Aggregate query result in mongodb












0














I have collection with documents like this one:



{  
"_id": 1,
"people": [
{
"name": "Bob",
"age": "15"
},
{
"name": "Alice",
"age": "18"
}
]
}


My query is:



db.groups.aggregate({ $match: { "_id": 1 }}, { $project: { "_id": 0, "people.name": 1 } })


This query returns:



{  
"people": [
{
"name": "Bob"
},
{
"name": "Alice"
}
]
}


But I need the result like:



{ "names": [ "Bob", "Alice" ] }


Which parameters should I add to the .aggregate() function?










share|improve this question


















  • 1




    No need to use $map here... Try this .groups.aggregate({ $match: { "_id": 1 }}, { $project: { "_id": 0, "names": "$people.name" } })
    – Anthony Winzlet
    Nov 23 '18 at 15:16












  • Thanks! It's helped
    – TheYarik
    Nov 23 '18 at 15:22
















0














I have collection with documents like this one:



{  
"_id": 1,
"people": [
{
"name": "Bob",
"age": "15"
},
{
"name": "Alice",
"age": "18"
}
]
}


My query is:



db.groups.aggregate({ $match: { "_id": 1 }}, { $project: { "_id": 0, "people.name": 1 } })


This query returns:



{  
"people": [
{
"name": "Bob"
},
{
"name": "Alice"
}
]
}


But I need the result like:



{ "names": [ "Bob", "Alice" ] }


Which parameters should I add to the .aggregate() function?










share|improve this question


















  • 1




    No need to use $map here... Try this .groups.aggregate({ $match: { "_id": 1 }}, { $project: { "_id": 0, "names": "$people.name" } })
    – Anthony Winzlet
    Nov 23 '18 at 15:16












  • Thanks! It's helped
    – TheYarik
    Nov 23 '18 at 15:22














0












0








0


0





I have collection with documents like this one:



{  
"_id": 1,
"people": [
{
"name": "Bob",
"age": "15"
},
{
"name": "Alice",
"age": "18"
}
]
}


My query is:



db.groups.aggregate({ $match: { "_id": 1 }}, { $project: { "_id": 0, "people.name": 1 } })


This query returns:



{  
"people": [
{
"name": "Bob"
},
{
"name": "Alice"
}
]
}


But I need the result like:



{ "names": [ "Bob", "Alice" ] }


Which parameters should I add to the .aggregate() function?










share|improve this question













I have collection with documents like this one:



{  
"_id": 1,
"people": [
{
"name": "Bob",
"age": "15"
},
{
"name": "Alice",
"age": "18"
}
]
}


My query is:



db.groups.aggregate({ $match: { "_id": 1 }}, { $project: { "_id": 0, "people.name": 1 } })


This query returns:



{  
"people": [
{
"name": "Bob"
},
{
"name": "Alice"
}
]
}


But I need the result like:



{ "names": [ "Bob", "Alice" ] }


Which parameters should I add to the .aggregate() function?







mongodb aggregate






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 23 '18 at 14:39









TheYarik

66




66








  • 1




    No need to use $map here... Try this .groups.aggregate({ $match: { "_id": 1 }}, { $project: { "_id": 0, "names": "$people.name" } })
    – Anthony Winzlet
    Nov 23 '18 at 15:16












  • Thanks! It's helped
    – TheYarik
    Nov 23 '18 at 15:22














  • 1




    No need to use $map here... Try this .groups.aggregate({ $match: { "_id": 1 }}, { $project: { "_id": 0, "names": "$people.name" } })
    – Anthony Winzlet
    Nov 23 '18 at 15:16












  • Thanks! It's helped
    – TheYarik
    Nov 23 '18 at 15:22








1




1




No need to use $map here... Try this .groups.aggregate({ $match: { "_id": 1 }}, { $project: { "_id": 0, "names": "$people.name" } })
– Anthony Winzlet
Nov 23 '18 at 15:16






No need to use $map here... Try this .groups.aggregate({ $match: { "_id": 1 }}, { $project: { "_id": 0, "names": "$people.name" } })
– Anthony Winzlet
Nov 23 '18 at 15:16














Thanks! It's helped
– TheYarik
Nov 23 '18 at 15:22




Thanks! It's helped
– TheYarik
Nov 23 '18 at 15:22












1 Answer
1






active

oldest

votes


















0














The solution is:



db.groups.aggregate({ $match: { "_id": 1 }}, { $project: { "_id": 0, "names": "$people.name" } })





share|improve this answer























    Your Answer






    StackExchange.ifUsing("editor", function () {
    StackExchange.using("externalEditor", function () {
    StackExchange.using("snippets", function () {
    StackExchange.snippets.init();
    });
    });
    }, "code-snippets");

    StackExchange.ready(function() {
    var channelOptions = {
    tags: "".split(" "),
    id: "1"
    };
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function() {
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled) {
    StackExchange.using("snippets", function() {
    createEditor();
    });
    }
    else {
    createEditor();
    }
    });

    function createEditor() {
    StackExchange.prepareEditor({
    heartbeatType: 'answer',
    autoActivateHeartbeat: false,
    convertImagesToLinks: true,
    noModals: true,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: 10,
    bindNavPrevention: true,
    postfix: "",
    imageUploader: {
    brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
    contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
    allowUrls: true
    },
    onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    });


    }
    });














    draft saved

    draft discarded


















    StackExchange.ready(
    function () {
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53448681%2faggregate-query-result-in-mongodb%23new-answer', 'question_page');
    }
    );

    Post as a guest















    Required, but never shown

























    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    0














    The solution is:



    db.groups.aggregate({ $match: { "_id": 1 }}, { $project: { "_id": 0, "names": "$people.name" } })





    share|improve this answer




























      0














      The solution is:



      db.groups.aggregate({ $match: { "_id": 1 }}, { $project: { "_id": 0, "names": "$people.name" } })





      share|improve this answer


























        0












        0








        0






        The solution is:



        db.groups.aggregate({ $match: { "_id": 1 }}, { $project: { "_id": 0, "names": "$people.name" } })





        share|improve this answer














        The solution is:



        db.groups.aggregate({ $match: { "_id": 1 }}, { $project: { "_id": 0, "names": "$people.name" } })






        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Nov 23 '18 at 15:23

























        answered Nov 23 '18 at 15:17









        TheYarik

        66




        66






























            draft saved

            draft discarded




















































            Thanks for contributing an answer to Stack Overflow!


            • Please be sure to answer the question. Provide details and share your research!

            But avoid



            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.


            To learn more, see our tips on writing great answers.





            Some of your past answers have not been well-received, and you're in danger of being blocked from answering.


            Please pay close attention to the following guidance:


            • Please be sure to answer the question. Provide details and share your research!

            But avoid



            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.


            To learn more, see our tips on writing great answers.




            draft saved


            draft discarded














            StackExchange.ready(
            function () {
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53448681%2faggregate-query-result-in-mongodb%23new-answer', 'question_page');
            }
            );

            Post as a guest















            Required, but never shown





















































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown

































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown







            Popular posts from this blog

            A CLEAN and SIMPLE way to add appendices to Table of Contents and bookmarks

            Calculate evaluation metrics using cross_val_predict sklearn

            Insert data from modal to MySQL (multiple modal on website)