grep pattern match with line number
I want to get the line number of the matched pattern but I have a condition that the pattern match should have 'digits' .
If I use
grep -ri -n "package $i " . | grep -P 'd'
then I would get the line number of the lines matching pattern but also I would get the lines with 'package ' without any digits:
Below output shows me line number 71 for 'package ca-certificates' but there are four more lines for gluterfs that I dont need . I dont need those lines as they dont have any digit in them .
for i in $(awk '{print $1}' ~/Version-pkgs)
do
grep -ri -n "package $i " . | grep -P 'd'
done
sh search-version-pkgs.sh
./core.pkglist:71:package ca-certificates 2017.2.14 65.0.1.el6_9 arch noarch
./dev.pkglist:1343:package glusterfs-devel
./dev.pkglist:1346:package glusterfs-api-devel
./dev.pkglist:1346:package glusterfs-api-devel
./dev.pkglist:1346:package glusterfs-api-devel
./dev.pkglist:1343:package glusterfs-devel
./core.pkglist:234:package initscripts 9.03.58 1.0.3.el6_9.2prerel7.6.0.0.0_88.51.0 arch ${bestArch}
./core.pkglist:397:package nspr 4.13.1 1.el6
./dev.pkglist:859:package nspr-devel
./dev.pkglist:859:package nspr-devel
./core.pkglist:401:package nss 3.28.4 4.0.1.el6_9 arch ${bestArch}
Running below script gives me exact pattern match i.e. 'package ' but I would not get the line number of them
for i in $(awk '{print $1}' ~/Version-pkgs)
do
egrep -ri "package $i " . | grep -P 'd'
done
sh search-version-pkgs.sh
./core.pkglist:package ca-certificates 2017.2.14 65.0.1.el6_9 arch noarch
./core.pkglist:package initscripts 9.03.58 1.0.3.el6_9.2prerel7.6.0.0.0_88.51.0 arch ${bestArch}
./core.pkglist:package nspr 4.13.1 1.el6
./core.pkglist:package nss 3.28.4 4.0.1.el6_9 arch ${bestArch}
./core.pkglist:package nss-util 3.28.4 1.el6_9 arch ${bestArch}
./core.pkglist:package tzdata 2018e 3.el6 arch noarch
How can get the output with the line number along with the pattern match as file:lineno.:package pkgname digits
awk sed grep
asked Nov 28 '18 at 15:02
Unixquest945Unixquest945
396
add a comment |
I want to get the line number of the matched pattern but I have a condition that the pattern match should have 'digits' .
If I use
grep -ri -n "package $i " . | grep -P 'd'
then I would get the line number of the lines matching pattern but also I would get the lines with 'package ' without any digits:
Below output shows me line number 71 for 'package ca-certificates' but there are four more lines for gluterfs that I dont need . I dont need those lines as they dont have any digit in them .
for i in $(awk '{print $1}' ~/Version-pkgs)
do
grep -ri -n "package $i " . | grep -P 'd'
done
sh search-version-pkgs.sh
./core.pkglist:71:package ca-certificates 2017.2.14 65.0.1.el6_9 arch noarch
./dev.pkglist:1343:package glusterfs-devel
./dev.pkglist:1346:package glusterfs-api-devel
./dev.pkglist:1346:package glusterfs-api-devel
./dev.pkglist:1346:package glusterfs-api-devel
./dev.pkglist:1343:package glusterfs-devel
./core.pkglist:234:package initscripts 9.03.58 1.0.3.el6_9.2prerel7.6.0.0.0_88.51.0 arch ${bestArch}
./core.pkglist:397:package nspr 4.13.1 1.el6
./dev.pkglist:859:package nspr-devel
./dev.pkglist:859:package nspr-devel
./core.pkglist:401:package nss 3.28.4 4.0.1.el6_9 arch ${bestArch}
Running below script gives me exact pattern match i.e. 'package ' but I would not get the line number of them
for i in $(awk '{print $1}' ~/Version-pkgs)
do
egrep -ri "package $i " . | grep -P 'd'
done
sh search-version-pkgs.sh
./core.pkglist:package ca-certificates 2017.2.14 65.0.1.el6_9 arch noarch
./core.pkglist:package initscripts 9.03.58 1.0.3.el6_9.2prerel7.6.0.0.0_88.51.0 arch ${bestArch}
./core.pkglist:package nspr 4.13.1 1.el6
./core.pkglist:package nss 3.28.4 4.0.1.el6_9 arch ${bestArch}
./core.pkglist:package nss-util 3.28.4 1.el6_9 arch ${bestArch}
./core.pkglist:package tzdata 2018e 3.el6 arch noarch
How can get the output with the line number along with the pattern match as file:lineno.:package pkgname digits
awk sed grep
asked Nov 28 '18 at 15:02
Unixquest945Unixquest945
396
not clear, could you please provide more details on input and expected output and let us know then.
– RavinderSingh13
Nov 28 '18 at 15:09
Outputs should not have lines without digits.
