Print xml nodes for each element in a single row
0
I need to print the category and hours values from all nodes in this xml as comma separated values in a single row through xslt -
XML
<?xml version="1.0" encoding="UTF-8"?>
<course>
<subcourse>
<code>ABC</code>
<name>REFCOURSE</name>
<date>Date</date>
<category>SDF</category>
<hours>7</hours>
</subcourse>
<subcourse>
<code>DEF</code>
<name>ORIGCOURSE</name>
<date>Date</date>
<category>UIT</category>
<hours>9</hours>
</subcourse>
</course>
Output needed -
SDF,7,UIT,9
By taking help from stakoverflow, here's what I've done so far -
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" version="2.0">
<xsl:param name="range-1-begin" select="4"/>
<xsl:param name="range-1-end" select="5"/>
<xsl:param name="range-2-begin" select="6"/>
<xsl:param name="range-2-end" select="7"/>
<xsl:output method="text" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="subcourse">
<info><xsl:apply-templates/></info>
</xsl:template>
<xsl:template match="subcourse">
<xsl:if test = "not(position()= 1)">
<xsl:text>,</xsl:text>
</xsl:if>
<xsl:value-of select="."/>
</xsl:template>
</xsl:stylesheet>
Output - ABCREFCOURSEDateSDF7,DEFORIGCOURSEDateUIT9
I need it to iterate through every subcourse and pick category and hours if exist. I could not find how to pick only category and hours.
node.js xml xslt foreach
asked Nov 24 '18 at 17:31
SkausSkaus
12
add a comment |
0
I need to print the category and hours values from all nodes in this xml as comma separated values in a single row through xslt -
XML
<?xml version="1.0" encoding="UTF-8"?>
<course>
<subcourse>
<code>ABC</code>
<name>REFCOURSE</name>
<date>Date</date>
<category>SDF</category>
<hours>7</hours>
</subcourse>
<subcourse>
<code>DEF</code>
<name>ORIGCOURSE</name>
<date>Date</date>
<category>UIT</category>
<hours>9</hours>
</subcourse>
</course>
Output needed -
SDF,7,UIT,9
By taking help from stakoverflow, here's what I've done so far -
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" version="2.0">
<xsl:param name="range-1-begin" select="4"/>
<xsl:param name="range-1-end" select="5"/>
<xsl:param name="range-2-begin" select="6"/>
<xsl:param name="range-2-end" select="7"/>
<xsl:output method="text" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="subcourse">
<info><xsl:apply-templates/></info>
</xsl:template>
<xsl:template match="subcourse">
<xsl:if test = "not(position()= 1)">
<xsl:text>,</xsl:text>
</xsl:if>
<xsl:value-of select="."/>
</xsl:template>
</xsl:stylesheet>
Output - ABCREFCOURSEDateSDF7,DEFORIGCOURSEDateUIT9
I need it to iterate through every subcourse and pick category and hours if exist. I could not find how to pick only category and hours.
node.js xml xslt foreach
asked Nov 24 '18 at 17:31
SkausSkaus
12
5
Welcome to StackOverflow. If you expect people to help, it will be a good idea to show us what you have done so far. You should edit your question.
– norbjd
Nov 24 '18 at 17:43
add a comment |
0
0
0
I need to print the category and hours values from all nodes in this xml as comma separated values in a single row through xslt -
XML
<?xml version="1.0" encoding="UTF-8"?>
<course>
<subcourse>
<code>ABC</code>
<name>REFCOURSE</name>
<date>Date</date>
<category>SDF</category>
<hours>7</hours>
</subcourse>
<subcourse>
<code>DEF</code>
<name>ORIGCOURSE</name>
<date>Date</date>
<category>UIT</category>
<hours>9</hours>
</subcourse>
</course>
Output needed -
SDF,7,UIT,9
By taking help from stakoverflow, here's what I've done so far -
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" version="2.0">
<xsl:param name="range-1-begin" select="4"/>
<xsl:param name="range-1-end" select="5"/>
<xsl:param name="range-2-begin" select="6"/>
<xsl:param name="range-2-end" select="7"/>
<xsl:output method="text" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="subcourse">
<info><xsl:apply-templates/></info>
</xsl:template>
<xsl:template match="subcourse">
<xsl:if test = "not(position()= 1)">
<xsl:text>,</xsl:text>
</xsl:if>
<xsl:value-of select="."/>
</xsl:template>
</xsl:stylesheet>
Output - ABCREFCOURSEDateSDF7,DEFORIGCOURSEDateUIT9
I need it to iterate through every subcourse and pick category and hours if exist. I could not find how to pick only category and hours.
