Enhanced for loop and lambda expressions
To my understanding, lambda expressions capture
values, not variables
. For example, the following is a compile-time error:
for (int k = 0; k < 10; k++) {
new Thread(() -> System.out.println(k)).start();
// Error—cannot capture k
//Local variable k defined in an enclosing scope must be final or effectively final
}
however when I try to ran the same logic with enhanced for-loop
every thing is working fine
ArrayList<Integer> listOfInt = new ArrayList<Integer>() {
{
add(1);
add(2);
add(3);
}
};
for (Integer arg : listOfInt) {
new Thread(() -> System.out.println(arg)).start();
// OK to capture arg
}
Please help me understand why it is working fine for enhanced for loop and not for normal loop, although enhanced for loop also somewhere inside incrementing the variable as done by normal loop.
java lambda
add a comment |
To my understanding, lambda expressions capture
values, not variables
. For example, the following is a compile-time error:
for (int k = 0; k < 10; k++) {
new Thread(() -> System.out.println(k)).start();
// Error—cannot capture k
//Local variable k defined in an enclosing scope must be final or effectively final
}
however when I try to ran the same logic with enhanced for-loop
every thing is working fine
ArrayList<Integer> listOfInt = new ArrayList<Integer>() {
{
add(1);
add(2);
add(3);
}
};
for (Integer arg : listOfInt) {
new Thread(() -> System.out.println(arg)).start();
// OK to capture arg
}
Please help me understand why it is working fine for enhanced for loop and not for normal loop, although enhanced for loop also somewhere inside incrementing the variable as done by normal loop.
java lambda
// Error—cannot capture i
Did you mean k rather than i?
– Prashant Zombade
1 hour ago
@PrashantZombade , typo please check the question again.
– Show Stopper
1 hour ago
add a comment |
To my understanding, lambda expressions capture
values, not variables
. For example, the following is a compile-time error:
for (int k = 0; k < 10; k++) {
new Thread(() -> System.out.println(k)).start();
// Error—cannot capture k
//Local variable k defined in an enclosing scope must be final or effectively final
}
however when I try to ran the same logic with enhanced for-loop
every thing is working fine
ArrayList<Integer> listOfInt = new ArrayList<Integer>() {
{
add(1);
add(2);
add(3);
}
};
for (Integer arg : listOfInt) {
new Thread(() -> System.out.println(arg)).start();
// OK to capture arg
}
Please help me understand why it is working fine for enhanced for loop and not for normal loop, although enhanced for loop also somewhere inside incrementing the variable as done by normal loop.
java lambda
To my understanding, lambda expressions capture
values, not variables
. For example, the following is a compile-time error:
for (int k = 0; k < 10; k++) {
new Thread(() -> System.out.println(k)).start();
// Error—cannot capture k
//Local variable k defined in an enclosing scope must be final or effectively final
}
however when I try to ran the same logic with enhanced for-loop
every thing is working fine
ArrayList<Integer> listOfInt = new ArrayList<Integer>() {
{
add(1);
add(2);
add(3);
}
};
for (Integer arg : listOfInt) {
new Thread(() -> System.out.println(arg)).start();
// OK to capture arg
}
Please help me understand why it is working fine for enhanced for loop and not for normal loop, although enhanced for loop also somewhere inside incrementing the variable as done by normal loop.
java lambda
java lambda
edited 1 hour ago
Show Stopper
asked 1 hour ago
Show StopperShow Stopper
5,1701965
5,1701965
// Error—cannot capture i
Did you mean k rather than i?
– Prashant Zombade
1 hour ago
@PrashantZombade , typo please check the question again.
– Show Stopper
1 hour ago
add a comment |
// Error—cannot capture i
Did you mean k rather than i?
– Prashant Zombade
1 hour ago
@PrashantZombade , typo please check the question again.
– Show Stopper
1 hour ago
// Error—cannot capture i
Did you mean k rather than i?– Prashant Zombade
1 hour ago
// Error—cannot capture i
Did you mean k rather than i?– Prashant Zombade
1 hour ago
@PrashantZombade , typo please check the question again.
– Show Stopper
1 hour ago
@PrashantZombade , typo please check the question again.
