Btukfyl

I am new to coding and I am wondering how I can make sure a specific array contains certain values?

This is what I have but it is not working for me. I have tried searing the internet for a solution but I am confused by a lot of them. Any feedback helps!

public static boolean allnumbers(int arr) {// makes sure only numbers 1-9 are used

    boolean found = new boolean[9]; // creates a boolean array 



    for (int row = 0; row > 1 && row > 9; row++) {

        int index = arr[row] - 1;

        if(!found[index]) {

            found[index] = true;

        } else{

            return false; //returns false if there are numbers that are not between 1-9

        }

    }

    return true;

}

/**

 * Checks if this array consists of numbers 1 to 9, with all unique numbers,

 * and no number missing.

 *

 * @param arr input array

 * @return true if this array has numbers 1 to 9, each occurring exactly once

 */

public static boolean allnumbers(int arr) {

    if (arr.length != 9) return false;

    return IntStream.rangeClosed(1, 9)

            .noneMatch(value -> Arrays.stream(arr).noneMatch(a -> a == value));

}

Another way...

public static boolean allnumbers(int arr) {

    return Arrays.stream(arr).boxed().collect(Collectors.toSet())

            .equals(IntStream.rangeClosed(1, 9).boxed().collect(Collectors.toSet()));

}

Or if you want to check only the fact that no number is outside the range of 1-9, you can use this:-

public static boolean allnumbers(int arr) {

    return Arrays.stream(arr)

            .noneMatch(i -> i < 1 || i > 9);

}

This is a solution for your problem:

public static boolean allnumbers(int arr) {// makes sure only numbers 1-9 are used

    for(int row=0; row < 9; row++){

        if (arr[row] < 1 || arr[row] > 9)

            return false;

    }

    return true;

}

this function will return true if and only if and only if the first 9 elements in arr are between 1 and 9 inclusive.