R stops subsetting when it gets to double digits
0
First time here:
I need to subset based on data results being >4.9 (and it goes up to 22.2), but R stop subsetting at 9.8 and leaves out 10-22.2.
My code:
rha.under.six.total.elevated<- rha.under.six.total[which(rha.under.six.total$lead_level>"4.9"),]
r subset
edited Nov 28 '18 at 21:07
joran
136k19328388
asked Nov 28 '18 at 21:03
M.FrumhM.Frumh
1
add a comment |
0
First time here:
I need to subset based on data results being >4.9 (and it goes up to 22.2), but R stop subsetting at 9.8 and leaves out 10-22.2.
My code:
rha.under.six.total.elevated<- rha.under.six.total[which(rha.under.six.total$lead_level>"4.9"),]
r subset
edited Nov 28 '18 at 21:07
joran
136k19328388
asked Nov 28 '18 at 21:03
M.FrumhM.Frumh
1
3
It's easier to help you if you include a simple reproducible example with sample input and desired output that can be used to test and verify possible solutions. Note that4.9is very different from"4.9"-- one is a numeric value and one is a character value. They have different rules for sorting.
– MrFlick
Nov 28 '18 at 21:05
I agree that your description stringly (pun intended) suggests that a column that you think is numbers is actually characters, but it's hard to say for sure without a more detailed example to work with.
– joran
Nov 28 '18 at 21:08
add a comment |
0
0
0
First time here:
I need to subset based on data results being >4.9 (and it goes up to 22.2), but R stop subsetting at 9.8 and leaves out 10-22.2.
My code:
rha.under.six.total.elevated<- rha.under.six.total[which(rha.under.six.total$lead_level>"4.9"),]
r subset
edited Nov 28 '18 at 21:07
joran
136k19328388
asked Nov 28 '18 at 21:03
M.FrumhM.Frumh
1
First time here:
I need to subset based on data results being >4.9 (and it goes up to 22.2), but R stop subsetting at 9.8 and leaves out 10-22.2.
My code:
rha.under.six.total.elevated<- rha.under.six.total[which(rha.under.six.total$lead_level>"4.9"),]
r subset
r subset
edited Nov 28 '18 at 21:07
joran
136k19328388
asked Nov 28 '18 at 21:03
M.FrumhM.Frumh
1
edited Nov 28 '18 at 21:07
joran
136k19328388
asked Nov 28 '18 at 21:03
M.FrumhM.Frumh
1
edited Nov 28 '18 at 21:07
joran
136k19328388
edited Nov 28 '18 at 21:07
joran
136k19328388
edited Nov 28 '18 at 21:07
joran
136k19328388
136k19328388
asked Nov 28 '18 at 21:03
M.FrumhM.Frumh
1
asked Nov 28 '18 at 21:03
M.FrumhM.Frumh
1
asked Nov 28 '18 at 21:03
M.FrumhM.Frumh
1
1
3
It's easier to help you if you include a simple reproducible example with sample input and desired output that can be used to test and verify possible solutions. Note that4.9is very different from"4.9"-- one is a numeric value and one is a character value. They have different rules for sorting.
– MrFlick
Nov 28 '18 at 21:05
I agree that your description stringly (pun intended) suggests that a column that you think is numbers is actually characters, but it's hard to say for sure without a more detailed example to work with.
– joran
Nov 28 '18 at 21:08
add a comment |
3
It's easier to help you if you include a simple reproducible example with sample input and desired output that can be used to test and verify possible solutions. Note that4.9is very different from"4.9"-- one is a numeric value and one is a character value. They have different rules for sorting.
– MrFlick
Nov 28 '18 at 21:05
I agree that your description stringly (pun intended) suggests that a column that you think is numbers is actually characters, but it's hard to say for sure without a more detailed example to work with.
