grep pattern match with line number












0















I want to get the line number of the matched pattern but I have a condition that the pattern match should have 'digits' .
If I use

grep -ri -n "package $i " . | grep -P 'd'

then I would get the line number of the lines matching pattern but also I would get the lines with 'package ' without any digits:



Below output shows me line number 71 for 'package ca-certificates' but there are four more lines for gluterfs that I dont need . I dont need those lines as they dont have any digit in them .



for i in $(awk '{print $1}' ~/Version-pkgs)

do

grep -ri -n   "package $i " . | grep -P 'd'

done



sh search-version-pkgs.sh

./core.pkglist:71:package ca-certificates         2017.2.14   65.0.1.el6_9               arch noarch

./dev.pkglist:1343:package glusterfs-devel 

./dev.pkglist:1346:package glusterfs-api-devel 

./dev.pkglist:1346:package glusterfs-api-devel 

./dev.pkglist:1346:package glusterfs-api-devel 

./dev.pkglist:1343:package glusterfs-devel 

./core.pkglist:234:package initscripts             9.03.58     1.0.3.el6_9.2prerel7.6.0.0.0_88.51.0            arch ${bestArch}

./core.pkglist:397:package nspr                    4.13.1      1.el6

./dev.pkglist:859:package nspr-devel 

./dev.pkglist:859:package nspr-devel 

./core.pkglist:401:package nss                     3.28.4      4.0.1.el6_9       arch ${bestArch}


Running below script gives me exact pattern match i.e. 'package ' but I would not get the line number of them 



for i in $(awk '{print $1}' ~/Version-pkgs)

do

egrep -ri    "package $i " . | grep -P 'd'

done



sh search-version-pkgs.sh

./core.pkglist:package ca-certificates         2017.2.14   65.0.1.el6_9               arch noarch

./core.pkglist:package initscripts             9.03.58     1.0.3.el6_9.2prerel7.6.0.0.0_88.51.0            arch ${bestArch}

./core.pkglist:package nspr                    4.13.1      1.el6

./core.pkglist:package nss                     3.28.4      4.0.1.el6_9       arch ${bestArch}

./core.pkglist:package nss-util                3.28.4      1.el6_9          arch ${bestArch}

./core.pkglist:package tzdata                  2018e       3.el6    arch noarch


How can get the output with the line number along with the pattern match as file:lineno.:package pkgname digits






awk sed grep







share|improve this question























  • not clear, could you please provide more details on input and expected output and let us know then.

    – RavinderSingh13
    Nov 28 '18 at 15:09













  • Outputs should not have lines without digits.

    – Unixquest945
    Nov 28 '18 at 15:22













  • Which block of text in your question is the sample input and which is the expected output?

    – Ed Morton
    Nov 28 '18 at 17:48
















0















I want to get the line number of the matched pattern but I have a condition that the pattern match should have 'digits' .
If I use

grep -ri -n "package $i " . | grep -P 'd'

then I would get the line number of the lines matching pattern but also I would get the lines with 'package ' without any digits:



Below output shows me line number 71 for 'package ca-certificates' but there are four more lines for gluterfs that I dont need . I dont need those lines as they dont have any digit in them .



for i in $(awk '{print $1}' ~/Version-pkgs)

do

grep -ri -n   "package $i " . | grep -P 'd'

done



sh search-version-pkgs.sh

./core.pkglist:71:package ca-certificates         2017.2.14   65.0.1.el6_9               arch noarch

./dev.pkglist:1343:package glusterfs-devel 

./dev.pkglist:1346:package glusterfs-api-devel 

./dev.pkglist:1346:package glusterfs-api-devel 

./dev.pkglist:1346:package glusterfs-api-devel 

./dev.pkglist:1343:package glusterfs-devel 

./core.pkglist:234:package initscripts             9.03.58     1.0.3.el6_9.2prerel7.6.0.0.0_88.51.0            arch ${bestArch}

./core.pkglist:397:package nspr                    4.13.1      1.el6

./dev.pkglist:859:package nspr-devel 

./dev.pkglist:859:package nspr-devel 

./core.pkglist:401:package nss                     3.28.4      4.0.1.el6_9       arch ${bestArch}


Running below script gives me exact pattern match i.e. 'package ' but I would not get the line number of them 



for i in $(awk '{print $1}' ~/Version-pkgs)

do

egrep -ri    "package $i " . | grep -P 'd'

done



sh search-version-pkgs.sh

./core.pkglist:package ca-certificates         2017.2.14   65.0.1.el6_9               arch noarch

./core.pkglist:package initscripts             9.03.58     1.0.3.el6_9.2prerel7.6.0.0.0_88.51.0            arch ${bestArch}

./core.pkglist:package nspr                    4.13.1      1.el6

./core.pkglist:package nss                     3.28.4      4.0.1.el6_9       arch ${bestArch}

./core.pkglist:package nss-util                3.28.4      1.el6_9          arch ${bestArch}

./core.pkglist:package tzdata                  2018e       3.el6    arch noarch


How can get the output with the line number along with the pattern match as file:lineno.:package pkgname digits






awk sed grep







share|improve this question























  • not clear, could you please provide more details on input and expected output and let us know then.

