How to use @NotNull?
I have a Spring Boot app using Jackson. I'm not using Jersey just regular Spring MVC. I have a Wrapper Request class:
public class WrapperRequest {
@NotNull
private final Object obj; // some object that corresponds with a JSON object
@JsonCreator
public WrapperRequest(@JsonProperty("wrapper") final Object obj) {
this.obj = obj;
}
public Object getObj() {return obj}
}
The JSON for this would look like:
{
"wrapper":{
//Object data
}
}
The @NotNull from javax isn't working as I excepted. The way I want it to work is that if the consumer sends in a JSON that have a typo like:
{
"wrapperr":{
//Object data
}
}
Jackson will not map my wrapper class because the key in the JSON doesnt match the JsonProperty i.e ("wrapper") (so Object will be null and then I will get NPE later on if I tried to interact with Object. Am I using Jackson wrong? i.e Jackson maps things that it knows about and the rest is null or am I not using the @NotNull annotation correctly?
java spring spring-mvc
asked Nov 28 '18 at 4:58
Dixon IveyDixon Ivey
194
add a comment |
I have a Spring Boot app using Jackson. I'm not using Jersey just regular Spring MVC. I have a Wrapper Request class:
public class WrapperRequest {
@NotNull
private final Object obj; // some object that corresponds with a JSON object
@JsonCreator
public WrapperRequest(@JsonProperty("wrapper") final Object obj) {
this.obj = obj;
}
public Object getObj() {return obj}
}
The JSON for this would look like:
{
"wrapper":{
//Object data
}
}
The @NotNull from javax isn't working as I excepted. The way I want it to work is that if the consumer sends in a JSON that have a typo like:
{
"wrapperr":{
//Object data
}
}
Jackson will not map my wrapper class because the key in the JSON doesnt match the JsonProperty i.e ("wrapper") (so Object will be null and then I will get NPE later on if I tried to interact with Object. Am I using Jackson wrong? i.e Jackson maps things that it knows about and the rest is null or am I not using the @NotNull annotation correctly?
java spring spring-mvc
asked Nov 28 '18 at 4:58
Dixon IveyDixon Ivey
194
add a comment |
I have a Spring Boot app using Jackson. I'm not using Jersey just regular Spring MVC. I have a Wrapper Request class:
public class WrapperRequest {
@NotNull
private final Object obj; // some object that corresponds with a JSON object
@JsonCreator
public WrapperRequest(@JsonProperty("wrapper") final Object obj) {
this.obj = obj;
}
public Object getObj() {return obj}
}
The JSON for this would look like:
{
"wrapper":{
//Object data
}
}
The @NotNull from javax isn't working as I excepted. The way I want it to work is that if the consumer sends in a JSON that have a typo like:
{
"wrapperr":{
//Object data
}
}
Jackson will not map my wrapper class because the key in the JSON doesnt match the JsonProperty i.e ("wrapper") (so Object will be null and then I will get NPE later on if I tried to interact with Object. Am I using Jackson wrong? i.e Jackson maps things that it knows about and the rest is null or am I not using the @NotNull annotation correctly?
java spring spring-mvc
asked Nov 28 '18 at 4:58
Dixon IveyDixon Ivey
194
I have a Spring Boot app using Jackson. I'm not using Jersey just regular Spring MVC. I have a Wrapper Request class:
public class WrapperRequest {
@NotNull
private final Object obj; // some object that corresponds with a JSON object
@JsonCreator
public WrapperRequest(@JsonProperty("wrapper") final Object obj) {
this.obj = obj;
}
public Object getObj() {return obj}
}
The JSON for this would look like:
{
"wrapper":{
//Object data
}
}
The @NotNull from javax isn't working as I excepted. The way I want it to work is that if the consumer sends in a JSON that have a typo like:
{
"wrapperr":{
//Object data
}
}
Jackson will not map my wrapper class because the key in the JSON doesnt match the JsonProperty i.e ("wrapper") (so Object will be null and then I will get NPE later on if I tried to interact with Object. Am I using Jackson wrong? i.e Jackson maps things that it knows about and the rest is null or am I not using the @NotNull annotation correctly?