node.js xml xslt foreach
asked Nov 24 '18 at 17:31
SkausSkaus
12
I need to print the category and hours values from all nodes in this xml as comma separated values in a single row through xslt -
XML
<?xml version="1.0" encoding="UTF-8"?>
<course>
<subcourse>
<code>ABC</code>
<name>REFCOURSE</name>
<date>Date</date>
<category>SDF</category>
<hours>7</hours>
</subcourse>
<subcourse>
<code>DEF</code>
<name>ORIGCOURSE</name>
<date>Date</date>
<category>UIT</category>
<hours>9</hours>
</subcourse>
</course>
Output needed -
SDF,7,UIT,9
By taking help from stakoverflow, here's what I've done so far -
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" version="2.0">
<xsl:param name="range-1-begin" select="4"/>
<xsl:param name="range-1-end" select="5"/>
<xsl:param name="range-2-begin" select="6"/>
<xsl:param name="range-2-end" select="7"/>
<xsl:output method="text" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="subcourse">
<info><xsl:apply-templates/></info>
</xsl:template>
<xsl:template match="subcourse">
<xsl:if test = "not(position()= 1)">
<xsl:text>,</xsl:text>
</xsl:if>
<xsl:value-of select="."/>
</xsl:template>
</xsl:stylesheet>
Output - ABCREFCOURSEDateSDF7,DEFORIGCOURSEDateUIT9
I need it to iterate through every subcourse and pick category and hours if exist. I could not find how to pick only category and hours.
node.js xml xslt foreach
node.js xml xslt foreach
asked Nov 24 '18 at 17:31
SkausSkaus
12
asked Nov 24 '18 at 17:31
SkausSkaus
12
edited Nov 25 '18 at 2:28
Skaus
asked Nov 24 '18 at 17:31
SkausSkaus
12
asked Nov 24 '18 at 17:31
SkausSkaus
12
asked Nov 24 '18 at 17:31
SkausSkaus
12
12
5
Welcome to StackOverflow. If you expect people to help, it will be a good idea to show us what you have done so far. You should edit your question.
– norbjd
Nov 24 '18 at 17:43
add a comment |
5
Welcome to StackOverflow. If you expect people to help, it will be a good idea to show us what you have done so far. You should edit your question.
– norbjd
Nov 24 '18 at 17:43
5
5
Welcome to StackOverflow. If you expect people to help, it will be a good idea to show us what you have done so far. You should edit your question.
– norbjd
Nov 24 '18 at 17:43
Welcome to StackOverflow. If you expect people to help, it will be a good idea to show us what you have done so far. You should edit your question.
– norbjd
Nov 24 '18 at 17:43
add a comment |
1 Answer
1
active
oldest
votes
0
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" version="2.0">
<xsl:template match="//subcource">
<xsl:if test="category">
<xsl:if test = "not(position()=1)">
<xsl:text>,</xsl:text>
</xsl:if>
<xsl:value-of select="category"/><xsl:text>,</xsl:text><xsl:value-of select="hours"/>
</xsl:if>
</xsl:template>
</xsl:stylesheet>
answered Nov 25 '18 at 1:37
TARiKTARiK
161
add a comment |
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1 Answer
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<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" version="2.0">
<xsl:template match="//subcource">
<xsl:if test="category">
<xsl:if test = "not(position()=1)">
<xsl:text>,</xsl:text>
</xsl:if>
<xsl:value-of select="category"/><xsl:text>,</xsl:text><xsl:value-of select="hours"/>
</xsl:if>
</xsl:template>
</xsl:stylesheet>
answered Nov 25 '18 at 1:37
TARiKTARiK
161
add a comment |
0
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" version="2.0">
<xsl:template match="//subcource">
<xsl:if test="category">
<xsl:if test = "not(position()=1)">
<xsl:text>,</xsl:text>
</xsl:if>
<xsl:value-of select="category"/><xsl:text>,</xsl:text><xsl:value-of select="hours"/>
</xsl:if>
</xsl:template>
</xsl:stylesheet>
answered Nov 25 '18 at 1:37
TARiKTARiK
161
add a comment |
0
0
0
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" version="2.0">
<xsl:template match="//subcource">
<xsl:if test="category">
<xsl:if test = "not(position()=1)">
<xsl:text>,</xsl:text>
</xsl:if>
<xsl:value-of select="category"/><xsl:text>,</xsl:text><xsl:value-of select="hours"/>
</xsl:if>
</xsl:template>
</xsl:stylesheet>
answered Nov 25 '18 at 1:37
TARiKTARiK
161
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" version="2.0">
<xsl:template match="//subcource">
<xsl:if test="category">
<xsl:if test = "not(position()=1)">
<xsl:text>,</xsl:text>
</xsl:if>
<xsl:value-of select="category"/><xsl:text>,</xsl:text><xsl:value-of select="hours"/>
</xsl:if>
</xsl:template>
</xsl:stylesheet>
answered Nov 25 '18 at 1:37
TARiKTARiK
161
answered Nov 25 '18 at 1:37
TARiKTARiK
161
answered Nov 25 '18 at 1:37
TARiKTARiK
161
answered Nov 25 '18 at 1:37
TARiKTARiK
161
161
add a comment |
add a comment |
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5
Welcome to StackOverflow. If you expect people to help, it will be a good idea to show us what you have done so far. You should edit your question.
– norbjd
Nov 24 '18 at 17:43