Excel - assign the index of every value is a sorted array
I know that the question may not really explain what I am asking about, so let me explain it here. Basically, I have a row in my spreadsheet, that contains i.e. 10 values. Let's say it looks like this:
0.60|0.60|0.60|1.40|0.90|1.05|0.00|0.00
Under this row, I have an empty row, and the problem is I have to assign to every of this value it's position in a reversely sorted array of those values (with no duplicates). In this particular case:
Sorted array: 0.00, 0.60, 0.90, 1.05, 1.40
So I would write down a row like this: 4|4|4|1|3|2|5|5| (indexing from 1)
Is there a way to write a formula for this kind of problem? Or do I have to do it manually?
excel formula
asked Nov 28 '18 at 22:10
dabljuesdabljues
1997
add a comment |
I know that the question may not really explain what I am asking about, so let me explain it here. Basically, I have a row in my spreadsheet, that contains i.e. 10 values. Let's say it looks like this:
0.60|0.60|0.60|1.40|0.90|1.05|0.00|0.00
Under this row, I have an empty row, and the problem is I have to assign to every of this value it's position in a reversely sorted array of those values (with no duplicates). In this particular case:
Sorted array: 0.00, 0.60, 0.90, 1.05, 1.40
So I would write down a row like this: 4|4|4|1|3|2|5|5| (indexing from 1)
Is there a way to write a formula for this kind of problem? Or do I have to do it manually?
excel formula
asked Nov 28 '18 at 22:10
dabljuesdabljues
1997
add a comment |
I know that the question may not really explain what I am asking about, so let me explain it here. Basically, I have a row in my spreadsheet, that contains i.e. 10 values. Let's say it looks like this:
0.60|0.60|0.60|1.40|0.90|1.05|0.00|0.00
Under this row, I have an empty row, and the problem is I have to assign to every of this value it's position in a reversely sorted array of those values (with no duplicates). In this particular case:
Sorted array: 0.00, 0.60, 0.90, 1.05, 1.40
So I would write down a row like this: 4|4|4|1|3|2|5|5| (indexing from 1)
Is there a way to write a formula for this kind of problem? Or do I have to do it manually?
excel formula
asked Nov 28 '18 at 22:10
dabljuesdabljues
1997
I know that the question may not really explain what I am asking about, so let me explain it here. Basically, I have a row in my spreadsheet, that contains i.e. 10 values. Let's say it looks like this:
0.60|0.60|0.60|1.40|0.90|1.05|0.00|0.00
Under this row, I have an empty row, and the problem is I have to assign to every of this value it's position in a reversely sorted array of those values (with no duplicates). In this particular case:
Sorted array: 0.00, 0.60, 0.90, 1.05, 1.40
So I would write down a row like this: 4|4|4|1|3|2|5|5| (indexing from 1)
Is there a way to write a formula for this kind of problem? Or do I have to do it manually?
excel formula
excel formula
asked Nov 28 '18 at 22:10
dabljuesdabljues
1997
asked Nov 28 '18 at 22:10
dabljuesdabljues
1997
asked Nov 28 '18 at 22:10
dabljuesdabljues
1997
asked Nov 28 '18 at 22:10
dabljuesdabljues
1997
asked Nov 28 '18 at 22:10
dabljuesdabljues
1997
1997
add a comment |
add a comment |
1 Answer
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Use this array formula:
=MATCH(A1,LARGE(IF(MATCH($A$1:$H$1,$A$1:$H$1,0)=COLUMN($A$1:$H$1)-COLUMN($A$1)+1,$A$1:$H$1),ROW($A$1:INDEX($A:$A,SUMPRODUCT(1/COUNTIF($A$1:$H$1,$A$1:$H$1))))),0)
Being an array formula one must put the formula in the first cell, confirm with Ctrl-Shift-Enter instead of Enter when exiting edit mode and then copy across.
The LARGE(IF(MATCH($A$1:$H$1,$A$1:$H$1,0)=COLUMN($A$1:$H$1)-COLUMN($A$1)+1,$A$1:$H$1),ROW($A$1:INDEX($A:$A,SUMPRODUCT(1/COUNTIF($A$1:$H$1,$A$1:$H$1))))) returns the sorted array and the MATCH will find the numbers location in that array.
Adjust all the ranges to your dataset EXCEPT ...ROW($A$1:INDEX($A:$A,... These are counters and must remain as is regardless where the dataset is located.
answered Nov 28 '18 at 22:34
Scott CranerScott Craner
93.3k82652
1
Absolutely beautiful.
– BigBen
Nov 28 '18 at 22:36
Jesus, that's terrific. Thank you!
– dabljues
Nov 28 '18 at 22:43
add a comment |
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1 Answer
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active
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Use this array formula:
=MATCH(A1,LARGE(IF(MATCH($A$1:$H$1,$A$1:$H$1,0)=COLUMN($A$1:$H$1)-COLUMN($A$1)+1,$A$1:$H$1),ROW($A$1:INDEX($A:$A,SUMPRODUCT(1/COUNTIF($A$1:$H$1,$A$1:$H$1))))),0)
Being an array formula one must put the formula in the first cell, confirm with Ctrl-Shift-Enter instead of Enter when exiting edit mode and then copy across.
