How to align addlegendtry with the plot

Please consider this MWE:

documentclass{article}

usepackage[english]{babel}

usepackage[utf8]{inputenc}

usepackage[T1]{fontenc}

usepackage[a4paper,margin=1in,footskip=0.25in]{geometry}

usepackage{amssymb}

usepackage{amsmath}



usepackage{pgfplots}

pgfplotsset{compat=1.15}

pgfplotsset{soldot/.style={color=black,only marks,mark=*}}

pgfplotsset{holdot/.style={color=red,fill=white,very thick,only marks,mark=*}}



begin{document}

begin{center}

    begin{tikzpicture}[declare function={f(x,y)=(x*y)/(x*x+2*y*y);}]

        begin{axis} [

                axis on top,

                axis equal image,

                axis lines=center,

                xlabel=$x$,

                ylabel=$y$,

                zlabel=$z$,

                zmin=-1,

                zmax=1,

                ztick={-1,0,0.33,1},

                zticklabels={$-1$,$0$,$1/3$,$1$},

                ticklabel style={font=tiny},

                legend pos=outer north east,

                legend style={cells={align=left}},

                legend cell align={left},

                view={-135}{25},

            ]

            addplot3[surf,mesh/ordering=y varies,shader=interp,domain=-1:1,domain y=-1:1,samples=61, samples y=61] {f(x,y)};

            addlegendentry{(f(x,y))}

        end{axis}

    end{tikzpicture}

end{center}



end{document}

MWE output

As you can see, addlegendentry as far from the graph. How can we keep them together? Something like:

What I want

Thanks!!

edited 6 mins ago

asked 1 hour ago

manooooh

1,0681516

1

Are you sure you want to plot the function in this way? If you use polar coordinates in the x-y plane, x=r cos(phi) and y=r sin(phi), you see that the function does not depend on r but only on the angle. This explains the behavior at 0, where the function is not well-defined. And otherwise the function depends only on one variable, so I am wondering if you would be better off if you plotted a function of one variable only, or at least use a different parametrization.

– marmot
47 mins ago

@marmot please see the edit. The function has a "normal" behaviour when changing domain y=-1.2:1 to domain y=-1:1. If you want to use change of variables go ahead :). Do you know how to "enlarge" the axis without rescaling the entire function in order to make it a little more bigger?

– manooooh
45 mins ago

1

Normally you can set width=15cm or something like this. Of course, with axis equal image, one needs to be a bit careful. What I meant to say is that the function is not well-defined at x=y=0 and otherwise only a function that depends on one variable, not on two. You see this actually rather well in the upper plot.

– marmot
39 mins ago

1

I need to sleep so I will just post some 1d plot.

– marmot
21 mins ago

1

Please do not alter the question that essentially by editing. It is much better to ask a new question.

– TeXnician
4 mins ago

|
show 5 more comments

Please consider this MWE:

documentclass{article}

usepackage[english]{babel}

usepackage[utf8]{inputenc}

usepackage[T1]{fontenc}

usepackage[a4paper,margin=1in,footskip=0.25in]{geometry}

usepackage{amssymb}

usepackage{amsmath}



usepackage{pgfplots}

pgfplotsset{compat=1.15}

pgfplotsset{soldot/.style={color=black,only marks,mark=*}}

pgfplotsset{holdot/.style={color=red,fill=white,very thick,only marks,mark=*}}



begin{document}

begin{center}

    begin{tikzpicture}[declare function={f(x,y)=(x*y)/(x*x+2*y*y);}]

        begin{axis} [

                axis on top,

                axis equal image,

                axis lines=center,

                xlabel=$x$,

                ylabel=$y$,

                zlabel=$z$,

                zmin=-1,

                zmax=1,

                ztick={-1,0,0.33,1},

                zticklabels={$-1$,$0$,$1/3$,$1$},

                ticklabel style={font=tiny},

                legend pos=outer north east,

                legend style={cells={align=left}},

                legend cell align={left},

                view={-135}{25},

            ]

            addplot3[surf,mesh/ordering=y varies,shader=interp,domain=-1:1,domain y=-1:1,samples=61, samples y=61] {f(x,y)};

            addlegendentry{(f(x,y))}

        end{axis}

    end{tikzpicture}

end{center}



end{document}

MWE output

As you can see, addlegendentry as far from the graph. How can we keep them together? Something like:

