Applying Posixlt to column with multiple formats












1















I have a very large dataset that contains a list of different date formats, namely the following:



2016-12-07 06:24:49

05/12/2017 08:01

05/12/2018 08

19.02.2018 04:32:35

06-01-2018 00:32:24


I am trying to convert them all to posixlt since the entire column is of the character class. I need to keep all the information though.



I tried the following for each one: 



df.all.copy$Time <- as.POSIXlt(df.all.copy$Time, tz="GMT", format = c("%d-%m-%Y %H:%M:%S"), optional = F)


This one after applying the following function: 



df.all.copy$Time <- gsub("/", "-", df.all.copy$Time)

df.all.copy$Time <- gsub(".", "-", df.all.copy$Time)





df.all.copy$Time <- as.POSIXlt(df.all.copy$Time, tz="GMT", format, tryFormats = c("%Y-%m-%d %H:%M:%S",

                                                                        "%d-%m-%Y %H:%M:%S"), optional = F)


But it just doesn't work, the above only applies the function to 1/2 of them, leaving the rest as NA.



Any help would be welcome.






r







share|improve this question

























  • Use parse_date_time from lubridate which takes multiple formats

    – akrun
    Nov 26 '18 at 22:34











  • I'll give it a go!

    – Thejohn
    Nov 26 '18 at 22:53
















1















I have a very large dataset that contains a list of different date formats, namely the following:



2016-12-07 06:24:49

05/12/2017 08:01

05/12/2018 08

19.02.2018 04:32:35

06-01-2018 00:32:24


I am trying to convert them all to posixlt since the entire column is of the character class. I need to keep all the information though.



I tried the following for each one: 



df.all.copy$Time <- as.POSIXlt(df.all.copy$Time, tz="GMT", format = c("%d-%m-%Y %H:%M:%S"), optional = F)


This one after applying the following function: 



df.all.copy$Time <- gsub("/", "-", df.all.copy$Time)

df.all.copy$Time <- gsub(".", "-", df.all.copy$Time)





df.all.copy$Time <- as.POSIXlt(df.all.copy$Time, tz="GMT", format, tryFormats = c("%Y-%m-%d %H:%M:%S",

                                                                        "%d-%m-%Y %H:%M:%S"), optional = F)


But it just doesn't work, the above only applies the function to 1/2 of them, leaving the rest as NA.



Any help would be welcome.






r







share|improve this question

























  • Use parse_date_time from lubridate which takes multiple formats

    – akrun
    Nov 26 '18 at 22:34











  • I'll give it a go!

    – Thejohn
    Nov 26 '18 at 22:53














1












1








1








I have a very large dataset that contains a list of different date formats, namely the following:



2016-12-07 06:24:49

05/12/2017 08:01

05/12/2018 08

19.02.2018 04:32:35

06-01-2018 00:32:24


I am trying to convert them all to posixlt since the entire column is of the character class. I need to keep all the information though.



I tried the following for each one: 



df.all.copy$Time <- as.POSIXlt(df.all.copy$Time, tz="GMT", format = c("%d-%m-%Y %H:%M:%S"), optional = F)


This one after applying the following function: 



df.all.copy$Time <- gsub("/", "-", df.all.copy$Time)

df.all.copy$Time <- gsub(".", "-", df.all.copy$Time)





df.all.copy$Time <- as.POSIXlt(df.all.copy$Time, tz="GMT", format, tryFormats = c("%Y-%m-%d %H:%M:%S",

                                                                        "%d-%m-%Y %H:%M:%S"), optional = F)


But it just doesn't work, the above only applies the function to 1/2 of them, leaving the rest as NA.



Any help would be welcome.






r







share|improve this question
















I have a very large dataset that contains a list of different date formats, namely the following:



2016-12-07 06:24:49

05/12/2017 08:01

05/12/2018 08

19.02.2018 04:32:35

06-01-2018 00:32:24


I am trying to convert them all to posixlt since the entire column is of the character class. I need to keep all the information though.



I tried the following for each one: 



df.all.copy$Time <- as.POSIXlt(df.all.copy$Time, tz="GMT", format = c("%d-%m-%Y %H:%M:%S"), optional = F)


This one after applying the following function: 



df.all.copy$Time <- gsub("/", "-", df.all.copy$Time)

df.all.copy$Time <- gsub(".", "-", df.all.copy$Time)





df.all.copy$Time <- as.POSIXlt(df.all.copy$Time, tz="GMT", format, tryFormats = c("%Y-%m-%d %H:%M:%S",

                                                                        "%d-%m-%Y %H:%M:%S"), optional = F)


But it just doesn't work, the above only applies the function to 1/2 of them, leaving the rest as NA.



Any help would be welcome.






r




r






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share|improve this question













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edited Nov 26 '18 at 22:43









r2evans

27.2k33058




27.2k33058










asked Nov 26 '18 at 22:30









ThejohnThejohn

277




277













  • Use parse_date_time from lubridate which takes multiple formats

    – akrun
    Nov 26 '18 at 22:34











  • I'll give it a go!

    – Thejohn
    Nov 26 '18 at 22:53



















  • Use parse_date_time from lubridate which takes multiple formats

    – akrun
    Nov 26 '18 at 22:34











  • I'll give it a go!