The LARGE(IF(MATCH($A$1:$H$1,$A$1:$H$1,0)=COLUMN($A$1:$H$1)-COLUMN($A$1)+1,$A$1:$H$1),ROW($A$1:INDEX($A:$A,SUMPRODUCT(1/COUNTIF($A$1:$H$1,$A$1:$H$1))))) returns the sorted array and the MATCH will find the numbers location in that array.
Adjust all the ranges to your dataset EXCEPT ...ROW($A$1:INDEX($A:$A,... These are counters and must remain as is regardless where the dataset is located.
answered Nov 28 '18 at 22:34
Scott CranerScott Craner
93.3k82652
1
Absolutely beautiful.
– BigBen
Nov 28 '18 at 22:36
Jesus, that's terrific. Thank you!
– dabljues
Nov 28 '18 at 22:43
add a comment |
Use this array formula:
=MATCH(A1,LARGE(IF(MATCH($A$1:$H$1,$A$1:$H$1,0)=COLUMN($A$1:$H$1)-COLUMN($A$1)+1,$A$1:$H$1),ROW($A$1:INDEX($A:$A,SUMPRODUCT(1/COUNTIF($A$1:$H$1,$A$1:$H$1))))),0)
Being an array formula one must put the formula in the first cell, confirm with Ctrl-Shift-Enter instead of Enter when exiting edit mode and then copy across.
The LARGE(IF(MATCH($A$1:$H$1,$A$1:$H$1,0)=COLUMN($A$1:$H$1)-COLUMN($A$1)+1,$A$1:$H$1),ROW($A$1:INDEX($A:$A,SUMPRODUCT(1/COUNTIF($A$1:$H$1,$A$1:$H$1))))) returns the sorted array and the MATCH will find the numbers location in that array.
Adjust all the ranges to your dataset EXCEPT ...ROW($A$1:INDEX($A:$A,... These are counters and must remain as is regardless where the dataset is located.
answered Nov 28 '18 at 22:34
Scott CranerScott Craner
93.3k82652
1
Absolutely beautiful.
– BigBen
Nov 28 '18 at 22:36
Jesus, that's terrific. Thank you!
– dabljues
Nov 28 '18 at 22:43
add a comment |
Use this array formula:
=MATCH(A1,LARGE(IF(MATCH($A$1:$H$1,$A$1:$H$1,0)=COLUMN($A$1:$H$1)-COLUMN($A$1)+1,$A$1:$H$1),ROW($A$1:INDEX($A:$A,SUMPRODUCT(1/COUNTIF($A$1:$H$1,$A$1:$H$1))))),0)
Being an array formula one must put the formula in the first cell, confirm with Ctrl-Shift-Enter instead of Enter when exiting edit mode and then copy across.
The LARGE(IF(MATCH($A$1:$H$1,$A$1:$H$1,0)=COLUMN($A$1:$H$1)-COLUMN($A$1)+1,$A$1:$H$1),ROW($A$1:INDEX($A:$A,SUMPRODUCT(1/COUNTIF($A$1:$H$1,$A$1:$H$1))))) returns the sorted array and the MATCH will find the numbers location in that array.
Adjust all the ranges to your dataset EXCEPT ...ROW($A$1:INDEX($A:$A,... These are counters and must remain as is regardless where the dataset is located.
answered Nov 28 '18 at 22:34
Scott CranerScott Craner
93.3k82652
Use this array formula:
=MATCH(A1,LARGE(IF(MATCH($A$1:$H$1,$A$1:$H$1,0)=COLUMN($A$1:$H$1)-COLUMN($A$1)+1,$A$1:$H$1),ROW($A$1:INDEX($A:$A,SUMPRODUCT(1/COUNTIF($A$1:$H$1,$A$1:$H$1))))),0)
Being an array formula one must put the formula in the first cell, confirm with Ctrl-Shift-Enter instead of Enter when exiting edit mode and then copy across.
The LARGE(IF(MATCH($A$1:$H$1,$A$1:$H$1,0)=COLUMN($A$1:$H$1)-COLUMN($A$1)+1,$A$1:$H$1),ROW($A$1:INDEX($A:$A,SUMPRODUCT(1/COUNTIF($A$1:$H$1,$A$1:$H$1))))) returns the sorted array and the MATCH will find the numbers location in that array.
Adjust all the ranges to your dataset EXCEPT ...ROW($A$1:INDEX($A:$A,... These are counters and must remain as is regardless where the dataset is located.
answered Nov 28 '18 at 22:34
Scott CranerScott Craner
93.3k82652
edited Nov 28 '18 at 22:40
answered Nov 28 '18 at 22:34
Scott CranerScott Craner
93.3k82652
answered Nov 28 '18 at 22:34
Scott CranerScott Craner
93.3k82652
answered Nov 28 '18 at 22:34
Scott CranerScott Craner
93.3k82652
93.3k82652
1
Absolutely beautiful.
– BigBen
Nov 28 '18 at 22:36
Jesus, that's terrific. Thank you!
– dabljues
Nov 28 '18 at 22:43
add a comment |
1
Absolutely beautiful.
– BigBen
Nov 28 '18 at 22:36
Jesus, that's terrific. Thank you!
– dabljues
Nov 28 '18 at 22:43
1
1
Absolutely beautiful.
– BigBen
Nov 28 '18 at 22:36
Absolutely beautiful.
– BigBen
Nov 28 '18 at 22:36
Jesus, that's terrific. Thank you!
– dabljues
Nov 28 '18 at 22:43
Jesus, that's terrific. Thank you!
– dabljues
Nov 28 '18 at 22:43
add a comment |
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