    – RavinderSingh13
    Nov 28 '18 at 15:09













  • Outputs should not have lines without digits.

    – Unixquest945
    Nov 28 '18 at 15:22













  • Which block of text in your question is the sample input and which is the expected output?

    – Ed Morton
    Nov 28 '18 at 17:48














0












0








0








I want to get the line number of the matched pattern but I have a condition that the pattern match should have 'digits' .
If I use

grep -ri -n "package $i " . | grep -P 'd'

then I would get the line number of the lines matching pattern but also I would get the lines with 'package ' without any digits:



Below output shows me line number 71 for 'package ca-certificates' but there are four more lines for gluterfs that I dont need . I dont need those lines as they dont have any digit in them .



for i in $(awk '{print $1}' ~/Version-pkgs)

do

grep -ri -n   "package $i " . | grep -P 'd'

done



sh search-version-pkgs.sh

./core.pkglist:71:package ca-certificates         2017.2.14   65.0.1.el6_9               arch noarch

./dev.pkglist:1343:package glusterfs-devel 

./dev.pkglist:1346:package glusterfs-api-devel 

./dev.pkglist:1346:package glusterfs-api-devel 

./dev.pkglist:1346:package glusterfs-api-devel 

./dev.pkglist:1343:package glusterfs-devel 

./core.pkglist:234:package initscripts             9.03.58     1.0.3.el6_9.2prerel7.6.0.0.0_88.51.0            arch ${bestArch}

./core.pkglist:397:package nspr                    4.13.1      1.el6

./dev.pkglist:859:package nspr-devel 

./dev.pkglist:859:package nspr-devel 

./core.pkglist:401:package nss                     3.28.4      4.0.1.el6_9       arch ${bestArch}


Running below script gives me exact pattern match i.e. 'package ' but I would not get the line number of them 



for i in $(awk '{print $1}' ~/Version-pkgs)

do

egrep -ri    "package $i " . | grep -P 'd'

done



sh search-version-pkgs.sh

./core.pkglist:package ca-certificates         2017.2.14   65.0.1.el6_9               arch noarch

./core.pkglist:package initscripts             9.03.58     1.0.3.el6_9.2prerel7.6.0.0.0_88.51.0            arch ${bestArch}

./core.pkglist:package nspr                    4.13.1      1.el6

./core.pkglist:package nss                     3.28.4      4.0.1.el6_9       arch ${bestArch}

./core.pkglist:package nss-util                3.28.4      1.el6_9          arch ${bestArch}

./core.pkglist:package tzdata                  2018e       3.el6    arch noarch


How can get the output with the line number along with the pattern match as file:lineno.:package pkgname digits






awk sed grep







share|improve this question














I want to get the line number of the matched pattern but I have a condition that the pattern match should have 'digits' .
If I use

grep -ri -n "package $i " . | grep -P 'd'

then I would get the line number of the lines matching pattern but also I would get the lines with 'package ' without any digits:



Below output shows me line number 71 for 'package ca-certificates' but there are four more lines for gluterfs that I dont need . I dont need those lines as they dont have any digit in them .



for i in $(awk '{print $1}' ~/Version-pkgs)

do

grep -ri -n   "package $i " . | grep -P 'd'

done



sh search-version-pkgs.sh

./core.pkglist:71:package ca-certificates         2017.2.14   65.0.1.el6_9               arch noarch

./dev.pkglist:1343:package glusterfs-devel 

./dev.pkglist:1346:package glusterfs-api-devel 

./dev.pkglist:1346:package glusterfs-api-devel 

./dev.pkglist:1346:package glusterfs-api-devel 

./dev.pkglist:1343:package glusterfs-devel 

./core.pkglist:234:package initscripts             9.03.58     1.0.3.el6_9.2prerel7.6.0.0.0_88.51.0            arch ${bestArch}

./core.pkglist:397:package nspr                    4.13.1      1.el6

./dev.pkglist:859:package nspr-devel 

./dev.pkglist:859:package nspr-devel 

./core.pkglist:401:package nss                     3.28.4      4.0.1.el6_9       arch ${bestArch}


Running below script gives me exact pattern match i.e. 'package ' but I would not get the line number of them 



for i in $(awk '{print $1}' ~/Version-pkgs)

do

egrep -ri    "package $i " . | grep -P 'd'

done



sh search-version-pkgs.sh

./core.pkglist:package ca-certificates         2017.2.14   65.0.1.el6_9               arch noarch

