How do I calculate n modulo 3 in LaTeX?











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I don't want to display the modulo symbol, I want to programmatically calculate n modulo 3 and display the result.










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migrated from stackoverflow.com Nov 11 '11 at 0:54


This question came from our site for professional and enthusiast programmers.



















    up vote
    42
    down vote

    favorite
    9












    I don't want to display the modulo symbol, I want to programmatically calculate n modulo 3 and display the result.










    share|improve this question















    migrated from stackoverflow.com Nov 11 '11 at 0:54


    This question came from our site for professional and enthusiast programmers.

















      up vote
      42
      down vote

      favorite
      9









      up vote
      42
      down vote

      favorite
      9






      9





      I don't want to display the modulo symbol, I want to programmatically calculate n modulo 3 and display the result.










      share|improve this question















      I don't want to display the modulo symbol, I want to programmatically calculate n modulo 3 and display the result.







      calculations






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 11 '11 at 1:47









      Gonzalo Medina

      392k4012861555




      392k4012861555










      asked Nov 11 '11 at 0:03









      mcandre

      4111511




      4111511




      migrated from stackoverflow.com Nov 11 '11 at 0:54


      This question came from our site for professional and enthusiast programmers.






      migrated from stackoverflow.com Nov 11 '11 at 0:54


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          8 Answers
          8






          active

          oldest

          votes

















          up vote
          30
          down vote



          accepted










          You can also use intcalcMod from the intcalc package:



          documentclass{article}
          usepackage{amsmath}
          usepackage{ifthen}
          usepackage{intcalc}

          newcounter{mycount}
          newcommandNmodiii[1]{%
          setcounter{mycount}{0}whiledo{value{mycount}<#1}
          {$themycountpmod 3=intcalcMod{value{mycount}}{3}$\stepcounter{mycount}}
          }
          begin{document}

          noindent A little example: $8pmod 3=intcalcMod{8}{3}$

          noindent And a little loop:\
          Nmodiii{20}

          end{document}


          enter image description here



          The code that appears in the link posted in a comment, there are some spurious blank spaces producing an undesired indentation of the first line; here's a corrected version:



          documentclass{article}
          usepackage{ifthen}
          usepackage{forloop}
          usepackage{fmtcount}
          usepackage{intcalc}
          usepackage{multicol}

          begin{document}
          begin{multicols}{2}
          newcounter{i}
          noindentforloop{i}{1}{value{i} < 101}{%
          ifthenelse{equal{intcalcMod{value{i}}{15}}{0}}{
          FizzBuzz
          }{%
          ifthenelse{equal{intcalcMod{value{i}}{3}}{0}}{
          Fizz
          }{%
          ifthenelse{equal{intcalcMod{value{i}}{5}}{0}}{
          Buzz
          }{%
          thei
          }
          }
          }\
          }
          end{multicols}
          end{document}





          share|improve this answer























          • ! Missing number, treated as zero. <to be read again> v l.32 }
            – mcandre
            Nov 11 '11 at 1:13










          • Thanks, that helps. I'm writing FizzBuzz for LaTeX, so I need to use the mod result in further calculations, not just display it.
            – mcandre
            Nov 11 '11 at 1:14










          • @mcandre: nothing prevents you from using the result in your calculations!
            – Gonzalo Medina
            Nov 11 '11 at 1:15










          • Hmm. When I do this, I get ! Missing number, treated as zero. github.com/mcandre/mcandre/blob/master/latex/fizzy.tex
            – mcandre
            Nov 11 '11 at 1:30










          • You are using "value" in your code and you should use value (with a backslash). Also, you could have included that code in an edit to your original question.
            – Gonzalo Medina
            Nov 11 '11 at 1:34


















          up vote
          29
          down vote













          There are several nice answers using different packages. I'd like to note that TeX uses integer arithmetics, so it is easy to program the standard formula a-(a/b)*b, where / means integer division.



          Plain TeX solution:



          newcounttmpcnta
          defmodulo#1#2{tmpcnta=#1
          dividetmpcnta by #2
          multiplytmpcnta by #2
          multiplytmpcnta by -1
          advancetmpcnta by #1relax
          thetmpcnta}
          modulo{17}{3}
          modulo{19}{3}
          bye


          LaTeX solution:



          documentclass{article} 
          makeatletter
          newcommandmodulo[2]{@tempcnta=#1
          divide@tempcnta by #2
          multiply@tempcnta by #2
          multiply@tempcnta by -1
          advance@tempcnta by #1relax
          the@tempcnta}
          makeatother
          begin{document}
          modulo{17}{3}
          modulo{19}{3}
          end{document}





          share|improve this answer























          • I used a similar solution in a calendar.
            – starblue
            Nov 11 '11 at 14:21






          • 1




            Why can't you write divide#1 by #2 or dividenumbernumexpr#1relax by #2?
            – A.Ellett
            Dec 19 '13 at 7:52






          • 1




            @A.Ellett divide mutates (changes) the thing being divided (as do multiply and advance), and so we want to change our own counter tmpcnta rather than #1.
            – ShreevatsaR
            Nov 2 '17 at 20:30


















          up vote
          21
          down vote













          The fp package is small and provides the functionality to do quite complex arithmetic. In the minimal example below the macro modulo{<a>}{<b>} stores the result of <a> mod <b> in the macro result, which is then directly printed:



          enter image description here



          documentclass{article}
          usepackage[nomessages]{fp}% http://ctan.org/pkg/fp
          newcommand{modulo}[2]{%
          FPeval{result}{trunc(#1-(#2*trunc(#1/#2,0)),0)}result%
          }
          begin{document}
          Some modular arithmetic:
          begin{itemize}
          item $512 pmod{7}=modulo{512}{7}$
          item $6 pmod{4}=modulo{6}{4}$
          item $15 pmod{4}=modulo{15}{4}$
          item $1234567 pmod{3}=modulo{1234567}{3}$
          end{itemize}
          end{document}


          Since the result is stored in result, it can be used later in the text as well, until another execution of modulo will overwrite result.



