how execute if condition several times without break inside for loop in java?

In the following code I want to execute the if condition inside the outer for loop several times, but in the following code it only executes once and executes the steps after it. binaryHashResult is an array and innerNode is a List. I want to check if all values in array exist in list.

for (int j = 0; j < binaryHashResult.length; j++) 

    if (innerNode[binaryHashResult[j]] == 1.0)

        for (int h = 0; h < m.children.size(); h++) {

            BloomFilterIndex.BFINode<Integer> s=m.children.get(h);

            searchencryptedNode(binaryHashResult, e,  k, s);

        }

edited Nov 25 '18 at 1:26

dave

8,48752850

asked Nov 25 '18 at 1:13

user9860564

194

2

How do you know it is only executed once? Did you use a debugger?

– Michael Butscher
Nov 25 '18 at 1:18

2

@W.Ambrozic a for loop does not require braces, although it's generally a good practice to do so.

– dave
Nov 25 '18 at 1:24

Please show a Minimal, Complete, and Verifiable example... If it only execute once, then are you ever changing the values in the array? What are the values?

– cricket_007
Nov 25 '18 at 1:27

Might want to check out some debugging tips too ericlippert.com/2014/03/05/how-to-debug-small-programs

– cricket_007
Nov 25 '18 at 1:29

1

@W.Ambrozic Not quite. It's not one line but one statement. The next statement is an if and it (and its contained for loop) form the single statement of the outer for loop. So the five lines following the initial for form its body.

– dave
Nov 25 '18 at 1:30

|
show 2 more comments

for (int j = 0; j < binaryHashResult.length; j++) 

    if (innerNode[binaryHashResult[j]] == 1.0)

        for (int h = 0; h < m.children.size(); h++) {

            BloomFilterIndex.BFINode<Integer> s=m.children.get(h);

            searchencryptedNode(binaryHashResult, e,  k, s);

        }

edited Nov 25 '18 at 1:26

dave

8,48752850

asked Nov 25 '18 at 1:13

user9860564

194

2

How do you know it is only executed once? Did you use a debugger?

– Michael Butscher
Nov 25 '18 at 1:18

2

@W.Ambrozic a for loop does not require braces, although it's generally a good practice to do so.

– dave
Nov 25 '18 at 1:24

Please show a Minimal, Complete, and Verifiable example... If it only execute once, then are you ever changing the values in the array? What are the values?

– cricket_007
Nov 25 '18 at 1:27

Might want to check out some debugging tips too ericlippert.com/2014/03/05/how-to-debug-small-programs

– cricket_007
Nov 25 '18 at 1:29

1

@W.Ambrozic Not quite. It's not one line but one statement. The next statement is an if and it (and its contained for loop) form the single statement of the outer for loop. So the five lines following the initial for form its body.

– dave
Nov 25 '18 at 1:30

|
show 2 more comments

for (int j = 0; j < binaryHashResult.length; j++) 

    if (innerNode[binaryHashResult[j]] == 1.0)

        for (int h = 0; h < m.children.size(); h++) {

            BloomFilterIndex.BFINode<Integer> s=m.children.get(h);

            searchencryptedNode(binaryHashResult, e,  k, s);

        }

edited Nov 25 '18 at 1:26

dave

8,48752850

asked Nov 25 '18 at 1:13

user9860564

194

for (int j = 0; j < binaryHashResult.length; j++) 

    if (innerNode[binaryHashResult[j]] == 1.0)

        for (int h = 0; h < m.children.size(); h++) {

            BloomFilterIndex.BFINode<Integer> s=m.children.get(h);

            searchencryptedNode(binaryHashResult, e,  k, s);

        }

java

edited Nov 25 '18 at 1:26

dave

8,48752850

asked Nov 25 '18 at 1:13

user9860564

194

edited Nov 25 '18 at 1:26

dave

8,48752850

asked Nov 25 '18 at 1:13

user9860564

194

edited Nov 25 '18 at 1:26

dave

8,48752850

edited Nov 25 '18 at 1:26

dave

8,48752850

edited Nov 25 '18 at 1:26

dave

8,48752850

asked Nov 25 '18 at 1:13

user9860564

194

asked Nov 25 '18 at 1:13

user9860564

194

asked Nov 25 '18 at 1:13

user9860564

194

2

How do you know it is only executed once? Did you use a debugger?

– Michael Butscher
Nov 25 '18 at 1:18

2

@W.Ambrozic a for loop does not require braces, although it's generally a good practice to do so.

– dave
Nov 25 '18 at 1:24

Please show a Minimal, Complete, and Verifiable example... If it only execute once, then are you ever changing the values in the array? What are the values?

– cricket_007
Nov 25 '18 at 1:27

Might want to check out some debugging tips too ericlippert.com/2014/03/05/how-to-debug-small-programs

– cricket_007
Nov 25 '18 at 1:29

1

@W.Ambrozic Not quite. It's not one line but one statement. The next statement is an if and it (and its contained for loop) form the single statement of the outer for loop. So the five lines following the initial for form its body.