– Show Stopper
1 hour ago
add a comment |
3 Answers
3
active
oldest
votes
Lambda-Expressions work like callbacks. The moment they are passed in the code, they 'store' any external values (or references) they require to operate (as if these values were passed as arguments in a function call. This is just hidden from the developer). In your first example, you could work around the problem by storing k to a separate variable, like d:
for (int k = 0; k < 10; k++) {
final int d = k
new Thread(() -> System.out.println(d)).start();
}
Effectively final means, that in the above example, you can leave the 'final' keyword out, because d
is effectively final, since it is never changed within it's scope.
for-loops operate differently. They are iterative code (as opposed to a callback). They work within their respective scope and can use all variables on their own stack. This means, that the for-loop's code block is part of the external code block.
As to your highlighted question:
An enhanced for-loop does not operate with a regular index-counter, at least not directly. Enhanced for loops (over non-arrays) create a hidden Iterator. You can test this the following way:
Collection<String> mySet = new HashSet<>();
mySet.addAll(Arrays.asList("A", "B", "C"));
for (String myString : mySet) {
if (myString.equals("B")) {
mySet.remove(myString);
}
}
The above example will cause a ConcurrentModificationException. This is due to the iterator noticing, that the underlying collection has changed during the execution. However in your very example, the external loop creates an 'effectively final' variable arg
which can be referenced within the lambda expression, because the value is captured at execution time.
The prevention of the capture of 'non-effectively-final' values is more or less just a precaution in Java, because in other languages (like JavaScript e.g.) this works differently. So the compiler could theoretically translate your code, capture the value, and continue, but it would have to store that value differently, and you would probably get unexpected results. Therefore the team developing lambdas for Java 8 correctly excluded this scenario, by preventing it with an exception.
If you ever need to change values of external variables within lambda expressions, you can either declare a one-element array:
String myStringRef = { "before" };
someCallingMethod(() -> myStringRef[0] = "after" );
System.out.println(myStringRef[0]);
Or use Atomic to make it thread-safe. However with your example, this would probably return "before" since the thread would most likely execute after the execution of println.
add a comment |
In an enhanced for loop the variable is initialized for each iteration. From §14.14.2 of the JLS:
...
When an enhanced for statement is executed, the local variable is initialized, on each iteration of the loop, to successive elements of the array or Iterable produced by the expression. The precise meaning of the enhanced for statement is given by translation into a basic for statement, as follows:
If the type of Expression is a subtype of Iterable, then the translation is as follows.
If the type of Expression is a subtype of Iterable for some type argument X, then let I be the type java.util.Iterator; otherwise, let I be the raw type java.util.Iterator.
The enhanced for statement is equivalent to a basic for statement of the form:
for (I #i = Expression.iterator(); #i.hasNext(); ) {
{VariableModifier} TargetType Identifier =
(TargetType) #i.next();
Statement
}
...
Otherwise, the Expression necessarily has an array type, T.
Let L1 ... Lm be the (possibly empty) sequence of labels immediately preceding the enhanced for statement.
The enhanced for statement is equivalent to a basic for statement of the form:
T #a = Expression;
L1: L2: ... Lm:
for (int #i = 0; #i < #a.length; #i++) {
{VariableModifier} TargetType Identifier = #a[#i];
Statement
}
...
In other words, your enhanced for loop is equivalent to:
ArrayList<Integer> listOfInt = new ArrayList<>();
// add elements...
for (Iterator<Integer> itr = listOfInt.iterator(); itr.hasNext(); ) {
Integer arg = itr.next();
new Thread(() -> System.out.println(arg)).start();
}
Since the variable is initialized each iteration it is effectively final (unless you modify the variable inside the loop).
In contrast, the variable in the basic for loop (k
in your case) is initialized once and updated each iteration (if a "ForUpdate" is present, e.g. k++
). See §14.14.1 of the JLS for more information. Since the variable is updated each iteration is is not final nor effectively final.
add a comment |
An enhanced for
loop is defined to be equivalent to this code:
for (Iterator<T> it = iterable.iterator(); it.hasNext(); ) {
T loopvar = it.next();
…
}
This substitution code explains why the variable of an enhanced for
loop is considered effectively final.