          Similar functionality in terms of mathematical functions is provided with pgf as well.






          share|improve this answer





















          • ! Undefined control sequence. FP@@upn ...on string "#2string "}edef FP@tmp {[#2]}expandafter FP@upn... l.38 }
            – mcandre
            Nov 11 '11 at 0:42










          • Do you receive this error when compiling my MWE?
            – Werner
            Nov 11 '11 at 0:47










          • Yes. Specs: TeXworks on Mac OS X 10.7.2.
            – mcandre
            Nov 11 '11 at 0:53










          • What distribution of TeX do you have installed? I have TeX Live 2011 with fp verion 1995/04/02.
            – Werner
            Nov 11 '11 at 0:58






          • 2




            I like that a LaTeX solution to doing modular arithmetic is to load a package designed to do floating point calculations. WHAT!?
            – Seamus
            Feb 2 '12 at 17:08


















          up vote
          21
          down vote













          The "expandable" version, using e-TeX's numexpr:



          deftruncdiv#1#2{((#1-(#2-1)/2)/#2)}
          defmoduloop#1#2{(#1-truncdiv{#1}{#2}*#2)}
          defmodulo#1#2{numbernumexprmoduloop{#1}{#2}relax}


          truncdiv and moduloop can be plugged into other expressions. It's necessary to do like this because numexpr performs rounded integer division.






          share|improve this answer





















          • the same idea was used in the calendarweek TeX package.
            – ogerard
            Jun 5 '13 at 9:27






          • 1




            Hmm, from truncdiv{0}{64} I get -1 and so modulo{0}{64} gives 64.
            – ShreevatsaR
            Nov 2 '17 at 20:26










          • I'm using the following for now, which works for positive #2: defmoduloop#1#2{ifnum numexpr(#1 - (#1/#2)*(#2))relax < 0 (#1 - (#1/#2)*(#2) + #2) else (#1 - (#1/#2)*(#2)) fi} and deftruncdiv#1#2{((#1 - moduloop{#1}{#2})/(#2))}
            – ShreevatsaR
            Nov 2 '17 at 20:44


















          up vote
          12
          down vote













          Another solution is to use pgfmath



          documentclass{article} 
          input{pgfutil-common.tex}
          usepackage{pgfkeys,pgfmath}
          begin{document}

          pgfmathparse{mod(20,6)} pgfmathresult %displays 2.0
          pgfmathtruncatemacro{myint}{ pgfmathresult}

          myint %displays 2
          end{document}





          share|improve this answer




























            up vote
            11
            down vote













            LaTeX3 (the expl3 package) also has a facility for computing modulus (moduli?), namely int_mod:nn.



            documentclass{article}
            usepackage{expl3}
            ExplSyntaxOn
            newcommand{mymod}[2]{int_mod:nn{#1}{#2}}
            ExplSyntaxOff
            begin{document}
            The residue of $45$ modulo $19$ is $mymod{45}{19}$.
            end{document}





            share|improve this answer




























              up vote
              7
              down vote













              You can use the calculator package then, type this code:



              MODULO{14}{3}{sol}

              $14pmod{3}=sol$





              share|improve this answer























              • Nice, a new package! But you might want to make it clearer that you are the package author...
                – clemens
                Jun 12 '12 at 10:35










              • How nice! :) Feel free to add your package to our list. And by the way, welcome to TeX.sx! :)
                – Paulo Cereda
                Jun 12 '12 at 10:54


















              up vote
              0
              down vote













              You may use calc package as long as the absolute values of the numbers are not exceeding 2^31-1=2147483647. Otherwise you may use bigintcalc package.



              documentclass{article}
              usepackage{amsmath}
              usepackage{calc}
              newcounter{modulo}
              newcommandmodulo[2]{%
              setcounter{modulo}{#1-(#1/#2)*#2}%
              arabic{modulo}%
              }
              begin{document}
              begin{align*}
              131 equiv modulo{131}{3} &pmod{3} \
              131 equiv modulo{131}{5} &pmod{5} \
              131 equiv modulo{131}{7} &pmod{7} \
              131 equiv modulo{131}{8} &pmod{8} \
              -97 equiv modulo{-97}{3} &pmod{3} \
              -97 equiv modulo{-97}{5} &pmod{5} \
              -97 equiv modulo{-97}{7} &pmod{7} \
              -97 equiv modulo{-97}{8} &pmod{8} \
              end{align*}
              end{document}


              result of modulo commands






              share|improve this answer





















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                8 Answers
                8






                active

                oldest

                votes








                8 Answers
                8






                active

                oldest

                votes









                active

                oldest

                votes






                active

                oldest

                votes








                up vote
                30
                down vote



                accepted










                You can also use intcalcMod from the intcalc package:



                documentclass{article}
                usepackage{amsmath}
                usepackage{ifthen}
                usepackage{intcalc}

                newcounter{mycount}
                newcommandNmodiii[1]{%
                setcounter{mycount}{0}whiledo{value{mycount}<#1}
                {$themycountpmod 3=intcalcMod{value{mycount}}{3}$\stepcounter{mycount}}
                }
                begin{document}

                noindent A little example: $8pmod 3=intcalcMod{8}{3}$

                noindent And a little loop:\
                Nmodiii{20}

                end{document}


                enter image description here



                The code that appears in the link posted in a comment, there are some spurious blank spaces producing an undesired indentation of the first line; here's a corrected version:



                documentclass{article}
                usepackage{ifthen}
                usepackage{forloop}
                usepackage{fmtcount}
                usepackage{intcalc}
                usepackage{multicol}

                begin{document}
                begin{multicols}{2}
                newcounter{i}
                noindentforloop{i}{1}{value{i} < 101}{%
                ifthenelse{equal{intcalcMod{value{i}}{15}}{0}}{
                FizzBuzz
                }{%
                ifthenelse{equal{intcalcMod{value{i}}{3}}{0}}{
                Fizz
                }{%
                ifthenelse{equal{intcalcMod{value{i}}{5}}{0}}{
                Buzz
                }{%
                thei
                }
                }
                }\
                }
                end{multicols}
                end{document}





                share|improve this answer























                • ! Missing number, treated as zero. <to be read again> v l.32 }
                  – mcandre
                  Nov 11 '11 at 1:13










                • Thanks, that helps. I'm writing FizzBuzz for LaTeX, so I need to use the mod result in further calculations, not just display it.
                  – mcandre
                  Nov 11 '11 at 1:14










                • @mcandre: nothing prevents you from using the result in your calculations!
                  – Gonzalo Medina
                  Nov 11 '11 at 1:15










                • Hmm. When I do this, I get ! Missing number, treated as zero. github.com/mcandre/mcandre/blob/master/latex/fizzy.tex
                  – mcandre
                  Nov 11 '11 at 1:30










                • You are using "value" in your code and you should use value (with a backslash). Also, you could have included that code in an edit to your original question.
                  – Gonzalo Medina
                  Nov 11 '11 at 1:34















                up vote
                30
                down vote



                accepted










                You can also use intcalcMod from the intcalc package:



                documentclass{article}
                usepackage{amsmath}
                usepackage{ifthen}
                usepackage{intcalc}

                newcounter{mycount}
                newcommandNmodiii[1]{%
                setcounter{mycount}{0}whiledo{value{mycount}<#1}
                {$themycountpmod 3=intcalcMod{value{mycount}}{3}$\stepcounter{mycount}}
                }
                begin{document}

                noindent A little example: $8pmod 3=intcalcMod{8}{3}$

                noindent And a little loop:\
                Nmodiii{20}

                end{document}


                enter image description here



                The code that appears in the link posted in a comment, there are some spurious blank spaces producing an undesired indentation of the first line; here's a corrected version:



                documentclass{article}
                usepackage{ifthen}
                usepackage{forloop}
                usepackage{fmtcount}
                usepackage{intcalc}
                usepackage{multicol}

                begin{document}
                begin{multicols}{2}
                newcounter{i}
                noindentforloop{i}{1}{value{i} < 101}{%
                ifthenelse{equal{intcalcMod{value{i}}{15}}{0}}{
                FizzBuzz
                }{%
                ifthenelse{equal{intcalcMod{value{i}}{3}}{0}}{
                Fizz
                }{%
                ifthenelse{equal{intcalcMod{value{i}}{5}}{0}}{
                Buzz
                }{%
                thei
                }
                }
                }\
                }
                end{multicols}
                end{document}





                share|improve this answer























                • ! Missing number, treated as zero. <to be read again> v l.32 }
                  – mcandre
                  Nov 11 '11 at 1:13










