Node position in TreeView
How can I get the position of a node from a TreeView with onclick event in JavaFX?
Let's say when I click on the node (dolor sit amet,) selected with the black circle how can I get the position?
I have tried this with an event when a node is expanded:
root.addEventHandler(EventType.ROOT, (Event event) -> {
if (event.getEventType().getName().equals("BranchExpandedEvent")) {
TreeItem item = (TreeItem) event.getSource();
//here I want to know item position
}
});
java javafx
asked Nov 27 '18 at 10:19
ASTeamASTeam
178211
add a comment |
How can I get the position of a node from a TreeView with onclick event in JavaFX?
Let's say when I click on the node (dolor sit amet,) selected with the black circle how can I get the position?
I have tried this with an event when a node is expanded:
root.addEventHandler(EventType.ROOT, (Event event) -> {
if (event.getEventType().getName().equals("BranchExpandedEvent")) {
TreeItem item = (TreeItem) event.getSource();
//here I want to know item position
}
});
java javafx
asked Nov 27 '18 at 10:19
ASTeamASTeam
178211
there is no item position, there's a cell position that has the item - please read a basic tutorial to learn how to implement and configure custom TreeCells
– kleopatra
Nov 27 '18 at 10:51
What do you want to do with the position(x,y) ? be specific.
– Calips
Nov 27 '18 at 12:17
@Calips I want to have this position and to add some other Nodes (Vertical line in my case to connect the treeitems at the same level) in the TreeView.
– ASTeam
Nov 27 '18 at 20:05
@kleopatra Can you give me some suggestion about that. To let you know I have done some of my CustomCell that extend TreeCell using the HBox widget, not so much success to achieve something out of the TreeItems so a Vertical Line that goes on top of them which should not be connected with TreeItems but only with the TreeView.
– ASTeam
Nov 27 '18 at 20:05
add a comment |
How can I get the position of a node from a TreeView with onclick event in JavaFX?
Let's say when I click on the node (dolor sit amet,) selected with the black circle how can I get the position?
I have tried this with an event when a node is expanded:
root.addEventHandler(EventType.ROOT, (Event event) -> {
if (event.getEventType().getName().equals("BranchExpandedEvent")) {
TreeItem item = (TreeItem) event.getSource();
//here I want to know item position
}
});
java javafx
asked Nov 27 '18 at 10:19
ASTeamASTeam
178211
How can I get the position of a node from a TreeView with onclick event in JavaFX?
Let's say when I click on the node (dolor sit amet,) selected with the black circle how can I get the position?
I have tried this with an event when a node is expanded:
root.addEventHandler(EventType.ROOT, (Event event) -> {
if (event.getEventType().getName().equals("BranchExpandedEvent")) {
TreeItem item = (TreeItem) event.getSource();
//here I want to know item position
}
});
java javafx
java javafx
asked Nov 27 '18 at 10:19
ASTeamASTeam
178211
asked Nov 27 '18 at 10:19
ASTeamASTeam
178211
asked Nov 27 '18 at 10:19
ASTeamASTeam
178211
asked Nov 27 '18 at 10:19
ASTeamASTeam
178211
asked Nov 27 '18 at 10:19
ASTeamASTeam
178211
178211
there is no item position, there's a cell position that has the item - please read a basic tutorial to learn how to implement and configure custom TreeCells
– kleopatra
Nov 27 '18 at 10:51
What do you want to do with the position(x,y) ? be specific.
– Calips
Nov 27 '18 at 12:17
@Calips I want to have this position and to add some other Nodes (Vertical line in my case to connect the treeitems at the same level) in the TreeView.
– ASTeam
Nov 27 '18 at 20:05
@kleopatra Can you give me some suggestion about that. To let you know I have done some of my CustomCell that extend TreeCell using the HBox widget, not so much success to achieve something out of the TreeItems so a Vertical Line that goes on top of them which should not be connected with TreeItems but only with the TreeView.
