mysql implicit join+ subquery












0














I'm meant to use an implicit join to get all the movies with angelina jolie as director or were she stars here's what I have so far



SELECT DISTINCT title, relYear
FROM actor,movie
WHERE director ='Angelina Jolie' OR aID in (SELECT aID
FROM actor
WHERE fName='Angelina' and surname='Jolie'


Here are the relevant tables



movie(id, title, relYear, category, runTime, director,
studioName, description, rating)
actor(aID, fName, surname, gender)
stars(movieID, actorID)
movGenre(movieID, genre)


This returns all of the movies , I think that's because of aID in (SELECT aID



I don't know how to do this without using explicit join on three tables is the subquery even the most efficient approach ? Thanks










share|improve this question






















  • Which college/university teaches still teaches and insist implicit joins ? They should upgrade the coursework and switch to modern approaches.
    – Madhur Bhaiya
    Nov 23 '18 at 14:39


















0














I'm meant to use an implicit join to get all the movies with angelina jolie as director or were she stars here's what I have so far



SELECT DISTINCT title, relYear
FROM actor,movie
WHERE director ='Angelina Jolie' OR aID in (SELECT aID
FROM actor
WHERE fName='Angelina' and surname='Jolie'


Here are the relevant tables



movie(id, title, relYear, category, runTime, director,
studioName, description, rating)
actor(aID, fName, surname, gender)
stars(movieID, actorID)
movGenre(movieID, genre)


This returns all of the movies , I think that's because of aID in (SELECT aID



I don't know how to do this without using explicit join on three tables is the subquery even the most efficient approach ? Thanks










share|improve this question






















  • Which college/university teaches still teaches and insist implicit joins ? They should upgrade the coursework and switch to modern approaches.
    – Madhur Bhaiya
    Nov 23 '18 at 14:39
















0












0








0







I'm meant to use an implicit join to get all the movies with angelina jolie as director or were she stars here's what I have so far



SELECT DISTINCT title, relYear
FROM actor,movie
WHERE director ='Angelina Jolie' OR aID in (SELECT aID
FROM actor
WHERE fName='Angelina' and surname='Jolie'


Here are the relevant tables



movie(id, title, relYear, category, runTime, director,
studioName, description, rating)
actor(aID, fName, surname, gender)
stars(movieID, actorID)
movGenre(movieID, genre)


This returns all of the movies , I think that's because of aID in (SELECT aID



I don't know how to do this without using explicit join on three tables is the subquery even the most efficient approach ? Thanks










share|improve this question













I'm meant to use an implicit join to get all the movies with angelina jolie as director or were she stars here's what I have so far



SELECT DISTINCT title, relYear
FROM actor,movie
WHERE director ='Angelina Jolie' OR aID in (SELECT aID
FROM actor
WHERE fName='Angelina' and surname='Jolie'


Here are the relevant tables



movie(id, title, relYear, category, runTime, director,
studioName, description, rating)
actor(aID, fName, surname, gender)
stars(movieID, actorID)
movGenre(movieID, genre)


This returns all of the movies , I think that's because of aID in (SELECT aID



I don't know how to do this without using explicit join on three tables is the subquery even the most efficient approach ? Thanks







mysql subquery implicit






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asked Nov 23 '18 at 14:34









sarahwert

32




32












  • Which college/university teaches still teaches and insist implicit joins ? They should upgrade the coursework and switch to modern approaches.
    – Madhur Bhaiya
    Nov 23 '18 at 14:39




















  • Which college/university teaches still teaches and insist implicit joins ? They should upgrade the coursework and switch to modern approaches.
    – Madhur Bhaiya
    Nov 23 '18 at 14:39


















Which college/university teaches still teaches and insist implicit joins ? They should upgrade the coursework and switch to modern approaches.
– Madhur Bhaiya
Nov 23 '18 at 14:39






Which college/university teaches still teaches and insist implicit joins ? They should upgrade the coursework and switch to modern approaches.
– Madhur Bhaiya
Nov 23 '18 at 14:39














1 Answer
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This is what I would do on MSSQL. Think it should work on MySql.



Select title, relYear FROM movie WHERE director = 'Angelina Jolie' OR id IN 
(SELECT movieId FROM stars inner join actor ON stars.actorId = actor.aID WHERE
actor.fName = 'Angelina' AND surname = 'Jolie')





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    1 Answer
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    1 Answer
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    0














    This is what I would do on MSSQL. Think it should work on MySql.



    Select title, relYear FROM movie WHERE director = 'Angelina Jolie' OR id IN 
    (SELECT movieId FROM stars inner join actor ON stars.actorId = actor.aID WHERE
    actor.fName = 'Angelina' AND surname = 'Jolie')





    share|improve this answer


























      0














      This is what I would do on MSSQL. Think it should work on MySql.



      Select title, relYear FROM movie WHERE director = 'Angelina Jolie' OR id IN 
      (SELECT movieId FROM stars inner join actor ON stars.actorId = actor.aID WHERE
      actor.fName = 'Angelina' AND surname = 'Jolie')





      share|improve this answer
























        0












        0








        0






        This is what I would do on MSSQL. Think it should work on MySql.



        Select title, relYear FROM movie WHERE director = 'Angelina Jolie' OR id IN 
        (SELECT movieId FROM stars inner join actor ON stars.actorId = actor.aID WHERE
        actor.fName = 'Angelina' AND surname = 'Jolie')





        share|improve this answer












        This is what I would do on MSSQL. Think it should work on MySql.



        Select title, relYear FROM movie WHERE director = 'Angelina Jolie' OR id IN 
        (SELECT movieId FROM stars inner join actor ON stars.actorId = actor.aID WHERE
        actor.fName = 'Angelina' AND surname = 'Jolie')






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 23 '18 at 14:42









        Marc Hägele

        1908




        1908






























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