I want that it should stop when the user entered 3 times wrong ID and Password (ID and PW are correct ones)
0
In my program it is ending when the user entered 3 times wrong ID and Password (ID and PW are correct ones)-there is no problem with ending-In the same time it says "welcome..." after saying "Your account has been blocked".
Scanner enter = new Scanner(System.in);
String ID2, PW2, PW = "qwerty123", ID = "theman" ;
int entry=0;
do {entry++;
System.out.println("Please enter you ID.");
ID2 = enter.nextLine();
System.out.println("Please enter your password.");
PW2 = enter.nextLine();
if(!(ID.equals(ID2)) && ((PW.equals(PW2)))) {
System.out.println("Try again!");
}
else if((ID.equals(ID2)) && (!(PW.equals(PW2)))) {
System.out.println("Try again!");
}
else if(!(ID.equals(ID2)) && !((PW.equals(PW2)))) {
System.out.println("Try again!");
}
if(entry==3) {
System.out.println("**Your account has been blocked**");
break;
}
}while(!(ID.equals(ID2)) && !((PW.equals(PW2))));
System.out.println("Welcome...");
java do-while
edited Dec 9 '18 at 9:38
Cœur
17.8k9106145
asked Nov 25 '18 at 11:43
İhsanİhsan
33
add a comment |
0
In my program it is ending when the user entered 3 times wrong ID and Password (ID and PW are correct ones)-there is no problem with ending-In the same time it says "welcome..." after saying "Your account has been blocked".
Scanner enter = new Scanner(System.in);
String ID2, PW2, PW = "qwerty123", ID = "theman" ;
int entry=0;
do {entry++;
System.out.println("Please enter you ID.");
ID2 = enter.nextLine();
System.out.println("Please enter your password.");
PW2 = enter.nextLine();
if(!(ID.equals(ID2)) && ((PW.equals(PW2)))) {
System.out.println("Try again!");
}
else if((ID.equals(ID2)) && (!(PW.equals(PW2)))) {
System.out.println("Try again!");
}
else if(!(ID.equals(ID2)) && !((PW.equals(PW2)))) {
System.out.println("Try again!");
}
if(entry==3) {
System.out.println("**Your account has been blocked**");
break;
}
}while(!(ID.equals(ID2)) && !((PW.equals(PW2))));
System.out.println("Welcome...");
java do-while
edited Dec 9 '18 at 9:38
Cœur
17.8k9106145
asked Nov 25 '18 at 11:43
İhsanİhsan
33
What do you mean by "wrongly", be specific!
– Skemelio
Nov 25 '18 at 11:49
1
Of course it says "welcome". The last line of the program is a println which tells the program to say "welcome". What else would you expect it to do!?
– Robin Green
Nov 25 '18 at 11:49
Just delete the last println()
– Skemelio
Nov 25 '18 at 11:59
If you run the program you are going to see that if the user enters wrong ıd or password program prints "try again" until user enters true Id and Password. Then it says "welcome" and it stops.So If I delete the last println() program won't have any meaning.
– İhsan
Nov 25 '18 at 12:49
Thebreakdoes not stop the program, it just terminates the enclosing while loop
– Klaus Gütter
Nov 25 '18 at 13:51
add a comment |
0
0
0
In my program it is ending when the user entered 3 times wrong ID and Password (ID and PW are correct ones)-there is no problem with ending-In the same time it says "welcome..." after saying "Your account has been blocked".
Scanner enter = new Scanner(System.in);
String ID2, PW2, PW = "qwerty123", ID = "theman" ;
int entry=0;
do {entry++;
System.out.println("Please enter you ID.");
ID2 = enter.nextLine();
System.out.println("Please enter your password.");
PW2 = enter.nextLine();
if(!(ID.equals(ID2)) && ((PW.equals(PW2)))) {
System.out.println("Try again!");
}
else if((ID.equals(ID2)) && (!(PW.equals(PW2)))) {
System.out.println("Try again!");
}
else if(!(ID.equals(ID2)) && !((PW.equals(PW2)))) {
System.out.println("Try again!");
}
if(entry==3) {
System.out.println("**Your account has been blocked**");
break;
}
}while(!(ID.equals(ID2)) && !((PW.equals(PW2))));
System.out.println("Welcome...");
java do-while
edited Dec 9 '18 at 9:38
Cœur
17.8k9106145
asked Nov 25 '18 at 11:43
İhsanİhsan
33
In my program it is ending when the user entered 3 times wrong ID and Password (ID and PW are correct ones)-there is no problem with ending-In the same time it says "welcome..." after saying "Your account has been blocked".
