R stops subsetting when it gets to double digits












0















First time here:



I need to subset based on data results being >4.9 (and it goes up to 22.2), but R stop subsetting at 9.8 and leaves out 10-22.2.
My code:



rha.under.six.total.elevated<- rha.under.six.total[which(rha.under.six.total$lead_level>"4.9"),]









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  • 3





    It's easier to help you if you include a simple reproducible example with sample input and desired output that can be used to test and verify possible solutions. Note that 4.9 is very different from "4.9" -- one is a numeric value and one is a character value. They have different rules for sorting.

    – MrFlick
    Nov 28 '18 at 21:05











  • I agree that your description stringly (pun intended) suggests that a column that you think is numbers is actually characters, but it's hard to say for sure without a more detailed example to work with.

    – joran
    Nov 28 '18 at 21:08
















0















First time here:



I need to subset based on data results being >4.9 (and it goes up to 22.2), but R stop subsetting at 9.8 and leaves out 10-22.2.
My code:



rha.under.six.total.elevated<- rha.under.six.total[which(rha.under.six.total$lead_level>"4.9"),]









share|improve this question




















  • 3





    It's easier to help you if you include a simple reproducible example with sample input and desired output that can be used to test and verify possible solutions. Note that 4.9 is very different from "4.9" -- one is a numeric value and one is a character value. They have different rules for sorting.

    – MrFlick
    Nov 28 '18 at 21:05











  • I agree that your description stringly (pun intended) suggests that a column that you think is numbers is actually characters, but it's hard to say for sure without a more detailed example to work with.

    – joran
    Nov 28 '18 at 21:08














0












0








0








First time here:



I need to subset based on data results being >4.9 (and it goes up to 22.2), but R stop subsetting at 9.8 and leaves out 10-22.2.
My code:



rha.under.six.total.elevated<- rha.under.six.total[which(rha.under.six.total$lead_level>"4.9"),]









share|improve this question
















First time here:



I need to subset based on data results being >4.9 (and it goes up to 22.2), but R stop subsetting at 9.8 and leaves out 10-22.2.
My code:



rha.under.six.total.elevated<- rha.under.six.total[which(rha.under.six.total$lead_level>"4.9"),]






r subset






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edited Nov 28 '18 at 21:07









joran

136k19328388




136k19328388










asked Nov 28 '18 at 21:03









M.FrumhM.Frumh

1




1








  • 3





    It's easier to help you if you include a simple reproducible example with sample input and desired output that can be used to test and verify possible solutions. Note that 4.9 is very different from "4.9" -- one is a numeric value and one is a character value. They have different rules for sorting.

    – MrFlick
    Nov 28 '18 at 21:05











  • I agree that your description stringly (pun intended) suggests that a column that you think is numbers is actually characters, but it's hard to say for sure without a more detailed example to work with.

    – joran
    Nov 28 '18 at 21:08














  • 3





    It's easier to help you if you include a simple reproducible example with sample input and desired output that can be used to test and verify possible solutions. Note that 4.9 is very different from "4.9" -- one is a numeric value and one is a character value. They have different rules for sorting.

    – MrFlick
    Nov 28 '18 at 21:05











  • I agree that your description stringly (pun intended) suggests that a column that you think is numbers is actually characters, but it's hard to say for sure without a more detailed example to work with.

    – joran
    Nov 28 '18 at 21:08








3




3





It's easier to help you if you include a simple reproducible example with sample input and desired output that can be used to test and verify possible solutions. Note that 4.9 is very different from "4.9" -- one is a numeric value and one is a character value. They have different rules for sorting.

– MrFlick
Nov 28 '18 at 21:05





It's easier to help you if you include a simple reproducible example with sample input and desired output that can be used to test and verify possible solutions. Note that 4.9 is very different from "4.9" -- one is a numeric value and one is a character value. They have different rules for sorting.

– MrFlick
Nov 28 '18 at 21:05













I agree that your description stringly (pun intended) suggests that a column that you think is numbers is actually characters, but it's hard to say for sure without a more detailed example to work with.

– joran
Nov 28 '18 at 21:08





I agree that your description stringly (pun intended) suggests that a column that you think is numbers is actually characters, but it's hard to say for sure without a more detailed example to work with.

– joran
Nov 28 '18 at 21:08












1 Answer
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try with this:



rha.under.six.total.elevated <- rha.under.six.total[rha.under.six.total$lead_level>4.9, ]


I think the which() statement is superfluous, you just need a "boolean" condition in order to filter rows. Then you don't need to represent the "4.9" as a character.






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  • The which() can make a big difference if you have NA values.

    – MrFlick
    Nov 28 '18 at 21:20












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1 Answer
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1 Answer
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0














try with this:



rha.under.six.total.elevated <- rha.under.six.total[rha.under.six.total$lead_level>4.9, ]


I think the which() statement is superfluous, you just need a "boolean" condition in order to filter rows. Then you don't need to represent the "4.9" as a character.






share|improve this answer
























  • The which() can make a big difference if you have NA values.

    – MrFlick
    Nov 28 '18 at 21:20
















0














try with this:



rha.under.six.total.elevated <- rha.under.six.total[rha.under.six.total$lead_level>4.9, ]


I think the which() statement is superfluous, you just need a "boolean" condition in order to filter rows. Then you don't need to represent the "4.9" as a character.






share|improve this answer
























  • The which() can make a big difference if you have NA values.

    – MrFlick
    Nov 28 '18 at 21:20














0












0








0







try with this:



rha.under.six.total.elevated <- rha.under.six.total[rha.under.six.total$lead_level>4.9, ]


I think the which() statement is superfluous, you just need a "boolean" condition in order to filter rows. Then you don't need to represent the "4.9" as a character.






share|improve this answer













try with this:



rha.under.six.total.elevated <- rha.under.six.total[rha.under.six.total$lead_level>4.9, ]


I think the which() statement is superfluous, you just need a "boolean" condition in order to filter rows. Then you don't need to represent the "4.9" as a character.







share|improve this answer












share|improve this answer



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answered Nov 28 '18 at 21:15









LeevoLeevo

33519




33519













  • The which() can make a big difference if you have NA values.

    – MrFlick
    Nov 28 '18 at 21:20



















  • The which() can make a big difference if you have NA values.

    – MrFlick
    Nov 28 '18 at 21:20

















The which() can make a big difference if you have NA values.

– MrFlick
Nov 28 '18 at 21:20





The which() can make a big difference if you have NA values.

– MrFlick
Nov 28 '18 at 21:20




















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