Print xml nodes for each element in a single row












0















I need to print the category and hours values from all nodes in this xml as comma separated values in a single row through xslt -



XML



    <?xml version="1.0" encoding="UTF-8"?>
<course>
<subcourse>
<code>ABC</code>
<name>REFCOURSE</name>
<date>Date</date>
<category>SDF</category>
<hours>7</hours>
</subcourse>
<subcourse>
<code>DEF</code>
<name>ORIGCOURSE</name>
<date>Date</date>
<category>UIT</category>
<hours>9</hours>
</subcourse>
</course>


Output needed -



SDF,7,UIT,9


By taking help from stakoverflow, here's what I've done so far -



<?xml version="1.0" encoding="UTF-8"?>

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" version="2.0">

<xsl:param name="range-1-begin" select="4"/>
<xsl:param name="range-1-end" select="5"/>

<xsl:param name="range-2-begin" select="6"/>
<xsl:param name="range-2-end" select="7"/>


<xsl:output method="text" indent="yes"/>
<xsl:strip-space elements="*"/>

<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>

<xsl:template match="subcourse">
<info><xsl:apply-templates/></info>
</xsl:template>

<xsl:template match="subcourse">
<xsl:if test = "not(position()= 1)">
<xsl:text>,</xsl:text>
</xsl:if>
<xsl:value-of select="."/>
</xsl:template>


</xsl:stylesheet>


Output - ABCREFCOURSEDateSDF7,DEFORIGCOURSEDateUIT9



I need it to iterate through every subcourse and pick category and hours if exist. I could not find how to pick only category and hours.










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  • 5





    Welcome to StackOverflow. If you expect people to help, it will be a good idea to show us what you have done so far. You should edit your question.

    – norbjd
    Nov 24 '18 at 17:43
















0















I need to print the category and hours values from all nodes in this xml as comma separated values in a single row through xslt -



XML



    <?xml version="1.0" encoding="UTF-8"?>
<course>
<subcourse>
<code>ABC</code>
<name>REFCOURSE</name>
<date>Date</date>
<category>SDF</category>
<hours>7</hours>
</subcourse>
<subcourse>
<code>DEF</code>
<name>ORIGCOURSE</name>
<date>Date</date>
<category>UIT</category>
<hours>9</hours>
</subcourse>
</course>


Output needed -



SDF,7,UIT,9


By taking help from stakoverflow, here's what I've done so far -



<?xml version="1.0" encoding="UTF-8"?>

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" version="2.0">

<xsl:param name="range-1-begin" select="4"/>
<xsl:param name="range-1-end" select="5"/>

<xsl:param name="range-2-begin" select="6"/>
<xsl:param name="range-2-end" select="7"/>


<xsl:output method="text" indent="yes"/>
<xsl:strip-space elements="*"/>

<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>

<xsl:template match="subcourse">
<info><xsl:apply-templates/></info>
</xsl:template>

<xsl:template match="subcourse">
<xsl:if test = "not(position()= 1)">
<xsl:text>,</xsl:text>
</xsl:if>
<xsl:value-of select="."/>
</xsl:template>


</xsl:stylesheet>


Output - ABCREFCOURSEDateSDF7,DEFORIGCOURSEDateUIT9



I need it to iterate through every subcourse and pick category and hours if exist. I could not find how to pick only category and hours.










share|improve this question




















  • 5





    Welcome to StackOverflow. If you expect people to help, it will be a good idea to show us what you have done so far. You should edit your question.

    – norbjd
    Nov 24 '18 at 17:43














0












0








0








I need to print the category and hours values from all nodes in this xml as comma separated values in a single row through xslt -



XML



    <?xml version="1.0" encoding="UTF-8"?>
<course>
<subcourse>
<code>ABC</code>
<name>REFCOURSE</name>
<date>Date</date>
<category>SDF</category>
<hours>7</hours>
</subcourse>
<subcourse>
<code>DEF</code>
<name>ORIGCOURSE</name>
<date>Date</date>
<category>UIT</category>
<hours>9</hours>
</subcourse>
</course>


Output needed -



SDF,7,UIT,9


By taking help from stakoverflow, here's what I've done so far -



<?xml version="1.0" encoding="UTF-8"?>

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" version="2.0">

<xsl:param name="range-1-begin" select="4"/>
<xsl:param name="range-1-end" select="5"/>

<xsl:param name="range-2-begin" select="6"/>
<xsl:param name="range-2-end" select="7"/>


<xsl:output method="text" indent="yes"/>
<xsl:strip-space elements="*"/>

<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>

<xsl:template match="subcourse">
<info><xsl:apply-templates/></info>
</xsl:template>

<xsl:template match="subcourse">
<xsl:if test = "not(position()= 1)">
<xsl:text>,</xsl:text>
</xsl:if>
<xsl:value-of select="."/>
</xsl:template>