                • Thanks, that helps. I'm writing FizzBuzz for LaTeX, so I need to use the mod result in further calculations, not just display it.
                  – mcandre
                  Nov 11 '11 at 1:14










                • @mcandre: nothing prevents you from using the result in your calculations!
                  – Gonzalo Medina
                  Nov 11 '11 at 1:15










                • Hmm. When I do this, I get ! Missing number, treated as zero. github.com/mcandre/mcandre/blob/master/latex/fizzy.tex
                  – mcandre
                  Nov 11 '11 at 1:30










                • You are using "value" in your code and you should use value (with a backslash). Also, you could have included that code in an edit to your original question.
                  – Gonzalo Medina
                  Nov 11 '11 at 1:34













                up vote
                30
                down vote



                accepted







                up vote
                30
                down vote



                accepted






                You can also use intcalcMod from the intcalc package:



                documentclass{article}
                usepackage{amsmath}
                usepackage{ifthen}
                usepackage{intcalc}

                newcounter{mycount}
                newcommandNmodiii[1]{%
                setcounter{mycount}{0}whiledo{value{mycount}<#1}
                {$themycountpmod 3=intcalcMod{value{mycount}}{3}$\stepcounter{mycount}}
                }
                begin{document}

                noindent A little example: $8pmod 3=intcalcMod{8}{3}$

                noindent And a little loop:\
                Nmodiii{20}

                end{document}


                enter image description here



                The code that appears in the link posted in a comment, there are some spurious blank spaces producing an undesired indentation of the first line; here's a corrected version:



                documentclass{article}
                usepackage{ifthen}
                usepackage{forloop}
                usepackage{fmtcount}
                usepackage{intcalc}
                usepackage{multicol}

                begin{document}
                begin{multicols}{2}
                newcounter{i}
                noindentforloop{i}{1}{value{i} < 101}{%
                ifthenelse{equal{intcalcMod{value{i}}{15}}{0}}{
                FizzBuzz
                }{%
                ifthenelse{equal{intcalcMod{value{i}}{3}}{0}}{
                Fizz
                }{%
                ifthenelse{equal{intcalcMod{value{i}}{5}}{0}}{
                Buzz
                }{%
                thei
                }
                }
                }\
                }
                end{multicols}
                end{document}





                share|improve this answer














                You can also use intcalcMod from the intcalc package:



                documentclass{article}
                usepackage{amsmath}
                usepackage{ifthen}
                usepackage{intcalc}

                newcounter{mycount}
                newcommandNmodiii[1]{%
                setcounter{mycount}{0}whiledo{value{mycount}<#1}
                {$themycountpmod 3=intcalcMod{value{mycount}}{3}$\stepcounter{mycount}}
                }
                begin{document}

                noindent A little example: $8pmod 3=intcalcMod{8}{3}$

                noindent And a little loop:\
                Nmodiii{20}

                end{document}


                enter image description here



                The code that appears in the link posted in a comment, there are some spurious blank spaces producing an undesired indentation of the first line; here's a corrected version:



                documentclass{article}
                usepackage{ifthen}
                usepackage{forloop}
                usepackage{fmtcount}
                usepackage{intcalc}
                usepackage{multicol}

                begin{document}
                begin{multicols}{2}
                newcounter{i}
                noindentforloop{i}{1}{value{i} < 101}{%
                ifthenelse{equal{intcalcMod{value{i}}{15}}{0}}{
                FizzBuzz
                }{%
                ifthenelse{equal{intcalcMod{value{i}}{3}}{0}}{
                Fizz
                }{%
                ifthenelse{equal{intcalcMod{value{i}}{5}}{0}}{
                Buzz
                }{%
                thei
                }
                }
                }\
                }
                end{multicols}
                end{document}






                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited Jun 3 '17 at 12:06









                Moriambar

                7,82731845




                7,82731845










                answered Nov 11 '11 at 1:03









                Gonzalo Medina

                392k4012861555




                392k4012861555












                • ! Missing number, treated as zero. <to be read again> v l.32 }
                  – mcandre
                  Nov 11 '11 at 1:13










                • Thanks, that helps. I'm writing FizzBuzz for LaTeX, so I need to use the mod result in further calculations, not just display it.
                  – mcandre
                  Nov 11 '11 at 1:14










                • @mcandre: nothing prevents you from using the result in your calculations!
                  – Gonzalo Medina
                  Nov 11 '11 at 1:15










                • Hmm. When I do this, I get ! Missing number, treated as zero. github.com/mcandre/mcandre/blob/master/latex/fizzy.tex
                  – mcandre
                  Nov 11 '11 at 1:30










                • You are using "value" in your code and you should use value (with a backslash). Also, you could have included that code in an edit to your original question.
                  – Gonzalo Medina
                  Nov 11 '11 at 1:34


















                • ! Missing number, treated as zero. <to be read again> v l.32 }
                  – mcandre
                  Nov 11 '11 at 1:13










                • Thanks, that helps. I'm writing FizzBuzz for LaTeX, so I need to use the mod result in further calculations, not just display it.
                  – mcandre
                  Nov 11 '11 at 1:14










                • @mcandre: nothing prevents you from using the result in your calculations!
                  – Gonzalo Medina
                  Nov 11 '11 at 1:15










                • Hmm. When I do this, I get ! Missing number, treated as zero. github.com/mcandre/mcandre/blob/master/latex/fizzy.tex
                  – mcandre
                  Nov 11 '11 at 1:30










                • You are using "value" in your code and you should use value (with a backslash). Also, you could have included that code in an edit to your original question.
                  – Gonzalo Medina
                  Nov 11 '11 at 1:34
















                ! Missing number, treated as zero. <to be read again> v l.32 }
                – mcandre
                Nov 11 '11 at 1:13




                ! Missing number, treated as zero. <to be read again> v l.32 }
                – mcandre
                Nov 11 '11 at 1:13












                Thanks, that helps. I'm writing FizzBuzz for LaTeX, so I need to use the mod result in further calculations, not just display it.
                – mcandre
                Nov 11 '11 at 1:14




                Thanks, that helps. I'm writing FizzBuzz for LaTeX, so I need to use the mod result in further calculations, not just display it.
                – mcandre
                Nov 11 '11 at 1:14