– Unixquest945
Nov 28 '18 at 15:22
Which block of text in your question is the sample input and which is the expected output?
– Ed Morton
Nov 28 '18 at 17:48
add a comment |
I want to get the line number of the matched pattern but I have a condition that the pattern match should have 'digits' .
If I use
grep -ri -n "package $i " . | grep -P 'd'
then I would get the line number of the lines matching pattern but also I would get the lines with 'package ' without any digits:
Below output shows me line number 71 for 'package ca-certificates' but there are four more lines for gluterfs that I dont need . I dont need those lines as they dont have any digit in them .
for i in $(awk '{print $1}' ~/Version-pkgs)
do
grep -ri -n "package $i " . | grep -P 'd'
done
sh search-version-pkgs.sh
./core.pkglist:71:package ca-certificates 2017.2.14 65.0.1.el6_9 arch noarch
./dev.pkglist:1343:package glusterfs-devel
./dev.pkglist:1346:package glusterfs-api-devel
./dev.pkglist:1346:package glusterfs-api-devel
./dev.pkglist:1346:package glusterfs-api-devel
./dev.pkglist:1343:package glusterfs-devel
./core.pkglist:234:package initscripts 9.03.58 1.0.3.el6_9.2prerel7.6.0.0.0_88.51.0 arch ${bestArch}
./core.pkglist:397:package nspr 4.13.1 1.el6
./dev.pkglist:859:package nspr-devel
./dev.pkglist:859:package nspr-devel
./core.pkglist:401:package nss 3.28.4 4.0.1.el6_9 arch ${bestArch}
Running below script gives me exact pattern match i.e. 'package ' but I would not get the line number of them
for i in $(awk '{print $1}' ~/Version-pkgs)
do
egrep -ri "package $i " . | grep -P 'd'
done
sh search-version-pkgs.sh
./core.pkglist:package ca-certificates 2017.2.14 65.0.1.el6_9 arch noarch
./core.pkglist:package initscripts 9.03.58 1.0.3.el6_9.2prerel7.6.0.0.0_88.51.0 arch ${bestArch}
./core.pkglist:package nspr 4.13.1 1.el6
./core.pkglist:package nss 3.28.4 4.0.1.el6_9 arch ${bestArch}
./core.pkglist:package nss-util 3.28.4 1.el6_9 arch ${bestArch}
./core.pkglist:package tzdata 2018e 3.el6 arch noarch
How can get the output with the line number along with the pattern match as file:lineno.:package pkgname digits
awk sed grep
asked Nov 28 '18 at 15:02
Unixquest945Unixquest945
396
I want to get the line number of the matched pattern but I have a condition that the pattern match should have 'digits' .
If I use
grep -ri -n "package $i " . | grep -P 'd'
then I would get the line number of the lines matching pattern but also I would get the lines with 'package ' without any digits:
Below output shows me line number 71 for 'package ca-certificates' but there are four more lines for gluterfs that I dont need . I dont need those lines as they dont have any digit in them .
for i in $(awk '{print $1}' ~/Version-pkgs)
do
grep -ri -n "package $i " . | grep -P 'd'
done
sh search-version-pkgs.sh
./core.pkglist:71:package ca-certificates 2017.2.14 65.0.1.el6_9 arch noarch
./dev.pkglist:1343:package glusterfs-devel
./dev.pkglist:1346:package glusterfs-api-devel
./dev.pkglist:1346:package glusterfs-api-devel
./dev.pkglist:1346:package glusterfs-api-devel
./dev.pkglist:1343:package glusterfs-devel
./core.pkglist:234:package initscripts 9.03.58 1.0.3.el6_9.2prerel7.6.0.0.0_88.51.0 arch ${bestArch}
./core.pkglist:397:package nspr 4.13.1 1.el6
./dev.pkglist:859:package nspr-devel
./dev.pkglist:859:package nspr-devel
./core.pkglist:401:package nss 3.28.4 4.0.1.el6_9 arch ${bestArch}
Running below script gives me exact pattern match i.e. 'package ' but I would not get the line number of them
for i in $(awk '{print $1}' ~/Version-pkgs)
do
egrep -ri "package $i " . | grep -P 'd'
done
sh search-version-pkgs.sh
./core.pkglist:package ca-certificates 2017.2.14 65.0.1.el6_9 arch noarch
./core.pkglist:package initscripts 9.03.58 1.0.3.el6_9.2prerel7.6.0.0.0_88.51.0 arch ${bestArch}
./core.pkglist:package nspr 4.13.1 1.el6
./core.pkglist:package nss 3.28.4 4.0.1.el6_9 arch ${bestArch}
./core.pkglist:package nss-util 3.28.4 1.el6_9 arch ${bestArch}
./core.pkglist:package tzdata 2018e 3.el6 arch noarch
How can get the output with the line number along with the pattern match as file:lineno.:package pkgname digits
awk sed grep
awk sed grep
asked Nov 28 '18 at 15:02
Unixquest945Unixquest945
396
asked Nov 28 '18 at 15:02
Unixquest945Unixquest945
396
asked Nov 28 '18 at 15:02
Unixquest945Unixquest945
396
asked Nov 28 '18 at 15:02
Unixquest945Unixquest945
396
asked Nov 28 '18 at 15:02
Unixquest945Unixquest945
396
396
not clear, could you please provide more details on input and expected output and let us know then.