</xsl:stylesheet>


Output - ABCREFCOURSEDateSDF7,DEFORIGCOURSEDateUIT9



I need it to iterate through every subcourse and pick category and hours if exist. I could not find how to pick only category and hours.










share|improve this question
















I need to print the category and hours values from all nodes in this xml as comma separated values in a single row through xslt -



XML



    <?xml version="1.0" encoding="UTF-8"?>
<course>
<subcourse>
<code>ABC</code>
<name>REFCOURSE</name>
<date>Date</date>
<category>SDF</category>
<hours>7</hours>
</subcourse>
<subcourse>
<code>DEF</code>
<name>ORIGCOURSE</name>
<date>Date</date>
<category>UIT</category>
<hours>9</hours>
</subcourse>
</course>


Output needed -



SDF,7,UIT,9


By taking help from stakoverflow, here's what I've done so far -



<?xml version="1.0" encoding="UTF-8"?>

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" version="2.0">

<xsl:param name="range-1-begin" select="4"/>
<xsl:param name="range-1-end" select="5"/>

<xsl:param name="range-2-begin" select="6"/>
<xsl:param name="range-2-end" select="7"/>


<xsl:output method="text" indent="yes"/>
<xsl:strip-space elements="*"/>

<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>

<xsl:template match="subcourse">
<info><xsl:apply-templates/></info>
</xsl:template>

<xsl:template match="subcourse">
<xsl:if test = "not(position()= 1)">
<xsl:text>,</xsl:text>
</xsl:if>
<xsl:value-of select="."/>
</xsl:template>


</xsl:stylesheet>


Output - ABCREFCOURSEDateSDF7,DEFORIGCOURSEDateUIT9



I need it to iterate through every subcourse and pick category and hours if exist. I could not find how to pick only category and hours.







node.js xml xslt foreach






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share|improve this question








edited Nov 25 '18 at 2:28







Skaus

















asked Nov 24 '18 at 17:31









SkausSkaus

12




12








  • 5





    Welcome to StackOverflow. If you expect people to help, it will be a good idea to show us what you have done so far. You should edit your question.

    – norbjd
    Nov 24 '18 at 17:43














  • 5





    Welcome to StackOverflow. If you expect people to help, it will be a good idea to show us what you have done so far. You should edit your question.

    – norbjd
    Nov 24 '18 at 17:43








5




5





Welcome to StackOverflow. If you expect people to help, it will be a good idea to show us what you have done so far. You should edit your question.

– norbjd
Nov 24 '18 at 17:43





Welcome to StackOverflow. If you expect people to help, it will be a good idea to show us what you have done so far. You should edit your question.

– norbjd
Nov 24 '18 at 17:43












1 Answer
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<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" version="2.0">
<xsl:template match="//subcource">
<xsl:if test="category">
<xsl:if test = "not(position()=1)">
<xsl:text>,</xsl:text>
</xsl:if>
<xsl:value-of select="category"/><xsl:text>,</xsl:text><xsl:value-of select="hours"/>
</xsl:if>
</xsl:template>
</xsl:stylesheet>





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    <?xml version="1.0" encoding="UTF-8"?>
    <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" version="2.0">
    <xsl:template match="//subcource">
    <xsl:if test="category">
    <xsl:if test = "not(position()=1)">
    <xsl:text>,</xsl:text>
    </xsl:if>
    <xsl:value-of select="category"/><xsl:text>,</xsl:text><xsl:value-of select="hours"/>
    </xsl:if>
    </xsl:template>
    </xsl:stylesheet>





    share|improve this answer




























      0














      <?xml version="1.0" encoding="UTF-8"?>
      <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" version="2.0">
      <xsl:template match="//subcource">
      <xsl:if test="category">
      <xsl:if test = "not(position()=1)">
      <xsl:text>,</xsl:text>
      </xsl:if>
      <xsl:value-of select="category"/><xsl:text>,</xsl:text><xsl:value-of select="hours"/>
      </xsl:if>
      </xsl:template>
      </xsl:stylesheet>





      share|improve this answer


























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        <?xml version="1.0" encoding="UTF-8"?>
        <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" version="2.0">
        <xsl:template match="//subcource">
        <xsl:if test="category">
        <xsl:if test = "not(position()=1)">
        <xsl:text>,</xsl:text>
        </xsl:if>
        <xsl:value-of select="category"/><xsl:text>,</xsl:text><xsl:value-of select="hours"/>
        </xsl:if>
        </xsl:template>
        </xsl:stylesheet>





        share|improve this answer













        <?xml version="1.0" encoding="UTF-8"?>
        <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" version="2.0">
        <xsl:template match="//subcource">
        <xsl:if test="category">
        <xsl:if test = "not(position()=1)">
        <xsl:text>,</xsl:text>
        </xsl:if>
        <xsl:value-of select="category"/><xsl:text>,</xsl:text><xsl:value-of select="hours"/>
        </xsl:if>
        </xsl:template>
        </xsl:stylesheet>






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 25 '18 at 1:37









        TARiKTARiK

        161




        161






























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