What I want

Thanks!!

edited 6 mins ago

asked 1 hour ago

manooooh

1,0681516

1

Are you sure you want to plot the function in this way? If you use polar coordinates in the x-y plane, x=r cos(phi) and y=r sin(phi), you see that the function does not depend on r but only on the angle. This explains the behavior at 0, where the function is not well-defined. And otherwise the function depends only on one variable, so I am wondering if you would be better off if you plotted a function of one variable only, or at least use a different parametrization.

– marmot
47 mins ago

@marmot please see the edit. The function has a "normal" behaviour when changing domain y=-1.2:1 to domain y=-1:1. If you want to use change of variables go ahead :). Do you know how to "enlarge" the axis without rescaling the entire function in order to make it a little more bigger?

– manooooh
45 mins ago

1

Normally you can set width=15cm or something like this. Of course, with axis equal image, one needs to be a bit careful. What I meant to say is that the function is not well-defined at x=y=0 and otherwise only a function that depends on one variable, not on two. You see this actually rather well in the upper plot.

– marmot
39 mins ago

1

I need to sleep so I will just post some 1d plot.

– marmot
21 mins ago

1

Please do not alter the question that essentially by editing. It is much better to ask a new question.

– TeXnician
4 mins ago

|
show 5 more comments

Please consider this MWE:

documentclass{article}

usepackage[english]{babel}

usepackage[utf8]{inputenc}

usepackage[T1]{fontenc}

usepackage[a4paper,margin=1in,footskip=0.25in]{geometry}

usepackage{amssymb}

usepackage{amsmath}



usepackage{pgfplots}

pgfplotsset{compat=1.15}

pgfplotsset{soldot/.style={color=black,only marks,mark=*}}

pgfplotsset{holdot/.style={color=red,fill=white,very thick,only marks,mark=*}}



begin{document}

begin{center}

    begin{tikzpicture}[declare function={f(x,y)=(x*y)/(x*x+2*y*y);}]

        begin{axis} [

                axis on top,

                axis equal image,

                axis lines=center,

                xlabel=$x$,

                ylabel=$y$,

                zlabel=$z$,

                zmin=-1,

                zmax=1,

                ztick={-1,0,0.33,1},

                zticklabels={$-1$,$0$,$1/3$,$1$},

                ticklabel style={font=tiny},

                legend pos=outer north east,

                legend style={cells={align=left}},

                legend cell align={left},

                view={-135}{25},

            ]

            addplot3[surf,mesh/ordering=y varies,shader=interp,domain=-1:1,domain y=-1:1,samples=61, samples y=61] {f(x,y)};

            addlegendentry{(f(x,y))}

        end{axis}

    end{tikzpicture}

end{center}



end{document}

MWE output

As you can see, addlegendentry as far from the graph. How can we keep them together? Something like:

What I want

Thanks!!

edited 6 mins ago

asked 1 hour ago

manooooh

1,0681516

Please consider this MWE:

documentclass{article}

usepackage[english]{babel}

usepackage[utf8]{inputenc}

usepackage[T1]{fontenc}

usepackage[a4paper,margin=1in,footskip=0.25in]{geometry}

usepackage{amssymb}

usepackage{amsmath}



usepackage{pgfplots}

pgfplotsset{compat=1.15}

pgfplotsset{soldot/.style={color=black,only marks,mark=*}}

pgfplotsset{holdot/.style={color=red,fill=white,very thick,only marks,mark=*}}



begin{document}

begin{center}

    begin{tikzpicture}[declare function={f(x,y)=(x*y)/(x*x+2*y*y);}]

        begin{axis} [

                axis on top,

                axis equal image,

                axis lines=center,

                xlabel=$x$,

                ylabel=$y$,

                zlabel=$z$,

                zmin=-1,

                zmax=1,

                ztick={-1,0,0.33,1},

                zticklabels={$-1$,$0$,$1/3$,$1$},

                ticklabel style={font=tiny},

                legend pos=outer north east,

                legend style={cells={align=left}},

                legend cell align={left},

                view={-135}{25},

            ]

            addplot3[surf,mesh/ordering=y varies,shader=interp,domain=-1:1,domain y=-1:1,samples=61, samples y=61] {f(x,y)};

            addlegendentry{(f(x,y))}

        end{axis}

    end{tikzpicture}

end{center}



end{document}

MWE output

As you can see, addlegendentry as far from the graph. How can we keep them together? Something like:

What I want

Thanks!!

tikz-pgf

edited 6 mins ago

asked 1 hour ago

manooooh

1,0681516

edited 6 mins ago

asked 1 hour ago

manooooh

1,0681516

edited 6 mins ago

asked 1 hour ago

manooooh

1,0681516

asked 1 hour ago

manooooh

1,0681516

asked 1 hour ago

manooooh

1,0681516

1

Are you sure you want to plot the function in this way? If you use polar coordinates in the x-y plane, x=r cos(phi) and y=r sin(phi), you see that the function does not depend on r but only on the angle. This explains the behavior at 0, where the function is not well-defined. And otherwise the function depends only on one variable, so I am wondering if you would be better off if you plotted a function of one variable only, or at least use a different parametrization.

– marmot
47 mins ago

@marmot please see the edit. The function has a "normal" behaviour when changing domain y=-1.2:1 to domain y=-1:1. If you want to use change of variables go ahead :). Do you know how to "enlarge" the axis without rescaling the entire function in order to make it a little more bigger?

– manooooh
45 mins ago

1

Normally you can set width=15cm or something like this. Of course, with axis equal image, one needs to be a bit careful. What I meant to say is that the function is not well-defined at x=y=0 and otherwise only a function that depends on one variable, not on two. You see this actually rather well in the upper plot.

– marmot
39 mins ago

1

I need to sleep so I will just post some 1d plot.

– marmot
21 mins ago

1

Please do not alter the question that essentially by editing. It is much better to ask a new question.

– TeXnician
4 mins ago

|
show 5 more comments

1

Are you sure you want to plot the function in this way? If you use polar coordinates in the x-y plane, x=r cos(phi) and y=r sin(phi), you see that the function does not depend on r but only on the angle. This explains the behavior at 0, where the function is not well-defined. And otherwise the function depends only on one variable, so I am wondering if you would be better off if you plotted a function of one variable only, or at least use a different parametrization.

– marmot
47 mins ago

@marmot please see the edit. The function has a "normal" behaviour when changing domain y=-1.2:1 to domain y=-1:1. If you want to use change of variables go ahead :). Do you know how to "enlarge" the axis without rescaling the entire function in order to make it a little more bigger?

– manooooh
45 mins ago

1

Normally you can set width=15cm or something like this. Of course, with axis equal image, one needs to be a bit careful. What I meant to say is that the function is not well-defined at x=y=0 and otherwise only a function that depends on one variable, not on two. You see this actually rather well in the upper plot.

– marmot
39 mins ago

1

I need to sleep so I will just post some 1d plot.

– marmot
21 mins ago

1

Please do not alter the question that essentially by editing. It is much better to ask a new question.

– TeXnician
4 mins ago

Are you sure you want to plot the function in this way? If you use polar coordinates in the x-y plane, x=r cos(phi) and y=r sin(phi), you see that the function does not depend on r but only on the angle. This explains the behavior at 0, where the function is not well-defined. And otherwise the function depends only on one variable, so I am wondering if you would be better off if you plotted a function of one variable only, or at least use a different parametrization.

– marmot
47 mins ago

@marmot please see the edit. The function has a "normal" behaviour when changing domain y=-1.2:1 to domain y=-1:1. If you want to use change of variables go ahead :). Do you know how to "enlarge" the axis without rescaling the entire function in order to make it a little more bigger?

– manooooh
45 mins ago

Normally you can set width=15cm or something like this. Of course, with axis equal image, one needs to be a bit careful. What I meant to say is that the function is not well-defined at x=y=0 and otherwise only a function that depends on one variable, not on two. You see this actually rather well in the upper plot.