    – Thejohn
    Nov 26 '18 at 22:53

















Use parse_date_time from lubridate which takes multiple formats

– akrun
Nov 26 '18 at 22:34





Use parse_date_time from lubridate which takes multiple formats

– akrun
Nov 26 '18 at 22:34













I'll give it a go!

– Thejohn
Nov 26 '18 at 22:53





I'll give it a go!

– Thejohn
Nov 26 '18 at 22:53












1 Answer
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Assuming that the ambiguous day/month for the 2nd and 3rd case is day followed by month, we can use anytime to automatically pick up the format and convert to DateTime format



library(anytime)

anytime(v1)

#[1] "2016-12-07 06:24:49 EST" "2017-05-12 08:01:00 EDT" "2018-05-12 08:00:00 EDT" NA                       

#[5] "2018-06-01 00:00:00 EDT"


or specify the format in parse_date_time



library(lubridate)

parse_date_time(v1,   c("%Y-%m-%d %H:%M:%S", "%d/%m/%Y %H:%M",

    "%d/%m/%Y %H", "%d.%m.%Y %H:%M:%S",  "%d-%m-%Y %H:%M:%S"))


data



v1 <- c('2016-12-07 06:24:49', '05/12/2017 08:01', '05/12/2018 08', 

      '19.02.2018 04:32:35', '06-01-2018 00:32:24 ')





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    1














    Assuming that the ambiguous day/month for the 2nd and 3rd case is day followed by month, we can use anytime to automatically pick up the format and convert to DateTime format



    library(anytime)
    
anytime(v1)
    
#[1] "2016-12-07 06:24:49 EST" "2017-05-12 08:01:00 EDT" "2018-05-12 08:00:00 EDT" NA                       
    
#[5] "2018-06-01 00:00:00 EDT"


    or specify the format in parse_date_time



    library(lubridate)
    
parse_date_time(v1,   c("%Y-%m-%d %H:%M:%S", "%d/%m/%Y %H:%M",
    
    "%d/%m/%Y %H", "%d.%m.%Y %H:%M:%S",  "%d-%m-%Y %H:%M:%S"))


    data



    v1 <- c('2016-12-07 06:24:49', '05/12/2017 08:01', '05/12/2018 08', 
    
      '19.02.2018 04:32:35', '06-01-2018 00:32:24 ')





    share|improve this answer




























      1














      Assuming that the ambiguous day/month for the 2nd and 3rd case is day followed by month, we can use anytime to automatically pick up the format and convert to DateTime format



      library(anytime)
      
anytime(v1)
      
#[1] "2016-12-07 06:24:49 EST" "2017-05-12 08:01:00 EDT" "2018-05-12 08:00:00 EDT" NA                       
      
#[5] "2018-06-01 00:00:00 EDT"


      or specify the format in parse_date_time



      library(lubridate)
      
parse_date_time(v1,   c("%Y-%m-%d %H:%M:%S", "%d/%m/%Y %H:%M",
      
    "%d/%m/%Y %H", "%d.%m.%Y %H:%M:%S",  "%d-%m-%Y %H:%M:%S"))


      data



      v1 <- c('2016-12-07 06:24:49', '05/12/2017 08:01', '05/12/2018 08', 
      
      '19.02.2018 04:32:35', '06-01-2018 00:32:24 ')





      share|improve this answer


























        1












        1








        1







        Assuming that the ambiguous day/month for the 2nd and 3rd case is day followed by month, we can use anytime to automatically pick up the format and convert to DateTime format



        library(anytime)
        
anytime(v1)
        
#[1] "2016-12-07 06:24:49 EST" "2017-05-12 08:01:00 EDT" "2018-05-12 08:00:00 EDT" NA                       
        
#[5] "2018-06-01 00:00:00 EDT"


        or specify the format in parse_date_time



        library(lubridate)
        
parse_date_time(v1,   c("%Y-%m-%d %H:%M:%S", "%d/%m/%Y %H:%M",
        
    "%d/%m/%Y %H", "%d.%m.%Y %H:%M:%S",  "%d-%m-%Y %H:%M:%S"))


        data



        v1 <- c('2016-12-07 06:24:49', '05/12/2017 08:01', '05/12/2018 08', 
        
      '19.02.2018 04:32:35', '06-01-2018 00:32:24 ')





        share|improve this answer













        Assuming that the ambiguous day/month for the 2nd and 3rd case is day followed by month, we can use anytime to automatically pick up the format and convert to DateTime format



        library(anytime)
        
anytime(v1)
        
#[1] "2016-12-07 06:24:49 EST" "2017-05-12 08:01:00 EDT" "2018-05-12 08:00:00 EDT" NA                       
        
#[5] "2018-06-01 00:00:00 EDT"


        or specify the format in parse_date_time



        library(lubridate)
        
parse_date_time(v1,   c("%Y-%m-%d %H:%M:%S", "%d/%m/%Y %H:%M",
        
    "%d/%m/%Y %H", "%d.%m.%Y %H:%M:%S",  "%d-%m-%Y %H:%M:%S"))


        data



        v1 <- c('2016-12-07 06:24:49', '05/12/2017 08:01', '05/12/2018 08', 
        
      '19.02.2018 04:32:35', '06-01-2018 00:32:24 ')






        share|improve this answer












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        share|improve this answer










        answered Nov 26 '18 at 22:51









        akrunakrun

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