Prepend data in a key-value Object in php












1














I'm quite unfamiliar with php and I'm having difficults to prepend data in a key-value Object. I have this:



 {"5ba68024f109b61fe95ccd02":"asistent","5bd0c379f109b673c11c9502":"seller","5be0addcf109b64c847abd26":"coder","5be0b26af109b64c847abd2c":"teacher","5becab8cf109b676d935e289":"engineer"}


I need place this at the beginning:



"no_job":"Please select an option"


So then my data need to be something like this:



{"no_job":"Please select an option", "5ba68024f109b61fe95ccd02":"asistent","5bd0c379f109b673c11c9502":"seller","5be0addcf109b64c847abd26":"coder","5be0b26af109b64c847abd2c":"teacher","5becab8cf109b676d935e289":"engineer"}


I've tried with:



 $job_list["no_job"] = "Please select an option";

 array_unshift($job_list, $job_list["no_job"]);


However the option then is duplicated at the end of the Object:



{"no_job":"Please select an option", "5ba68024f109b61fe95ccd02":"asistent","5bd0c379f109b673c11c9502":"seller","5be0addcf109b64c847abd26":"coder","5be0b26af109b64c847abd2c":"teacher","5becab8cf109b676d935e289":"engineer", "no_job":"Please select an option"}


How can I achieve that?






php







share|improve this question


















  • 1




    Problem is your already adding the item into the array at $job_list["no_job"] = "Please select an option"; as well as adding it in with the array_unshift()
    – Nigel Ren
    Nov 22 at 19:44
















1














I'm quite unfamiliar with php and I'm having difficults to prepend data in a key-value Object. I have this:



 {"5ba68024f109b61fe95ccd02":"asistent","5bd0c379f109b673c11c9502":"seller","5be0addcf109b64c847abd26":"coder","5be0b26af109b64c847abd2c":"teacher","5becab8cf109b676d935e289":"engineer"}


I need place this at the beginning:



"no_job":"Please select an option"


So then my data need to be something like this:



{"no_job":"Please select an option", "5ba68024f109b61fe95ccd02":"asistent","5bd0c379f109b673c11c9502":"seller","5be0addcf109b64c847abd26":"coder","5be0b26af109b64c847abd2c":"teacher","5becab8cf109b676d935e289":"engineer"}


I've tried with:



 $job_list["no_job"] = "Please select an option";

 array_unshift($job_list, $job_list["no_job"]);


However the option then is duplicated at the end of the Object:



{"no_job":"Please select an option", "5ba68024f109b61fe95ccd02":"asistent","5bd0c379f109b673c11c9502":"seller","5be0addcf109b64c847abd26":"coder","5be0b26af109b64c847abd2c":"teacher","5becab8cf109b676d935e289":"engineer", "no_job":"Please select an option"}


How can I achieve that?






php







share|improve this question


















  • 1




    Problem is your already adding the item into the array at $job_list["no_job"] = "Please select an option"; as well as adding it in with the array_unshift()
    – Nigel Ren
    Nov 22 at 19:44














1












1








1







I'm quite unfamiliar with php and I'm having difficults to prepend data in a key-value Object. I have this:



 {"5ba68024f109b61fe95ccd02":"asistent","5bd0c379f109b673c11c9502":"seller","5be0addcf109b64c847abd26":"coder","5be0b26af109b64c847abd2c":"teacher","5becab8cf109b676d935e289":"engineer"}


I need place this at the beginning:



"no_job":"Please select an option"


So then my data need to be something like this:



{"no_job":"Please select an option", "5ba68024f109b61fe95ccd02":"asistent","5bd0c379f109b673c11c9502":"seller","5be0addcf109b64c847abd26":"coder","5be0b26af109b64c847abd2c":"teacher","5becab8cf109b676d935e289":"engineer"}


I've tried with:



 $job_list["no_job"] = "Please select an option";

 array_unshift($job_list, $job_list["no_job"]);


However the option then is duplicated at the end of the Object:



{"no_job":"Please select an option", "5ba68024f109b61fe95ccd02":"asistent","5bd0c379f109b673c11c9502":"seller","5be0addcf109b64c847abd26":"coder","5be0b26af109b64c847abd2c":"teacher","5becab8cf109b676d935e289":"engineer", "no_job":"Please select an option"}


How can I achieve that?






php







share|improve this question













I'm quite unfamiliar with php and I'm having difficults to prepend data in a key-value Object. I have this:



 {"5ba68024f109b61fe95ccd02":"asistent","5bd0c379f109b673c11c9502":"seller","5be0addcf109b64c847abd26":"coder","5be0b26af109b64c847abd2c":"teacher","5becab8cf109b676d935e289":"engineer"}