– dave
Nov 25 '18 at 1:30

|
show 2 more comments

2

How do you know it is only executed once? Did you use a debugger?

– Michael Butscher
Nov 25 '18 at 1:18

2

@W.Ambrozic a for loop does not require braces, although it's generally a good practice to do so.

– dave
Nov 25 '18 at 1:24

Please show a Minimal, Complete, and Verifiable example... If it only execute once, then are you ever changing the values in the array? What are the values?

– cricket_007
Nov 25 '18 at 1:27

Might want to check out some debugging tips too ericlippert.com/2014/03/05/how-to-debug-small-programs

– cricket_007
Nov 25 '18 at 1:29

1

@W.Ambrozic Not quite. It's not one line but one statement. The next statement is an if and it (and its contained for loop) form the single statement of the outer for loop. So the five lines following the initial for form its body.

– dave
Nov 25 '18 at 1:30

How do you know it is only executed once? Did you use a debugger?

– Michael Butscher
Nov 25 '18 at 1:18

@W.Ambrozic a for loop does not require braces, although it's generally a good practice to do so.

– dave
Nov 25 '18 at 1:24

Please show a Minimal, Complete, and Verifiable example... If it only execute once, then are you ever changing the values in the array? What are the values?

– cricket_007
Nov 25 '18 at 1:27

Might want to check out some debugging tips too ericlippert.com/2014/03/05/how-to-debug-small-programs

– cricket_007
Nov 25 '18 at 1:29

@W.Ambrozic Not quite. It's not one line but one statement. The next statement is an if and it (and its contained for loop) form the single statement of the outer for loop. So the five lines following the initial for form its body.

– dave
Nov 25 '18 at 1:30

|
show 2 more comments

1 Answer
1

active

oldest

votes

Always wrap blocks of code with {} regardless if the block has only one line.

for (int j = 0; j < binaryHashResult.length; j++) 

    if (innerNode[binaryHashResult[j]] == 1.0) {

        for (int h = 0; h < m.children.size(); h++) {

            BloomFilterIndex.BFINode<Integer> s=m.children.get(h);

            searchencryptedNode(binaryHashResult, e,  k, s);

        } // closes inner for loop

   } // closes if

} // closes outer for loop

answered Nov 29 '18 at 10:42

fpezzini

177111

add a comment |

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1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

Always wrap blocks of code with {} regardless if the block has only one line.

for (int j = 0; j < binaryHashResult.length; j++) 

    if (innerNode[binaryHashResult[j]] == 1.0) {

        for (int h = 0; h < m.children.size(); h++) {

            BloomFilterIndex.BFINode<Integer> s=m.children.get(h);

            searchencryptedNode(binaryHashResult, e,  k, s);

        } // closes inner for loop

   } // closes if

} // closes outer for loop

answered Nov 29 '18 at 10:42

fpezzini

177111

add a comment |

Always wrap blocks of code with {} regardless if the block has only one line.

for (int j = 0; j < binaryHashResult.length; j++) 

    if (innerNode[binaryHashResult[j]] == 1.0) {

        for (int h = 0; h < m.children.size(); h++) {

            BloomFilterIndex.BFINode<Integer> s=m.children.get(h);

            searchencryptedNode(binaryHashResult, e,  k, s);

        } // closes inner for loop

   } // closes if

} // closes outer for loop

answered Nov 29 '18 at 10:42

fpezzini

177111

add a comment |

Always wrap blocks of code with {} regardless if the block has only one line.

for (int j = 0; j < binaryHashResult.length; j++) 

    if (innerNode[binaryHashResult[j]] == 1.0) {

        for (int h = 0; h < m.children.size(); h++) {

            BloomFilterIndex.BFINode<Integer> s=m.children.get(h);

            searchencryptedNode(binaryHashResult, e,  k, s);

        } // closes inner for loop

   } // closes if

} // closes outer for loop

answered Nov 29 '18 at 10:42

fpezzini

177111

Always wrap blocks of code with {} regardless if the block has only one line.

for (int j = 0; j < binaryHashResult.length; j++) 

    if (innerNode[binaryHashResult[j]] == 1.0) {

        for (int h = 0; h < m.children.size(); h++) {

            BloomFilterIndex.BFINode<Integer> s=m.children.get(h);

            searchencryptedNode(binaryHashResult, e,  k, s);

        } // closes inner for loop

   } // closes if

} // closes outer for loop

answered Nov 29 '18 at 10:42

fpezzini

177111

answered Nov 29 '18 at 10:42

fpezzini

177111

answered Nov 29 '18 at 10:42

fpezzini

177111

answered Nov 29 '18 at 10:42

fpezzini

177111

add a comment |

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