PHP Object is destroyed
0
I am upgrading testlink (1.9.4 to 1.9.17). The older version uses php5 and the latest one uses php7.
My bellow code (putting partial lines) stopped working as the object is losing its value at fetchFirstRow on line #5.
If I comment fetchFirstRow then object $db loses its value in readFromDB on line #3.
Can someone help me in what is going wrong? The same thing works without any errors in the older version.
doDBConnect($db)
doDBConnect(&$db){
$db=new database(); //Create database class
}
myfunction(&$db){
$user->readFromDB($db);
}
readFromDB(&$db){
var_dump($db); //Shows DB object
$info = $db-> fetchFirstRow($sql);
var_dump($db); //Shows nothing (Object gets destroued and web page looks like 404 page).
}
function fetchFirstRow($sql){
$result = $this->exec_query($sql);
$row = null;
if ($result){
$row = $this->fetch_array($result);
}
unset($result);
//var_dump($this->db);die(); //If unset is not commentd then this
return $row;
}
php testlink
edited Nov 27 '18 at 10:08
treyBake
3,31031136
asked Nov 27 '18 at 10:05
Vinaykumar PatelVinaykumar Patel
389414
add a comment |
0
I am upgrading testlink (1.9.4 to 1.9.17). The older version uses php5 and the latest one uses php7.
My bellow code (putting partial lines) stopped working as the object is losing its value at fetchFirstRow on line #5.
If I comment fetchFirstRow then object $db loses its value in readFromDB on line #3.
Can someone help me in what is going wrong? The same thing works without any errors in the older version.
doDBConnect($db)
doDBConnect(&$db){
$db=new database(); //Create database class
}
myfunction(&$db){
$user->readFromDB($db);
}
readFromDB(&$db){
var_dump($db); //Shows DB object
$info = $db-> fetchFirstRow($sql);
var_dump($db); //Shows nothing (Object gets destroued and web page looks like 404 page).
}
function fetchFirstRow($sql){
$result = $this->exec_query($sql);
$row = null;
if ($result){
$row = $this->fetch_array($result);
}
unset($result);
//var_dump($this->db);die(); //If unset is not commentd then this
return $row;
}
php testlink
edited Nov 27 '18 at 10:08
treyBake
3,31031136
asked Nov 27 '18 at 10:05
Vinaykumar PatelVinaykumar Patel
389414
I had no idea functions can be defined / used how you are using them, are you sure that is valid?
– Script47
Nov 27 '18 at 10:07
@Script47 The functions are scattered across class. fetchFirstRow is part of database class whose object is getting created in line 4 of example.
– Vinaykumar Patel
Nov 27 '18 at 10:09
The only thing I can see in your code that could destroy a reference is unset(). Have you tried running exec_query and fetch_array outside fetchFirstRow()?
– Patrick
Nov 27 '18 at 10:29
@Patrick, I tried commenting unset (though it is destroying $result and not $this) but the values of $db is still gone after this function is over. I have mention that in my problem statement,
– Vinaykumar Patel
Nov 27 '18 at 12:23
add a comment |
0
0
0
I am upgrading testlink (1.9.4 to 1.9.17). The older version uses php5 and the latest one uses php7.
My bellow code (putting partial lines) stopped working as the object is losing its value at fetchFirstRow on line #5.
If I comment fetchFirstRow then object $db loses its value in readFromDB on line #3.
Can someone help me in what is going wrong? The same thing works without any errors in the older version.
doDBConnect($db)
doDBConnect(&$db){
$db=new database(); //Create database class
}
myfunction(&$db){
$user->readFromDB($db);
}
readFromDB(&$db){
var_dump($db); //Shows DB object
$info = $db-> fetchFirstRow($sql);
var_dump($db); //Shows nothing (Object gets destroued and web page looks like 404 page).
}
function fetchFirstRow($sql){
$result = $this->exec_query($sql);
$row = null;
if ($result){
$row = $this->fetch_array($result);
}
unset($result);
//var_dump($this->db);die(); //If unset is not commentd then this
return $row;
}
php testlink
edited Nov 27 '18 at 10:08
treyBake
3,31031136
asked Nov 27 '18 at 10:05
Vinaykumar PatelVinaykumar Patel
389414
I am upgrading testlink (1.9.4 to 1.9.17). The older version uses php5 and the latest one uses php7.
My bellow code (putting partial lines) stopped working as the object is losing its value at fetchFirstRow on line #5.
If I comment fetchFirstRow then object $db loses its value in readFromDB on line #3.
Can someone help me in what is going wrong? The same thing works without any errors in the older version.
doDBConnect($db)
doDBConnect(&$db){
$db=new database(); //Create database class
}
myfunction(&$db){
$user->readFromDB($db);
}
readFromDB(&$db){
var_dump($db); //Shows DB object
$info = $db-> fetchFirstRow($sql);
var_dump($db); //Shows nothing (Object gets destroued and web page looks like 404 page).