I need place this at the beginning:



"no_job":"Please select an option"


So then my data need to be something like this:



{"no_job":"Please select an option", "5ba68024f109b61fe95ccd02":"asistent","5bd0c379f109b673c11c9502":"seller","5be0addcf109b64c847abd26":"coder","5be0b26af109b64c847abd2c":"teacher","5becab8cf109b676d935e289":"engineer"}


I've tried with:



 $job_list["no_job"] = "Please select an option";

 array_unshift($job_list, $job_list["no_job"]);


However the option then is duplicated at the end of the Object:



{"no_job":"Please select an option", "5ba68024f109b61fe95ccd02":"asistent","5bd0c379f109b673c11c9502":"seller","5be0addcf109b64c847abd26":"coder","5be0b26af109b64c847abd2c":"teacher","5becab8cf109b676d935e289":"engineer", "no_job":"Please select an option"}


How can I achieve that?






php




php






share|improve this question













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asked Nov 22 at 19:37









Cesar Jr Rodriguez

5481821




5481821








  • 1




    Problem is your already adding the item into the array at $job_list["no_job"] = "Please select an option"; as well as adding it in with the array_unshift()
    – Nigel Ren
    Nov 22 at 19:44














  • 1




    Problem is your already adding the item into the array at $job_list["no_job"] = "Please select an option"; as well as adding it in with the array_unshift()
    – Nigel Ren
    Nov 22 at 19:44








1




1




Problem is your already adding the item into the array at $job_list["no_job"] = "Please select an option"; as well as adding it in with the array_unshift()
– Nigel Ren
Nov 22 at 19:44




Problem is your already adding the item into the array at $job_list["no_job"] = "Please select an option"; as well as adding it in with the array_unshift()
– Nigel Ren
Nov 22 at 19:44












2 Answers
2






active

oldest

votes


















2














PHP natively understands JSON, so turn it into an array, then use array_merge:



$originalArray = json_decode('{"5ba68024f109b61fe95ccd02":"asistent","5bd0c379f109b673c11c9502":"seller","5be0addcf109b64c847abd26":"coder","5be0b26af109b64c847abd2c":"teacher","5becab8cf109b676d935e289":"engineer"}', true);



$newArray = array_merge(['no_job' => 'Please select an option'], $originalArray);



print json_encode($newArray);





share|improve this answer





























    2














    To add the key and value at the beginning of the string, turn your json into an associative array using json_decode and true as the second parameter. Then you could use the union + operator:



    $job_list = json_decode(' {"5ba68024f109b61fe95ccd02":"asistent","5bd0c379f109b673c11c9502":"seller","5be0addcf109b64c847abd26":"coder","5be0b26af109b64c847abd2c":"teacher","5becab8cf109b676d935e289":"engineer"}
    
', true);
    
$job_list = ['no_job' => 'Please select an option'] + $job_list;
    
echo json_encode($job_list);


    Result:



    {"no_job":"Please select an option","5ba68024f109b61fe95ccd02":"asistent","5bd0c379f109b673c11c9502":"seller","5be0addcf109b64c847abd26":"coder","5be0b26af109b64c847abd2c":"teacher","5becab8cf109b676d935e289":"engineer"}





    share|improve this answer























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      2 Answers
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      2 Answers
      2






      active

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      active

      oldest

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      active

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      2














      PHP natively understands JSON, so turn it into an array, then use array_merge:



      $originalArray = json_decode('{"5ba68024f109b61fe95ccd02":"asistent","5bd0c379f109b673c11c9502":"seller","5be0addcf109b64c847abd26":"coder","5be0b26af109b64c847abd2c":"teacher","5becab8cf109b676d935e289":"engineer"}', true);
      

      
$newArray = array_merge(['no_job' => 'Please select an option'], $originalArray);
      

      
print json_encode($newArray);





      share|improve this answer


























        2














        PHP natively understands JSON, so turn it into an array, then use array_merge:



        $originalArray = json_decode('{"5ba68024f109b61fe95ccd02":"asistent","5bd0c379f109b673c11c9502":"seller","5be0addcf109b64c847abd26":"coder","5be0b26af109b64c847abd2c":"teacher","5becab8cf109b676d935e289":"engineer"}', true);
        

        
$newArray = array_merge(['no_job' => 'Please select an option'], $originalArray);
        

        
print json_encode($newArray);





        share|improve this answer
























          2












          2








          2






          PHP natively understands JSON, so turn it into an array, then use array_merge:



          $originalArray = json_decode('{"5ba68024f109b61fe95ccd02":"asistent","5bd0c379f109b673c11c9502":"seller","5be0addcf109b64c847abd26":"coder","5be0b26af109b64c847abd2c":"teacher","5becab8cf109b676d935e289":"engineer"}', true);
          

          
$newArray = array_merge(['no_job' => 'Please select an option'], $originalArray);
          

          
print json_encode($newArray);





          share|improve this answer












          PHP natively understands JSON, so turn it into an array, then use array_merge:



          $originalArray = json_decode('{"5ba68024f109b61fe95ccd02":"asistent","5bd0c379f109b673c11c9502":"seller","5be0addcf109b64c847abd26":"coder","5be0b26af109b64c847abd2c":"teacher","5becab8cf109b676d935e289":"engineer"}', true);
          

          
$newArray = array_merge(['no_job' => 'Please select an option'], $originalArray);
          

          
print json_encode($newArray);






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 22 at 19:42









          ceejayoz

          140k34215299




          140k34215299

























              2














              To add the key and value at the beginning of the string, turn your json into an associative array using json_decode and true as the second parameter. Then you could use the union + operator:



              $job_list = json_decode(' {"5ba68024f109b61fe95ccd02":"asistent","5bd0c379f109b673c11c9502":"seller","5be0addcf109b64c847abd26":"coder","5be0b26af109b64c847abd2c":"teacher","5becab8cf109b676d935e289":"engineer"}
              
', true);
              
$job_list = ['no_job' => 'Please select an option'] + $job_list;
              
echo json_encode($job_list);


              Result:



              {"no_job":"Please select an option","5ba68024f109b61fe95ccd02":"asistent","5bd0c379f109b673c11c9502":"seller","5be0addcf109b64c847abd26":"coder","5be0b26af109b64c847abd2c":"teacher","5becab8cf109b676d935e289":"engineer"}





              share|improve this answer




























                2














                To add the key and value at the beginning of the string, turn your json into an associative array using json_decode and true as the second parameter. Then you could use the union + operator:



                $job_list = json_decode(' {"5ba68024f109b61fe95ccd02":"asistent","5bd0c379f109b673c11c9502":"seller","5be0addcf109b64c847abd26":"coder","5be0b26af109b64c847abd2c":"teacher","5becab8cf109b676d935e289":"engineer"}
                
', true);
                
$job_list = ['no_job' => 'Please select an option'] + $job_list;
                
echo json_encode($job_list);


                Result:



                {"no_job":"Please select an option","5ba68024f109b61fe95ccd02":"asistent","5bd0c379f109b673c11c9502":"seller","5be0addcf109b64c847abd26":"coder","5be0b26af109b64c847abd2c":"teacher","5becab8cf109b676d935e289":"engineer"}





                share|improve this answer


























                  2












                  2








                  2






                  To add the key and value at the beginning of the string, turn your json into an associative array using json_decode and true as the second parameter. Then you could use the union + operator:



                  $job_list = json_decode(' {"5ba68024f109b61fe95ccd02":"asistent","5bd0c379f109b673c11c9502":"seller","5be0addcf109b64c847abd26":"coder","5be0b26af109b64c847abd2c":"teacher","5becab8cf109b676d935e289":"engineer"}
                  
', true);
                  
$job_list = ['no_job' => 'Please select an option'] + $job_list;
                  
echo json_encode($job_list);


                  Result:



                  {"no_job":"Please select an option","5ba68024f109b61fe95ccd02":"asistent","5bd0c379f109b673c11c9502":"seller","5be0addcf109b64c847abd26":"coder","5be0b26af109b64c847abd2c":"teacher","5becab8cf109b676d935e289":"engineer"}





                  share|improve this answer














                  To add the key and value at the beginning of the string, turn your json into an associative array using json_decode and true as the second parameter. Then you could use the union + operator:



                  $job_list = json_decode(' {"5ba68024f109b61fe95ccd02":"asistent","5bd0c379f109b673c11c9502":"seller","5be0addcf109b64c847abd26":"coder","5be0b26af109b64c847abd2c":"teacher","5becab8cf109b676d935e289":"engineer"}
                  
', true);
                  
$job_list = ['no_job' => 'Please select an option'] + $job_list;
                  
echo json_encode($job_list);


                  Result:



                  {"no_job":"Please select an option","5ba68024f109b61fe95ccd02":"asistent","5bd0c379f109b673c11c9502":"seller","5be0addcf109b64c847abd26":"coder","5be0b26af109b64c847abd2c":"teacher","5becab8cf109b676d935e289":"engineer"}






                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited Nov 22 at 20:00

























                  answered Nov 22 at 19:46









                  The fourth bird

                  20.2k71326




                  20.2k71326






























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