./core.pkglist:package initscripts             9.03.58     1.0.3.el6_9.2prerel7.6.0.0.0_88.51.0            arch ${bestArch}

./core.pkglist:package nspr                    4.13.1      1.el6

./core.pkglist:package nss                     3.28.4      4.0.1.el6_9       arch ${bestArch}

./core.pkglist:package nss-util                3.28.4      1.el6_9          arch ${bestArch}

./core.pkglist:package tzdata                  2018e       3.el6    arch noarch


How can get the output with the line number along with the pattern match as file:lineno.:package pkgname digits






awk sed grep




awk sed grep






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 28 '18 at 15:02









Unixquest945Unixquest945

396




396













  • not clear, could you please provide more details on input and expected output and let us know then.

    – RavinderSingh13
    Nov 28 '18 at 15:09













  • Outputs should not have lines without digits.

    – Unixquest945
    Nov 28 '18 at 15:22













  • Which block of text in your question is the sample input and which is the expected output?

    – Ed Morton
    Nov 28 '18 at 17:48



















  • not clear, could you please provide more details on input and expected output and let us know then.

    – RavinderSingh13
    Nov 28 '18 at 15:09













  • Outputs should not have lines without digits.

    – Unixquest945
    Nov 28 '18 at 15:22













  • Which block of text in your question is the sample input and which is the expected output?

    – Ed Morton
    Nov 28 '18 at 17:48

















not clear, could you please provide more details on input and expected output and let us know then.

– RavinderSingh13
Nov 28 '18 at 15:09







not clear, could you please provide more details on input and expected output and let us know then.

– RavinderSingh13
Nov 28 '18 at 15:09















Outputs should not have lines without digits.

– Unixquest945
Nov 28 '18 at 15:22







Outputs should not have lines without digits.

– Unixquest945
Nov 28 '18 at 15:22















Which block of text in your question is the sample input and which is the expected output?

– Ed Morton
Nov 28 '18 at 17:48





Which block of text in your question is the sample input and which is the expected output?

– Ed Morton
Nov 28 '18 at 17:48












1 Answer
1






active

oldest

votes


















2














for i in $(cut -f1 ~/Version-pkgs)

do

    grep -rin   "package $i.*[0-9]" .

done


no need to use grep twice



Oneliner : 



grep -rinf <(sed -E 's,([^ ]*).*,package 1.*[0-9],' ~/Version-pkgs) .





share|improve this answer


























  • Thanks Corentin Limier , it worked and shown expected results.

    – Unixquest945
    Nov 28 '18 at 16:17











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









2














for i in $(cut -f1 ~/Version-pkgs)

do

    grep -rin   "package $i.*[0-9]" .

done


no need to use grep twice



Oneliner : 



grep -rinf <(sed -E 's,([^ ]*).*,package 1.*[0-9],' ~/Version-pkgs) .





share|improve this answer


























  • Thanks Corentin Limier , it worked and shown expected results.

    – Unixquest945
    Nov 28 '18 at 16:17
















2














for i in $(cut -f1 ~/Version-pkgs)

do

    grep -rin   "package $i.*[0-9]" .

done


no need to use grep twice



Oneliner : 



grep -rinf <(sed -E 's,([^ ]*).*,package 1.*[0-9],' ~/Version-pkgs) .





share|improve this answer


























  • Thanks Corentin Limier , it worked and shown expected results.

    – Unixquest945
    Nov 28 '18 at 16:17














2












2








2







for i in $(cut -f1 ~/Version-pkgs)

do

    grep -rin   "package $i.*[0-9]" .

done


no need to use grep twice



Oneliner : 



grep -rinf <(sed -E 's,([^ ]*).*,package 1.*[0-9],' ~/Version-pkgs) .





share|improve this answer















for i in $(cut -f1 ~/Version-pkgs)

do

    grep -rin   "package $i.*[0-9]" .

done


no need to use grep twice



Oneliner : 



grep -rinf <(sed -E 's,([^ ]*).*,package 1.*[0-9],' ~/Version-pkgs) .






share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 28 '18 at 16:55

























answered Nov 28 '18 at 15:31









Corentin LimierCorentin Limier

2,0511611




2,0511611













  • Thanks Corentin Limier , it worked and shown expected results.

    – Unixquest945
    Nov 28 '18 at 16:17



















  • Thanks Corentin Limier , it worked and shown expected results.

    – Unixquest945
    Nov 28 '18 at 16:17

















Thanks Corentin Limier , it worked and shown expected results.

– Unixquest945
Nov 28 '18 at 16:17





Thanks Corentin Limier , it worked and shown expected results.

– Unixquest945
Nov 28 '18 at 16:17




















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