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
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oldest
votes
active
oldest
votes
Lambda-Expressions work like callbacks. The moment they are passed in the code, they 'store' any external values (or references) they require to operate (as if these values were passed as arguments in a function call. This is just hidden from the developer). In your first example, you could work around the problem by storing k to a separate variable, like d:
for (int k = 0; k < 10; k++) {
final int d = k
new Thread(() -> System.out.println(d)).start();
}
Effectively final means, that in the above example, you can leave the 'final' keyword out, because d
is effectively final, since it is never changed within it's scope.
for-loops operate differently. They are iterative code (as opposed to a callback). They work within their respective scope and can use all variables on their own stack. This means, that the for-loop's code block is part of the external code block.
As to your highlighted question:
An enhanced for-loop does not operate with a regular index-counter, at least not directly. Enhanced for loops (over non-arrays) create a hidden Iterator. You can test this the following way:
Collection<String> mySet = new HashSet<>();
mySet.addAll(Arrays.asList("A", "B", "C"));
for (String myString : mySet) {
if (myString.equals("B")) {
mySet.remove(myString);
}
}
The above example will cause a ConcurrentModificationException. This is due to the iterator noticing, that the underlying collection has changed during the execution. However in your very example, the external loop creates an 'effectively final' variable arg
which can be referenced within the lambda expression, because the value is captured at execution time.
The prevention of the capture of 'non-effectively-final' values is more or less just a precaution in Java, because in other languages (like JavaScript e.g.) this works differently. So the compiler could theoretically translate your code, capture the value, and continue, but it would have to store that value differently, and you would probably get unexpected results. Therefore the team developing lambdas for Java 8 correctly excluded this scenario, by preventing it with an exception.
If you ever need to change values of external variables within lambda expressions, you can either declare a one-element array:
String myStringRef = { "before" };
someCallingMethod(() -> myStringRef[0] = "after" );
System.out.println(myStringRef[0]);
Or use Atomic to make it thread-safe. However with your example, this would probably return "before" since the thread would most likely execute after the execution of println.
add a comment |
Lambda-Expressions work like callbacks. The moment they are passed in the code, they 'store' any external values (or references) they require to operate (as if these values were passed as arguments in a function call. This is just hidden from the developer). In your first example, you could work around the problem by storing k to a separate variable, like d:
for (int k = 0; k < 10; k++) {
final int d = k
new Thread(() -> System.out.println(d)).start();
}
Effectively final means, that in the above example, you can leave the 'final' keyword out, because d
is effectively final, since it is never changed within it's scope.
for-loops operate differently. They are iterative code (as opposed to a callback). They work within their respective scope and can use all variables on their own stack. This means, that the for-loop's code block is part of the external code block.
As to your highlighted question:
An enhanced for-loop does not operate with a regular index-counter, at least not directly. Enhanced for loops (over non-arrays) create a hidden Iterator. You can test this the following way:
Collection<String> mySet = new HashSet<>();
mySet.addAll(Arrays.asList("A", "B", "C"));
for (String myString : mySet) {
if (myString.equals("B")) {
mySet.remove(myString);
}
}
The above example will cause a ConcurrentModificationException. This is due to the iterator noticing, that the underlying collection has changed during the execution. However in your very example, the external loop creates an 'effectively final' variable arg
which can be referenced within the lambda expression, because the value is captured at execution time.
The prevention of the capture of 'non-effectively-final' values is more or less just a precaution in Java, because in other languages (like JavaScript e.g.) this works differently. So the compiler could theoretically translate your code, capture the value, and continue, but it would have to store that value differently, and you would probably get unexpected results. Therefore the team developing lambdas for Java 8 correctly excluded this scenario, by preventing it with an exception.
If you ever need to change values of external variables within lambda expressions, you can either declare a one-element array:
String myStringRef = { "before" };
someCallingMethod(() -> myStringRef[0] = "after" );
System.out.println(myStringRef[0]);
Or use Atomic to make it thread-safe. However with your example, this would probably return "before" since the thread would most likely execute after the execution of println.
add a comment |
Lambda-Expressions work like callbacks. The moment they are passed in the code, they 'store' any external values (or references) they require to operate (as if these values were passed as arguments in a function call. This is just hidden from the developer). In your first example, you could work around the problem by storing k to a separate variable, like d:
for (int k = 0; k < 10; k++) {
final int d = k
new Thread(() -> System.out.println(d)).start();
}
Effectively final means, that in the above example, you can leave the 'final' keyword out, because d
is effectively final, since it is never changed within it's scope.
for-loops operate differently. They are iterative code (as opposed to a callback). They work within their respective scope and can use all variables on their own stack. This means, that the for-loop's code block is part of the external code block.
