about rxjava request url
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1
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I have four Http Url, I need to try one by one.But there is a problem,when one of the url is error,the after url not call. The pseudocode like this:
i = 0;
Observable.fromArray("http://www.baidu.com/", "http://www.google.com/", "https://www.bing.com/")
.concatMap(new Function<String, ObservableSource<String>>() {
@Override
public ObservableSource<String> apply(String s) throws Exception {
return Observable.create(new ObservableOnSubscribe<String>() {
@Override
public void subscribe(ObservableEmitter<String> emitter) throws Exception {
Log.i("settingsubscribe", i + "");
if (i == 1) {
emitter.onError(new Throwable("error"));
//emitter.onComplete();
} else {
emitter.onNext(s.concat("_1"));
emitter.onComplete();
}
i ++;
}
});
}
})
.subscribe(new Consumer<String>() {
@Override
public void accept(String s) throws Exception {
Log.i("settingfffff", s);
}
}, new Consumer<Throwable>() {
@Override
public void accept(Throwable throwable) throws Exception {
Log.i("settingfffff", throwable.getMessage());
}
}, new Action() {
@Override
public void run() throws Exception {
Log.i("settingfffff", "onComplete");
}
});
when i = 1,send the error and the event stoped, I hope continue, How can I do?
java
android rx-java edited Nov 22 at 6:30
Milind Mevada
1,335617
asked Nov 22 at 3:55
mars
61
add a comment |
up vote
1
down vote
favorite
I have four Http Url, I need to try one by one.But there is a problem,when one of the url is error,the after url not call. The pseudocode like this:
i = 0;
Observable.fromArray("http://www.baidu.com/", "http://www.google.com/", "https://www.bing.com/")
.concatMap(new Function<String, ObservableSource<String>>() {
@Override
public ObservableSource<String> apply(String s) throws Exception {
return Observable.create(new ObservableOnSubscribe<String>() {
@Override
public void subscribe(ObservableEmitter<String> emitter) throws Exception {
Log.i("settingsubscribe", i + "");
if (i == 1) {
emitter.onError(new Throwable("error"));
//emitter.onComplete();
} else {
emitter.onNext(s.concat("_1"));
emitter.onComplete();
}
i ++;
}
});
}
})
.subscribe(new Consumer<String>() {
@Override
public void accept(String s) throws Exception {
Log.i("settingfffff", s);
}
}, new Consumer<Throwable>() {
@Override
public void accept(Throwable throwable) throws Exception {
Log.i("settingfffff", throwable.getMessage());
}
}, new Action() {
@Override
public void run() throws Exception {
Log.i("settingfffff", "onComplete");
}
});
when i = 1,send the error and the event stoped, I hope continue, How can I do?
java
android rx-java edited Nov 22 at 6:30
Milind Mevada
1,335617
asked Nov 22 at 3:55
mars
61
See reactivex.io/RxJava/2.x/javadoc/io/reactivex/…
– akarnokd
Nov 22 at 8:25
add a comment |
up vote
1
down vote
favorite
up vote
1
down vote
favorite
I have four Http Url, I need to try one by one.But there is a problem,when one of the url is error,the after url not call. The pseudocode like this:
i = 0;
Observable.fromArray("http://www.baidu.com/", "http://www.google.com/", "https://www.bing.com/")
.concatMap(new Function<String, ObservableSource<String>>() {
@Override
public ObservableSource<String> apply(String s) throws Exception {
return Observable.create(new ObservableOnSubscribe<String>() {
@Override
public void subscribe(ObservableEmitter<String> emitter) throws Exception {
Log.i("settingsubscribe", i + "");
if (i == 1) {
emitter.onError(new Throwable("error"));
//emitter.onComplete();
} else {
emitter.onNext(s.concat("_1"));
emitter.onComplete();
}
i ++;
}
});
}
})
.subscribe(new Consumer<String>() {
@Override
public void accept(String s) throws Exception {
Log.i("settingfffff", s);
}
}, new Consumer<Throwable>() {
@Override
public void accept(Throwable throwable) throws Exception {
Log.i("settingfffff", throwable.getMessage());
}
}, new Action() {
@Override
public void run() throws Exception {
Log.i("settingfffff", "onComplete");
}
});
when i = 1,send the error and the event stoped, I hope continue, How can I do?
java
android rx-java edited Nov 22 at 6:30
Milind Mevada
1,335617
asked Nov 22 at 3:55
mars
61
I have four Http Url, I need to try one by one.But there is a problem,when one of the url is error,the after url not call. The pseudocode like this:
i = 0;
Observable.fromArray("http://www.baidu.com/", "http://www.google.com/", "https://www.bing.com/")
.concatMap(new Function<String, ObservableSource<String>>() {
@Override
public ObservableSource<String> apply(String s) throws Exception {
return Observable.create(new ObservableOnSubscribe<String>() {
@Override
public void subscribe(ObservableEmitter<String> emitter) throws Exception {
Log.i("settingsubscribe", i + "");
if (i == 1) {
emitter.onError(new Throwable("error"));
//emitter.onComplete();
} else {
emitter.onNext(s.concat("_1"));
emitter.onComplete();
}
i ++;
}
});
}
})
.subscribe(new Consumer<String>() {
@Override
public void accept(String s) throws Exception {
Log.i("settingfffff", s);
}
}, new Consumer<Throwable>() {
@Override
public void accept(Throwable throwable) throws Exception {
Log.i("settingfffff", throwable.getMessage());
}
}, new Action() {
@Override
public void run() throws Exception {
Log.i("settingfffff", "onComplete");
}
});
when i = 1,send the error and the event stoped, I hope continue, How can I do?
java
android rx-java java
android rx-java edited Nov 22 at 6:30
Milind Mevada
1,335617
asked Nov 22 at 3:55
mars
61
edited Nov 22 at 6:30
Milind Mevada
1,335617
asked Nov 22 at 3:55
mars
61
edited Nov 22 at 6:30
Milind Mevada
1,335617
edited Nov 22 at 6:30
Milind Mevada
1,335617
edited Nov 22 at 6:30
Milind Mevada
1,335617
1,335617
asked Nov 22 at 3:55
mars
61
asked Nov 22 at 3:55
mars
61
asked Nov 22 at 3:55
mars
61
61
See reactivex.io/RxJava/2.x/javadoc/io/reactivex/…
– akarnokd
Nov 22 at 8:25
add a comment |
See reactivex.io/RxJava/2.x/javadoc/io/reactivex/…
– akarnokd
Nov 22 at 8:25
See reactivex.io/RxJava/2.x/javadoc/io/reactivex/…
– akarnokd
Nov 22 at 8:25
See reactivex.io/RxJava/2.x/javadoc/io/reactivex/…
– akarnokd
Nov 22 at 8:25
add a comment |
1 Answer
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emitter.onError(new Throwable("error"));
in above line of code, onError you are creating new Throwable, instead can you just log the error
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
emitter.onError(new Throwable("error"));
in above line of code, onError you are creating new Throwable, instead can you just log the error
add a comment |
up vote
0
down vote
emitter.onError(new Throwable("error"));
in above line of code, onError you are creating new Throwable, instead can you just log the error
add a comment |
up vote
0
down vote
up vote
0
down vote
emitter.onError(new Throwable("error"));
in above line of code, onError you are creating new Throwable, instead can you just log the error
emitter.onError(new Throwable("error"));
in above line of code, onError you are creating new Throwable, instead can you just log the error
answered Nov 22 at 5:59
user7154703
add a comment |
add a comment |
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See reactivex.io/RxJava/2.x/javadoc/io/reactivex/…
– akarnokd
Nov 22 at 8:25