                @mcandre: nothing prevents you from using the result in your calculations!
                – Gonzalo Medina
                Nov 11 '11 at 1:15




                @mcandre: nothing prevents you from using the result in your calculations!
                – Gonzalo Medina
                Nov 11 '11 at 1:15












                Hmm. When I do this, I get ! Missing number, treated as zero. github.com/mcandre/mcandre/blob/master/latex/fizzy.tex
                – mcandre
                Nov 11 '11 at 1:30




                Hmm. When I do this, I get ! Missing number, treated as zero. github.com/mcandre/mcandre/blob/master/latex/fizzy.tex
                – mcandre
                Nov 11 '11 at 1:30












                You are using "value" in your code and you should use value (with a backslash). Also, you could have included that code in an edit to your original question.
                – Gonzalo Medina
                Nov 11 '11 at 1:34




                You are using "value" in your code and you should use value (with a backslash). Also, you could have included that code in an edit to your original question.
                – Gonzalo Medina
                Nov 11 '11 at 1:34










                up vote
                29
                down vote













                There are several nice answers using different packages. I'd like to note that TeX uses integer arithmetics, so it is easy to program the standard formula a-(a/b)*b, where / means integer division.



                Plain TeX solution:



                newcounttmpcnta
                defmodulo#1#2{tmpcnta=#1
                dividetmpcnta by #2
                multiplytmpcnta by #2
                multiplytmpcnta by -1
                advancetmpcnta by #1relax
                thetmpcnta}
                modulo{17}{3}
                modulo{19}{3}
                bye


                LaTeX solution:



                documentclass{article} 
                makeatletter
                newcommandmodulo[2]{@tempcnta=#1
                divide@tempcnta by #2
                multiply@tempcnta by #2
                multiply@tempcnta by -1
                advance@tempcnta by #1relax
                the@tempcnta}
                makeatother
                begin{document}
                modulo{17}{3}
                modulo{19}{3}
                end{document}





                share|improve this answer























                • I used a similar solution in a calendar.
                  – starblue
                  Nov 11 '11 at 14:21






                • 1




                  Why can't you write divide#1 by #2 or dividenumbernumexpr#1relax by #2?
                  – A.Ellett
                  Dec 19 '13 at 7:52






                • 1




                  @A.Ellett divide mutates (changes) the thing being divided (as do multiply and advance), and so we want to change our own counter tmpcnta rather than #1.
                  – ShreevatsaR
                  Nov 2 '17 at 20:30















                up vote
                29
                down vote













                There are several nice answers using different packages. I'd like to note that TeX uses integer arithmetics, so it is easy to program the standard formula a-(a/b)*b, where / means integer division.



                Plain TeX solution:



                newcounttmpcnta
                defmodulo#1#2{tmpcnta=#1
                dividetmpcnta by #2
                multiplytmpcnta by #2
                multiplytmpcnta by -1
                advancetmpcnta by #1relax
                thetmpcnta}
                modulo{17}{3}
                modulo{19}{3}
                bye


                LaTeX solution:



                documentclass{article} 
                makeatletter
                newcommandmodulo[2]{@tempcnta=#1
                divide@tempcnta by #2
                multiply@tempcnta by #2
                multiply@tempcnta by -1
                advance@tempcnta by #1relax
                the@tempcnta}
                makeatother
                begin{document}
                modulo{17}{3}
                modulo{19}{3}
                end{document}





                share|improve this answer























                • I used a similar solution in a calendar.
                  – starblue
                  Nov 11 '11 at 14:21






                • 1




                  Why can't you write divide#1 by #2 or dividenumbernumexpr#1relax by #2?
                  – A.Ellett
                  Dec 19 '13 at 7:52






                • 1




                  @A.Ellett divide mutates (changes) the thing being divided (as do multiply and advance), and so we want to change our own counter tmpcnta rather than #1.
                  – ShreevatsaR
                  Nov 2 '17 at 20:30













                up vote
                29
                down vote










                up vote
                29
                down vote









                There are several nice answers using different packages. I'd like to note that TeX uses integer arithmetics, so it is easy to program the standard formula a-(a/b)*b, where / means integer division.



                Plain TeX solution:



                newcounttmpcnta
                defmodulo#1#2{tmpcnta=#1
                dividetmpcnta by #2
                multiplytmpcnta by #2
                multiplytmpcnta by -1
                advancetmpcnta by #1relax
                thetmpcnta}
                modulo{17}{3}
                modulo{19}{3}
                bye


                LaTeX solution:



                documentclass{article} 
                makeatletter
                newcommandmodulo[2]{@tempcnta=#1
                divide@tempcnta by #2
                multiply@tempcnta by #2
                multiply@tempcnta by -1
                advance@tempcnta by #1relax
                the@tempcnta}
                makeatother
                begin{document}
                modulo{17}{3}
                modulo{19}{3}
                end{document}





                share|improve this answer














                There are several nice answers using different packages. I'd like to note that TeX uses integer arithmetics, so it is easy to program the standard formula a-(a/b)*b, where / means integer division.



                Plain TeX solution:



                newcounttmpcnta
                defmodulo#1#2{tmpcnta=#1
                dividetmpcnta by #2
                multiplytmpcnta by #2
                multiplytmpcnta by -1
                advancetmpcnta by #1relax
                thetmpcnta}
                modulo{17}{3}
                modulo{19}{3}
                bye


                LaTeX solution:



                documentclass{article} 
                makeatletter
                newcommandmodulo[2]{@tempcnta=#1
                divide@tempcnta by #2
                multiply@tempcnta by #2
                multiply@tempcnta by -1
                advance@tempcnta by #1relax
                the@tempcnta}
                makeatother
                begin{document}
                modulo{17}{3}
                modulo{19}{3}
                end{document}






                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited Nov 11 '11 at 4:12









                Werner

                431k599501628




                431k599501628










                answered Nov 11 '11 at 3:34









                Boris

                29.8k262106




                29.8k262106












                • I used a similar solution in a calendar.
                  – starblue
                  Nov 11 '11 at 14:21






                • 1




                  Why can't you write divide#1 by #2 or dividenumbernumexpr#1relax by #2?
                  – A.Ellett
                  Dec 19 '13 at 7:52






                • 1




                  @A.Ellett divide mutates (changes) the thing being divided (as do multiply and advance), and so we want to change our own counter tmpcnta rather than #1.
                  – ShreevatsaR
                  Nov 2 '17 at 20:30


















                • I used a similar solution in a calendar.
                  – starblue
                  Nov 11 '11 at 14:21






                • 1




                  Why can't you write divide#1 by #2 or dividenumbernumexpr#1relax by #2?
                  – A.Ellett
                  Dec 19 '13 at 7:52






                • 1




                  @A.Ellett divide mutates (changes) the thing being divided (as do multiply and advance), and so we want to change our own counter tmpcnta rather than #1.
                  – ShreevatsaR
                  Nov 2 '17 at 20:30
