– RavinderSingh13
Nov 28 '18 at 15:09
Outputs should not have lines without digits.
– Unixquest945
Nov 28 '18 at 15:22
Which block of text in your question is the sample input and which is the expected output?
– Ed Morton
Nov 28 '18 at 17:48
add a comment |
not clear, could you please provide more details on input and expected output and let us know then.
– RavinderSingh13
Nov 28 '18 at 15:09
Outputs should not have lines without digits.
– Unixquest945
Nov 28 '18 at 15:22
Which block of text in your question is the sample input and which is the expected output?
– Ed Morton
Nov 28 '18 at 17:48
not clear, could you please provide more details on input and expected output and let us know then.
– RavinderSingh13
Nov 28 '18 at 15:09
not clear, could you please provide more details on input and expected output and let us know then.
– RavinderSingh13
Nov 28 '18 at 15:09
Outputs should not have lines without digits.
– Unixquest945
Nov 28 '18 at 15:22
Outputs should not have lines without digits.
– Unixquest945
Nov 28 '18 at 15:22
Which block of text in your question is the sample input and which is the expected output?
– Ed Morton
Nov 28 '18 at 17:48
Which block of text in your question is the sample input and which is the expected output?
– Ed Morton
Nov 28 '18 at 17:48
add a comment |
1 Answer
1
active
oldest
votes
for i in $(cut -f1 ~/Version-pkgs)
do
grep -rin "package $i.*[0-9]" .
done
no need to use grep twice
Oneliner :
grep -rinf <(sed -E 's,([^ ]*).*,package 1.*[0-9],' ~/Version-pkgs) .
answered Nov 28 '18 at 15:31
Corentin LimierCorentin Limier
2,0511611
Thanks Corentin Limier , it worked and shown expected results.
– Unixquest945
Nov 28 '18 at 16:17
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
for i in $(cut -f1 ~/Version-pkgs)
do
grep -rin "package $i.*[0-9]" .
done
no need to use grep twice
Oneliner :
grep -rinf <(sed -E 's,([^ ]*).*,package 1.*[0-9],' ~/Version-pkgs) .
answered Nov 28 '18 at 15:31
Corentin LimierCorentin Limier
2,0511611
Thanks Corentin Limier , it worked and shown expected results.
– Unixquest945
Nov 28 '18 at 16:17
add a comment |
for i in $(cut -f1 ~/Version-pkgs)
do
grep -rin "package $i.*[0-9]" .
done
no need to use grep twice
Oneliner :
grep -rinf <(sed -E 's,([^ ]*).*,package 1.*[0-9],' ~/Version-pkgs) .
answered Nov 28 '18 at 15:31
Corentin LimierCorentin Limier
2,0511611
Thanks Corentin Limier , it worked and shown expected results.
– Unixquest945
Nov 28 '18 at 16:17
add a comment |
for i in $(cut -f1 ~/Version-pkgs)
do
grep -rin "package $i.*[0-9]" .
done
no need to use grep twice
Oneliner :
grep -rinf <(sed -E 's,([^ ]*).*,package 1.*[0-9],' ~/Version-pkgs) .
answered Nov 28 '18 at 15:31
Corentin LimierCorentin Limier
2,0511611
for i in $(cut -f1 ~/Version-pkgs)
do
grep -rin "package $i.*[0-9]" .
done
no need to use grep twice
Oneliner :
grep -rinf <(sed -E 's,([^ ]*).*,package 1.*[0-9],' ~/Version-pkgs) .
answered Nov 28 '18 at 15:31
Corentin LimierCorentin Limier
2,0511611
edited Nov 28 '18 at 16:55
answered Nov 28 '18 at 15:31
Corentin LimierCorentin Limier
2,0511611
answered Nov 28 '18 at 15:31
Corentin LimierCorentin Limier
2,0511611
answered Nov 28 '18 at 15:31
Corentin LimierCorentin Limier
2,0511611
2,0511611
Thanks Corentin Limier , it worked and shown expected results.
– Unixquest945
Nov 28 '18 at 16:17
add a comment |
Thanks Corentin Limier , it worked and shown expected results.
– Unixquest945
Nov 28 '18 at 16:17
Thanks Corentin Limier , it worked and shown expected results.
– Unixquest945
Nov 28 '18 at 16:17
Thanks Corentin Limier , it worked and shown expected results.
– Unixquest945
Nov 28 '18 at 16:17
add a comment |
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not clear, could you please provide more details on input and expected output and let us know then.
– RavinderSingh13
Nov 28 '18 at 15:09
Outputs should not have lines without digits.
– Unixquest945
Nov 28 '18 at 15:22
Which block of text in your question is the sample input and which is the expected output?
– Ed Morton
Nov 28 '18 at 17:48