www.w3.org/TR/xquery-31/#id-group-by which says




      In the post-grouping tuple generated for a given group, each
      non-grouping variable is bound to a sequence containing the
      concatenated values of that variable in all the pre-grouping tuples
      that were assigned to that group.




      and then




      This behavior may be surprising to SQL programmers, since SQL reduces
      the equivalent of a non-grouping variable to one representative value.







      share|improve this answer


























        2












        2








        2






        With XQuery and group by, the variable $y in your return clause is bound to the whole group you have created so to eliminate duplicates you need to use return $y[1]. See https://www.w3.org/TR/xquery-31/#id-group-by which says




        In the post-grouping tuple generated for a given group, each
        non-grouping variable is bound to a sequence containing the
        concatenated values of that variable in all the pre-grouping tuples
        that were assigned to that group.




        and then




        This behavior may be surprising to SQL programmers, since SQL reduces
        the equivalent of a non-grouping variable to one representative value.







        share|improve this answer














        With XQuery and group by, the variable $y in your return clause is bound to the whole group you have created so to eliminate duplicates you need to use return $y[1]. See https://www.w3.org/TR/xquery-31/#id-group-by which says




        In the post-grouping tuple generated for a given group, each
        non-grouping variable is bound to a sequence containing the
        concatenated values of that variable in all the pre-grouping tuples
        that were assigned to that group.




        and then




        This behavior may be surprising to SQL programmers, since SQL reduces
        the equivalent of a non-grouping variable to one representative value.








        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Nov 23 '18 at 20:41

























        answered Nov 23 '18 at 19:55









        Martin Honnen

        111k65876




        111k65876






























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