As to your highlighted question:
An enhanced for-loop does not operate with a regular index-counter, at least not directly. Enhanced for loops (over non-arrays) create a hidden Iterator. You can test this the following way:
Collection<String> mySet = new HashSet<>();
mySet.addAll(Arrays.asList("A", "B", "C"));
for (String myString : mySet) {
if (myString.equals("B")) {
mySet.remove(myString);
}
}
The above example will cause a ConcurrentModificationException. This is due to the iterator noticing, that the underlying collection has changed during the execution. However in your very example, the external loop creates an 'effectively final' variable arg
which can be referenced within the lambda expression, because the value is captured at execution time.
The prevention of the capture of 'non-effectively-final' values is more or less just a precaution in Java, because in other languages (like JavaScript e.g.) this works differently. So the compiler could theoretically translate your code, capture the value, and continue, but it would have to store that value differently, and you would probably get unexpected results. Therefore the team developing lambdas for Java 8 correctly excluded this scenario, by preventing it with an exception.
If you ever need to change values of external variables within lambda expressions, you can either declare a one-element array:
String myStringRef = { "before" };
someCallingMethod(() -> myStringRef[0] = "after" );
System.out.println(myStringRef[0]);
Or use Atomic to make it thread-safe. However with your example, this would probably return "before" since the thread would most likely execute after the execution of println.
Lambda-Expressions work like callbacks. The moment they are passed in the code, they 'store' any external values (or references) they require to operate (as if these values were passed as arguments in a function call. This is just hidden from the developer). In your first example, you could work around the problem by storing k to a separate variable, like d:
for (int k = 0; k < 10; k++) {
final int d = k
new Thread(() -> System.out.println(d)).start();
}
Effectively final means, that in the above example, you can leave the 'final' keyword out, because d
is effectively final, since it is never changed within it's scope.
for-loops operate differently. They are iterative code (as opposed to a callback). They work within their respective scope and can use all variables on their own stack. This means, that the for-loop's code block is part of the external code block.
As to your highlighted question:
An enhanced for-loop does not operate with a regular index-counter, at least not directly. Enhanced for loops (over non-arrays) create a hidden Iterator. You can test this the following way:
Collection<String> mySet = new HashSet<>();
mySet.addAll(Arrays.asList("A", "B", "C"));
for (String myString : mySet) {
if (myString.equals("B")) {
mySet.remove(myString);
}
}
The above example will cause a ConcurrentModificationException. This is due to the iterator noticing, that the underlying collection has changed during the execution. However in your very example, the external loop creates an 'effectively final' variable arg
which can be referenced within the lambda expression, because the value is captured at execution time.
The prevention of the capture of 'non-effectively-final' values is more or less just a precaution in Java, because in other languages (like JavaScript e.g.) this works differently. So the compiler could theoretically translate your code, capture the value, and continue, but it would have to store that value differently, and you would probably get unexpected results. Therefore the team developing lambdas for Java 8 correctly excluded this scenario, by preventing it with an exception.
If you ever need to change values of external variables within lambda expressions, you can either declare a one-element array:
String myStringRef = { "before" };
someCallingMethod(() -> myStringRef[0] = "after" );
System.out.println(myStringRef[0]);
Or use Atomic to make it thread-safe. However with your example, this would probably return "before" since the thread would most likely execute after the execution of println.
edited 43 mins ago
answered 1 hour ago
TreffnonXTreffnonX
34219
34219
add a comment |
add a comment |
In an enhanced for loop the variable is initialized for each iteration. From §14.14.2 of the JLS:
...
When an enhanced for statement is executed, the local variable is initialized, on each iteration of the loop, to successive elements of the array or Iterable produced by the expression. The precise meaning of the enhanced for statement is given by translation into a basic for statement, as follows:
If the type of Expression is a subtype of Iterable, then the translation is as follows.