– ASTeam
Nov 27 '18 at 20:05
add a comment |
there is no item position, there's a cell position that has the item - please read a basic tutorial to learn how to implement and configure custom TreeCells
– kleopatra
Nov 27 '18 at 10:51
What do you want to do with the position(x,y) ? be specific.
– Calips
Nov 27 '18 at 12:17
@Calips I want to have this position and to add some other Nodes (Vertical line in my case to connect the treeitems at the same level) in the TreeView.
– ASTeam
Nov 27 '18 at 20:05
@kleopatra Can you give me some suggestion about that. To let you know I have done some of my CustomCell that extend TreeCell using the HBox widget, not so much success to achieve something out of the TreeItems so a Vertical Line that goes on top of them which should not be connected with TreeItems but only with the TreeView.
– ASTeam
Nov 27 '18 at 20:05
there is no item position, there's a cell position that has the item - please read a basic tutorial to learn how to implement and configure custom TreeCells
– kleopatra
Nov 27 '18 at 10:51
there is no item position, there's a cell position that has the item - please read a basic tutorial to learn how to implement and configure custom TreeCells
– kleopatra
Nov 27 '18 at 10:51
What do you want to do with the position(x,y) ? be specific.
– Calips
Nov 27 '18 at 12:17
What do you want to do with the position(x,y) ? be specific.
– Calips
Nov 27 '18 at 12:17
@Calips I want to have this position and to add some other Nodes (Vertical line in my case to connect the treeitems at the same level) in the TreeView.
– ASTeam
Nov 27 '18 at 20:05
@Calips I want to have this position and to add some other Nodes (Vertical line in my case to connect the treeitems at the same level) in the TreeView.
– ASTeam
Nov 27 '18 at 20:05
@kleopatra Can you give me some suggestion about that. To let you know I have done some of my CustomCell that extend TreeCell using the HBox widget, not so much success to achieve something out of the TreeItems so a Vertical Line that goes on top of them which should not be connected with TreeItems but only with the TreeView.
– ASTeam
Nov 27 '18 at 20:05
@kleopatra Can you give me some suggestion about that. To let you know I have done some of my CustomCell that extend TreeCell using the HBox widget, not so much success to achieve something out of the TreeItems so a Vertical Line that goes on top of them which should not be connected with TreeItems but only with the TreeView.
– ASTeam
Nov 27 '18 at 20:05
add a comment |
1 Answer
1
active
oldest
votes
The Node you're talking about is known as the disclosureNode and is accessible via the TreeCell.
The disclosure node is commonly seen represented as a triangle that rotates on screen to indicate whether or not the TreeItem that it is placed beside is expanded or collapsed.
You can get the position of this Node with properties such as Node.boundsInLocal or Node.boundsInParent. There are also methods in Node to help convert between coordinate spaces (e.g. localToScene, sceneToLocal, etc...).
Also, the following code is suspect:
root.addEventHandler(EventType.ROOT, (Event event) -> {
if (event.getEventType().getName().equals("BranchExpandedEvent")) {
}
});
You shouldn't need to check the name of the EventType. Instead, register the EventHandler for the EventType you want to listen for—in this case, TreeItem.branchExpandedEvent(). For example, if your TreeItems have values of type String:
// "root" is a TreeItem<String>
// "event" is a TreeItem.TreeModificationEvent<String>
root.addEventHandler(TreeItem.<String>branchExpandedEvent(), event -> {
// do something...
});
If you must check the EventType inside the EventHandler then test that the EventTypes are equal, not their names; it's less error-prone.
root.addEventHandler(Event.ANY, event -> {
if (event.getEventType().equals(TreeItem.branchExpandedEvent()) {
// do something...
}
});
I want to have this position and to add some other Nodes (Vertical line in my case to connect the treeitems at the same level) in the TreeView.