                I used a similar solution in a calendar.
                – starblue
                Nov 11 '11 at 14:21




                I used a similar solution in a calendar.
                – starblue
                Nov 11 '11 at 14:21




                1




                1




                Why can't you write divide#1 by #2 or dividenumbernumexpr#1relax by #2?
                – A.Ellett
                Dec 19 '13 at 7:52




                Why can't you write divide#1 by #2 or dividenumbernumexpr#1relax by #2?
                – A.Ellett
                Dec 19 '13 at 7:52




                1




                1




                @A.Ellett divide mutates (changes) the thing being divided (as do multiply and advance), and so we want to change our own counter tmpcnta rather than #1.
                – ShreevatsaR
                Nov 2 '17 at 20:30




                @A.Ellett divide mutates (changes) the thing being divided (as do multiply and advance), and so we want to change our own counter tmpcnta rather than #1.
                – ShreevatsaR
                Nov 2 '17 at 20:30










                up vote
                21
                down vote













                The fp package is small and provides the functionality to do quite complex arithmetic. In the minimal example below the macro modulo{<a>}{<b>} stores the result of <a> mod <b> in the macro result, which is then directly printed:



                enter image description here



                documentclass{article}
                usepackage[nomessages]{fp}% http://ctan.org/pkg/fp
                newcommand{modulo}[2]{%
                FPeval{result}{trunc(#1-(#2*trunc(#1/#2,0)),0)}result%
                }
                begin{document}
                Some modular arithmetic:
                begin{itemize}
                item $512 pmod{7}=modulo{512}{7}$
                item $6 pmod{4}=modulo{6}{4}$
                item $15 pmod{4}=modulo{15}{4}$
                item $1234567 pmod{3}=modulo{1234567}{3}$
                end{itemize}
                end{document}


                Since the result is stored in result, it can be used later in the text as well, until another execution of modulo will overwrite result.



                Similar functionality in terms of mathematical functions is provided with pgf as well.






                share|improve this answer





















                • ! Undefined control sequence. FP@@upn ...on string "#2string "}edef FP@tmp {[#2]}expandafter FP@upn... l.38 }
                  – mcandre
                  Nov 11 '11 at 0:42










                • Do you receive this error when compiling my MWE?
                  – Werner
                  Nov 11 '11 at 0:47










                • Yes. Specs: TeXworks on Mac OS X 10.7.2.
                  – mcandre
                  Nov 11 '11 at 0:53










                • What distribution of TeX do you have installed? I have TeX Live 2011 with fp verion 1995/04/02.
                  – Werner
                  Nov 11 '11 at 0:58






                • 2




                  I like that a LaTeX solution to doing modular arithmetic is to load a package designed to do floating point calculations. WHAT!?
                  – Seamus
                  Feb 2 '12 at 17:08















                up vote
                21
                down vote













                The fp package is small and provides the functionality to do quite complex arithmetic. In the minimal example below the macro modulo{<a>}{<b>} stores the result of <a> mod <b> in the macro result, which is then directly printed:



                enter image description here



                documentclass{article}
                usepackage[nomessages]{fp}% http://ctan.org/pkg/fp
                newcommand{modulo}[2]{%
                FPeval{result}{trunc(#1-(#2*trunc(#1/#2,0)),0)}result%
                }
                begin{document}
                Some modular arithmetic:
                begin{itemize}
                item $512 pmod{7}=modulo{512}{7}$
                item $6 pmod{4}=modulo{6}{4}$
                item $15 pmod{4}=modulo{15}{4}$
                item $1234567 pmod{3}=modulo{1234567}{3}$
                end{itemize}
                end{document}


                Since the result is stored in result, it can be used later in the text as well, until another execution of modulo will overwrite result.



                Similar functionality in terms of mathematical functions is provided with pgf as well.






                share|improve this answer





















                • ! Undefined control sequence. FP@@upn ...on string "#2string "}edef FP@tmp {[#2]}expandafter FP@upn... l.38 }
                  – mcandre
                  Nov 11 '11 at 0:42










                • Do you receive this error when compiling my MWE?
                  – Werner
                  Nov 11 '11 at 0:47










                • Yes. Specs: TeXworks on Mac OS X 10.7.2.
                  – mcandre
                  Nov 11 '11 at 0:53










                • What distribution of TeX do you have installed? I have TeX Live 2011 with fp verion 1995/04/02.
                  – Werner
                  Nov 11 '11 at 0:58






                • 2




                  I like that a LaTeX solution to doing modular arithmetic is to load a package designed to do floating point calculations. WHAT!?
                  – Seamus
                  Feb 2 '12 at 17:08













                up vote
                21
                down vote










                up vote
                21
                down vote









                The fp package is small and provides the functionality to do quite complex arithmetic. In the minimal example below the macro modulo{<a>}{<b>} stores the result of <a> mod <b> in the macro result, which is then directly printed:



                enter image description here



                documentclass{article}
                usepackage[nomessages]{fp}% http://ctan.org/pkg/fp
                newcommand{modulo}[2]{%
                FPeval{result}{trunc(#1-(#2*trunc(#1/#2,0)),0)}result%
                }
                begin{document}
                Some modular arithmetic:
                begin{itemize}
                item $512 pmod{7}=modulo{512}{7}$
                item $6 pmod{4}=modulo{6}{4}$
                item $15 pmod{4}=modulo{15}{4}$
                item $1234567 pmod{3}=modulo{1234567}{3}$
                end{itemize}
                end{document}


                Since the result is stored in result, it can be used later in the text as well, until another execution of modulo will overwrite result.



                Similar functionality in terms of mathematical functions is provided with pgf as well.






                share|improve this answer












                The fp package is small and provides the functionality to do quite complex arithmetic. In the minimal example below the macro modulo{<a>}{<b>} stores the result of <a> mod <b> in the macro result, which is then directly printed:



                enter image description here



                documentclass{article}
                usepackage[nomessages]{fp}% http://ctan.org/pkg/fp
                newcommand{modulo}[2]{%
                FPeval{result}{trunc(#1-(#2*trunc(#1/#2,0)),0)}result%
                }
                begin{document}
                Some modular arithmetic:
                begin{itemize}
                item $512 pmod{7}=modulo{512}{7}$
                item $6 pmod{4}=modulo{6}{4}$
                item $15 pmod{4}=modulo{15}{4}$
                item $1234567 pmod{3}=modulo{1234567}{3}$
                end{itemize}
                end{document}


                Since the result is stored in result, it can be used later in the text as well, until another execution of modulo will overwrite result.



                Similar functionality in terms of mathematical functions is provided with pgf as well.