}
function fetchFirstRow($sql){
$result = $this->exec_query($sql);
$row = null;
if ($result){
$row = $this->fetch_array($result);
}
unset($result);
//var_dump($this->db);die(); //If unset is not commentd then this
return $row;
}
php testlink
php testlink
edited Nov 27 '18 at 10:08
treyBake
3,31031136
asked Nov 27 '18 at 10:05
Vinaykumar PatelVinaykumar Patel
389414
edited Nov 27 '18 at 10:08
treyBake
3,31031136
asked Nov 27 '18 at 10:05
Vinaykumar PatelVinaykumar Patel
389414
edited Nov 27 '18 at 10:08
treyBake
3,31031136
edited Nov 27 '18 at 10:08
treyBake
3,31031136
edited Nov 27 '18 at 10:08
treyBake
3,31031136
3,31031136
asked Nov 27 '18 at 10:05
Vinaykumar PatelVinaykumar Patel
389414
asked Nov 27 '18 at 10:05
Vinaykumar PatelVinaykumar Patel
389414
asked Nov 27 '18 at 10:05
Vinaykumar PatelVinaykumar Patel
389414
389414
I had no idea functions can be defined / used how you are using them, are you sure that is valid?
– Script47
Nov 27 '18 at 10:07
@Script47 The functions are scattered across class. fetchFirstRow is part of database class whose object is getting created in line 4 of example.
– Vinaykumar Patel
Nov 27 '18 at 10:09
The only thing I can see in your code that could destroy a reference is unset(). Have you tried running exec_query and fetch_array outside fetchFirstRow()?
– Patrick
Nov 27 '18 at 10:29
@Patrick, I tried commenting unset (though it is destroying $result and not $this) but the values of $db is still gone after this function is over. I have mention that in my problem statement,
– Vinaykumar Patel
Nov 27 '18 at 12:23
add a comment |
I had no idea functions can be defined / used how you are using them, are you sure that is valid?
– Script47
Nov 27 '18 at 10:07
@Script47 The functions are scattered across class. fetchFirstRow is part of database class whose object is getting created in line 4 of example.
– Vinaykumar Patel
Nov 27 '18 at 10:09
The only thing I can see in your code that could destroy a reference is unset(). Have you tried running exec_query and fetch_array outside fetchFirstRow()?
– Patrick
Nov 27 '18 at 10:29
@Patrick, I tried commenting unset (though it is destroying $result and not $this) but the values of $db is still gone after this function is over. I have mention that in my problem statement,
– Vinaykumar Patel
Nov 27 '18 at 12:23
I had no idea functions can be defined / used how you are using them, are you sure that is valid?
– Script47
Nov 27 '18 at 10:07
I had no idea functions can be defined / used how you are using them, are you sure that is valid?
– Script47
Nov 27 '18 at 10:07
@Script47 The functions are scattered across class. fetchFirstRow is part of database class whose object is getting created in line 4 of example.
– Vinaykumar Patel
Nov 27 '18 at 10:09
@Script47 The functions are scattered across class. fetchFirstRow is part of database class whose object is getting created in line 4 of example.
– Vinaykumar Patel
Nov 27 '18 at 10:09
The only thing I can see in your code that could destroy a reference is unset(). Have you tried running exec_query and fetch_array outside fetchFirstRow()?
– Patrick
Nov 27 '18 at 10:29
The only thing I can see in your code that could destroy a reference is unset(). Have you tried running exec_query and fetch_array outside fetchFirstRow()?
– Patrick
Nov 27 '18 at 10:29
@Patrick, I tried commenting unset (though it is destroying $result and not $this) but the values of $db is still gone after this function is over. I have mention that in my problem statement,
– Vinaykumar Patel
Nov 27 '18 at 12:23
@Patrick, I tried commenting unset (though it is destroying $result and not $this) but the values of $db is still gone after this function is over. I have mention that in my problem statement,
– Vinaykumar Patel
Nov 27 '18 at 12:23
add a comment |
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I had no idea functions can be defined / used how you are using them, are you sure that is valid?
– Script47
Nov 27 '18 at 10:07
@Script47 The functions are scattered across class. fetchFirstRow is part of database class whose object is getting created in line 4 of example.
– Vinaykumar Patel
Nov 27 '18 at 10:09
The only thing I can see in your code that could destroy a reference is unset(). Have you tried running exec_query and fetch_array outside fetchFirstRow()?
– Patrick
Nov 27 '18 at 10:29
@Patrick, I tried commenting unset (though it is destroying $result and not $this) but the values of $db is still gone after this function is over. I have mention that in my problem statement,
– Vinaykumar Patel
Nov 27 '18 at 12:23