I haven't looked into it, but this sounds like it should be implemented by the TreeCell. The TreeItem shouldn't know much, if anything, about the view. In other words, handling this inside an event handler added to the root TreeItem seems like the wrong place. Note, you can get the expanded status of a TreeItem from within a TreeCell as it has access to its TreeItem.
answered Nov 28 '18 at 0:16
SlawSlaw
8,75631234
I have problems accessing the TreeCell from the TreeItem. In the event, I can get easily the TreeItemTreeItem item = (TreeItem) event.getSource();. How to access the TreeCell in order to access the disclosureNode and to use the properties of it.
– ASTeam
Nov 28 '18 at 11:43
You likely can't from theTreeItem. You can use your ownTreeCellimplementation by setting theTreeView.cellFactoryproperty. You may need to subclassTreeCellSkinas well.
– Slaw
Nov 28 '18 at 21:52
add a comment |
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1 Answer
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The Node you're talking about is known as the disclosureNode and is accessible via the TreeCell.
The disclosure node is commonly seen represented as a triangle that rotates on screen to indicate whether or not the TreeItem that it is placed beside is expanded or collapsed.
You can get the position of this Node with properties such as Node.boundsInLocal or Node.boundsInParent. There are also methods in Node to help convert between coordinate spaces (e.g. localToScene, sceneToLocal, etc...).
Also, the following code is suspect:
root.addEventHandler(EventType.ROOT, (Event event) -> {
if (event.getEventType().getName().equals("BranchExpandedEvent")) {
}
});
You shouldn't need to check the name of the EventType. Instead, register the EventHandler for the EventType you want to listen for—in this case, TreeItem.branchExpandedEvent(). For example, if your TreeItems have values of type String:
// "root" is a TreeItem<String>
// "event" is a TreeItem.TreeModificationEvent<String>
root.addEventHandler(TreeItem.<String>branchExpandedEvent(), event -> {
// do something...
});
If you must check the EventType inside the EventHandler then test that the EventTypes are equal, not their names; it's less error-prone.
root.addEventHandler(Event.ANY, event -> {
if (event.getEventType().equals(TreeItem.branchExpandedEvent()) {
// do something...
}
});
I want to have this position and to add some other Nodes (Vertical line in my case to connect the treeitems at the same level) in the TreeView.
I haven't looked into it, but this sounds like it should be implemented by the TreeCell. The TreeItem shouldn't know much, if anything, about the view. In other words, handling this inside an event handler added to the root TreeItem seems like the wrong place. Note, you can get the expanded status of a TreeItem from within a TreeCell as it has access to its TreeItem.
answered Nov 28 '18 at 0:16
SlawSlaw
8,75631234
I have problems accessing the TreeCell from the TreeItem. In the event, I can get easily the TreeItemTreeItem item = (TreeItem) event.getSource();. How to access the TreeCell in order to access the disclosureNode and to use the properties of it.
– ASTeam
Nov 28 '18 at 11:43
You likely can't from theTreeItem. You can use your ownTreeCellimplementation by setting theTreeView.cellFactoryproperty. You may need to subclassTreeCellSkinas well.
– Slaw
Nov 28 '18 at 21:52
add a comment |
The Node you're talking about is known as the disclosureNode and is accessible via the TreeCell.
The disclosure node is commonly seen represented as a triangle that rotates on screen to indicate whether or not the TreeItem that it is placed beside is expanded or collapsed.
You can get the position of this Node with properties such as Node.boundsInLocal or Node.boundsInParent. There are also methods in Node to help convert between coordinate spaces (e.g. localToScene, sceneToLocal, etc...).
Also, the following code is suspect:
root.addEventHandler(EventType.ROOT, (Event event) -> {
if (event.getEventType().getName().equals("BranchExpandedEvent")) {
}
});
You shouldn't need to check the name of the EventType. Instead, register the EventHandler for the EventType you want to listen for—in this case, TreeItem.branchExpandedEvent(). For example, if your TreeItems have values of type String:
// "root" is a TreeItem<String>
// "event" is a TreeItem.TreeModificationEvent<String>
root.addEventHandler(TreeItem.<String>branchExpandedEvent(), event -> {
// do something...