– marmot
39 mins ago

I need to sleep so I will just post some 1d plot.

– marmot
21 mins ago

Please do not alter the question that essentially by editing. It is much better to ask a new question.

– TeXnician
4 mins ago

|
show 5 more comments

1 Answer
1

active

oldest

votes

Not an answer to the (LaTeX part of the) question. However, if you use polar coordinates in the x-y plane, x=r cos(phi) and y=r sin(phi), you see that the function does not depend on r but only on the angle. So away from the origin x=y=0 all the information is already in a one-dimensional plot.

documentclass[tikz,border=3.14mm]{standalone}

usepackage{pgfplots}

pgfplotsset{compat=1.15}

begin{document}

begin{tikzpicture}[declare function={fan(t)=-(sin(2*t)/(-3 + cos(2*t)));}]

begin{axis}

 addplot[domain=0:360,smooth,samples=101] {fan(x)};

end{axis}

end{tikzpicture}

end{document}

enter image description here

answered 21 mins ago

marmot

103k4121233

I am so sorry, I have not found any problem with the requirement I thought I had a while ago. Please look at the question again. Apologies.

– manooooh
5 mins ago

add a comment |

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1 Answer
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1 Answer
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active

oldest

votes

documentclass[tikz,border=3.14mm]{standalone}

usepackage{pgfplots}

pgfplotsset{compat=1.15}

begin{document}

begin{tikzpicture}[declare function={fan(t)=-(sin(2*t)/(-3 + cos(2*t)));}]

begin{axis}

 addplot[domain=0:360,smooth,samples=101] {fan(x)};

end{axis}

end{tikzpicture}

end{document}

enter image description here

answered 21 mins ago

marmot

103k4121233

I am so sorry, I have not found any problem with the requirement I thought I had a while ago. Please look at the question again. Apologies.

– manooooh
5 mins ago

add a comment |

documentclass[tikz,border=3.14mm]{standalone}

usepackage{pgfplots}

pgfplotsset{compat=1.15}

begin{document}

begin{tikzpicture}[declare function={fan(t)=-(sin(2*t)/(-3 + cos(2*t)));}]

begin{axis}

 addplot[domain=0:360,smooth,samples=101] {fan(x)};

end{axis}

end{tikzpicture}

end{document}

enter image description here

answered 21 mins ago

marmot

103k4121233

I am so sorry, I have not found any problem with the requirement I thought I had a while ago. Please look at the question again. Apologies.

– manooooh
5 mins ago

add a comment |

documentclass[tikz,border=3.14mm]{standalone}

usepackage{pgfplots}

pgfplotsset{compat=1.15}

begin{document}

begin{tikzpicture}[declare function={fan(t)=-(sin(2*t)/(-3 + cos(2*t)));}]

begin{axis}

 addplot[domain=0:360,smooth,samples=101] {fan(x)};

end{axis}

end{tikzpicture}

end{document}

enter image description here

answered 21 mins ago

marmot

103k4121233

documentclass[tikz,border=3.14mm]{standalone}

usepackage{pgfplots}

pgfplotsset{compat=1.15}

begin{document}

begin{tikzpicture}[declare function={fan(t)=-(sin(2*t)/(-3 + cos(2*t)));}]

begin{axis}

 addplot[domain=0:360,smooth,samples=101] {fan(x)};

end{axis}

end{tikzpicture}

end{document}

enter image description here

answered 21 mins ago

marmot

103k4121233

answered 21 mins ago

marmot

103k4121233

answered 21 mins ago

marmot

103k4121233

answered 21 mins ago

marmot

103k4121233

I am so sorry, I have not found any problem with the requirement I thought I had a while ago. Please look at the question again. Apologies.

– manooooh
5 mins ago

add a comment |

I am so sorry, I have not found any problem with the requirement I thought I had a while ago. Please look at the question again. Apologies.

– manooooh
5 mins ago

I am so sorry, I have not found any problem with the requirement I thought I had a while ago. Please look at the question again. Apologies.

– manooooh
5 mins ago

add a comment |

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