If the type of Expression is a subtype of Iterable for some type argument X, then let I be the type java.util.Iterator; otherwise, let I be the raw type java.util.Iterator.
The enhanced for statement is equivalent to a basic for statement of the form:
for (I #i = Expression.iterator(); #i.hasNext(); ) {
{VariableModifier} TargetType Identifier =
(TargetType) #i.next();
Statement
}
...
Otherwise, the Expression necessarily has an array type, T.
Let L1 ... Lm be the (possibly empty) sequence of labels immediately preceding the enhanced for statement.
The enhanced for statement is equivalent to a basic for statement of the form:
T #a = Expression;
L1: L2: ... Lm:
for (int #i = 0; #i < #a.length; #i++) {
{VariableModifier} TargetType Identifier = #a[#i];
Statement
}
...
In other words, your enhanced for loop is equivalent to:
ArrayList<Integer> listOfInt = new ArrayList<>();
// add elements...
for (Iterator<Integer> itr = listOfInt.iterator(); itr.hasNext(); ) {
Integer arg = itr.next();
new Thread(() -> System.out.println(arg)).start();
}
Since the variable is initialized each iteration it is effectively final (unless you modify the variable inside the loop).
In contrast, the variable in the basic for loop (k
in your case) is initialized once and updated each iteration (if a "ForUpdate" is present, e.g. k++
). See §14.14.1 of the JLS for more information. Since the variable is updated each iteration is is not final nor effectively final.
add a comment |
In an enhanced for loop the variable is initialized for each iteration. From §14.14.2 of the JLS:
...
When an enhanced for statement is executed, the local variable is initialized, on each iteration of the loop, to successive elements of the array or Iterable produced by the expression. The precise meaning of the enhanced for statement is given by translation into a basic for statement, as follows:
If the type of Expression is a subtype of Iterable, then the translation is as follows.
If the type of Expression is a subtype of Iterable for some type argument X, then let I be the type java.util.Iterator; otherwise, let I be the raw type java.util.Iterator.
The enhanced for statement is equivalent to a basic for statement of the form:
for (I #i = Expression.iterator(); #i.hasNext(); ) {
{VariableModifier} TargetType Identifier =
(TargetType) #i.next();
Statement
}
...
Otherwise, the Expression necessarily has an array type, T.
Let L1 ... Lm be the (possibly empty) sequence of labels immediately preceding the enhanced for statement.
The enhanced for statement is equivalent to a basic for statement of the form:
T #a = Expression;
L1: L2: ... Lm:
for (int #i = 0; #i < #a.length; #i++) {
{VariableModifier} TargetType Identifier = #a[#i];
Statement
}
...
In other words, your enhanced for loop is equivalent to:
ArrayList<Integer> listOfInt = new ArrayList<>();
// add elements...
for (Iterator<Integer> itr = listOfInt.iterator(); itr.hasNext(); ) {
Integer arg = itr.next();
new Thread(() -> System.out.println(arg)).start();
}
Since the variable is initialized each iteration it is effectively final (unless you modify the variable inside the loop).
In contrast, the variable in the basic for loop (k
in your case) is initialized once and updated each iteration (if a "ForUpdate" is present, e.g. k++
). See §14.14.1 of the JLS for more information. Since the variable is updated each iteration is is not final nor effectively final.
add a comment |
In an enhanced for loop the variable is initialized for each iteration. From §14.14.2 of the JLS:
...
When an enhanced for statement is executed, the local variable is initialized, on each iteration of the loop, to successive elements of the array or Iterable produced by the expression. The precise meaning of the enhanced for statement is given by translation into a basic for statement, as follows:
If the type of Expression is a subtype of Iterable, then the translation is as follows.
If the type of Expression is a subtype of Iterable for some type argument X, then let I be the type java.util.Iterator; otherwise, let I be the raw type java.util.Iterator.
The enhanced for statement is equivalent to a basic for statement of the form:
for (I #i = Expression.iterator(); #i.hasNext(); ) {
{VariableModifier} TargetType Identifier =
(TargetType) #i.next();
Statement
}
...
Otherwise, the Expression necessarily has an array type, T.
Let L1 ... Lm be the (possibly empty) sequence of labels immediately preceding the enhanced for statement.
