c++ Trying to delete last row and column of a 2d array











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I am trying to delete last row and the last column of a 2d array. I created this method for this purpose.



void deleteLastRowColumn(int **A, int row, int column)
{
int **temp = A;
A = new int *[row - 1];
for (int i = 0; i < row - 1; i++)
{
A[i] = new int[column - 1];
for (int j = 0; j < column - 1; j++)
{
A[i][j] = temp[i][j];
}
delete temp[i];
}
}


and printing the result with



void printArray(int **a, int row, int column)
{
for (int i = 0; i < row; i++)
{
for (int j = 0; j < column; j++)
{
cout << a[i][j] << " ";
}
cout << endl;
}
}


And my main method creates a 5x5 array



int main()
{
int **a;
a = new int *[5];
for (int i = 0; i < 5; i++)
a[i] = new int[5];
for(int i = 0; i < 5; i++)
{
for(int j = 0; j < 5; j++)
{
a[i][j] = (i*5) + j + 1;
}
}
printArray(a, 5, 5);
cout << "nnnn";
deleteLastRowColumn(a,5,5);
printArray(a,4,4);
}


The output didn't make sense to me:



1   2   3   4   5   
6 7 8 9 10
11 12 13 14 15
16 17 18 19 20
21 22 23 24 25




6 7 8 9
11 12 13 14
16 17 18 19
0 0 18 19


I expected it to remove last column and last row but something different happened. If you can explain me what's wrong here that would be great!



Thank you.










share|improve this question


















  • 1




    Are you willing to switch from pointers to std::vector?
    – Micha Wiedenmann
    Nov 22 at 13:56






  • 4




    If you want to change A in deleteLastRowColumn - pass it by reference.
    – Algirdas Preidžius
    Nov 22 at 13:56










  • @MichaWiedenmann I wish I could. The course I'm taking doesn't let me...
    – burakokumus
    Nov 22 at 14:03










  • @burakokumus: That is a problem in your course. You can only change *A, not A, so you cannot resize both dimensions. Therefore, A remains a (int*)[5], The best you can do is to set A[0] to A[3] to int[4] and A[4] to nullptr.
    – MSalters
    Nov 22 at 14:08










  • I made the change proposed by Algirdas Preidzius and test it, it works. Just add a delete tempat the end of the function, but it was not the cause of the problem
    – Damien
    Nov 22 at 15:13















up vote
0
down vote

favorite












I am trying to delete last row and the last column of a 2d array. I created this method for this purpose.



void deleteLastRowColumn(int **A, int row, int column)
{
int **temp = A;
A = new int *[row - 1];
for (int i = 0; i < row - 1; i++)
{
A[i] = new int[column - 1];
for (int j = 0; j < column - 1; j++)
{
A[i][j] = temp[i][j];
}
delete temp[i];
}
}


and printing the result with



void printArray(int **a, int row, int column)
{
for (int i = 0; i < row; i++)
{
for (int j = 0; j < column; j++)
{
cout << a[i][j] << " ";
}
cout << endl;
}
}


And my main method creates a 5x5 array



int main()
{
int **a;
a = new int *[5];
for (int i = 0; i < 5; i++)
a[i] = new int[5];
for(int i = 0; i < 5; i++)
{
for(int j = 0; j < 5; j++)
{
a[i][j] = (i*5) + j + 1;
}
}
printArray(a, 5, 5);
cout << "nnnn";
deleteLastRowColumn(a,5,5);
printArray(a,4,4);
}


The output didn't make sense to me:



1   2   3   4   5   
6 7 8 9 10
11 12 13 14 15
16 17 18 19 20
21 22 23 24 25




6 7 8 9
11 12 13 14
16 17 18 19
0 0 18 19


I expected it to remove last column and last row but something different happened. If you can explain me what's wrong here that would be great!



Thank you.










share|improve this question


















  • 1




    Are you willing to switch from pointers to std::vector?
    – Micha Wiedenmann
    Nov 22 at 13:56






  • 4




    If you want to change A in deleteLastRowColumn - pass it by reference.
    – Algirdas Preidžius
    Nov 22 at 13:56










  • @MichaWiedenmann I wish I could. The course I'm taking doesn't let me...
    – burakokumus
    Nov 22 at 14:03










  • @burakokumus: That is a problem in your course. You can only change *A, not A, so you cannot resize both dimensions. Therefore, A remains a (int*)[5], The best you can do is to set A[0] to A[3] to int[4] and A[4] to nullptr.
    – MSalters
    Nov 22 at 14:08










  • I made the change proposed by Algirdas Preidzius and test it, it works. Just add a delete tempat the end of the function, but it was not the cause of the problem
    – Damien
    Nov 22 at 15:13













up vote
0
down vote

favorite









up vote
0
down vote

favorite











I am trying to delete last row and the last column of a 2d array. I created this method for this purpose.



void deleteLastRowColumn(int **A, int row, int column)
{
int **temp = A;
A = new int *[row - 1];
for (int i = 0; i < row - 1; i++)
{
A[i] = new int[column - 1];
for (int j = 0; j < column - 1; j++)
{
A[i][j] = temp[i][j];
}
delete temp[i];
}
}


and printing the result with



void printArray(int **a, int row, int column)
{
for (int i = 0; i < row; i++)
{
for (int j = 0; j < column; j++)
{
cout << a[i][j] << " ";
}
cout << endl;
}
}


And my main method creates a 5x5 array



int main()
{
int **a;
a = new int *[5];
for (int i = 0; i < 5; i++)
a[i] = new int[5];
for(int i = 0; i < 5; i++)
{
for(int j = 0; j < 5; j++)
{
a[i][j] = (i*5) + j + 1;
}
}
printArray(a, 5, 5);
cout << "nnnn";
deleteLastRowColumn(a,5,5);
printArray(a,4,4);
}


The output didn't make sense to me:



1   2   3   4   5   
6 7 8 9 10
11 12 13 14 15
16 17 18 19 20
21 22 23 24 25




6 7 8 9
11 12 13 14
16 17 18 19
0 0 18 19


I expected it to remove last column and last row but something different happened. If you can explain me what's wrong here that would be great!