Scanner enter = new Scanner(System.in);
String ID2, PW2, PW = "qwerty123", ID = "theman" ;
int entry=0;
do {entry++;
System.out.println("Please enter you ID.");
ID2 = enter.nextLine();
System.out.println("Please enter your password.");
PW2 = enter.nextLine();
if(!(ID.equals(ID2)) && ((PW.equals(PW2)))) {
System.out.println("Try again!");
}
else if((ID.equals(ID2)) && (!(PW.equals(PW2)))) {
System.out.println("Try again!");
}
else if(!(ID.equals(ID2)) && !((PW.equals(PW2)))) {
System.out.println("Try again!");
}
if(entry==3) {
System.out.println("**Your account has been blocked**");
break;
}
}while(!(ID.equals(ID2)) && !((PW.equals(PW2))));
System.out.println("Welcome...");
java do-while
java do-while
edited Dec 9 '18 at 9:38
Cœur
17.8k9106145
asked Nov 25 '18 at 11:43
İhsanİhsan
33
edited Dec 9 '18 at 9:38
Cœur
17.8k9106145
asked Nov 25 '18 at 11:43
İhsanİhsan
33
edited Dec 9 '18 at 9:38
Cœur
17.8k9106145
edited Dec 9 '18 at 9:38
Cœur
17.8k9106145
edited Dec 9 '18 at 9:38
Cœur
17.8k9106145
17.8k9106145
asked Nov 25 '18 at 11:43
İhsanİhsan
33
asked Nov 25 '18 at 11:43
İhsanİhsan
33
asked Nov 25 '18 at 11:43
İhsanİhsan
33
33
What do you mean by "wrongly", be specific!
– Skemelio
Nov 25 '18 at 11:49
1
Of course it says "welcome". The last line of the program is a println which tells the program to say "welcome". What else would you expect it to do!?
– Robin Green
Nov 25 '18 at 11:49
Just delete the last println()
– Skemelio
Nov 25 '18 at 11:59
If you run the program you are going to see that if the user enters wrong ıd or password program prints "try again" until user enters true Id and Password. Then it says "welcome" and it stops.So If I delete the last println() program won't have any meaning.
– İhsan
Nov 25 '18 at 12:49
Thebreakdoes not stop the program, it just terminates the enclosing while loop
– Klaus Gütter
Nov 25 '18 at 13:51
add a comment |
What do you mean by "wrongly", be specific!
– Skemelio
Nov 25 '18 at 11:49
1
Of course it says "welcome". The last line of the program is a println which tells the program to say "welcome". What else would you expect it to do!?
– Robin Green
Nov 25 '18 at 11:49
Just delete the last println()
– Skemelio
Nov 25 '18 at 11:59
If you run the program you are going to see that if the user enters wrong ıd or password program prints "try again" until user enters true Id and Password. Then it says "welcome" and it stops.So If I delete the last println() program won't have any meaning.
– İhsan
Nov 25 '18 at 12:49
Thebreakdoes not stop the program, it just terminates the enclosing while loop
– Klaus Gütter
Nov 25 '18 at 13:51
What do you mean by "wrongly", be specific!
– Skemelio
Nov 25 '18 at 11:49
What do you mean by "wrongly", be specific!
– Skemelio
Nov 25 '18 at 11:49
1
1
Of course it says "welcome". The last line of the program is a println which tells the program to say "welcome". What else would you expect it to do!?
– Robin Green
Nov 25 '18 at 11:49
Of course it says "welcome". The last line of the program is a println which tells the program to say "welcome". What else would you expect it to do!?
– Robin Green
Nov 25 '18 at 11:49
Just delete the last println()
– Skemelio
Nov 25 '18 at 11:59
Just delete the last println()
– Skemelio
Nov 25 '18 at 11:59
If you run the program you are going to see that if the user enters wrong ıd or password program prints "try again" until user enters true Id and Password. Then it says "welcome" and it stops.So If I delete the last println() program won't have any meaning.
– İhsan
Nov 25 '18 at 12:49
If you run the program you are going to see that if the user enters wrong ıd or password program prints "try again" until user enters true Id and Password. Then it says "welcome" and it stops.So If I delete the last println() program won't have any meaning.