});
If you must check the EventType inside the EventHandler then test that the EventTypes are equal, not their names; it's less error-prone.
root.addEventHandler(Event.ANY, event -> {
if (event.getEventType().equals(TreeItem.branchExpandedEvent()) {
// do something...
}
});
I want to have this position and to add some other Nodes (Vertical line in my case to connect the treeitems at the same level) in the TreeView.
I haven't looked into it, but this sounds like it should be implemented by the TreeCell. The TreeItem shouldn't know much, if anything, about the view. In other words, handling this inside an event handler added to the root TreeItem seems like the wrong place. Note, you can get the expanded status of a TreeItem from within a TreeCell as it has access to its TreeItem.
answered Nov 28 '18 at 0:16
SlawSlaw
8,75631234
I have problems accessing the TreeCell from the TreeItem. In the event, I can get easily the TreeItemTreeItem item = (TreeItem) event.getSource();. How to access the TreeCell in order to access the disclosureNode and to use the properties of it.
– ASTeam
Nov 28 '18 at 11:43
You likely can't from theTreeItem. You can use your ownTreeCellimplementation by setting theTreeView.cellFactoryproperty. You may need to subclassTreeCellSkinas well.
– Slaw
Nov 28 '18 at 21:52
add a comment |
The Node you're talking about is known as the disclosureNode and is accessible via the TreeCell.
The disclosure node is commonly seen represented as a triangle that rotates on screen to indicate whether or not the TreeItem that it is placed beside is expanded or collapsed.
You can get the position of this Node with properties such as Node.boundsInLocal or Node.boundsInParent. There are also methods in Node to help convert between coordinate spaces (e.g. localToScene, sceneToLocal, etc...).
Also, the following code is suspect:
root.addEventHandler(EventType.ROOT, (Event event) -> {
if (event.getEventType().getName().equals("BranchExpandedEvent")) {
}
});
You shouldn't need to check the name of the EventType. Instead, register the EventHandler for the EventType you want to listen for—in this case, TreeItem.branchExpandedEvent(). For example, if your TreeItems have values of type String:
// "root" is a TreeItem<String>
// "event" is a TreeItem.TreeModificationEvent<String>
root.addEventHandler(TreeItem.<String>branchExpandedEvent(), event -> {
// do something...
});
If you must check the EventType inside the EventHandler then test that the EventTypes are equal, not their names; it's less error-prone.
root.addEventHandler(Event.ANY, event -> {
if (event.getEventType().equals(TreeItem.branchExpandedEvent()) {
// do something...
}
});
I want to have this position and to add some other Nodes (Vertical line in my case to connect the treeitems at the same level) in the TreeView.
I haven't looked into it, but this sounds like it should be implemented by the TreeCell. The TreeItem shouldn't know much, if anything, about the view. In other words, handling this inside an event handler added to the root TreeItem seems like the wrong place. Note, you can get the expanded status of a TreeItem from within a TreeCell as it has access to its TreeItem.
answered Nov 28 '18 at 0:16
SlawSlaw
8,75631234
The Node you're talking about is known as the disclosureNode and is accessible via the TreeCell.
The disclosure node is commonly seen represented as a triangle that rotates on screen to indicate whether or not the TreeItem that it is placed beside is expanded or collapsed.
You can get the position of this Node with properties such as Node.boundsInLocal or Node.boundsInParent. There are also methods in Node to help convert between coordinate spaces (e.g. localToScene, sceneToLocal, etc...).
Also, the following code is suspect:
root.addEventHandler(EventType.ROOT, (Event event) -> {
if (event.getEventType().getName().equals("BranchExpandedEvent")) {
}
});
You shouldn't need to check the name of the EventType. Instead, register the EventHandler for the EventType you want to listen for—in this case, TreeItem.branchExpandedEvent(). For example, if your TreeItems have values of type String:
// "root" is a TreeItem<String>
// "event" is a TreeItem.TreeModificationEvent<String>
root.addEventHandler(TreeItem.<String>branchExpandedEvent(), event -> {
// do something...