Thank you.










share|improve this question













I am trying to delete last row and the last column of a 2d array. I created this method for this purpose.



void deleteLastRowColumn(int **A, int row, int column)
{
int **temp = A;
A = new int *[row - 1];
for (int i = 0; i < row - 1; i++)
{
A[i] = new int[column - 1];
for (int j = 0; j < column - 1; j++)
{
A[i][j] = temp[i][j];
}
delete temp[i];
}
}


and printing the result with



void printArray(int **a, int row, int column)
{
for (int i = 0; i < row; i++)
{
for (int j = 0; j < column; j++)
{
cout << a[i][j] << " ";
}
cout << endl;
}
}


And my main method creates a 5x5 array



int main()
{
int **a;
a = new int *[5];
for (int i = 0; i < 5; i++)
a[i] = new int[5];
for(int i = 0; i < 5; i++)
{
for(int j = 0; j < 5; j++)
{
a[i][j] = (i*5) + j + 1;
}
}
printArray(a, 5, 5);
cout << "nnnn";
deleteLastRowColumn(a,5,5);
printArray(a,4,4);
}


The output didn't make sense to me:



1   2   3   4   5   
6 7 8 9 10
11 12 13 14 15
16 17 18 19 20
21 22 23 24 25




6 7 8 9
11 12 13 14
16 17 18 19
0 0 18 19


I expected it to remove last column and last row but something different happened. If you can explain me what's wrong here that would be great!



Thank you.







c++ arrays dynamic-arrays






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 22 at 13:53









burakokumus

41




41








  • 1




    Are you willing to switch from pointers to std::vector?
    – Micha Wiedenmann
    Nov 22 at 13:56






  • 4




    If you want to change A in deleteLastRowColumn - pass it by reference.
    – Algirdas Preidžius
    Nov 22 at 13:56










  • @MichaWiedenmann I wish I could. The course I'm taking doesn't let me...
    – burakokumus
    Nov 22 at 14:03










  • @burakokumus: That is a problem in your course. You can only change *A, not A, so you cannot resize both dimensions. Therefore, A remains a (int*)[5], The best you can do is to set A[0] to A[3] to int[4] and A[4] to nullptr.
    – MSalters
    Nov 22 at 14:08










  • I made the change proposed by Algirdas Preidzius and test it, it works. Just add a delete tempat the end of the function, but it was not the cause of the problem
    – Damien
    Nov 22 at 15:13














  • 1




    Are you willing to switch from pointers to std::vector?
    – Micha Wiedenmann
    Nov 22 at 13:56






  • 4




    If you want to change A in deleteLastRowColumn - pass it by reference.
    – Algirdas Preidžius
    Nov 22 at 13:56










  • @MichaWiedenmann I wish I could. The course I'm taking doesn't let me...
    – burakokumus
    Nov 22 at 14:03










  • @burakokumus: That is a problem in your course. You can only change *A, not A, so you cannot resize both dimensions. Therefore, A remains a (int*)[5], The best you can do is to set A[0] to A[3] to int[4] and A[4] to nullptr.
    – MSalters
    Nov 22 at 14:08










  • I made the change proposed by Algirdas Preidzius and test it, it works. Just add a delete tempat the end of the function, but it was not the cause of the problem
    – Damien
    Nov 22 at 15:13








1




1




Are you willing to switch from pointers to std::vector?
– Micha Wiedenmann
Nov 22 at 13:56




Are you willing to switch from pointers to std::vector?
– Micha Wiedenmann
Nov 22 at 13:56




4




4




If you want to change A in deleteLastRowColumn - pass it by reference.
– Algirdas Preidžius
Nov 22 at 13:56




If you want to change A in deleteLastRowColumn - pass it by reference.
– Algirdas Preidžius
Nov 22 at 13:56












@MichaWiedenmann I wish I could. The course I'm taking doesn't let me...
– burakokumus
Nov 22 at 14:03




@MichaWiedenmann I wish I could. The course I'm taking doesn't let me...
– burakokumus
Nov 22 at 14:03












@burakokumus: That is a problem in your course. You can only change *A, not A, so you cannot resize both dimensions. Therefore, A remains a (int*)[5], The best you can do is to set A[0] to A[3] to int[4] and A[4] to nullptr.
– MSalters
Nov 22 at 14:08




@burakokumus: That is a problem in your course. You can only change *A, not A, so you cannot resize both dimensions. Therefore, A remains a (int*)[5], The best you can do is to set A[0] to A[3] to int[4] and A[4] to nullptr.
– MSalters
Nov 22 at 14:08












I made the change proposed by Algirdas Preidzius and test it, it works. Just add a delete tempat the end of the function, but it was not the cause of the problem
– Damien
Nov 22 at 15:13




I made the change proposed by Algirdas Preidzius and test it, it works. Just add a delete tempat the end of the function, but it was not the cause of the problem
– Damien
Nov 22 at 15:13

















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