– joran
Nov 28 '18 at 21:08
3
3
It's easier to help you if you include a simple reproducible example with sample input and desired output that can be used to test and verify possible solutions. Note that
4.9 is very different from "4.9" -- one is a numeric value and one is a character value. They have different rules for sorting.– MrFlick
Nov 28 '18 at 21:05
It's easier to help you if you include a simple reproducible example with sample input and desired output that can be used to test and verify possible solutions. Note that
4.9 is very different from "4.9" -- one is a numeric value and one is a character value. They have different rules for sorting.– MrFlick
Nov 28 '18 at 21:05
I agree that your description stringly (pun intended) suggests that a column that you think is numbers is actually characters, but it's hard to say for sure without a more detailed example to work with.
– joran
Nov 28 '18 at 21:08
I agree that your description stringly (pun intended) suggests that a column that you think is numbers is actually characters, but it's hard to say for sure without a more detailed example to work with.
– joran
Nov 28 '18 at 21:08
add a comment |
1 Answer
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try with this:
rha.under.six.total.elevated <- rha.under.six.total[rha.under.six.total$lead_level>4.9, ]
I think the which() statement is superfluous, you just need a "boolean" condition in order to filter rows. Then you don't need to represent the "4.9" as a character.
answered Nov 28 '18 at 21:15
LeevoLeevo
33519
Thewhich()can make a big difference if you have NA values.
– MrFlick
Nov 28 '18 at 21:20
add a comment |
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0
try with this:
rha.under.six.total.elevated <- rha.under.six.total[rha.under.six.total$lead_level>4.9, ]
I think the which() statement is superfluous, you just need a "boolean" condition in order to filter rows. Then you don't need to represent the "4.9" as a character.
answered Nov 28 '18 at 21:15
LeevoLeevo
33519
Thewhich()can make a big difference if you have NA values.
– MrFlick
Nov 28 '18 at 21:20
add a comment |
0
try with this:
rha.under.six.total.elevated <- rha.under.six.total[rha.under.six.total$lead_level>4.9, ]
I think the which() statement is superfluous, you just need a "boolean" condition in order to filter rows. Then you don't need to represent the "4.9" as a character.
answered Nov 28 '18 at 21:15
LeevoLeevo
33519
Thewhich()can make a big difference if you have NA values.
– MrFlick
Nov 28 '18 at 21:20
add a comment |
0
0
0
try with this:
rha.under.six.total.elevated <- rha.under.six.total[rha.under.six.total$lead_level>4.9, ]
I think the which() statement is superfluous, you just need a "boolean" condition in order to filter rows. Then you don't need to represent the "4.9" as a character.
answered Nov 28 '18 at 21:15
LeevoLeevo
33519
try with this:
rha.under.six.total.elevated <- rha.under.six.total[rha.under.six.total$lead_level>4.9, ]
I think the which() statement is superfluous, you just need a "boolean" condition in order to filter rows. Then you don't need to represent the "4.9" as a character.
answered Nov 28 '18 at 21:15
LeevoLeevo
33519
answered Nov 28 '18 at 21:15
LeevoLeevo
33519
answered Nov 28 '18 at 21:15
LeevoLeevo
33519
answered Nov 28 '18 at 21:15
LeevoLeevo
33519
33519
Thewhich()can make a big difference if you have NA values.
– MrFlick
Nov 28 '18 at 21:20
add a comment |
Thewhich()can make a big difference if you have NA values.
– MrFlick
Nov 28 '18 at 21:20
The
which() can make a big difference if you have NA values.– MrFlick
Nov 28 '18 at 21:20
The
which() can make a big difference if you have NA values.– MrFlick
Nov 28 '18 at 21:20
add a comment |
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3
It's easier to help you if you include a simple reproducible example with sample input and desired output that can be used to test and verify possible solutions. Note that
4.9is very different from"4.9"-- one is a numeric value and one is a character value. They have different rules for sorting.– MrFlick
Nov 28 '18 at 21:05
I agree that your description stringly (pun intended) suggests that a column that you think is numbers is actually characters, but it's hard to say for sure without a more detailed example to work with.
– joran
Nov 28 '18 at 21:08