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 11 '11 at 0:30









                Werner

                431k599501628




                431k599501628












                • ! Undefined control sequence. FP@@upn ...on string "#2string "}edef FP@tmp {[#2]}expandafter FP@upn... l.38 }
                  – mcandre
                  Nov 11 '11 at 0:42










                • Do you receive this error when compiling my MWE?
                  – Werner
                  Nov 11 '11 at 0:47










                • Yes. Specs: TeXworks on Mac OS X 10.7.2.
                  – mcandre
                  Nov 11 '11 at 0:53










                • What distribution of TeX do you have installed? I have TeX Live 2011 with fp verion 1995/04/02.
                  – Werner
                  Nov 11 '11 at 0:58






                • 2




                  I like that a LaTeX solution to doing modular arithmetic is to load a package designed to do floating point calculations. WHAT!?
                  – Seamus
                  Feb 2 '12 at 17:08


















                • ! Undefined control sequence. FP@@upn ...on string "#2string "}edef FP@tmp {[#2]}expandafter FP@upn... l.38 }
                  – mcandre
                  Nov 11 '11 at 0:42










                • Do you receive this error when compiling my MWE?
                  – Werner
                  Nov 11 '11 at 0:47










                • Yes. Specs: TeXworks on Mac OS X 10.7.2.
                  – mcandre
                  Nov 11 '11 at 0:53










                • What distribution of TeX do you have installed? I have TeX Live 2011 with fp verion 1995/04/02.
                  – Werner
                  Nov 11 '11 at 0:58






                • 2




                  I like that a LaTeX solution to doing modular arithmetic is to load a package designed to do floating point calculations. WHAT!?
                  – Seamus
                  Feb 2 '12 at 17:08
















                ! Undefined control sequence. FP@@upn ...on string "#2string "}edef FP@tmp {[#2]}expandafter FP@upn... l.38 }
                – mcandre
                Nov 11 '11 at 0:42




                ! Undefined control sequence. FP@@upn ...on string "#2string "}edef FP@tmp {[#2]}expandafter FP@upn... l.38 }
                – mcandre
                Nov 11 '11 at 0:42












                Do you receive this error when compiling my MWE?
                – Werner
                Nov 11 '11 at 0:47




                Do you receive this error when compiling my MWE?
                – Werner
                Nov 11 '11 at 0:47












                Yes. Specs: TeXworks on Mac OS X 10.7.2.
                – mcandre
                Nov 11 '11 at 0:53




                Yes. Specs: TeXworks on Mac OS X 10.7.2.
                – mcandre
                Nov 11 '11 at 0:53












                What distribution of TeX do you have installed? I have TeX Live 2011 with fp verion 1995/04/02.
                – Werner
                Nov 11 '11 at 0:58




                What distribution of TeX do you have installed? I have TeX Live 2011 with fp verion 1995/04/02.
                – Werner
                Nov 11 '11 at 0:58




                2




                2




                I like that a LaTeX solution to doing modular arithmetic is to load a package designed to do floating point calculations. WHAT!?
                – Seamus
                Feb 2 '12 at 17:08




                I like that a LaTeX solution to doing modular arithmetic is to load a package designed to do floating point calculations. WHAT!?
                – Seamus
                Feb 2 '12 at 17:08










                up vote
                21
                down vote













                The "expandable" version, using e-TeX's numexpr:



                deftruncdiv#1#2{((#1-(#2-1)/2)/#2)}
                defmoduloop#1#2{(#1-truncdiv{#1}{#2}*#2)}
                defmodulo#1#2{numbernumexprmoduloop{#1}{#2}relax}


                truncdiv and moduloop can be plugged into other expressions. It's necessary to do like this because numexpr performs rounded integer division.






                share|improve this answer





















                • the same idea was used in the calendarweek TeX package.
                  – ogerard
                  Jun 5 '13 at 9:27






                • 1




                  Hmm, from truncdiv{0}{64} I get -1 and so modulo{0}{64} gives 64.
                  – ShreevatsaR
                  Nov 2 '17 at 20:26










                • I'm using the following for now, which works for positive #2: defmoduloop#1#2{ifnum numexpr(#1 - (#1/#2)*(#2))relax < 0 (#1 - (#1/#2)*(#2) + #2) else (#1 - (#1/#2)*(#2)) fi} and deftruncdiv#1#2{((#1 - moduloop{#1}{#2})/(#2))}
                  – ShreevatsaR
                  Nov 2 '17 at 20:44















                up vote
                21
                down vote













                The "expandable" version, using e-TeX's numexpr:



                deftruncdiv#1#2{((#1-(#2-1)/2)/#2)}
                defmoduloop#1#2{(#1-truncdiv{#1}{#2}*#2)}
                defmodulo#1#2{numbernumexprmoduloop{#1}{#2}relax}


                truncdiv and moduloop can be plugged into other expressions. It's necessary to do like this because numexpr performs rounded integer division.






                share|improve this answer





















                • the same idea was used in the calendarweek TeX package.
                  – ogerard
                  Jun 5 '13 at 9:27






                • 1




                  Hmm, from truncdiv{0}{64} I get -1 and so modulo{0}{64} gives 64.
                  – ShreevatsaR
                  Nov 2 '17 at 20:26










                • I'm using the following for now, which works for positive #2: defmoduloop#1#2{ifnum numexpr(#1 - (#1/#2)*(#2))relax < 0 (#1 - (#1/#2)*(#2) + #2) else (#1 - (#1/#2)*(#2)) fi} and deftruncdiv#1#2{((#1 - moduloop{#1}{#2})/(#2))}
                  – ShreevatsaR
                  Nov 2 '17 at 20:44













                up vote
                21
                down vote










                up vote
                21
                down vote









                The "expandable" version, using e-TeX's numexpr:



                deftruncdiv#1#2{((#1-(#2-1)/2)/#2)}
                defmoduloop#1#2{(#1-truncdiv{#1}{#2}*#2)}
                defmodulo#1#2{numbernumexprmoduloop{#1}{#2}relax}


                truncdiv and moduloop can be plugged into other expressions. It's necessary to do like this because numexpr performs rounded integer division.






                share|improve this answer












                The "expandable" version, using e-TeX's numexpr:



                deftruncdiv#1#2{((#1-(#2-1)/2)/#2)}
                defmoduloop#1#2{(#1-truncdiv{#1}{#2}*#2)}
                defmodulo#1#2{numbernumexprmoduloop{#1}{#2}relax}


                truncdiv and moduloop can be plugged into other expressions. It's necessary to do like this because numexpr performs rounded integer division.