java spring spring-mvc
java spring spring-mvc
asked Nov 28 '18 at 4:58
Dixon IveyDixon Ivey
194
asked Nov 28 '18 at 4:58
Dixon IveyDixon Ivey
194
asked Nov 28 '18 at 4:58
Dixon IveyDixon Ivey
194
asked Nov 28 '18 at 4:58
Dixon IveyDixon Ivey
194
asked Nov 28 '18 at 4:58
Dixon IveyDixon Ivey
194
194
add a comment |
add a comment |
1 Answer
1
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oldest
votes
Jackson is not aware of Bean Validation annotations like @NotNull. For the specific case of "null", you can mark the constructor parameter as @JsonProperty(required = true). More generally, you can use @NotNull on a property as you did and mark your MVC controller parameter with @Valid (which will not cause deserialization to fail but will cause Spring MVC to return a 400 if the validation fails).
Note that you may also be interested in the UNWRAP_ROOT_VALUE feature, which would allow you to eliminate the need for the wrapper class in this particular case.
answered Nov 28 '18 at 5:27
chrylischrylis
51.6k1686118
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Jackson is not aware of Bean Validation annotations like @NotNull. For the specific case of "null", you can mark the constructor parameter as @JsonProperty(required = true). More generally, you can use @NotNull on a property as you did and mark your MVC controller parameter with @Valid (which will not cause deserialization to fail but will cause Spring MVC to return a 400 if the validation fails).
Note that you may also be interested in the UNWRAP_ROOT_VALUE feature, which would allow you to eliminate the need for the wrapper class in this particular case.
answered Nov 28 '18 at 5:27
chrylischrylis
51.6k1686118
add a comment |
Jackson is not aware of Bean Validation annotations like @NotNull. For the specific case of "null", you can mark the constructor parameter as @JsonProperty(required = true). More generally, you can use @NotNull on a property as you did and mark your MVC controller parameter with @Valid (which will not cause deserialization to fail but will cause Spring MVC to return a 400 if the validation fails).
Note that you may also be interested in the UNWRAP_ROOT_VALUE feature, which would allow you to eliminate the need for the wrapper class in this particular case.
answered Nov 28 '18 at 5:27
chrylischrylis
51.6k1686118
add a comment |
Jackson is not aware of Bean Validation annotations like @NotNull. For the specific case of "null", you can mark the constructor parameter as @JsonProperty(required = true). More generally, you can use @NotNull on a property as you did and mark your MVC controller parameter with @Valid (which will not cause deserialization to fail but will cause Spring MVC to return a 400 if the validation fails).
Note that you may also be interested in the UNWRAP_ROOT_VALUE feature, which would allow you to eliminate the need for the wrapper class in this particular case.
answered Nov 28 '18 at 5:27
chrylischrylis
51.6k1686118
Jackson is not aware of Bean Validation annotations like @NotNull. For the specific case of "null", you can mark the constructor parameter as @JsonProperty(required = true). More generally, you can use @NotNull on a property as you did and mark your MVC controller parameter with @Valid (which will not cause deserialization to fail but will cause Spring MVC to return a 400 if the validation fails).
Note that you may also be interested in the UNWRAP_ROOT_VALUE feature, which would allow you to eliminate the need for the wrapper class in this particular case.
answered Nov 28 '18 at 5:27
chrylischrylis
51.6k1686118
edited Nov 28 '18 at 5:33
answered Nov 28 '18 at 5:27
chrylischrylis
51.6k1686118
answered Nov 28 '18 at 5:27
chrylischrylis
51.6k1686118
answered Nov 28 '18 at 5:27
chrylischrylis
51.6k1686118
51.6k1686118
add a comment |
add a comment |
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