The enhanced for statement is equivalent to a basic for statement of the form:
T #a = Expression;
L1: L2: ... Lm:
for (int #i = 0; #i < #a.length; #i++) {
{VariableModifier} TargetType Identifier = #a[#i];
Statement
}
...
In other words, your enhanced for loop is equivalent to:
ArrayList<Integer> listOfInt = new ArrayList<>();
// add elements...
for (Iterator<Integer> itr = listOfInt.iterator(); itr.hasNext(); ) {
Integer arg = itr.next();
new Thread(() -> System.out.println(arg)).start();
}
Since the variable is initialized each iteration it is effectively final (unless you modify the variable inside the loop).
In contrast, the variable in the basic for loop (k
in your case) is initialized once and updated each iteration (if a "ForUpdate" is present, e.g. k++
). See §14.14.1 of the JLS for more information. Since the variable is updated each iteration is is not final nor effectively final.
In an enhanced for loop the variable is initialized for each iteration. From §14.14.2 of the JLS:
...
When an enhanced for statement is executed, the local variable is initialized, on each iteration of the loop, to successive elements of the array or Iterable produced by the expression. The precise meaning of the enhanced for statement is given by translation into a basic for statement, as follows:
If the type of Expression is a subtype of Iterable, then the translation is as follows.
If the type of Expression is a subtype of Iterable for some type argument X, then let I be the type java.util.Iterator; otherwise, let I be the raw type java.util.Iterator.
The enhanced for statement is equivalent to a basic for statement of the form:
for (I #i = Expression.iterator(); #i.hasNext(); ) {
{VariableModifier} TargetType Identifier =
(TargetType) #i.next();
Statement
}
...
Otherwise, the Expression necessarily has an array type, T.
Let L1 ... Lm be the (possibly empty) sequence of labels immediately preceding the enhanced for statement.
The enhanced for statement is equivalent to a basic for statement of the form:
T #a = Expression;
L1: L2: ... Lm:
for (int #i = 0; #i < #a.length; #i++) {
{VariableModifier} TargetType Identifier = #a[#i];
Statement
}
...
In other words, your enhanced for loop is equivalent to:
ArrayList<Integer> listOfInt = new ArrayList<>();
// add elements...
for (Iterator<Integer> itr = listOfInt.iterator(); itr.hasNext(); ) {
Integer arg = itr.next();
new Thread(() -> System.out.println(arg)).start();
}
Since the variable is initialized each iteration it is effectively final (unless you modify the variable inside the loop).
In contrast, the variable in the basic for loop (k
in your case) is initialized once and updated each iteration (if a "ForUpdate" is present, e.g. k++
). See §14.14.1 of the JLS for more information. Since the variable is updated each iteration is is not final nor effectively final.
edited 31 mins ago
answered 50 mins ago
SlawSlaw
7,6283932
7,6283932
add a comment |
add a comment |
An enhanced for
loop is defined to be equivalent to this code:
for (Iterator<T> it = iterable.iterator(); it.hasNext(); ) {
T loopvar = it.next();
…
}
This substitution code explains why the variable of an enhanced for
loop is considered effectively final.
add a comment |
An enhanced for
loop is defined to be equivalent to this code:
for (Iterator<T> it = iterable.iterator(); it.hasNext(); ) {
T loopvar = it.next();
…
}
This substitution code explains why the variable of an enhanced for
loop is considered effectively final.
add a comment |
An enhanced for
loop is defined to be equivalent to this code:
for (Iterator<T> it = iterable.iterator(); it.hasNext(); ) {
T loopvar = it.next();
…
}
This substitution code explains why the variable of an enhanced for
loop is considered effectively final.
An enhanced for
loop is defined to be equivalent to this code:
for (Iterator<T> it = iterable.iterator(); it.hasNext(); ) {
T loopvar = it.next();
…
}
This substitution code explains why the variable of an enhanced for
loop is considered effectively final.
answered 45 mins ago
Roland IlligRoland Illig
29.5k96091
29.5k96091
add a comment |
add a comment |
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// Error—cannot capture i
Did you mean k rather than i?– Prashant Zombade
1 hour ago
@PrashantZombade , typo please check the question again.
– Show Stopper
1 hour ago