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 11 '11 at 6:49









                egreg

                699k8518613132




                699k8518613132












                • the same idea was used in the calendarweek TeX package.
                  – ogerard
                  Jun 5 '13 at 9:27






                • 1




                  Hmm, from truncdiv{0}{64} I get -1 and so modulo{0}{64} gives 64.
                  – ShreevatsaR
                  Nov 2 '17 at 20:26










                • I'm using the following for now, which works for positive #2: defmoduloop#1#2{ifnum numexpr(#1 - (#1/#2)*(#2))relax < 0 (#1 - (#1/#2)*(#2) + #2) else (#1 - (#1/#2)*(#2)) fi} and deftruncdiv#1#2{((#1 - moduloop{#1}{#2})/(#2))}
                  – ShreevatsaR
                  Nov 2 '17 at 20:44


















                • the same idea was used in the calendarweek TeX package.
                  – ogerard
                  Jun 5 '13 at 9:27






                • 1




                  Hmm, from truncdiv{0}{64} I get -1 and so modulo{0}{64} gives 64.
                  – ShreevatsaR
                  Nov 2 '17 at 20:26










                • I'm using the following for now, which works for positive #2: defmoduloop#1#2{ifnum numexpr(#1 - (#1/#2)*(#2))relax < 0 (#1 - (#1/#2)*(#2) + #2) else (#1 - (#1/#2)*(#2)) fi} and deftruncdiv#1#2{((#1 - moduloop{#1}{#2})/(#2))}
                  – ShreevatsaR
                  Nov 2 '17 at 20:44
















                the same idea was used in the calendarweek TeX package.
                – ogerard
                Jun 5 '13 at 9:27




                the same idea was used in the calendarweek TeX package.
                – ogerard
                Jun 5 '13 at 9:27




                1




                1




                Hmm, from truncdiv{0}{64} I get -1 and so modulo{0}{64} gives 64.
                – ShreevatsaR
                Nov 2 '17 at 20:26




                Hmm, from truncdiv{0}{64} I get -1 and so modulo{0}{64} gives 64.
                – ShreevatsaR
                Nov 2 '17 at 20:26












                I'm using the following for now, which works for positive #2: defmoduloop#1#2{ifnum numexpr(#1 - (#1/#2)*(#2))relax < 0 (#1 - (#1/#2)*(#2) + #2) else (#1 - (#1/#2)*(#2)) fi} and deftruncdiv#1#2{((#1 - moduloop{#1}{#2})/(#2))}
                – ShreevatsaR
                Nov 2 '17 at 20:44




                I'm using the following for now, which works for positive #2: defmoduloop#1#2{ifnum numexpr(#1 - (#1/#2)*(#2))relax < 0 (#1 - (#1/#2)*(#2) + #2) else (#1 - (#1/#2)*(#2)) fi} and deftruncdiv#1#2{((#1 - moduloop{#1}{#2})/(#2))}
                – ShreevatsaR
                Nov 2 '17 at 20:44










                up vote
                12
                down vote













                Another solution is to use pgfmath



                documentclass{article} 
                input{pgfutil-common.tex}
                usepackage{pgfkeys,pgfmath}
                begin{document}

                pgfmathparse{mod(20,6)} pgfmathresult %displays 2.0
                pgfmathtruncatemacro{myint}{ pgfmathresult}

                myint %displays 2
                end{document}





                share|improve this answer

























                  up vote
                  12
                  down vote













                  Another solution is to use pgfmath



                  documentclass{article} 
                  input{pgfutil-common.tex}
                  usepackage{pgfkeys,pgfmath}
                  begin{document}

                  pgfmathparse{mod(20,6)} pgfmathresult %displays 2.0
                  pgfmathtruncatemacro{myint}{ pgfmathresult}

                  myint %displays 2
                  end{document}





                  share|improve this answer























                    up vote
                    12
                    down vote










                    up vote
                    12
                    down vote









                    Another solution is to use pgfmath



                    documentclass{article} 
                    input{pgfutil-common.tex}
                    usepackage{pgfkeys,pgfmath}
                    begin{document}

                    pgfmathparse{mod(20,6)} pgfmathresult %displays 2.0
                    pgfmathtruncatemacro{myint}{ pgfmathresult}

                    myint %displays 2
                    end{document}





                    share|improve this answer












                    Another solution is to use pgfmath



                    documentclass{article} 
                    input{pgfutil-common.tex}
                    usepackage{pgfkeys,pgfmath}
                    begin{document}

                    pgfmathparse{mod(20,6)} pgfmathresult %displays 2.0
                    pgfmathtruncatemacro{myint}{ pgfmathresult}

                    myint %displays 2
                    end{document}






                    share|improve this answer












                    share|improve this answer



                    share|improve this answer










                    answered Nov 11 '11 at 9:18









                    Alain Matthes

                    72k7158291




                    72k7158291






















                        up vote
                        11
                        down vote













                        LaTeX3 (the expl3 package) also has a facility for computing modulus (moduli?), namely int_mod:nn.



                        documentclass{article}
                        usepackage{expl3}
                        ExplSyntaxOn
                        newcommand{mymod}[2]{int_mod:nn{#1}{#2}}
                        ExplSyntaxOff
                        begin{document}
                        The residue of $45$ modulo $19$ is $mymod{45}{19}$.
                        end{document}





                        share|improve this answer

























                          up vote
                          11
                          down vote













                          LaTeX3 (the expl3 package) also has a facility for computing modulus (moduli?), namely int_mod:nn.



                          documentclass{article}
                          usepackage{expl3}
                          ExplSyntaxOn
                          newcommand{mymod}[2]{int_mod:nn{#1}{#2}}
                          ExplSyntaxOff
                          begin{document}
                          The residue of $45$ modulo $19$ is $mymod{45}{19}$.
                          end{document}





                          share|improve this answer























                            up vote
                            11
                            down vote










                            up vote
                            11
                            down vote









                            LaTeX3 (the expl3 package) also has a facility for computing modulus (moduli?), namely int_mod:nn.



                            documentclass{article}
                            usepackage{expl3}
                            ExplSyntaxOn
                            newcommand{mymod}[2]{int_mod:nn{#1}{#2}}
                            ExplSyntaxOff
                            begin{document}
                            The residue of $45$ modulo $19$ is $mymod{45}{19}$.
                            end{document}





                            share|improve this answer












                            LaTeX3 (the expl3 package) also has a facility for computing modulus (moduli?), namely int_mod:nn.



                            documentclass{article}
                            usepackage{expl3}
                            ExplSyntaxOn
                            newcommand{mymod}[2]{int_mod:nn{#1}{#2}}
                            ExplSyntaxOff
                            begin{document}
                            The residue of $45$ modulo $19$ is $mymod{45}{19}$.
                            end{document}






                            share|improve this answer












                            share|improve this answer



                            share|improve this answer










                            answered Feb 2 '12 at 17:04









                            Bruno Le Floch

                            33.7k5112211




                            33.7k5112211






















                                up vote
                                7
                                down vote













                                You can use the calculator package then, type this code:



                                MODULO{14}{3}{sol}

                                $14pmod{3}=sol$





                                share|improve this answer























                                • Nice, a new package! But you might want to make it clearer that you are the package author...
                                  – clemens
                                  Jun 12 '12 at 10:35










                                • How nice! :) Feel free to add your package to our list. And by the way, welcome to TeX.sx! :)
                                  – Paulo Cereda
                                  Jun 12 '12 at 10:54















                                up vote
                                7
                                down vote













                                You can use the calculator package then, type this code:



                                MODULO{14}{3}{sol}

                                $14pmod{3}=sol$





                                share|improve this answer























                                • Nice, a new package! But you might want to make it clearer that you are the package author...
                                  – clemens
                                  Jun 12 '12 at 10:35










                                • How nice! :) Feel free to add your package to our list. And by the way, welcome to TeX.sx! :)
                                  – Paulo Cereda
                                  Jun 12 '12 at 10:54













                                up vote
                                7
                                down vote










                                up vote
                                7
                                down vote









                                You can use the calculator package then, type this code:



                                MODULO{14}{3}{sol}

                                $14pmod{3}=sol$





                                share|improve this answer














                                You can use the calculator package then, type this code:



                                MODULO{14}{3}{sol}

                                $14pmod{3}=sol$






                                share|improve this answer














                                share|improve this answer



                                share|improve this answer








                                edited Jun 12 '12 at 9:27









                                Joseph Wright

                                200k21549874




                                200k21549874










                                answered Jun 12 '12 at 9:24









                                Robert Fuster

                                7111




                                7111












                                • Nice, a new package! But you might want to make it clearer that you are the package author...
                                  – clemens
                                  Jun 12 '12 at 10:35










                                • How nice! :) Feel free to add your package to our list. And by the way, welcome to TeX.sx! :)
                                  – Paulo Cereda
                                  Jun 12 '12 at 10:54


















                                • Nice, a new package! But you might want to make it clearer that you are the package author...
                                  – clemens
                                  Jun 12 '12 at 10:35










                                • How nice! :) Feel free to add your package to our list. And by the way, welcome to TeX.sx! :)
                                  – Paulo Cereda
                                  Jun 12 '12 at 10:54
















                                Nice, a new package! But you might want to make it clearer that you are the package author...
                                – clemens
                                Jun 12 '12 at 10:35




                                Nice, a new package! But you might want to make it clearer that you are the package author...
                                – clemens
                                Jun 12 '12 at 10:35












                                How nice! :) Feel free to add your package to our list. And by the way, welcome to TeX.sx! :)
                                – Paulo Cereda
                                Jun 12 '12 at 10:54




                                How nice! :) Feel free to add your package to our list. And by the way, welcome to TeX.sx! :)
                                – Paulo Cereda
                                Jun 12 '12 at 10:54










                                up vote
                                0
                                down vote













                                You may use calc package as long as the absolute values of the numbers are not exceeding 2^31-1=2147483647. Otherwise you may use bigintcalc package.



                                documentclass{article}
                                usepackage{amsmath}
                                usepackage{calc}
                                newcounter{modulo}
                                newcommandmodulo[2]{%
                                setcounter{modulo}{#1-(#1/#2)*#2}%
                                arabic{modulo}%
                                }
                                begin{document}
                                begin{align*}
                                131 equiv modulo{131}{3} &pmod{3} \
                                131 equiv modulo{131}{5} &pmod{5} \
                                131 equiv modulo{131}{7} &pmod{7} \
                                131 equiv modulo{131}{8} &pmod{8} \
                                -97 equiv modulo{-97}{3} &pmod{3} \
                                -97 equiv modulo{-97}{5} &pmod{5} \
                                -97 equiv modulo{-97}{7} &pmod{7} \
                                -97 equiv modulo{-97}{8} &pmod{8} \
                                end{align*}
                                end{document}


                                result of modulo commands






                                share|improve this answer

























                                  up vote
                                  0
                                  down vote













                                  You may use calc package as long as the absolute values of the numbers are not exceeding 2^31-1=2147483647. Otherwise you may use bigintcalc package.



                                  documentclass{article}
                                  usepackage{amsmath}
                                  usepackage{calc}
                                  newcounter{modulo}
                                  newcommandmodulo[2]{%
                                  setcounter{modulo}{#1-(#1/#2)*#2}%
                                  arabic{modulo}%
                                  }
                                  begin{document}
                                  begin{align*}
                                  131 equiv modulo{131}{3} &pmod{3} \
                                  131 equiv modulo{131}{5} &pmod{5} \
                                  131 equiv modulo{131}{7} &pmod{7} \
                                  131 equiv modulo{131}{8} &pmod{8} \
                                  -97 equiv modulo{-97}{3} &pmod{3} \
                                  -97 equiv modulo{-97}{5} &pmod{5} \
                                  -97 equiv modulo{-97}{7} &pmod{7} \
                                  -97 equiv modulo{-97}{8} &pmod{8} \
                                  end{align*}
                                  end{document}


                                  result of modulo commands






                                  share|improve this answer























                                    up vote
                                    0
                                    down vote










                                    up vote
                                    0
                                    down vote









                                    You may use calc package as long as the absolute values of the numbers are not exceeding 2^31-1=2147483647. Otherwise you may use bigintcalc package.



                                    documentclass{article}
                                    usepackage{amsmath}
                                    usepackage{calc}
                                    newcounter{modulo}
                                    newcommandmodulo[2]{%
                                    setcounter{modulo}{#1-(#1/#2)*#2}%
                                    arabic{modulo}%
                                    }
                                    begin{document}
                                    begin{align*}
                                    131 equiv modulo{131}{3} &pmod{3} \
                                    131 equiv modulo{131}{5} &pmod{5} \
                                    131 equiv modulo{131}{7} &pmod{7} \
                                    131 equiv modulo{131}{8} &pmod{8} \
                                    -97 equiv modulo{-97}{3} &pmod{3} \
                                    -97 equiv modulo{-97}{5} &pmod{5} \
                                    -97 equiv modulo{-97}{7} &pmod{7} \
                                    -97 equiv modulo{-97}{8} &pmod{8} \
                                    end{align*}
                                    end{document}


                                    result of modulo commands






                                    share|improve this answer












                                    You may use calc package as long as the absolute values of the numbers are not exceeding 2^31-1=2147483647. Otherwise you may use bigintcalc package.



                                    documentclass{article}
                                    usepackage{amsmath}
                                    usepackage{calc}
                                    newcounter{modulo}
                                    newcommandmodulo[2]{%
                                    setcounter{modulo}{#1-(#1/#2)*#2}%
                                    arabic{modulo}%
                                    }
                                    begin{document}
                                    begin{align*}
                                    131 equiv modulo{131}{3} &pmod{3} \
                                    131 equiv modulo{131}{5} &pmod{5} \
                                    131 equiv modulo{131}{7} &pmod{7} \
                                    131 equiv modulo{131}{8} &pmod{8} \
                                    -97 equiv modulo{-97}{3} &pmod{3} \
                                    -97 equiv modulo{-97}{5} &pmod{5} \
                                    -97 equiv modulo{-97}{7} &pmod{7} \
                                    -97 equiv modulo{-97}{8} &pmod{8} \
                                    end{align*}
                                    end{document}


                                    result of modulo commands







                                    share|improve this answer












                                    share|improve this answer



                                    share|improve this answer










                                    answered 1 hour ago









                                    Z.H.

                                    1,7411326




                                    1,7411326






























                                         

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