});
If you must check the EventType inside the EventHandler then test that the EventTypes are equal, not their names; it's less error-prone.
root.addEventHandler(Event.ANY, event -> {
if (event.getEventType().equals(TreeItem.branchExpandedEvent()) {
// do something...
}
});
I want to have this position and to add some other Nodes (Vertical line in my case to connect the treeitems at the same level) in the TreeView.
I haven't looked into it, but this sounds like it should be implemented by the TreeCell. The TreeItem shouldn't know much, if anything, about the view. In other words, handling this inside an event handler added to the root TreeItem seems like the wrong place. Note, you can get the expanded status of a TreeItem from within a TreeCell as it has access to its TreeItem.
answered Nov 28 '18 at 0:16
SlawSlaw
8,75631234
edited Nov 28 '18 at 0:39
answered Nov 28 '18 at 0:16
SlawSlaw
8,75631234
answered Nov 28 '18 at 0:16
SlawSlaw
8,75631234
answered Nov 28 '18 at 0:16
SlawSlaw
8,75631234
8,75631234
I have problems accessing the TreeCell from the TreeItem. In the event, I can get easily the TreeItemTreeItem item = (TreeItem) event.getSource();. How to access the TreeCell in order to access the disclosureNode and to use the properties of it.
– ASTeam
Nov 28 '18 at 11:43
You likely can't from theTreeItem. You can use your ownTreeCellimplementation by setting theTreeView.cellFactoryproperty. You may need to subclassTreeCellSkinas well.
– Slaw
Nov 28 '18 at 21:52
add a comment |
I have problems accessing the TreeCell from the TreeItem. In the event, I can get easily the TreeItemTreeItem item = (TreeItem) event.getSource();. How to access the TreeCell in order to access the disclosureNode and to use the properties of it.
– ASTeam
Nov 28 '18 at 11:43
You likely can't from theTreeItem. You can use your ownTreeCellimplementation by setting theTreeView.cellFactoryproperty. You may need to subclassTreeCellSkinas well.
– Slaw
Nov 28 '18 at 21:52
I have problems accessing the TreeCell from the TreeItem. In the event, I can get easily the TreeItem
TreeItem item = (TreeItem) event.getSource();. How to access the TreeCell in order to access the disclosureNode and to use the properties of it.– ASTeam
Nov 28 '18 at 11:43
I have problems accessing the TreeCell from the TreeItem. In the event, I can get easily the TreeItem
TreeItem item = (TreeItem) event.getSource();. How to access the TreeCell in order to access the disclosureNode and to use the properties of it.– ASTeam
Nov 28 '18 at 11:43
You likely can't from the
TreeItem. You can use your own TreeCell implementation by setting the TreeView.cellFactory property. You may need to subclass TreeCellSkin as well.– Slaw
Nov 28 '18 at 21:52
You likely can't from the
TreeItem. You can use your own TreeCell implementation by setting the TreeView.cellFactory property. You may need to subclass TreeCellSkin as well.– Slaw
Nov 28 '18 at 21:52
add a comment |
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there is no item position, there's a cell position that has the item - please read a basic tutorial to learn how to implement and configure custom TreeCells
– kleopatra
Nov 27 '18 at 10:51
What do you want to do with the position(x,y) ? be specific.
– Calips
Nov 27 '18 at 12:17
@Calips I want to have this position and to add some other Nodes (Vertical line in my case to connect the treeitems at the same level) in the TreeView.
– ASTeam
Nov 27 '18 at 20:05
@kleopatra Can you give me some suggestion about that. To let you know I have done some of my CustomCell that extend TreeCell using the HBox widget, not so much success to achieve something out of the TreeItems so a Vertical Line that goes on top of them which should not be connected with TreeItems but only with the TreeView.
– ASTeam
Nov 27 '18 at 20:05