How to evaluate df(x)/dx at x=c rather than df(c)/dx?











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The following macros define f[#1] and its derivative fp[#1].



deff[#1]{((#1)*(#1-1)*(#1-2)*(#1-3)*(#1-5)/10+1.5)}
edeffp[#1]{Derive(1,f[#1])}


Question



How to evaluate fp[0.8] that means the value of df/dx at x=0.8 rather than df[0.8]/dx that always equals to zero?



MWE



documentclass[pstricks]{standalone}
usepackage{pstricks-add}

deff[#1]{((#1)*(#1-1)*(#1-2)*(#1-3)*(#1-5)/10+1.5)}
edeffp[#1]{Derive(1,f[#1])}
edefg[#1]#2{(fp[#2]*((#1)-(#2))+f[#2])}

psset{algebraic,plotpoints=200,unit=2cm}
begin{document}
begin{pspicture}(-.75,-2)(5.75,3)
psplot[linecolor=red]{-.25}{5}{f[x]}
psplot[linecolor=green]{-.25}{5}{g[x]{.8}}
end{pspicture}
end{document}


enter image description here









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    up vote
    0
    down vote

    favorite












    The following macros define f[#1] and its derivative fp[#1].



    deff[#1]{((#1)*(#1-1)*(#1-2)*(#1-3)*(#1-5)/10+1.5)}
    edeffp[#1]{Derive(1,f[#1])}


    Question



    How to evaluate fp[0.8] that means the value of df/dx at x=0.8 rather than df[0.8]/dx that always equals to zero?



    MWE



    documentclass[pstricks]{standalone}
    usepackage{pstricks-add}

    deff[#1]{((#1)*(#1-1)*(#1-2)*(#1-3)*(#1-5)/10+1.5)}
    edeffp[#1]{Derive(1,f[#1])}
    edefg[#1]#2{(fp[#2]*((#1)-(#2))+f[#2])}

    psset{algebraic,plotpoints=200,unit=2cm}
    begin{document}
    begin{pspicture}(-.75,-2)(5.75,3)
    psplot[linecolor=red]{-.25}{5}{f[x]}
    psplot[linecolor=green]{-.25}{5}{g[x]{.8}}
    end{pspicture}
    end{document}


    enter image description here









    share
























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      The following macros define f[#1] and its derivative fp[#1].



      deff[#1]{((#1)*(#1-1)*(#1-2)*(#1-3)*(#1-5)/10+1.5)}
      edeffp[#1]{Derive(1,f[#1])}


      Question



      How to evaluate fp[0.8] that means the value of df/dx at x=0.8 rather than df[0.8]/dx that always equals to zero?



      MWE



      documentclass[pstricks]{standalone}
      usepackage{pstricks-add}

      deff[#1]{((#1)*(#1-1)*(#1-2)*(#1-3)*(#1-5)/10+1.5)}
      edeffp[#1]{Derive(1,f[#1])}
      edefg[#1]#2{(fp[#2]*((#1)-(#2))+f[#2])}

      psset{algebraic,plotpoints=200,unit=2cm}
      begin{document}
      begin{pspicture}(-.75,-2)(5.75,3)
      psplot[linecolor=red]{-.25}{5}{f[x]}
      psplot[linecolor=green]{-.25}{5}{g[x]{.8}}
      end{pspicture}
      end{document}


      enter image description here









      share













      The following macros define f[#1] and its derivative fp[#1].



      deff[#1]{((#1)*(#1-1)*(#1-2)*(#1-3)*(#1-5)/10+1.5)}
      edeffp[#1]{Derive(1,f[#1])}


      Question



      How to evaluate fp[0.8] that means the value of df/dx at x=0.8 rather than df[0.8]/dx that always equals to zero?



      MWE



      documentclass[pstricks]{standalone}
      usepackage{pstricks-add}

      deff[#1]{((#1)*(#1-1)*(#1-2)*(#1-3)*(#1-5)/10+1.5)}
      edeffp[#1]{Derive(1,f[#1])}
      edefg[#1]#2{(fp[#2]*((#1)-(#2))+f[#2])}

      psset{algebraic,plotpoints=200,unit=2cm}
      begin{document}
      begin{pspicture}(-.75,-2)(5.75,3)
      psplot[linecolor=red]{-.25}{5}{f[x]}
      psplot[linecolor=green]{-.25}{5}{g[x]{.8}}
      end{pspicture}
      end{document}


      enter image description here







      pstricks pst-plot pstricks-add





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