– İhsan
Nov 25 '18 at 12:49
The
break does not stop the program, it just terminates the enclosing while loop– Klaus Gütter
Nov 25 '18 at 13:51
The
break does not stop the program, it just terminates the enclosing while loop– Klaus Gütter
Nov 25 '18 at 13:51
add a comment |
1 Answer
1
active
oldest
votes
0
Try this;
Scanner enter = new Scanner(System.in);
String ID2, PW2, PW = "qwerty123", ID = "theman";
int entry = 0;
do {
entry++;
System.out.println("Please enter you ID.");
ID2 = enter.nextLine();
System.out.println("Please enter your password.");
PW2 = enter.nextLine();
if (ID.equals(ID2) && (PW.equals(PW2))) {
System.out.println("Welcome...");
} else if (!(ID.equals(ID2)) && ((PW.equals(PW2)))) {
System.out.println("Try again!");
} else if ((ID.equals(ID2)) && (!(PW.equals(PW2)))) {
System.out.println("Try again!");
} else if (!(ID.equals(ID2)) && !((PW.equals(PW2)))) {
System.out.println("Try again!");
}
if (entry == 3) {
System.out.println("**Your account has been blocked**");
break;
}
} while (!(ID.equals(ID2)) && !((PW.equals(PW2))));
}
answered Nov 25 '18 at 13:04
Erandika HarshaniErandika Harshani
1245
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
Try this;
Scanner enter = new Scanner(System.in);
String ID2, PW2, PW = "qwerty123", ID = "theman";
int entry = 0;
do {
entry++;
System.out.println("Please enter you ID.");
ID2 = enter.nextLine();
System.out.println("Please enter your password.");
PW2 = enter.nextLine();
if (ID.equals(ID2) && (PW.equals(PW2))) {
System.out.println("Welcome...");
} else if (!(ID.equals(ID2)) && ((PW.equals(PW2)))) {
System.out.println("Try again!");
} else if ((ID.equals(ID2)) && (!(PW.equals(PW2)))) {
System.out.println("Try again!");
} else if (!(ID.equals(ID2)) && !((PW.equals(PW2)))) {
System.out.println("Try again!");
}
if (entry == 3) {
System.out.println("**Your account has been blocked**");
break;
}
} while (!(ID.equals(ID2)) && !((PW.equals(PW2))));
}
answered Nov 25 '18 at 13:04
Erandika HarshaniErandika Harshani
1245
add a comment |
0
Try this;
Scanner enter = new Scanner(System.in);
String ID2, PW2, PW = "qwerty123", ID = "theman";
int entry = 0;
do {
entry++;
System.out.println("Please enter you ID.");
ID2 = enter.nextLine();
System.out.println("Please enter your password.");
PW2 = enter.nextLine();
if (ID.equals(ID2) && (PW.equals(PW2))) {
System.out.println("Welcome...");
} else if (!(ID.equals(ID2)) && ((PW.equals(PW2)))) {
System.out.println("Try again!");
} else if ((ID.equals(ID2)) && (!(PW.equals(PW2)))) {
System.out.println("Try again!");
} else if (!(ID.equals(ID2)) && !((PW.equals(PW2)))) {
System.out.println("Try again!");
}
if (entry == 3) {
System.out.println("**Your account has been blocked**");
break;
}
} while (!(ID.equals(ID2)) && !((PW.equals(PW2))));
}
answered Nov 25 '18 at 13:04
Erandika HarshaniErandika Harshani
1245
add a comment |
0
0
0
Try this;
Scanner enter = new Scanner(System.in);
String ID2, PW2, PW = "qwerty123", ID = "theman";
int entry = 0;
do {
entry++;
System.out.println("Please enter you ID.");
ID2 = enter.nextLine();
System.out.println("Please enter your password.");
PW2 = enter.nextLine();
if (ID.equals(ID2) && (PW.equals(PW2))) {
System.out.println("Welcome...");
} else if (!(ID.equals(ID2)) && ((PW.equals(PW2)))) {
System.out.println("Try again!");
} else if ((ID.equals(ID2)) && (!(PW.equals(PW2)))) {
System.out.println("Try again!");
} else if (!(ID.equals(ID2)) && !((PW.equals(PW2)))) {
System.out.println("Try again!");
}
if (entry == 3) {
System.out.println("**Your account has been blocked**");
break;
}
} while (!(ID.equals(ID2)) && !((PW.equals(PW2))));
}
answered Nov 25 '18 at 13:04
Erandika HarshaniErandika Harshani
1245
Try this;
Scanner enter = new Scanner(System.in);
String ID2, PW2, PW = "qwerty123", ID = "theman";
int entry = 0;
do {
entry++;
System.out.println("Please enter you ID.");
ID2 = enter.nextLine();
System.out.println("Please enter your password.");
PW2 = enter.nextLine();
if (ID.equals(ID2) && (PW.equals(PW2))) {
System.out.println("Welcome...");
} else if (!(ID.equals(ID2)) && ((PW.equals(PW2)))) {
System.out.println("Try again!");
} else if ((ID.equals(ID2)) && (!(PW.equals(PW2)))) {
System.out.println("Try again!");
} else if (!(ID.equals(ID2)) && !((PW.equals(PW2)))) {
System.out.println("Try again!");
}
if (entry == 3) {
System.out.println("**Your account has been blocked**");
break;
}
} while (!(ID.equals(ID2)) && !((PW.equals(PW2))));
}
answered Nov 25 '18 at 13:04
Erandika HarshaniErandika Harshani
1245
answered Nov 25 '18 at 13:04
Erandika HarshaniErandika Harshani
1245
answered Nov 25 '18 at 13:04
Erandika HarshaniErandika Harshani
1245
answered Nov 25 '18 at 13:04
Erandika HarshaniErandika Harshani
1245
1245
add a comment |
add a comment |
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What do you mean by "wrongly", be specific!
– Skemelio
Nov 25 '18 at 11:49
1
Of course it says "welcome". The last line of the program is a println which tells the program to say "welcome". What else would you expect it to do!?
– Robin Green
Nov 25 '18 at 11:49
Just delete the last println()
– Skemelio
Nov 25 '18 at 11:59
If you run the program you are going to see that if the user enters wrong ıd or password program prints "try again" until user enters true Id and Password. Then it says "welcome" and it stops.So If I delete the last println() program won't have any meaning.
– İhsan
Nov 25 '18 at 12:49
The
breakdoes not stop the program, it just terminates the enclosing while loop– Klaus Gütter
Nov 25 '18 at 13:51